Answer:
[tex]M=0.0513M[/tex]
Explanation:
Hello!
In this case, since the molarity of a solution is computed by dividing the moles of solute by the volume of solution, we notice we first need the moles of KHP as shown below:
[tex]n=0.5237g*\frac{1mol}{204.22 g} =0.00256mol[/tex]
Next, the volume in liters:
[tex]V=50.0mL*\frac{1L}{1000mL}\\\\V=0.0500L[/tex]
Thus, the molarity turns out to be:
[tex]M=\frac{n}{V}\\\\M=\frac{0.00256mol}{0.05000L} \\\\M=0.0513M[/tex]
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Which answer would represent 0.001 moles?
Answer:
Which answer would represent 0.001 moles?
A sealed 1.0L flask is filled with 0.500 mols of I_2 and 0.500 mols of Br_2. When the container achieves equilibrium the equilibrium constant is 1.10x10^{-2}. What is the equilibrium concentration of the product, IBr?
Answer:
[IBr] = 0.049 M.
Explanation:
Hello there!
In this case, according to the balanced chemical reaction:
[tex]I_2+Br_2\rightarrow 2IBr[/tex]
It is possible to set up the following equilibrium expression:
[tex]K=\frac{[IBr]^2}{[I_2][Br_2]} =0.0110[/tex]
Whereas the the initial concentrations of both iodine and bromine are 0.50 M; and in terms of [tex]x[/tex] (reaction extent) would be:
[tex]0.0110=\frac{(2x)^2}{(0.50-x)^2}[/tex]
Which can be solved for [tex]x[/tex] to obtain two possible results:
[tex]x_1=-0.0277M\\\\x_2=0.0245M[/tex]
Whereas the correct result is 0.0245 M since negative results does not make any sense. Thus, the concentration of the product turns out:
[tex][IBr]=2x=2*0.0249M=0.049M[/tex]
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