Based on historical data at Oxnard college, they believe that 34% of freshmen do not visit their advisors regularly. For this year, you would like to obtain a new sample to estimate the proportion of freshmen who do not visit their advisors regularly. You would like to be 95% confident that your estimate is within 4% of the true population proportion. How large of a sample size is required?

True. In compound time signatures, the top number represents the number of beats per measure. Compound time signatures are typically used for music that has a more complex rhythmic structure, and they are characterized by the subdivision of each beat into three equal parts (known as triplets).

The most common compound time signatures are 6/8, 9/8, and 12/8, with each representing six, nine, and twelve beats per measure respectively.
In 6/8 time, for example, there are two beats per measure, each of which is subdivided into three equal parts. This results in a feeling of two larger beats, each consisting of three smaller beats. In 9/8 time, there are three beats per measure, each of which is subdivided into three equal parts. This results in a feeling of three larger beats, each consisting of three smaller beats. Similarly, in 12/8 time, there are four beats per measure, each of which is subdivided into three equal parts, resulting in a feeling of four larger beats, each consisting of three smaller beats.
Overall, the top number in a compound time signature represents the number of larger beats per measure, while the bottom number represents the duration of each beat (usually an eighth note).

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The given system of equations has no solutions.

To determine the number of solutions for the given system of equations, let's analyze the equations:

Equation 1: 2x + y = 3

Equation 2: -2x - y = -6

We can solve this system of equations using the method of elimination or substitution.

Method 1: Elimination

If we add both equations, we get:

(2x + y) + (-2x - y) = 3 + (-6)

2x + y - 2x - y = -3

0 = -3

Since 0 does not equal -3, we have a contradiction. The left side of the equation simplifies to 0, but the right side is -3. This means that the system of equations is inconsistent and has no solutions. The lines represented by the equations are parallel and will never intersect.

Therefore, the given system of equations has no solutions.

Alternatively, we can also visualize this geometrically. The first equation represents a line, and the second equation represents another line. Since the lines are parallel, they will never intersect, indicating that there are no solutions.

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The percentag.e of female college runners between 114 - 138 pounds is 82%

Given that X is normally distributed with mean μ = 122 pounds and standard deviation σ = 8 pounds.

We want to find [tex]P(114 < X < 138)[/tex]

To get this, we will standardize X first:

[tex]P(114 < X < 138) = P((114 - 122)/8 < (X - 122)/8 < (138 - 122)/8)[/tex]

= P(-1 < Z < 2)

Using standard normal table, we find that probability of Z falling between -1 and 2 is:

= 0.8186

That means:

[tex]P(114 < X < 138)[/tex] = 0.8186

[tex]P(114 < X < 138)[/tex] = 81.86%

[tex]P(114 < X < 138)[/tex] = 82%

Missing options:

(A)18% (B) 32% (C) 68% (D) 82% (E)95%

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14 yards per minute is equal to 8.4 inches per second.

Unit multipliers is a method that is used to convert a measurement from one unit to another.

It is done by multiplying the main measurement by a fraction or ratio that is equal to one.

1 yard = 36 inches.

1 minute = 60 seconds.

We can cross multiply all there variables

14 yards/minute × (36 inches/1 yard) × (1 minute/60 seconds)

(14 /1) × (36/1) × (1/60)

14 × 36 × 1/60

(14 × 36) / 60

504 / 60

= 8.4

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Based on the information we can infer that Sophie is a Savvy Shopper.

A "savvy shopper" is an informal term used to refer to a person who is an expert in finding and taking advantage of the best deals and promotions when shopping. Another outstanding characteristic of these people is that they plan their purchases in advance and take advantage of promotions and discounts.

According to the above, we can infer that if Sophie is a bargain shopper who collects coupons and plans her route to take advantage of sales. She is a savvy shopper.

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The length of the curve is 20√40 units.

To find the distance traveled by the particle as t varies from 0 to 2√40, we need to integrate the speed function, which is the magnitude of the velocity vector. The velocity vector is given by:

v(t) = (x'(t), y'(t)) = (10 sin(t) cos(t), -10 sin(t) cos(t))

The magnitude of the velocity vector is given by:

|v(t)| = √((10 sin(t) cos(t))^2 + (-10 sin(t) cos(t))^2) = 10 |sin(t) cos(t)|

So the distance traveled by the particle is given by:

D = ∫(0 to 2√40) |v(t)| dt = ∫(0 to 2√40) 10 |sin(t) cos(t)| dt

Using the identity sin(2t) = 2 sin(t) cos(t), we can simplify this to:

D = ∫(0 to 2√40) 5 sin(2t) dt = [-5 cos(2t)](0 to 2√40) = 5(cos(0) - cos(4√10)) = 10

So the distance traveled by the particle is 10 units.

To compare this with the length of the curve, we can use the formula for the arc length of a curve given by:

l = ∫(a to b) √(x'(t)² + y'(t)²) dt

Substituting the given values, we get:

l = ∫(0 to 2√40) √((10 sin(t) cos(t))² + (-10 sin(t) cos(t))²) dt

Simplifying this, we get:

l = ∫(0 to 2√40) 10 dt = 20√40

We can see that the distance traveled by the particle (10 units) is half of the length of the curve (20√40 units). This is because the particle completes one full cycle in the given time interval, and the length of one cycle of the curve is twice the distance traveled by the particle during that cycle.

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Answer:

Ramon's null hypothesis (H0) is that the proportion of blue jelly beans in each bag is 30%:H0: p = 0.30His alternative hypothesis (Ha) is that the proportion of blue jelly beans in each bag is greater than 30%:Ha: p > 0.30To test this hypothesis, Ramon uses a significance level of alpha equals 0.1, which means that he is willing to accept a 10% chance of making a Type I error (rejecting the null hypothesis when it is true).From the sample of 25 bags of jelly beans, Ramon calculates a sample proportion of blue jelly beans of 36%. He then uses this value to calculate a test statistic and a corresponding p-value of 0.256.Since the p-value (0.256) is greater than the significance level (0.1), Ramon fails to reject the null hypothesis. This means that he does not have enough evidence to conclude that the proportion of blue jelly beans in each bag is significantly greater than 30%. It is possible that the observed difference in the sample proportion is due to random sampling variability.In other words, Ramon's conclusion is that there is not enough evidence to support his belief that there are actually a greater proportion of blue jelly beans than the specified 30%. He should not make any changes to the production or distribution process based on this sample result

Step-by-step explanation:

Answer:

See below!

Step-by-step explanation:

From the figure,

∠8 = ∠4 (Corresponding angles are equal)

So,

∠8 = 2x + 27

Also,

∠5 = ∠7 (Vertically opposite angles are equal)

∠5 = 3x - 22

So,

∠8 + ∠5 = 180°

2x + 27 + 3x - 22 = 180

2x + 3x + 27 - 22 = 180

5x + 5 = 180

5x = 180 - 5

5x = 175

x = 175 / 5

So,

∠8 = 2x + 27

∠8 = 2(35) + 27

∠8 = 70 + 27

Now,

∠5 = 3x - 22

∠5 = 3(35) - 22

∠5 = 105 - 22

[tex]\rule[225]{225}{2}[/tex]

The two points at which the line intersects the curve are (2, -2) and (4/3, -4).

To find the coordinates of the point at which the line with a gradient of 3 intersects the curve y = 3x² - 7x after passing through the point (2, -2), we can set the equation of the line equal to the equation of the curve and solve for x and y.

The equation of the line passing through (2, -2) with a gradient of 3 can be written as:

y = 3x - 8

Substituting this equation into the curve equation, we get:

3x - 8 = 3x² - 7x

Simplifying the equation:

3x² - 10x + 8 = 0

We can solve this quadratic equation to find the values of x. Using factoring or the quadratic formula, we find:

(x - 2)(3x - 4) = 0.

Setting each factor equal to zero:

x - 2 = 0 --> x = 2

3x - 4 = 0 --> x = 4/3

So, there are two possible x-values where the line can intersect the curve: x = 2 and x = 4/3.

Now, we can substitute these x-values back into the equation of the line to find the corresponding y-values:

For x = 2:

y = 3(2) - 8 = 6 - 8 = -2

For x = 4/3:

y = 3(4/3) - 8 = 4 - 8 = -4

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The ball hits the ground after a time of 3.05 seconds.

The quadratic function giving the ball's height after t seconds is given as follows:

h(t) = -16.1t² + 150.

(In which -16.1 is the gravity's effect, while 150 is the initial height).

The ball hits the ground when the height function has a numeric value of zero, that is:

h(t) = 0.

Hence the time is obtained solving the equation, isolating the variable t, as follows:

-16.1t² + 150 = 0

16.1t² = 150

t² = 150/16.1

[tex]t = \sqrt{\frac{150}{16.1}}[/tex]

t = 3.05 seconds.

The complete problem is:

The quadratic function h(t)=-16.1t^2 + 150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15 story building. After how many seconds, rounded to the nearest hundredth, did the ball hit the ground?

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The laptop will be worth $594.48 in two years.

To find the value of the laptop in two years, we need to substitute the given values into the formula:

Value = P x (1 - r)ⁿ

In this case, the original value of the laptop is $700, and it depreciates at a rate of 0.08 per year (which is 8% expressed as a decimal). We want to find the value in two years, so t = 2.

Substituting the values into the formula:

Value = $700 x (1 - 0.08)²

Value = $700 x (0.92)²

Value ≈ $700 x 0.8464

Value ≈ $594.48

Therefore, the laptop will be worth $594.48 in two years.

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The measure of <HOL = 35 degree.

We have,

Exterior of <OID= 125

Now, in Triangle ODI

<OID + <OIA = 180 (linear Pair)

125 + <OIA = 180

<OIA = 55

Now, using Angle Sum property

<ODI + <IOD + <DIO = 180

55+90+ <IOD = 180

<IOD = 180 - 145

<IOD = 35

So, <IOD = <HOL (vertically opposite angle)

<HOL = 35 degree

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Answer:108.12$

Step-by-step explanation:

Dwayne will get a discount of 15% on the price of the bowling ball which is $120. The discount will be $18. So the price of the bowling ball after the discount is $102.

Dwayne will have to pay 6% sales tax on the discounted price of the bowling ball which is $102. The sales tax will be $6.12.

Therefore, the final price Dwayne has to pay for the bowling ball is $108.12.

Answer:

108.12 bc it says don't use a label

Step-by-step explanation:

15% can be written as 0.15. Same thing.

So first the discount:

120 x 0.15 = $18

He'll get an $18 discount.

120-18 = $102. That's the discounted price he'll pay.

6% tax can be written as 0.06.

$102 x 0.06 = $6.12 That's the tax he needs to pay

So in total he'll pay $102 + $6.12 = $108.12

Your question says no label so just answer 108.12.

The five-number summary, as shown in the MINITAB output, includes the minimum value, Q1 (the first quartile), the median (Q2), Q3 (the third quartile), and the maximum value.

To calculate the interquartile range (IQR), we need to find the difference between Q3 and Q1. In this case, Q1 is 6 and Q3 is 11, so the IQR is 5.
To determine if there are any outliers in the data set, we can use the rule that any data points that are more than 1.5 times the IQR below Q1 or above Q3 are considered outliers. In this case, the lower limit would be 6 - (1.5 x 5) = -1.5 and the upper limit would be 11 + (1.5 x 5) = 18.5. Looking at the data in column 1, we can see that there are no values that fall outside of these limits, so there are no outliers in this set of data.
Using statistics software to calculate the five-number summary, IQR, and identify outliers is a quick and efficient way to analyze data. This information can provide valuable insights into the distribution of the data and help identify any potential issues or trends that need to be addressed.

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The answers to the information about the sets are:

(i) n(M) = 20 and n(S) = 30.

(ii) 10 students failed in both subjects.

(iii) No students passed in both subjects.

(iv) The number of students who passed in both subjects is 0.

(i) To find the value of n(M) and n(S), we need to calculate the number of students who passed in Mathematics (M) and Social Studies (S).

To find n(M) (number of students who passed in Mathematics):

n(M) = Number of students who passed in Mathematics - Number of students who failed in both subjects

n(M) = 30 - 10 = 20

To find n(S) (number of students who passed in Social Studies):

n(S) = Number of students who passed in Social Studies - Number of students who failed in both subjects

n(S) = 40 - 10 = 30

Therefore, n(M) = 20 and n(S) = 30.

(ii) To find the total number of students who failed in both subjects:

Number of students who failed in both subjects = 10

Therefore, 10 students failed in both subjects.

(iii) To find the number of students who passed in both subjects:

Number of students who passed in both subjects = Number of students who passed in Mathematics + Number of students who passed in Social Studies - Total number of students in the class

Number of students who passed in both subjects = 20 + 30 - 75

Number of students who passed in both subjects = 50 - 75

Number of students who passed in both subjects = -25 (Since the result is negative, it means no students passed in both subjects.)

Therefore, no students passed in both subjects.

(iv) The number of students who passed in both subjects is 0 (as calculated in part (iii)), indicating that there are no students who passed in both subjects.

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6√3 inches is the length of the altitude of the equilateral triangle.

Let x be the length of one side of the equilateral triangle.

The perimeter of the equilateral triangle is 3x since all sides are equal.

So, 3x = 36 inches.

Dividing by 3 on both sides, we get x = 12 inches.

Let h be the altitude of the equilateral triangle.

The altitude bisects the base of the equilateral triangle and creates two right triangles, each with a base of 6 inches (half of 12 inches) and a hypotenuse of 12 inches (the side of the equilateral triangle).

Using the Pythagorean theorem, we can find the height of the right triangle:

[tex]h^2 + 6^2 = 12^2\\\\h^2 + 36 = 144\\\\h^2 = 108\\\\h = sqrt{(108)} = 6\sqrt3\ inches.[/tex]

Therefore, the length of the altitude of the equilateral triangle is h = 6√3 inches.

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The proof that AC=2AB when B is the midpoint of segment AC involves the use of the given statement, segment addition postulate, definition of midpoint, and substitution method.

To prove that AC=2AB when B is the midpoint of segment AC, follow these steps:

Thus, by these steps, you can see that when B is the midpoint of AC, the length of segment AC is twice the length of segment AB.

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The gradient of the line, which is also the slope of the line is calculated as: m = -2.

The gradient of a line is the same as the slope of a line. It is calculated using the same slope formula which can be expressed as:

Gradient of a line (m) = change in y / change in x = rise/run = y2 - y1 / x2 - x1.

To calculate the gradient of the line, choose any two points on the graph:

(0, 5) = (x1, y1)

(3, -1) = (x2, y2)

Plug in the values into the formula:

Gradient of the line = (-1 - 5) / (3 - 0)

Gradient = -6/3 = -2.

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The area that was cut out is  457cm²

The formula for calculating the area of a semi-circle is expressed as;

A = 1/2 πr²

Given that the diameters = 2 radius

Radius = 20/2 = 10cm

Substitute the values

Area = 1/2 × 3.14 × 10²

Find the square and substitute

Area = 157 cm²

Area of the triangle = 1/2 × b  × h

Such that 'b' is the base and 'h' is the height

Substitute the values

Area = 1/2 × 20 × 30

Multiply the values

Area = 300cm²

Area cut out = 300 + 157 = 457cm²

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The measure of the angle μ∠ABD subtended by the arc AD at the circumference is equal to 27°

The angle subtended by an arc of a circle at it's center is twice the angle it substends anywhere on the circles circumference. Also the arc measure and the angle it subtends at the center of the circle are directly proportional.

arc AD = 2(μ∠ABD)

Also arc AD = 54°

2(μ∠ABD) = 54°

μ∠ABD = 54°/2 {divide through by 2}

μ∠ABD = 27°

Therefore, the measure of the angle μ∠ABD subtended by the arc AD at the circumference is equal to 27°

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Answer:

Out of the 200 students Judah asked, 60 said yes when asked if they play basketball while 140 said no. To determine the percentage of students who played basketball, we can divide the number of students who said yes by the total number of students and then multiply by 100. 

So, the percentage of students who played basketball is (60/200) x 100 = 30%.

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The area of the bounded region is 946.46 square units (rounded to two decimal places).

To find the area of the region bounded by the curves, we need to find the points of intersection between the curves.

Setting the two equations equal to each other gives:

110x² = x

Simplifying:

110x² - x = 0

Factor out x:

x(110x - 1) = 0

Solve for x:

x = 0 or x = 1/110

So the two curves intersect at x=0 and x=1/110.

To find the area, we integrate y=110x² from x=-4 to x=1/110 and y=x from x=1/110 to x=8.

∫(110x²) dx from x=-4 to x=1/110 + ∫x dx from x=1/110 to x=8

= (110/3)(1/110)³ - (-4)(110) + (1/2)(8²) - (1/2)(1/110)²

= 946.46 square units (rounded to two decimal places)

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The statement you provided is correct. In a period of rising prices, the cost of goods sold (COGS) will be lower if the items sold were purchased at a lower cost in a previous period. The ending inventory, on the other hand, will represent items purchased at a higher cost in the current period.

This is where the choice of inventory costing method comes into play. The FIFO (first in, first out) method assumes that the items sold are those that were purchased first, leaving the most recently purchased items in ending inventory. As a result, the COGS will reflect the lower cost of the earlier purchased items, leading to a lower COGS overall. Therefore, in a period of rising prices, the FIFO method will produce the lowest amount of COGS.

However, it is important to note that the choice of inventory costing method can also affect the valuation of ending inventory and ultimately impact the financial statements of a company.

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(a) The correlation coefficient between 1/2y1 and 3/4y2 is 0.2. (b) The correlation coefficient between 1/2y1 and 3/-4y2 is -0.2. (c) The correlation coefficient between 1/-2y1 and 3/-4y2 is 0.2.

The correlation coefficient measures the linear relationship between two variables and takes values between -1 and 1. If the correlation coefficient is positive, then the variables tend to increase or decrease together, while a negative correlation coefficient indicates that the variables tend to move in opposite directions. In this problem, the correlation coefficient between y1 and y2 is given as 0.2.

To find the correlation coefficient between the given combinations of variables, we use the formula r_xy = cov(x,y) / (s_x * s_y), where cov(x,y) is the covariance between x and y, and s_x and s_y are their respective standard deviations. We also use the properties of covariance and standard deviation to simplify the calculations.

For example, for part (a), we have cov(1/2y1, 3/4y2) = (1/2)(3/4)cov(y1,y2) = (3/8)(0.2)(5)(5) = 1.5, and s_x = (1/2)(5) = 2.5 and s_y = (3/4)(5) = 3.75, so r_xy = 1.5 / (2.5 * 3.75) = 0.2. Similarly, we can compute the correlation coefficients for parts (b) and (c).

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The length of XY in the shaded sector that has an area of 3/2pi is calculated as: XY = 2 units.

The area of a shaded sector = ∅/360 * πr², where r is the radius and ∅ is the central angle.

Given the following:

m<YXZ (∅) = 135 degrees

Area of the shaded sector = 3/2π

Radius (r) = XY = ?

Substitute the values:

3/2π = 135/360 * πr²

Solve for r (XY):

1.5π = 0.375 * πr²

Divide both sides by 0.375π:

1.5π/0.375π = r²

4 = r²

r = 2

XY = 2 units

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The result of applying formula 4 of the given theorem to the functions u(t) and v(t) is d/dt(u(t) · v(t)) = -20cos(4t) + 5cos(5t) + tcos(4t) + 5tsin(5t).

Formula 4 of the theorem states that the derivative of the product of two functions u(t) and v(t) is equal to u'(t)v(t) + u(t)v'(t).

In this case, we first take the derivative of u(t) and v(t) separately and then substitute into the formula to obtain the derivative of their product.

Applying this formula to the given functions u(t) = sin(5t), cos(4t), t and v(t) = t, cos(4t), sin(5t), we get d/dt(u(t) · v(t)) = (-5sin(5t))(t) + (cos(5t))(cos(4t)) + (1)(cos(4t)) + (tsin(5t))(5cos(5t)). Simplifying the expression gives us d/dt(u(t) · v(t)) = -20cos(4t) + 5cos(5t) + tcos(4t) + 5tsin(5t).

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The value of the given integral is 0.

The given integral is a double integral over the region R bounded by the x-axis, the line x=1, and the parabola y=x³. To evaluate this integral, we can use iterated integration, integrating first with respect to x and then with respect to y.

The limits of integration for x are from 0 to 1, since x varies from the y-axis to the line x=1. The limits of integration for y are from 0 to 1, since y varies from the x-axis to the point where y=x³ intersects the line x=1.

Evaluating the integral, we get:

∫[0,1] ∫[0,x³] (1-x³) dy dx

= ∫[0,1] [(1-x³) * x³] dx

= ∫[0,1] (x³ - x⁶) dx

= [1/4 - 1/7]

= 0.017857

Therefore, the value of the given integral is 0.

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The statement is true. If a matrix B can be expressed as B = PDP^T, where P is an invertible matrix and D is a diagonal matrix, then B is a symmetric matrix.

This can be proven as follows:
First, let's take the transpose of B:

B^T = (PDP^T)^T = (P^T)^TD^T P^T

Since D is a diagonal matrix, its transpose is equal to itself:

D^T = D

Therefore, we can substitute D^T with D in the above equation:

B^T = PDP^T = B

Since B is equal to its transpose, it is a symmetric matrix.

In other words, if a matrix B can be diagonalized by an orthogonal matrix P, which means that P^T=P^-1, then B is a symmetric matrix. This is because orthogonal matrices preserve the dot product and the symmetry of a matrix. The diagonal matrix D represents the eigenvalues of B, which can be either positive, negative, or zero. Therefore, if all the eigenvalues of B are non-negative, then B is positive definite, and if they are non-positive, then B is negative definite. If some eigenvalues are positive and some are negative, then B is indefinite.

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The ramp will rise approximately 15.95 inches from the ground at its highest end. Rounded to the nearest hundredth of an inch, the height is 15.95 inches.

To find the height the ramp will rise from the ground at its highest end, we can use trigonometry. The tangent function relates the angle of elevation (28°) to the height of the ramp.

Let's denote the height of the ramp as h. We can set up the equation:

tan(28°) = h / 30

To find h, we can rearrange the equation:

h = tan(28°) × 30

Using a calculator, we can calculate the value of tan(28°) ≈ 0.5317. Plugging this value into the equation, we get:

h = 0.5317 × 30

h ≈ 15.95

Therefore, the ramp will rise approximately 15.95 inches from the ground at its highest end. Rounded to the nearest hundredth of an inch, the height is 15.95 inches.

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