Answer:
E = 3.049 N/C
Explanation:
Induced electric field = e/2 *(pi) *r
Induced electric field = e /(3.14 *19.5) - Eq (1)
e = (pi)r^2*B/t
= 3.14 * (19.5/2*100)^2 * 0.50 T/ 0.1
= 1.867 V
Substituting this value in equation 1, we get –
E = 1.867 V/(3.14 *19.5/100)
E = 3.049 N/C
When measuring volume, your final
result must be in
A. linear units.
B. single units.
C. squared units.
D. cubed units.
A quantum dot may be modeled as an electron in a spherical well with perfectly reflecting walls. Design a quantum dot whose characteristic frequency of emission is 10 GHz, where characteristic frequency corresponds to decay from the first excited state to the ground state. In other words, obtain the radius a of the spherical cavity that has this property
Answer:
radius = 37.69 mm
Explanation:
Calculate the radius a of the spherical cavity that has this property
Frequency of emission = 10 GHz
This problem is similar to infinite spherical wall potential
first step:
Express the energy eigenvalue of the system : [tex]E_{100} =E_{Is} = \frac{9.87h^2}{2ma^2}[/tex]
First excited state energy can be expressed as : E[tex]_{IP}[/tex] = 20.19 h^2 / 2ma^2
Given that the frequency of emission (γ ) = 10 GHz
next step :
calculate the energy of emitted photon ( E ) = h γ
= 6.626 * 10^-36 * 10 * 10^9
= 6.626 * 10^-24 joules
E[tex]_{IP}[/tex] - E[tex]_{IS}[/tex] = 6.626 * 10^-24
∴ a^2 = 1.42 * 10^-13 m^2
hence a = √ 1.42 * 10^-13 m^2 = 37.69 * 10^-6 m ≈ 37.69 mm
a stone on the ground has zero energy why
Explanation:
it has no energy when considered with respect to earth ,as it has neither height (i e potential energy) nor velocity (i.e kinetic energy).
I will mark you brainlist!!
How is primary succession different from secondary succession? Give an example of an event that may lead to primary succession.
Answer:
Primary Succession is defined as the type of ecological succession, which occurs or start from the barren, uninhabited and unoccupied areas, such as the newly formed pond, rock, dunes, etc., while such kind of succession, which occurs in the area where there was the existence of life previously but got abandoned due to natural disturbances like deforestation, natural calamities (flood, earthquake, tsunami), the field with no vegetation is known as Secondary Succession
Explanation:
Some examples of primary succession include the formation of a new ecosystem after a volcano, glacier outbursts, or a nuclear explosion. Some examples of secondary succession include succession after fire, harvesting, logging, or abandonment of land or the renewal after a disease outbreak
i hope this answer helps :)
8. Cart 1 with mass of 2kg moving at +6m/s collides with cart 2 with a mass of 1kg,
which is at rest. If cart 1 moves at +2m/s after the collision, what is the velocity of
cart 2 after the collision? (include correct units, or you get no credit)
Answer:its 2kg
Explanation:
The head scale of a screw gauge contains 100 divisions and it's pitch is 1mm. what is the least count of the screw gauge
Answer:
0.01 mm
Explanation:
The least count of the screw gauge = pitch/number of divisions on circular scale
Pitch = 1 mm and number of divisions = 100
Substituting the values of the variables into the equation, we have
least count of the screw gauge = pitch/number of divisions on circular scale = 1 mm/100 = 0.01 mm
1:
This diagram shows four different dishes on the kitchen shelf.
tea cup
IN
2:
bowl
50 N
mug
10 N
plate
SON
3:
999
4
:
Which of these dishes has the least potential energy?
bowl
5:
plate
mug
6:
tea cup
Answer:
Bowl will have maximum potential energy
Explanation:
It is the bowl that will have maximum potential energy.
It is because potential energy is high when both height and mass of the object is high.
Here in this case the bowl has maximum weight with maximum height except the tea cup but the potential weight of cup will not make much impact as its weight is very low.
6. What is the wavelength of a wave that is traveling at 30 m/s and has a frequency of 3.2 Hz?
Answer:
6. 9.4 m
7. 1050 m/s.
Explanation:
6. Determination of the wavelength
Velocity (v) = 30 m/s
Frequency (f) = 3.2 Hz
Wavelength (λ) =?
v = λf
30 = λ × 3.2
Divide both side by 3.2
λ = 30 / 3.2
λ = 9.4 m
Thus, the wavelength of the wave is 9.4 m.
7. Determination of the speed of the wave.
Wavelength (λ) = 350 m
Frequency (f) = 3 Hz
Velocity (v) =.?
v = λf
v = 350 × 3
v = 1050 m/s
Thus, the speed of the wave is 1050 m/s
A 2-kg ball is thrown at a speed of ____, exhibits 25j of kinetic energy.
Answer:
A 2-kg ball is thrown at a speed of 5 m/s, exhibits 25 J of kinetic energy.
Explanation:
Given that,
The mass of a ball, m = 2 kg
Kinetic energy of the ball, K = 25 J
We need to find the speed of the ball. The formula for the kinetic energy is given by :
[tex]K=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2K}{m}} \\\\v=\sqrt{\dfrac{2\times 25}{2}} \\\\v=5\ m/s[/tex]
So,
A 2-kg ball is thrown at a speed of 5 m/s, exhibits 25 J of kinetic energy.
What would be the mass of an atom with 2 protons and 3 neutrons?
Answer:
5
Explanation:
From the question given above, the following data were obtained:
Proton number = 2
Neutron number = 3
Mass number =.?
The mass number of a given atom is simply the sum of the protons and neutrons in the nucleus of the atom. Mathematically, it is expressed as:
Mass number = proton + neutron
With the above formula, we can obtain the mass number of the atom as follow:
Proton number = 2
Neutron number = 3
Mass number =.?
Mass number = proton + neutron
Mass number = 2 + 3
Mass number = 5
Thus, the mass number the atom is 5.
do you think you will benefit from the discoveries of Archimedes’ and Pascal’s Principles?
Answer:
I hate to say it is a bit of the holiday but
The 6kg box is pushed to the left at a constant speed. The coefficient of friction is 0.78. Solve for the amount of force with which the hand pushes the box.
Answer:
45.864N
Explanation:
Using the formula
F = nR
n is the coefficient of friction
R is the normal reaction
R = mg
F = nmg
F = 0.78 * 6 * 9.8
F = 45.864N
Hence the amount of force with which the hand pushes the box is 45.864N
Focal distance of a concave lens is always:
O A. smaller than the image distance.
O B. positive.
O C. negative.
O D. larger than the object distance.
Water flows through a garden hose which is attached to a nozzle. The water flows through hose with a speed of 1.81 m/s and through the nozzle with a speed of 18.3 m/s. Calculate the maximum height (in m) to which water could be squirted if it emerges from the nozzle and emerges with the nozzle removed. (a) Emerges from the nozzle. m (b) Emerges with the nozzle removed, assuming the same flow rate. m
Answer:
a) 17.086m
b) 0.1671 m
Explanation:
Given data: speed of water through the hose = 1.81 m/s
through the nozzle = 18.3 m/s
We know that maximum height of an object with upward velocity v is given by,
a) H = v^2/2g
where H is the maximum height water emerges
= 18.3^2/(2×9.8) = 17.086 m answer
b) Again,
H = v^2/2g
= 1.81^2/(2×9.8) = 0.1671 m
is warming up important before doing an intense exercise or work-out? Wh?
Answer:
Yes, warming up is necessary before intense exercise, work-out or sports because they help regulate temperatures of your body. Warming up also makes your muscles ready for intense physical activities and prevents muscle cramps.
Explanation:
Future space rockets might propel themselves by firing laser beams, rather than exhaust gases, out the back. The acceleration would be small, but it could continue for months or years in the vacuum of space. Consider a 1200 kg uncrewed space probe powered by a 15 MW laser. After one year, how far will it have traveled and how fast will it be going
Answer:
Acceleration = 0.0282 m/s^2
Distance = 13.98 * 10^12 m
Explanation:
we will apply the energy theorem
work done = ΔK.E ( change in Kinetic energy ) ---- ( 1 )
where :
work done = p * t
= 15 * 10^6 watts * ( 1 year ) = 473040000 * 10^6 J
( note : convert 1 year to seconds )
and ΔK.E = 1/2 mVf^2 given ; m = 1200 kg and initial V = 0
back to equation 1
473040000 * 10^6 = 1/2 mv^2
Vf^2 = 2(473040000 * 10^6 ) / 1200
∴ Vf = 887918.92 m/s
i) Determine how fast the rocket is ( acceleration of the rocket )
a = Vf / t
= 887918.92 / ( 1 year )
= 0.0282 m/s^2
ii) determine distance travelled by rocket
Vf^2 - Vi^2 = 2as
Vi = 0
hence ; Vf^2 = 2as
s ( distance ) = Vf^2 / ( 2a )
= ( 887918.92 )^2 / ( 2 * 0.0282 )
= 13.98 * 10^12 m
the gravitational attraction between two masses of 3kg that are separated by a distance of 1cm is
Answer:
6.003×10¯⁶ N
Explanation:
We'll begin by converting 1 cm to m. This can be obtained as follow:
100 cm = 1 m
Therefore,
1 cm = 1 cm × 1 m / 100 cm
1 cm = 0.01 m
Finally, we shall determine the gravitational attraction. This can be obtained as follow:
Mass 1 (M₁) = 3 Kg
Mass 2 (M₂) = 3 Kg
Distance apart (r) = 0.01 m
Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
Force of attraction (F) =?
F = GM₁M₂ / r²
F = 6.67×10¯¹¹ × 3 × / 0.01²
F = 6.003×10¯¹⁰ / 1×10¯⁴
F = 6.003×10¯⁶ N
Thus the gravitational attraction is 6.003×10¯⁶ N
Explain what happens to the path of light as it hits a piece of black paper, a glass mirror, and a glass
of water. Explain why the light behaves the way it does as it hits each object.
1. Light is _________ by the black paper.
2. Light is _________ by the mirror.
3. Light is _________ by the glass of water.
Which two criteria are least important for engineers to consider when developing a process to produce an important chemical?
A. The process should be located in a major city.
B. The process should use local, organic reactants.
C. The process should produce a significant amount of the product.
D. The process should be cost-effective.
Answer:
two least important criteria are A and B.
Explanation:
In an industrial production process there are criteria on the location of the production plants. Among the most important criteria we have that a good quantity is produced from the producer and that the process is cost-beneficial - cats to increase the profit of the company.
There are other desirable but minor criteria
A) The size of the city is of minor importance
b) Finding raw material locally is interesting, but its importance is less, the raw material can be sent from other locations.
Consequently the two least important criteria are A and B.
Answer:
A. The process should be located in a major city.
B. The process should use local, organic reactants.
Explanation:
ap.ex
Which of the following describes the relationship between the velocity and
pressure of a fluid?
A. Pascal's principle
B. Archimedes' principle
C. Bernoulli's principle
D. Flow rate equation
Answer is c
Explanation:
I think its a option pascal's principal
Answer:
c
Explanation:
Just took the quiz
A small car is traveling at a speed of 60 mph on the highway. In the next lane, a large passenger bus is traveling at the same speed.
Answer:
A. The bus has more kinetic energy than the car.
Explanation:
As we know that
Kinetic energy is the amount of energy possessed by the body at the time when it is in motion.
Also,
Kinetic energy = 1 ÷ 2mv²
Here m denotes the mass of the body
and v denotes the velocity of the body.
So it would be based on the mass & velocity of the body
As if the passenger bus contains more kinetic energy as compared to the car because of the big mass
Hence, the first option is correct
1. Lucky Larry was in a car crash. He hit a brick wall going 40 mph. But his airbag
inflated and saved him because
A. it reduced the time of the collision.
B. it reduced his initial velocity.
C. it reduced his change in momentum.
D.it reduced his average
force.
Answer:
The answer is D (It reduced his average
force.)
a u tube contains a liquid of an unknown density an oil of density is poured into the right arm of the tube until the oil column is 16.0 cm high the oil air interfdace is 4.5 cm above the liquid level in the left arm of the u tube algrebraic expression to deter,ine the density of the unknown fluid
Answer:
The answer is "[tex]1155\ \frac{kg}{m^3}[/tex]"
Explanation:
Please find the complete question in the attached file.
[tex]p = p_0 + ?gh[/tex]
pi = pressure only at two liquids' devices
PA = pressure atmosphere.
1 = oil density
2 = uncertain fluid density
[tex]h_1 = 11 \ cm\\\\h_2= 3 \ cm[/tex]
The pressures would be proportional to the quantity [tex]11-3 = 8[/tex] cm from below the surface at the interface between both the oil and the liquid.
[tex]\to p_A + ?2g(h_1 - h_2) = p_A + ? 1gh_1\\\\\to ?2 = \frac{?1h_1}{(h_1 - h_2)} \\\\[/tex]
[tex]= \frac{840 \frac{kg}{m^3}}{\frac{11}{8}} \\\\= 1155\ \frac{kg}{m^3}[/tex]
A knife thrower throws a knife toward a 300 g target that is sliding in her direction at a speed of 2.30 m/s on a horizontal frictionless surface. She throws a 22.5 g knife at the target with a speed of 40.0 m/s. The target is stopped by the impact and the knife passes through the target. Determine the speed of the knife (in m/s) after passing through the target.
Answer:
The speed of the knife after passing through the target is 9.33 m/s.
Explanation:
We can find the speed of the knife after the impact by conservation of linear momentum:
[tex] p_{i} = p_{f} [/tex]
[tex] m_{k}v_{i_{k}} + m_{t}v_{i_{t}} = m_{k}v_{f_{k}} + m_{t}v_{f_{t}} [/tex]
Where:
[tex] m_{k}[/tex]: is the mass of the knife = 22.5 g = 0.0225 kg
[tex] m_{t}[/tex]: is the mass of the target = 300 g = 0.300 kg
[tex] v_{i_{k}}[/tex]: is the initial speed of the knife = 40.0 m/s
[tex] v_{i_{t}} [/tex]: is the initial speed of the target = 2.30 m/s
[tex]v_{f_{k}}[/tex]: is the final speed of the knife =?
[tex] v_{f_{t}} [/tex]: is the final speed of the target = 0 (it is stopped)
Taking as a positive direction the direction of the knife movement, we have:
[tex] m_{k}v_{i_{k}} - m_{t}v_{i_{t}} = m_{k}v_{f_{k}} [/tex]
[tex] v_{f_{k}} = \frac{m_{k}v_{i_{k}} - m_{t}v_{i_{t}}}{m_{k}} = \frac{0.0225 kg*40.0 m/s - 0.300 kg*2.30 m/s}{0.0225 kg} = 9.33 m/s [/tex]
Therefore, the speed of the knife after passing through the target is 9.33 m/s.
I hope it helps you!
An unknoAn unknown additional charge q3 is now placed at point B, located at coordinates (0 m, 15.0 m ). Find the magnitude and sign of q3 needed to make the total electric field at point A equal to zero.wn additional charge q3 is now placed at point B, located at coordinates (0 m, 15.0 m ). Find the magnitude and sign of q3 needed to make the total electric field at point A equal to zero.\
Answer:
hello your question has some missing information attached below is the missing information
answer : q3 = 0.300 nC
Explanation:
Given that Eay is in the Y axis ( upward ) , E3 will be downward and this will make the sign on the the charge ( q3 ) to be positive
E3 = Eay. ( for an electric field to be neutral/zero the electric field in the opposite direction will have same magnitude )
To calculate the value of q3 we will apply the relation below
K*q3/( 15 - 12 )^2 = 0.300
= (9 * 10^9) * (q3 / 9 ) = 0.300
∴ q3 = 0.300 / 10^9
= 0.300 nC
Note : The value of Eay is been calculated outside this solution as it is not part of the question asked
Three advantages of working as a nuclear physicist
9.
A 2.85-cm diameter coin is placed a distance of 31.4 cm from a diverging lens that has a focal length
of-11.6 cm. Determine the image distance and the diameter of the image.
Answer:
image distance = -8.47 cm
diameter of the image = 0.769 cm
choose the correct answer 14: which of the following force follows the inverse square law of distance A: gravitaional force B: electromagnetic force C: both (a) and (b) D: none of these
Answer:
C. both A and B
Explanation:
Sana nakatulong
If a wave is traveling at 60 cm/second and has a wavelength of 15 cm, what is the frequency?
A. 900 Hz
B. 60 Hz
C. 8 Hz
D. 4 Hz
Answer: B
G v = 60 cm/s λ = 15 cm E f = V / λ S f = 4 Hz U f = ? S f = (60 cm/s) / 15 cm 5.
Explanation:
Two vehicles are approaching an intersection. One is a 2600 kgkg pickup traveling at 17.0 m/sm/s from east to west (the −x−x- direction), and the other is a 1300 kgkg sedan going from south to north (the +y−+y− direction at 24.0 m/sm/s ). Part A Find the xx -component of the net momentum of this system. pxpx = nothing kg⋅m/skg⋅m/s SubmitRequest Answer Part B Find the yy-component of the net momentum of this system. pypy = 0 kg⋅m/skg⋅m/s SubmitPrevious AnswersRequest Answer Incorrect; Try Again; 4 attempts remaining Part C What is the magnitude of the net momentum?
Answer:
a) the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]
b) the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]
c) the magnitude of the net momentum is 54102.5 kgm/s
Explanation:
Given the data in the question;
a) x-component of the net momentum of this system.
the second vehicle ( sedan ) doesn't have momentum along x-axis, the momentum along x-axis is strictly contributed by the pick up
so;
Px = 2600 kg × 17.0 m/s [tex](-x)[/tex]
Px = 44200 kgm/s [tex](-x)[/tex]
Therefore, the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]
b) y-component of the net momentum of this system
Also, momentum along y-axis is entirely provided by the sedan
Py = 1300 kg × 24.0 m/s [tex](y)[/tex]
Py = 31200 kgm/s [tex](y)[/tex]
Therefore, the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]
c) magnitude of the net momentum?
magnitude of the net momentum P = √( Px² + Py² )
so we substitute
P = √( (44200)² + (31200)² )
P = √( 2927080000 )
P = 54102.5 kgm/s
Therefore, the magnitude of the net momentum is 54102.5 kgm/s