Please help 6 is the most important

Answer:

d)

Step-by-step explanation:

Equation of circle with center at point (h, k) and radius, r.

[tex] (x - h)^2 + (y - k)^2 = r^2 [/tex]

This problem:

(x − A)^2 + (y − B)^2 = C

The center is (A, B).

The radius is sqrt(C).

Answer: d)

Answer:

x = 12

Step-by-step explanation:

By the property of exterior angles of a triangle,

"Exterior angle of a triangle is equal to the sum of opposite angles of the triangle"

Since, ∠HRQ is the exterior angle of ΔPRQ and ∠RPQ and ∠RQP are the opposite angles.

m∠HRQ = m∠RPQ + m∠RQP

(8 + 6x)° = 30° + (4x + 2)°

6x - 4x = 30 + 2 - 8

2x = 24

x = 12

Therefore, value of x is 12.

Answer:

x = 12

Step-by-step explanation:

Hope this helps

Answer:

Answer Below  V

Step-by-step explanation:

1. They must be adjacent

2. They have to be connected with the line segment Z

Answer:

The area of the triangle is of 8 units of area.

Step-by-step explanation:

Answer:

The area of the triangle is of 21 units of area.

Step-by-step explanation:

The area of a triangle with three vertices [tex](x_1,y_1),(x_2,y_2),(x_3,y_3)[/tex] is given by the determinant of the following matrix:

[tex]A = \pm 0.5 \left|\begin{array}{ccc}x_1&y_1&1\\x_2&y_2&1\\1_3&y_3&1\end{array}\right|[/tex]

In this question:

Vertices (1,0) (5,0) (3,4). So

[tex]A = \pm 0.5 \left|\begin{array}{ccc}1&0&1\\5&0&1\\3&4&1\end{array}\right|[/tex]

[tex]A = \pm 0.5(1*0*1+0*1*3+1*5*4-1*0*3-0*5*1-1*1*4)[/tex]

[tex]A = \pm 0.5*(20-4)[/tex]

[tex]A = \pm 0.5*16 = 8[/tex]

The area of the triangle is of 8 units of area.

Answer:

how about no

Step-by-step explanation:

Answer:

-6

Step-by-step explanation:

4(2x+12)=0

8x+48=0

8x=-48

x=-6

Answer: I think it would be 1/2, 2/2 or 2/5. If i'm wrong then i'm sorry.

Answer:

Section 2

Step-by-step explanation:

I will pick the section with the largest angle.

Let's determine the size of the angle of each section.

Given:

m∠ABD = 2x+3,

m∠CBD = 4x+7,

m∠ABC = 40°

Thus:

m<ABD + m<CBD = m<ABC (angle addition postulate)

Substitute

2x + 3 + 4x + 7 = 40

Add like terms

6x + 10 = 40

6x + 10 - 10 = 40 - 10

6x = 30

6x/6 = 30/6

x = 5

✔️m∠ABD = 2x+3

Plug in the value of x

m<ABD = 2(5) + 3 = 13° (section 1)

✔️m∠CBD = 4x+7

m∠CBD = 4(5) + 7

m∠CBD = 27° (section 2)

✅I will pick section 2 because it is the section with the largest angle, which means it is the biggest.

Answer:

angle 7

hope it helps...

Answer:

C.

Step-by-step explanation:

Hope this helps! have a great day!

Answer:

All triangles add up to 180 degrees so...

180 - 43 - 59 = 78 degrees.

So x - 78 degrees.

x and y are supplementary angles so...

180 - 78 = 102.

So y = 102.

180 - 102 - 49 = 29 degrees

So z = 29 degrees

Hope this helps!

Answer:

Let's simplify step-by-step.

yz+40

There are no like terms.

Answer: =yz+40

Hope this help :D

Answer:

72

Step-by-step explanation:

Answer:

No possible triangles

Step-by-step explanation:

Deltamath

Answer:

2

Step-by-step explanation:

Answer:

9.  [tex] \frac{1}{10,000} = 0.0001 [/tex]

10. [tex] \frac{1}{81} [/tex]

Step-by-step explanation:

9. [tex] x^{-4} [/tex]

Evaluate when x = 10.

Substitute x = 10 into the expression

[tex] 10^{-4} [/tex]

Apply the negative exponent rule ([tex] a^{-n} = \frac{1}{a^n} [/tex])

Thus:

[tex] = \frac{1}{10^4} [/tex]

[tex] = \frac{1}{10^4} = \frac{1}{10,000} = 0.0001 [/tex]

10. [tex] 2a^{-1}b^{-3} [/tex]

Evaluate when a = 6 and b = 3

Substitute

[tex] (2*6^{-1})(3^{-3}) [/tex]

Apply the negative exponent rule

[tex] (2*\frac{1}{6})(\frac{1}{3^3}) [/tex]

[tex] (\frac{2}{6})(\frac{1}{27}) [/tex]

[tex] \frac{2*1}{6*27} [/tex]

[tex] \frac{1}{81} [/tex]

[tex]\huge{ \mathfrak{  \underline{ Answer }\:  \:  ✓ }}[/tex]

plugging the value of x as 10, we get

[tex]\longrightarrow\: \: x {}^{ - 4} [/tex]

[tex]\longrightarrow\: 10 {}^{ - 4} [/tex]

[tex]\longrightarrow \dfrac{1}{10 {}^{4} } [/tex]

[tex] \longrightarrow\dfrac{1}{10000} [/tex]

[tex]\longrightarrow0.0001[/tex]

plugging the value of

[tex]\longrightarrow2 {a}^{ - 1} b {}^{ - 3} [/tex]

[tex]\longrightarrow2 \times 6 {}^{ - 1} \times 3 {}^{ - 3} [/tex]

[tex]\longrightarrow \dfrac{2}{6 \times 27} [/tex]

[tex]\longrightarrow \dfrac{2}{162} [/tex]

[tex]\longrightarrow \dfrac{1}{81} [/tex]

_____________________________

[tex] \\ \\ \mathrm{ ☠ \: TeeNForeveR \:☠ }[/tex]

Answer: c

Step-by-step explanation:

Answer:

27.50

Step-by-step explanation:

I'm the one who just commented for you this is what I thought good luck.

Answer:

The answer is 91

Step-by-step explanation:

90 x 6 = 540

The numbers need to equal 540 all together to make an average of 90.

97 + 86 + 83 + 95 + 88 = 449

540 - 449 = 91

To check:

97 + 86 + 83 + 95 + 88 + 91 = 540

Therefore, the answer is 91

Answer:

I love algebra anyways  

the ans is in the picture with the steps  

(hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

Answer:

360

Step-by-step explanation:

Answer:

The discriminant is 0

Step-by-step explanation:

If the discriminant of a quadratic equation equals 0, it means 2 identical real roots existed. (x = -3 is the only x-intercept of the graph of a quadratic equation)

Answer:

x=33/5 and y=31/5

Answer:

x=33/5 = 6.6

y=31/5 = 6.2

Step-by-step explanation:

4x+3y=45

2x+4y=38

​In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other.

4x+3y=45,2x+4y=38

To make 4x and 2x equal, multiply all terms on each side of the first equation by 2 and all terms on each side of the second by 4.

2×4x+2×3y=2×45,4×2x+4×4y=4×38

Simplify.

8x+6y=90,8x+16y=152

Subtract 8x+16y=152 from 8x+6y=90 by subtracting like terms on each side of the equal sign.

8x−8x+6y−16y=90−152

Add 8x to −8x. Terms 8x and −8x cancel out, leaving an equation with only one variable that can be solved.

6y−16y=90−152

Add 6y to −16y.

−10y=90−152

Add 90 to −152.

−10y=−62

Divide both sides by −10.

y=31/5

Substitute 31/5 for y in 2x+4y=38. Because the resulting equation contains only one variable, you can solve for x directly.

2x+4×(31/5)=38

Multiply 4 times 31/5.

2x+125/5=38

Subtract 124/5 from both sides of the equation.

2x=66/5

Divide both sides by 2.

x=33/5,y=31/5

Answer:

The 95% confidence interval for the population mean mileage is

(27.917, 29.593)

The 98% confidence interval for the population mean mileage

(27.737, 29.762)

Step-by-step explanation:

Step(i):-

Given that the random sample size 'n' = 64

Given that the mean of sample x⁻ = 28.75miles

Given that the standard deviation of the sample (S) = 3.4 miles

Degrees of freedom = n-1 = 64-1 =63

t₀.₀₅ = 1.9983

Step(ii):-

95% confidence interval for the population mean mileage is determined by

[tex](x^{-} - t_{0.05} \frac{S}{\sqrt{n} } , x^{-} + t_{0.05} \frac{S}{\sqrt{n} })[/tex]

[tex](28.75-1.99\frac{3.4}{\sqrt{64} },28.75 + 1.99 \frac{3.4}{\sqrt{64} } )[/tex]

(28.75 - 0.845 , 28.75 + 0.845)

(27.917 , 29.593)

Step(iii):-

98% confidence interval for the population mean mileage is determined by

[tex](x^{-} - t_{0.02} \frac{S}{\sqrt{n} } , x^{-} + t_{0.02} \frac{S}{\sqrt{n} })[/tex]

[tex](28.75-2.3824\frac{3.4}{\sqrt{64} },28.75 + 2.3824 \frac{3.4}{\sqrt{64} } )[/tex]

(28.75 - 1.01252 , 28.75 + 1.01252)

(27.737 , 29.762)

Final answer:-

98% confidence interval for the population mean mileage is

(27.737 , 29.762)

Answer:

I think it is 2x-3y=-12 not sure but try it

Answer:

area = 77 m²

Step-by-step explanation:

area = (14 x 3) +(5 x 5) + (5 x 2) = 42 + 25 + 10 = 77 m²