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When 3.915 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 12.74 grams of CO2 and 3.913 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 54.09 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon.
Answer: The empirical formula and the molecular formula of the hydrocarbon is [tex]C_2H_3[/tex] and [tex]C_4H_6[/tex] respectivley.
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
[tex]C_xH_y+O_2\rightarrow CO_2+H_2O[/tex]
where, 'x', 'y' are the subscripts of Carbon, hydrogen
We are given:
Mass of [tex]CO_2[/tex] = 12.74 g
Mass of [tex]H_2O[/tex]= 3.913 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 12.74 g of carbon dioxide, =[tex]\frac{12}{44}\times 12.74=3.474g[/tex] of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 3.913 g of water, =[tex]\frac{2}{18}\times 3.913=0.435g[/tex] of hydrogen will be contained.
Mass of C = 3.474 g
Mass of H = 0.435 g
Step 1 : convert given masses into moles.
Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{3.474g}{12g/mole}=0.289moles[/tex]
Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.435g}{1g/mole}=0.435moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =[tex]\frac{0.289}{0.289}=1[/tex]
For H =[tex]\frac{0.435}{0.289}=1.5[/tex]
The ratio of C : H = 1: 1.5
The whole number ratio will be = 2: 3
Hence the empirical formula is [tex]C_2H_3[/tex].
The empirical weight of [tex]C_2H_3[/tex] = 2(12.01)+3(1.008)= 27.04 g.
The molecular weight = 54.09 g/mole
Now we have to calculate the molecular formula.
[tex]n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{54.09}{27.04}=2[/tex]
The molecular formula will be=[tex]2\times C_2H_3=C_4H_6[/tex]
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Answer:
If capital R is round, than the RR and Rr will mean round, and the two rr's are wrinkled. that means the answer to both is 50%
Explanation:
hope that helps
Write the Ground state electron configuration of Ca using the noble-gas shorthand notation
Answer:
[Ar] 4s2
Explanation:
The noble gas that comes before Ca is Ar, so that's what you'll use for the noble-gas shorthand part of it. Ca has two additional electrons in the 4s orbital, hence the 4s2.
The ground state electronic configuration of calcium using noble gas short hand notation is [Ar]4s².
What is noble gas short hand notation ?Noble gas short hand notation comprises of the symbol of the last noble gas which is prior to the concerned atom which is followed by the configuration of the electrons which remains.
This notation helps in shortening of electronic configuration which is otherwise huge for elements with high atomic numbers.This is possible cause it uses the preceding noble gas configuration which accounts for that many electrons and the remaining electrons are filled in the next higher sub shell.
For calcium, preceding noble gas is argon which accounts for 18 electrons and for remaining two electrons they are placed in 4s sub shell thus making the total count of electrons to 20.
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A sample of hydrogen has an initial temperature of 122.0 °F. When the temperature is lowered to -23.0 °F, the volume of hydrogen becomes 212 cm3. What was the initial volume of the hydrogen?
Answer: The initial volume of gas was [tex]282cm^3[/tex]
Explanation:
Charles's Law: This law states that volume is directly proportional to temperature of the gas at constant pressure and number of moles.
[tex]V\propto T[/tex] (At constant pressure and number of moles)
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1[/tex] = initial volume of gas =?
[tex]V_2[/tex] = final volume of gas = [tex]212cm^3[/tex]
[tex]T_1[/tex] = initial temperature of gas = [tex]122.0^0F=323.15K[/tex]
[tex](32^0C=273.15K)[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]-23.0^0F=242.59K[/tex]
[tex]\frac{V_1}{323.15}=\frac{212}{242.59}[/tex]
[tex]V_2=282cm^3[/tex]
Therefore, the initial volume of gas was [tex]282cm^3[/tex]
Determine the mass in grams of 4.69 x 1021 atoms of barium. (The
mass of one mole of barium is 137.33 g.)
Answer:
1.07 g Ba
Explanation:
Hello there!
In this case, according to the definition of the Avogadro's number and the molar mass, it is possible to say that 6.022x10^{23} atoms of barium equal one mole, and at the same time, 1 mole equals 137.327 grams of this element; thus, it is possible to say that 6.022x10^{23} atoms of barium have a mass of 137.327 grams; therefore, it i possible for us to calculate the required mass in grams as shown below:
[tex]4.69x10^{21}atoms*\frac{137.327gBa}{6.022x10^{23} atoms} \\\\=1.07gBa[/tex]
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Can somebody please help me!!!
Answer:
speed
Explanation:
Speed is the rate at which something moves. The speed of light is faster than the speed of sound.
In solution, strong acids and bases ionize completely, but weak acids and bases ionize only partially.
Answer:
A weak acid is one that does not dissociate completely in solution; this means that a weak acid does not donate all of its hydrogen ions (H+) in a solution. ... Therefore, the concentration of H+ ions in a weak acid solution is always less than the concentration of the undissociated species, HA.
Explanation:
Hope it helps
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What is the percent of Cu in CuSO4?
A 10.0-mL sample of sulfuric acid, H2SO4, from a battery of an old car is diluted to 100.0 mL, and a 10.00-mL aliquot (portion) of the diluted acid is then titrated with 0.2500 M NaOH solution. If the concentration of H2SO4 in the original battery was 3.25 M, how many milliliters (mL) of the NaOH solution is required to titrate the sulfuric acid present in the 10.0-mL portion of dilute acid solution
Answer:
26.0 mL
Explanation:
The reaction that takes place is:
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂OFirst we calculate the molar concentration of the diluted sulfuric acid solution, using the C₁V₁=C₂V₂ formula:
3.25 M * 10.0 mL = C₂ * 100 mLC₂ = 0.325 MNow we calculate how many H₂SO₄ moles would there be in 10.00 mL of this diluted solution, using the definition of molarity:
0.325 M * 10.00 mL = 3.25 mmol H₂SO₄Then we convert 3.25 mmoles of H₂SO₄ into mmoles of NaOH, using the stoichiometric coefficients of the balanced reaction:
3.25 mmol H₂SO₄ * [tex]\frac{2mmolNaOH}{1mmolH_2SO_4}[/tex] = 6.5 mmol NaOHFinally we calculate the required volume of the NaOH solution, using the definition of molarity:
6.5 mmol NaOH / 0.2500 M = 26.0 mLWhich solute generally creates aqueous solutions with lower freezing points? Explain why this substance has a greater effect on the freezing point.
pls help! ^^
Answer:
The freezing point depression can be calculated using the pure solvent freezing point and the molality of the solution.
At the freezing point, the vapor pressure of both the solid and liquid form of a compound must be equal.
The freezing point of a substance is the temperature at which the solid and liquid forms are in equilibrium.
To reattain equilibrium, the freezing point of the solute and solvent mixture is lowered relative to the original pure solvent.
what is the formal charge in SeCl4?
What occurs during interphase? (Select all that apply.)
cells store up energy
cells produce eight daughter cells
cells take in nutrients
cells grow
Answer:
during interphase the cells start to grow
cells grow, store up energy, and take in nutrients
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What must take place for an ionically bonded substance to melt?
Answer:
Heat reaction
Explanation:
Heat must be applied in order to melt a substance.
Equation: CH4 + 202 CO2 + 2H20
What is the mole ratio between oxygen and methane (CH4)? If you use 15 moles of 02, how many grams of methane would you predict would be needed?
Answer:
2:1
1.2 × 10² g
Explanation:
Step 1: Write the balanced combustion equation
CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of O₂ to CH₄ is 2:1.
Step 3: Calculate the moles of CH₄ required to react with 15 moles of O₂
We will use the previously established molar ratio.
15 mol O₂ 1 mol CH₄/2 mol O₂ = 7.5 mol CH₄
Step 4: Calculate the mass corresponding to 7.5 moles of CH₄
The molar mass of CH₄ is 16.04 g/mol.
7.5 mol × 16.04 g/mol = 1.2 × 10² g
name the following substances
KCl
FeCl2
CuSO4
Al2O3
Fe2O3
Potassium chloride
Iron (II) chloride
Copper (II) sulfate
Aluminum oxide
Iron (III) oxide
Remember to put roman numerals for the compounds where the metal has more than one possible oxidation state. For example, you see iron here with a +2 charge in one compound and then +3 charge in another. If the metal only has one possible oxidation state (like potassium and aluminum), you don't need a roman numeral.
chemistry in formula of water
Answer: Unbalanced : H2O
Balanced : 2H2O
Explanation:
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H2O
Explanation:
Water (chemical formula: H2O) is a transparent fluid which forms the world's streams, lakes, oceans and rain, and is the major constituent of the fluids of organisms. As a chemical compound, a water molecule contains one oxygen and two hydrogen atoms that are connected by covalent bonds.
how atom split go boom boom? :)
Answer:
To split an atom a neutron, traveling at an accurate speed must be shot at the nucleus.
Explanation:
How many moles are in 3.86 x 1023 molecules of Carbon Dioxide (CO2)?
Answer:
0.64 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
[tex]n = \frac{N}{L} [/tex]
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
[tex]n = \frac{3.86 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{3.86}{6.02} \\ = 0.641196...[/tex]
We have the final answer as
0.64 molesHope this helps you
Ultrasound waves do not transmit easily through bone. State what you think happens to ultrasound waves when they reach a bone in the body. Give evidence to support your claim and explain your answer.
Answer:
See explanation
Explanation:
Echo is the reflection of sound waves. Recall that ultrasound are also sound waves of high frequency.
When ultra sound meets an obstacle such as a bone, it is reflected backwards and gives rise to an echo back in the transducer.
Since ultrasound is high frequency sound wave wave; It does not passes through bone due to the high density of the bone, the data required may now be collected.
Is carbon moving into the air moving out of the air or both
Answer:
Carbon is moving into the air
Consider the following exothermic process at equilibrium:
CO(g)+H2O(g)⇌CO2(g)+H2(g)
Which of the following changes would increase the amount of H2(g) present in the equilibrium mixture?
Consider the following exothermic process at equilibrium:
Which of the following changes would increase the amount of present in the equilibrium mixture?
decrease the temperature
increase [CO2]
increase [CO]
increase the volume of the container in which the reaction occurs.
more than one of the above
(Answer is not increase [CO])
For the given exothermic process at equilibrium, an increase in the concentration of CO would increase the amount of H₂.
How is equilibrium affected by changes?When a perturbation is done on a system at equilibrium, it shifts its equilibrium position to counteract the perturbation.
Let's consider the following exothermic process at equilibrium.
CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g)
Which of the following changes would increase the amount of H₂(g) present in the equilibrium mixture?
decrease the temperature. NO. For an exothermic reaction, a decrease in the temperature will shift the equilibrium towards the reactants.increase [CO₂]. NO. This would shift the equilibrium towards the reactants.increase [CO]. YES. This would shift the equilibrium towards the products.increase the volume of the container in which the reaction occurs. NO. This wouldn't affect the equilibrium since the number of gaseous moles is the same on both sides.more than one of the above. NO.For the given exothermic process at equilibrium, an increase in the concentration of CO would increase the amount of H₂.
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A reaction has activation energy of 85kjper mol. What is the effect on the rate of raising the temperature from 20degree to 30 degree
Answer: The rate increases 3 times on raising the temperature from 20degree to 30 degree
Explanation:
According to Arrhenius equation with change in temperature, the formula is as follows.
[tex]ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}][/tex]
where [tex]k_2[/tex] = rate constant at temp [tex]T_2[/tex]
[tex]k_1[/tex] = rate constant at temp [tex]T_1[/tex]
[tex]E_a[/tex]= activation energy
R= gas constant
[tex]T_1[/tex]= temperature = [tex]20^0C=(20+273)K=293K[/tex]
[tex]T_2[/tex]= temperature = [tex]30^0C=(30+273)K=303K[/tex]
[tex]ln \frac{k_{2}}{k_{1}} = \frac{-85\times 1000J/mol}{8.314J/Kmol}[\frac{1}{303} - \frac{1}{293}][/tex]
[tex]ln \frac{k_{2}}{k_{1}}=1.15[/tex]
[tex]\frac{k_{2}}{k_{1}}=3[/tex]
Thus rate increases 3 times on raising the temperature from 20degree to 30 degree
Graphite and diamond are both solid forms of the element carbon. Which statement explains
the different properties of these two forms of carbon?
(1) Diamond has ionic bonding and graphite has metallic bonding.
(2) Diamond has metallic bonding and graphite has ionic bonding.
(3) Diamond has a different crystal structure from graphite.
(4) Diamond has carbon atoms with more valence electrons than graphite.
Answer: C diamond has a different crystal structure from graphite
Explanation:
The difference between the properties of two forms of carbon is that
Diamond has a crystal structure different from graphite.
Graphite and Diamond are known as allotropes of Carbon as they have the
same chemical properties but different crystal structure.
Diamonds form a 3 crystal lattice with no flexibility while Graphite are
bonded to sheets which makes them slide easily within one another and
gives it its soft texture.
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The two main categories of energy are ___________________ energy (stored
energy) and __________________________ energy (energy presently doing
work or causing change).
Explanation:
The two main categories of energy are potential energy (stored
energy) and kinetic energy (energy presently doing
work or causing change)...I hope this helps.
predict the product of the following reaction Ba + P
There are three types
of atoms, which on gains and looses electrons?
Answer:
https://courses.lumenlearning.com/boundless-biology/chapter/atoms-isotopes-ions-and-molecules/
Explanation:
Any type of material or substance that has mass and volume is called
Answer:
Matter
Explanation:
In classical physics and general chemistry, matter is any substance that has mass and takes up space by having volume.
can boron bond with lithium
Answer:
No, they are not able to bond.
Explanation:
Hello there!
In this case, regarding chemical bonds, it is necessary to remember that these come up when a metal is bonded with a nonmetal, or, when two nonmetals get bonded; however, even there exist a type of denominated metallic, it is not eligible for boron and lithium because they tend to stable as cations (positive) and therefore, equal charges are not eligible for bonding, thus, boron and lithium would not be able to bond.
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pls help i will mark as brainliest
Answer:
ano po ito?? isa po ba itong story
Can someone help me please
Answer:
(14)The pH is 8.3 and is basic
(15) pOH = 11.0 The solution is acidic
Explanation:
(14) From the question,
pH = -log[H₃O⁺]............... Equation 1
Given: H₃O⁺ = 5.6×10⁻⁹ M
Substitute the value above into equation 1
pH = -log[5.6×10⁻⁹]
pH = 8.3
The pH is 8.25 and is basic.
(15)
pOH = -log[OH⁺]................ Equation 2
Given: [OH⁺] = 8.34×10⁻¹² M
Substitute into equation 2
pOH = -log[8.34×10⁻¹²]
pOH = 11.0 Hence the solution is acidic