Calculate the reaction rate given the following:
After 2 minutes (120 seconds), the concentration of a product was measured to
increase from 0.0012 M to 1.48 M.

1.48 M/s
0.0123 M/s
0.0012 M/s
-0.0123 M/s

Answers

Answer 1

Answer:

0.0123 M/s

Explanation:

Answer 2

The reaction rate is the rate at which the reaction takes place and results in an increased concentration of the products. The rate of the reaction is 0.0123 M/s.

What is the reaction rate?

The reaction rate is the increase of the concentration of the product with respect to time in seconds. The rate of reaction is given by,

[tex]\rm rate = \rm \dfrac {\Delta C}{\Delta t}[/tex]

Given,

Change in product concentration = 1.478

Time period = 120 seconds

Substituting values in the above equation:

[tex]\begin{aligned} \rm rate &= \rm \dfrac {\Delta C}{\Delta t}\\\\& = \dfrac{1.478}{120}\\\\&= 0.0123 \end{aligned}[/tex]

Therefore, option B. 0.0123 M/s is the reaction rate.

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I think its 10 moles, hope this helps.

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Answers

Answer:

D

Explanation:

all ya got to do is divide the moles from the solution... so 3.0 divided by 0.25. put it in a calculator

hope this helps

The molarity of a solution made from dissolving 3.0 moles of Saline (NaCl) in 0.25 L of solution is 12M.

What is Molarity?

Molarity of a given solution is known as the total number of moles of solute per litre of the solution.  A solution that is 1.00 molar (written 1.00 M) contains 1.00 mole of solute for every liter of solution.

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The unit of molarity is mol L⁻¹.

Molarity is temperature dependent because as temperature changes, volume of the solution also changes.

Given,

3.0 moles of Saline (NaCl)

Volume of solution = 0.25L

Molarity = (No. of moles of solute ÷ Volume of solution in liters)

Molarity = 3 ÷ 0.25 = 12 M

Therefore, The molarity of a solution made from dissolving 3.0 moles of Saline (NaCl) in 0.25 L of solution is 12M.

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#SPJ2

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Answers

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Answers

Answer:

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Answers

Answer:

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Explanation:

Hope it helps

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