Find the unknown side length, x. Write your answer in simplest radical form.
A. 3
B. 34
C. 6.
D. 41

Find The Unknown Side Length, X. Write Your Answer In Simplest Radical Form.A. 3B. 34C. 6.D. 41

Answers

Answer 1

Answer:

√41

Step-by-step explanation:

Considering the sides with lengths 48 and 52 units, we would use Pythagoras theorem to find the third side. Let that side be t

52² = 48² + t²

t² = 52² - 48²

= 2704 - 2304

= 400

t = √400

= 20

Considering the next triangle with sides t (20 units) and 12 units, again using the theorem

20² = 12² + y²

where y is the third side

400 = 144 + y²

y² = 400 - 144

= 256

y = √256

= 16 units

Considering the triangle with two sides given as 5 and 13 units, the third side (which is part of the 16 units calculated earlier)

13² = 5² + u²

where u is the 3rd side

169 = 25 + u²

u² = 169 - 25

u² = 144

u = √144

u = 12

The other part of the side of that triangle

= 16 - 12

= 4

Considering the smallest triangle whose sides are x, 5 and 4,

x² = 5² + 4²

= 25 + 16

= 41

x = √41


Related Questions

Which two points are on the graph of y=-x+ 3?
(-1,-2), (1,4)
(1, 2), (0, -3)
(0, 3), (4, -1)
(4, -1), (1, 3)

Answers

Answer:

(0, 3), (4, -1)

(1, 2)

Step-by-step explanation:

If the answers that have been provided to you are only in pairs then it'd just be the first answer I wrote. The points (1, 2) also are on the graph of y=x+3 but if the answers aren't individual than I'd just stick with the (0, 3), (4, -1). Does that make sense? I used a graphing calculator online called Desmos, it's very good. I highly recommend it for problems like these.

I hope this helps:) Select as brainliest because I actually put work into this and tried.

Amina sold 1/3 of her goats to a butcher and gave 1/6 of the remaining goats to her children. If she was left with 90 goats how many goats had she at the beginning?​

Answers

Answer:

180 goats

Step-by-step explanation:

3/3-1/3=2/3.

2/3=4/6 remaining.

4/6-1/6=3/6 which also equals 1/2.

If 90=1/2 then 90*2=180.

Hope this helps!! <3

What is the missing term that makes these ratios equivalent? 1.5:3, 31.5:____

Answers

Answer:  63

=========================================

Work Shown:

1.5/3 = 31.5/x

1.5x = 3*31.5  cross multiply

1.5x = 94.5

x = 94.5/1.5  dividing both sides by 1.5

x = 63

-----------

An alternative equation to solve is

1.5/31.5 = 3/x

1.5x = 31.5*3

1.5x = 94.5

The remainder of the steps are the same as in the previous section above.

Write 3 expressions containing exponents so that each expression equals 81

Answers

Answer:

9x9= 81

3x3x3x3=81

81 to the first power.

Step-by-step explanation:

I hope this helps in any way:)

At the start of 2010 karim had rm5000

Answers

Step-by-step explanation:

Tell the whole question please

In the last year, the population of Japan had a decay rate of 0.17% and decreased to 127,484,450. If this rate continues, what will be the population in 7 more years? Round your answer to the nearest whole number.

Answers

Answer:

125975100 the population in 7 years

Step-by-step explanation:

the population in 7 more years : 127,484450(1-0.0017)^7=125975100.1919 close to 125975100

Answer: 125,976,376 IN 7 YEARS

Step-by-step explanation:

A=127,484,450

R=-0.0017/YEAR

T=7/YEARS

[tex]A=127,484,450E ^{-0.0017.7}[/tex]a=125,976,375.88a=125,976,376 in 7years

Given the sample mean = 23.375, sample standard deviation = 5.29, and N = 40 for the low income group, Test the claim that the mean nickel diameter drawn by children in the low income group is greater than 21.21 mm. Test at the 0.01 significance level.
a) Identify the correct alternative hypothesis:
A. p > 21.21
B. p < 21.21
C. p = 21.21
D. μ < 21.21
E. μ > 21.21
F. μ = 21.21
Give all answers correct to 3 decimal places
b) The test statistic value is:_______
c) Using the Traditional method, the critical value is:_______

Answers

Answer:

Step-by-step explanation:

a. To identify the alternative hypothesis, we have to examine the claim

The claim is that the mean nickel diameter drawn by children in the low income group is greater than 21.21 mm

Thus, alternative hypothesis is μ > 21.21

b. The test statistics is

z score = x - u /(sd/√n)

Where x (sample mean) is 23.375, u is pop. mean is 21.21, sd is 5.29 and n (sample size) is 40

z = 23.375 - 21.21 /(5.29/√40)

z = 2.165 / (5.29/6.3246)

z = 2.165/0.8364

z = 2.588

c. The critical value is

Alpha for this case study is 0.01. Then the critical probability is 1 - (alpha/2) =

1 - (0.01/2) = 1 - 0.005 = 0.995

To express the critical value as a z score, find the z score corresponding to the critical probability using the z table. Which is 0.8389.

Classify the polynomial 2x^3+6x^2-4 by the number of terms. binomial. trinomial. cubic. quadratic.

Answers

Answer:

monomial

Step-by-step explanation:

URGENT


What is the length of?

Answers

Answer:

option (c) 4

Step-by-step explanation:

sides opposite to equal angles are equal

so ML = MN

that is 4x = x+3

4x - x = 3

3x = 3

x= 1

ML= 4x = 4*1 = 4 units

MN = x+3= 1+3= 4 units

so answer is option (c) 4

hope this answer help you

The equations x + 5 y = 10, 3 x minus y = 1, x minus 5 y = 10, and 3 x + y = 1 are shown on the graph below. On a coordinate plane, there are 4 lines. Green line goes through (0, negative 1) and (1, 2). Blue line goes through (0, 1) and (1, negative 2). Pink line goes through (0, 2), and (2, 1.5). Orange line goes through (negative 2, negative 2.5) and (2, negative 1.5). Which is the approximate solution for the system of equations x + 5 y = 10 and 3 x + y = 1? (–0.3, 2.1) (–0.3, –2.1) (0.9, –1.8) (0.9, 1.8)

Answers

Answer:

A: (–0.3, 2.1)

Answer:a

Step-by-step explanation:

Find three consecutive even integers such that the square of the third is 60 more that the square of the second

Answers

Answer:

-4,4,16

Step-by-step explanation:

They are all even integers.

-4^2=16

4^2=16

16^2=256

the square of the third,16 is 256 which is more than the square of the second,4=16

The three consecutive even integers such that the square of the third is 60 more than the square of the second are -18, -16 and -14.

What are integers?

Any positive or negative number without fractions or decimal places is known as an integer, often known as a "round number" or "whole number."

Given:

Let the three even consecutive integers are 2n-2, 2n and 2n + 2.

According to the question,

So,

(2n + 2)² = (2n)² - 60

4n² + 4 + 8n = 4n² -60

8n = -64

n = -8

That means, the integers are -18, -16 and -14.

Therefore, the required even integers are -18, -16 and -14.

To learn more about the integers;

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PLEASEEEEE HELPPOO
For Individual or Group Explorations
Maximizing the Total Profit
Payles at The Christmas Store very periodically with a high ef 550.000 in December
the Christmas Stove also comes the Powe, where profits reach a high of $80,000
in Aurust and a few of $20,000 in February Assume that the profit function for
Crm Store
Save
40
20
10
1 2 3 4 5 6 7 8 9 10 11 12
Month
a) Write the profit function for The Christmas Store as a function of the month
and sketch its graph
b)
Write the profit function for The Pool Store as a function of the month and
sketch its graph.
are are length
Write the total profit as a function of the month and sketch its graph. What is
the period?
are inside the
est enth of a
Use the maximum feature of a graphing calculator to find the owner's maxi-
mum total profit and the month in which it occurs.
Find the owner's minimum total profit and the month in which it occurs.
We know that y -a sin x + bcos x is a sine function. However, the sum of
two arbitrary sine or cosine functions is not necessarily a sine function. Find an
example in which the graph of the sum of two sine functions does not look like
a sine curve.
Explain.
is tangent to one

Answers

Answer:

what

Step-by-step explanation:

What is the value of x in the equation 5 (4 x minus 10) + 10 x = 4 (2 x minus 3) + 2 (x minus 4)?

Answers

Answer:

x = 1.5

Step-by-step explanation:

5(4x-10)+10x=4(2x-3)+2(x-4)

Distribute(5)

20x-50+10x=4(2x-3)+2(x-4)

Distribute(4)

20x-50+10x=8x-12+2(x-4)

Distribute(2)

20x-50+10x=8x-12+2x-8

Combine like terms

30x-50=10x-20

Subtract(10x)

20x-50=-20

Add(50)

20x=30

Divide(20)

x = 1.5

Hope it helps <3

Answer:

x = 3/2

Step-by-step explanation:

5 ( 4x - 10) + 10x = 4(2x - 3) + 2(x - 4)

Expand the terms

That's

20x - 50 + 10x = 8x - 12 + 2x - 8

Simplify

30x - 50 = 10x - 20

Group the constants at the right side of the equation

That's

30x - 10x = - 20 + 50

20x = 30

Divide both sides by 20

x = 3/2

Hope this helps you

Taylor and Jeff have been selling frozen pizzas for a class fundraiser. Taylor has sold half as many
pizzas as Jeff. Together they have sold a total of 126 pizzas. How many pizzas did Taylor sell?

Answers

Answer:

Taylor sold 42 pizzas

Step-by-step explanation:

Make a system of equations where t represents the number of pizzas Taylor sold and j represents the number that Jeff sold:

t + j = 126

j = 2t

We can solve this system by substitution, since we can substitute 2t as j.

t + j = 126

t + 2t = 126

3t = 126

t = 42

Taylor sold 42 pizzas.

Answer:

Step-by-step explanation:

Let x represent the number of pizzas that Tailor sold.

Let y represent the number of pizzas that Jeff sold.

Together they have sold a total of 126 pizzas. This means that

x + y = 126- - - - - - - - -1

Taylor has sold half as many

pizzas as Jeff. This means that

x = 1/2 × y = y/2

Substituting x = y/2 into equation 1, it becomes

y/2 + y = 126

Multiplying both sides of the equation by 2, it becomes

y + 2y = 252

3y = 252

y = 252/3

y = 84

x = y/2 = 84/2

x = 42

Taylor sold 42 pizzas

An object is moving at a speed of 7300 inches every 3 seconds. Express this speed in miles per day.

Answers

Answer:

≈3318 miles per day....

Step-by-step explanation:

Please answer this correctly without making mistakes

Answers

Answer:

d = 115.4 mi

Step-by-step explanation:

Since it gives us the distance in between the locations, we simply label the distances:

From the Garbage to the Hotel is 58.3 miles.

From the Hotel to the Hardware Store is 57.1 miles.

We are trying to find the distance from the Garbage to the Hardware Store, we simply add the distances between:

58.3 mi + 57.1 mi = 115.4 mi

slope=4/3 find the equation of the parallel line through (5,5)

Answers

Answer:

[tex]y=\frac{4}{3}x-1.75[/tex]

Step-by-step explanation:

If the slope of a line is 4/3,

and we wanna find the equation of a line that is parallel to it and crosses through (5,5).

So we already have the slope because the slope of 2 parallel lines are the same.

y = 4/3x

Look at the image below↓

So now we just need to find the y-intercept.

After some numbers we got,

[tex]y=\frac{4}{3}x-1.75[/tex]

Look at the other image below↓

Thus,

the equation of the parallel line is [tex]y=\frac{4}{3}x-1.75[/tex].

Hope this helps :)

Determine whether the function below is an even function, an odd function, both, or neither.
f(x)=x^6 + 10x^4-11x^2+19
ОА.
neither even nor odd
OB.
odd function
Ос.
both even and odd
OD.
even function
Reset
Next

Answers

Even function because the highest exponent of the variable is a 6, and 6 is an even number.

Answer:

Step-by-step explanation:

even function are symmetrical about the y axis or f(-x)=f(x)

odd function are symmetrical about the origin -f(-x)=f(x)

f(x)=x^6 + 10x^4-11x^2+19

f(-x)=(-x)^6+10(-x)^4+11(-x)^2+19=x^6 + 10x^4-11x^2+19

the function is even

3/4 (1/2x - 12) + 4/5 HELP

Answers

Answer:

3/8x - 9 4/5

Step-by-step explanation:

Well we need to simplify the following expression,

[tex]\frac{3}{4} (\frac{1}{2}x - 12) + \frac{4}{5}[/tex]

So we need to distribute 3/4 to (1/2x - 12)

3/8x - 9 + 4/5

3/8x - 9 4/5

Thus,

the answer is 3/8x - 9 4/5.

Hope this helps :)

What is the distance to the earth’s horizon from point P? Enter your answer as a decimal in the box. Round only your final answer to the nearest tenth.

Answers

Answer:

156.7 miles

Step-by-step explanation:

Since [tex]x[/tex] is tangent to the circle, then it is also a right angle with the radius, from here, just do Pythagorean theorem ([tex]a^{2}+b^{2}=c^{2}[/tex]) to solve for [tex]x[/tex].

Since 1 leg and the hypotenuse is given to you, you want to solve for the other leg, which is [tex]x[/tex] (either [tex]a[/tex] or [tex]b[/tex]). Lets use [tex]b[/tex] for [tex]x[/tex] and set up the equation.

[tex]b^{2}=c^2-a^2[/tex]

[tex]b^2=(3959+3.1)^2-3959^2[/tex]

[tex]b^2 = 3962.1^2 - 3959^2[/tex]

[tex]b^2 = 15,698,236.41 - 15,673,681[/tex]

[tex]b^2 = 24,555.41[/tex]

[tex]\sqrt{b^2}=\sqrt{24,555.41}[/tex]

[tex]b=156.7016592[/tex]

[tex]b=156.7[/tex] (round to nearest tenth)

The distance to the earth’s horizon from point P is 281.6 miles

What is distance?

The distance between two points is the length of the line joining the two points. Distance is a numerical or occasionally qualitative measurement of how far apart objects or points are. In physics or everyday usage, distance may refer to a physical length or an estimation based on other criteria.

here, we have,

to determine the distance to the earth’s horizon from point P:

The tangent line from P meets the radius of the earth at a right angle.

This means that the triangle is a right triangle.

The length of x is then calculated as:

(3959 + 10)^2= 3959^2 + x^2

Rewrite as:

x^2 = (3959 + 10)^2- 3959^2

Evaluate

x^2 = 79280

Take the square root of both sides

x = 281.6

Hence, the distance to the earth’s horizon from point P is 281.6 miles

Read more about distance at:

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x/3 ≥−33 solve for x answer must be simplified

Answers

Answer:

[tex]\boxed{x\geq -99}[/tex]

Step-by-step explanation:

[tex]\frac{x}{3} \geq -33[/tex]

[tex]\sf Multiply \ both \ sides \ by \ 3.[/tex]

[tex]\frac{x}{3} (3) \geq -33(3)[/tex]

[tex]x\geq -99[/tex]

Answer:

[tex]\boxed{\red{x \geqslant - 99}}[/tex]

Step-by-step explanation:

[tex] \frac{x}{3} \geqslant - 33 \\ x \geqslant - 33 \times 3 \\ x \geqslant - 99[/tex]

hope this helps you!

in the life of a car engine, calculatedin miles, is normally distributed, with a mean of 17,000 miels and a standard deviation of 16,500 miles, what should be the guarantee period if the company wants less than 2% of the engines to fail while under warranty g

Answers

Answer:

the guarantee period should be less than 136010 miles

Step-by-step explanation:

From the given information;

Let consider Y to be the life of a car engine

with a mean μ = 170000

and a standard deviation σ = 16500

The objective is to determine what should be the guarantee period T if the company wants less than 2% of the engines to fail.

i.e

P(Y < T ) < 0.02

For the variable of z ; we have:

[tex]z = \dfrac{x - \mu }{\sigma}[/tex]

[tex]z = \dfrac{x - 170000 }{16500}[/tex]

Now;

[tex]P(Y < T ) = P( Z < \dfrac{T- 170000}{16500})[/tex]

[tex]P( Z < \dfrac{T- 170000}{16500})< 0.02[/tex]

From Z table ;

At P(Z < -2.06) ≅ 0.0197  which is close to 0.02

[tex]\dfrac{T- 170000}{16500}<- 2.06[/tex]

[tex]{T- 170000}<- 2.06({16500})[/tex]

[tex]{T- 170000}< - 33990[/tex]

[tex]{T}< - 33990+ 170000[/tex]

[tex]{T}<136010[/tex]

Thus; the guarantee period should be less than 136010 miles

What is a3 if an=64(12)n−1

Answers

Answer:

[tex]\huge\boxed{a_3=9,216}[/tex]

Step-by-step explanation:

[tex]a_n=64(12)^{n-1}\\\\\text{substitute}\ n=3:\\\\a_3=64(12)^{3-1}=64(12)^2=64(144)=9,216[/tex]

Adam is going to cook a turkey for 14 people

Answers

Answer:

they divied the turkey into 14 pices

Step-by-step explanation:

Does the mean represent the center of the​ data? A. The mean represents the center. B. The mean does not represent the center because it is the smallest data value. C. The mean does not represent the center because it is the largest data value. D. The mean does not represent the center because it is not a data value. E. There is no mean age.

Answers

Answer:

A. The mean represents the center.

A. The median represents the center.

B. The mode does not represent the center because it is the smallest data value.

Step-by-step explanation:

Mean

(9 + 9 + 12 + 12 + 9 + 8 + 8 + 8 + 10 + 8 + 8 + 8 + 11)/13 = 120/13 = 9.2

The mean 9.2 and it represents the center of data.

Median

By arranging the set of data, the median, the median is the center number

8,8,8,8,8,8,(9),9,9,10,11,12,12

The median is 9 and it represents the center of data.

Mode

The mode is the number that appears most in the set of data.

The number that appears most in the set of data is 8 and does not represent the set of data.

Given the data set, 9, 9, 12, 12, 9, 8, 8, 8, 10, 8, 8, 8,11:

the mean is: 9.2the median is: 9the mode is: 8

A. The mean does represents the center of the data set

Given the following data set:

9, 9, 12, 12, 9, 8, 8, 8, 10, 8, 8, 8, 11

Let's find the mean, median, and mode.

Mean of the data set:

Mean = sum of all values / number of values

Mean = [tex]\frac{9 + 9 + 12 + 12 + 9 + 8 + 8 + 8 + 10 + 8 + 8 + 8 + 11}{13}[/tex]

Mean = [tex]\frac{120}{13} = 9.2[/tex]

Median of the data set:

Order the data from the least to the greatest then find the middle value.

Thus:

8, 8, 8, 8, 8, 8, (9,) 9, 9, 10, 11, 12, 12

The middle value is 9.

The median = 9

Mode of the data set:

The mode = the data value that appears most

8 appeared the most, therefore, the mode = 8

If you observe, you will note that the mean and median of the data set are similar. We can as well conclude that the mean represents the center of the data set.

In summary, given the data set, 9, 9, 12, 12, 9, 8, 8, 8, 10, 8, 8, 8,11:

the mean is: 9.2the median is: 9the mode is: 8

A. The mean does represents the center of the data set

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what are the coordinates of point b on ac such that ab=2/5ac

Answers

Answer:

[tex](-\frac{36}{7},\frac{40}{7})[/tex]

Step-by-step explanation:

Coordinates of points A and C are (-8, 6) and (2, 5).

If a point B intersects the segment AB in the ratio of 2 : 5

Then coordinates of the point B will be,

x = [tex]\frac{mx_2+nx_1}{m+n}[/tex]

and y = [tex]\frac{my_2+ny_1}{m+n}[/tex]

where [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] are the coordinates of the extreme end of the segment and a point divides the segment in the ratio of m : n.

For the coordinates of point B,

x = [tex]\frac{2\times 2+(-8)\times 5}{2+5}[/tex]

  = [tex]-\frac{36}{7}[/tex]

y = [tex]\frac{2\times 5+5\times 6}{2+5}[/tex]

  = [tex]\frac{40}{7}[/tex]

Therefore, coordinates of pint B will be,

[tex](-\frac{36}{7},\frac{40}{7})[/tex]

WHY CAN'T ANYONE HELP ME :( Solve the formula for the specified variable. tex]D=\frac{1}{4}fk for f.

Answers

Answer:

4d/k or [tex]\frac{4d}{k}[/tex]

Step-by-step explanation:

first multiply both sides by four

you will have 4d=fk

then divide by k

4d/k=f

magazine provided results from a poll of adults who were asked to identify their favorite pie. Among the ​respondents, ​% chose chocolate​ pie, and the margin of error was given as percentage points. What values do ​, ​, ​n, E, and p​ represent? If the confidence level is ​%, what is the value of ​?

Answers

Complete Question

A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie. Among the 500 ​respondents, 12 ​% chose chocolate​ pie, and the margin of error was given as plus or minus 5 percentage points.What values do ​ [tex]\r p , \ \r q[/tex], ​n, E, and p​ represent? If the confidence level is 90​%, what is the value of [tex]\alpha[/tex] ​?

Answer:

a

   [tex]\r p[/tex] is the sample proportion   [tex]\r p = 0.12[/tex]

   [tex]n[/tex] is the  sample size is  [tex]n = 500[/tex]

   [tex]E[/tex] is the  margin of error is [tex]E = 0.05[/tex]

   [tex]\r q[/tex] represents the proportion of those that did not chose chocolate​ pie i.e                        [tex]\r q = 1- \r p[/tex]

b

   [tex]\alpha = 10\%[/tex]

Step-by-step explanation:

Here

    [tex]\r p[/tex] is the sample proportion   [tex]\r p = 0.12[/tex]

   [tex]n[/tex] is the  sample size is  [tex]n = 500[/tex]

    [tex]\r q[/tex] represents the proportion of those that did not chose chocolate​ pie i.e  

      [tex]\r q = 1- \r p[/tex]

      [tex]\r q = 1- 0.12[/tex]

      [tex]\r q = 0.88[/tex]

     [tex]E[/tex] is the  margin of error is [tex]E = 0.05[/tex]

Generally [tex]\alpha[/tex] is the level of significance and it value is mathematically evaluated as

     [tex]\alpha = ( 100 - C )\%[/tex]

Where  [tex]C[/tex] is the confidence level which is given in this question as  [tex]C = 90 \%[/tex]

So  

    [tex]\alpha = ( 100 - 90 )\%[/tex]

    [tex]\alpha = 10\%[/tex]

Nakashima Gallery had the following petty cash transactions in February of the current year. Nakashima uses the perpetual system to account for merchandise inventory. Feb 2 Write a $400 check to establish a petty cash fund. Feb 5 Purchased paper for the copier for $14.15 that is immediately used. Feb 9 Paid $32.50 shipping charges (transportation in) on merchandise purchased for resale, terms FOB shipping point. These costs are added to merchandise inventory. Feb 12 Paid $7.95 postage to deliver a contract to a client Feb 14 Reimbursed Adina Sharon, the manager, $68 for mileage on her car. Feb 20 Purchased office paper for $67.77 that is immediately used. Feb 23 Paid a courier $20 to deliver merchandise sold to a customer, terms FOB destination. Feb 25 Paid $13.10 shipping charges (transportation in) on merchandise purchased for resale, terms FOB shipping point. These cost are added to merchandise inventory. Feb 27 Paid $54 for postage expenses Feb 28 The fund had $120.42 remaining in the petty cashbox. Sorted the petty cash receipts by accounts affected and exchanged them for a check to reimburse the fund for expenditures. Feb 28 The petty cash fund amount is increased by $100 to a total of $500

Answers

Answer:

1. Debit Petty cash for $400; and Credit Cash for $400.

2. Total petty cash payment = $270.57

3(a) Cash reimbursement is $279.58; and Cash over and short is $9.01.

3(b) Debit Petty cash for $100; and Credit Cash for $100.

Step-by-step explanation:

Note: This question is not complete. The full complete question is therefore provided before answering the question. See the attached pdf file for the full question.

The explanations to the answers are now given as follows:

1. Prepare the journal entry to establish the petty cash fund.

Note: See the journal entry in the attached excel file

2. Prepare a petty cash payments report for February with these categories: delivery expense, mileage expense, postage expense, merchandise inventory (for transportation-in), and office supplies expense. Sort the payments into the appropriate categories and total the expenditures in each category.

Note: See the petty cash payments report in the attached excel file.

3. Prepare the journal entries for required 2 to both (a) reimburse and (b) increase the fund amount.

Note: See the journal entries (a) and (b) in the attached excel file

3(a) Reimburse Workings:

w.1: Calculation of Cash reimbursement

Cash reimbursement = Petty cash fund - Petty cash fund balance = $400 - $120.42 = $279.58

w.2: Calculation of the Cash over and short

Cash over and short = Cash reimbursement – Total expenses = $279.58 - $270.57 - $120.42 = $9.01

AACB ~AEFD
x = [?]
Enter your answer in decimal form.

Answers

Answer:

11.4

Solution,

ACB = EFD

finding the value of X,

[tex] \frac{x}{3.8} = \frac{15}{5} [/tex]

Apply cross product property

[tex]x \times 5 = 15 \times 3.8[/tex]

Calculate the product

[tex]5x = 57[/tex]

Divide both sides by 5

[tex] \frac{5x}{5} = \frac{57}{5} [/tex]

Calculate

[tex]x = 11.4[/tex]

Hope this helps...

Good luck on your assignment...

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