Can you find the mass of the angles?

Answer:

r1 and r2 are the radii of two concentric circles

To find:

The length of the chord of the larger circle.

Solution:

We have given the two concentric circles which means both the circles have the same centre.

The chord of the larger circle toches the inner circle so the chord of the larger circle will be the tangent of the smaller circle.

And we know that the radius of the circle is perpendicular to the tangent of the circle.

Let 2x be the length of the chord of the circle.

r1 is the radius of the larger circle.

r2 is the radius of the smaller circle.

So by the Pythagoras theorem,

The length of the half of the chord is given by:

r1² = x² + r2²

x² = r1² - r2²

x = √r1² - r2²

So,

The length of the chord will be 2x = 2√r1² - r2² units

Step-by-step explanation:

I think it is A)2 because 3^2 = 9 and 9×4 = 36

Step-by-step explanation:

[tex] \underline{ \underline{ \text{Given}}} : [/tex]

[tex] \underline{ \underline{ \text{To \: find}}} : [/tex]

[tex] \underline{ \underline{ \text{Solution}}} : [/tex]

~ Plug the value of x and then multiply !

⇾ [tex] \tt{6x = 6 \times 6 \times = \boxed{36}}[/tex]

[tex] \red{ \boxed{ \boxed{ \text{Our \: final \: answer : \boxed{ \tt{36}}}}}}[/tex]

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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Answer:

340

Step-by-step explanation:

Answer:

a. Negation of ∃x ∀y(P(x,y) → Q(x,y)) = ∀x  ∃y P(x,y)  ∧ ¬Q(x,y) ]

b. Negation of ∃x ∀y(P(x,y) → P(y,x)) = ∀x ∃y  [ ¬P(x,y) ∨ ¬P(y,x) ] ∧ [P(x,y) ∨ P(y,x)]

c. Negation of ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y) = ∀x ∀y ¬ [P(x,y)]  ∨ ∃x ∃y ¬ [Q(x,y)]

Step-by-step explanation:

a.∃x ∀y(P(x,y) → Q(x,y))

Negation = ¬ [ ∃x ∀y(P(x,y) → Q(x,y)) ]

                = ∀x  ¬ [ ∀y(P(x,y) → Q(x,y)) ]

                = ∀x  ∃y ¬ [ (P(x,y) → Q(x,y)) ]

                = ∀x  ∃y ¬ [  ¬P(x,y)  ∨ Q(x,y) ]

                = ∀x  ∃y P(x,y)  ∧ ¬Q(x,y) ]

Negation of ∃x ∀y(P(x,y) → Q(x,y)) = ∀x  ∃y P(x,y)  ∧ ¬Q(x,y) ]

b. ∃x ∀y(P(x,y) → P(y,x))

Negation = ¬ [ ∃x ∀y(P(x,y) → P(y,x)) ]

               = ∀x ¬ [ ∀y(P(x,y) → P(y,x)) ]

               = ∀x ∃y ¬ [ (P(x,y) → P(y,x)) ]

               = ∀x ∃y ¬ [ ( P(x,y) ∧ P(y,x) ) ∨ ( ¬P(x,y) ∧ ¬P(y,x) )]

               = ∀x ∃y ¬ [ P(x,y) ∧ P(y,x) ] ∧ ¬[ ¬P(x,y) ∧ ¬P(y,x) ]

               = ∀x ∃y  [ ¬P(x,y) ∨ ¬P(y,x) ] ∧ [ P(x,y) ∨ P(y,x) ]

∴ we get

Negation of ∃x ∀y(P(x,y) → P(y,x)) = ∀x ∃y  [ ¬P(x,y) ∨ ¬P(y,x) ] ∧ [P(x,y) ∨ P(y,x)]

c. ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y)

Negation = ¬ [ ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y) ]

                = ¬ [ ∃x ∃y P(x,y) ]  ∨ ¬ [ ∀x ∀y Q(x,y) ]

                = ∀x¬ [  ∃y P(x,y) ]  ∨ ∃x ¬ [ ∀y Q(x,y) ]

                = ∀x ∀y ¬ [ P(x,y) ]  ∨ ∃x ∃y ¬ [ Q(x,y) ]

∴ we get

Negation of ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y) = ∀x ∀y ¬ [ P(x,y) ]  ∨ ∃x ∃y ¬ [ Q(x,y) ]

Answer:

[tex]7\sqrt{2}[/tex]

Step-by-step explanation:

a^2 + b^2 = c^2

8^2 + [tex](\sqrt{34} )^2[/tex] = 64 + 34 = 98 = c^2

c = [tex]\sqrt{98}[/tex] = [tex]7\sqrt{2}[/tex]

34.9 is the length of the third side needed

Step-by-step explanation:

a²+b²=c²

Answer:

circle D

Step-by-step explanation:

Answer:

(d+5)^2

Step-by-step explanation:

Answer:1/8

Step-by-step explanation:

Answer:

1/8

Step-by-step explanation:

1/2 x 1/2 x 1/2 = 1/8

Answer:

A≈149.57

Step-by-step explanation:

Answer:

[tex](-2-2\sqrt{2},3+2\sqrt{2})\,,\,(-2+2\sqrt{2},3-2\sqrt{2})[/tex]

Step-by-step explanation:

Given:

[tex](x+2)^2+(y-3)^2=16\\x+y-1=0[/tex]

To find: value of [tex]x,y[/tex]

Solution:

[tex](x+2)^2+(y-3)^2=16\,\,\,...(i)\\x+y-1=0\,\,\,(ii)[/tex]

From (ii),

[tex]x=1-y[/tex]

Put this value of [tex]x[/tex] in (i)

[tex](1-y+2)^2+(y-3)^2=16\\(3-y)^2+(y-3)^2=16\\(y-3)^2+(y-3)^2=16\\2(y-3)^2=16\\(y-3)^2=8[/tex]

[tex]y-3=[/tex] ± [tex]\sqrt{8}[/tex] = ± [tex]2\sqrt{2}[/tex]

[tex]y=3[/tex] ± [tex]2\sqrt{2}[/tex]

At [tex]y=3[/tex] + [tex]2\sqrt{2}[/tex] ,

[tex]x=1-(3+2\sqrt{2})=1-3-2\sqrt{2}=-2-2\sqrt{2}[/tex]

At [tex]y=3-2\sqrt{2}[/tex] ,

[tex]x=1-(3-2\sqrt{2})=1-3+2\sqrt{2}=-2+2\sqrt{2}[/tex]

Solutions are [tex](-2-2\sqrt{2},3+2\sqrt{2})\,,\,(-2+2\sqrt{2},3-2\sqrt{2})[/tex]

Step-by-step explanation:

first term

degree 1

coefficient 4

second term

degree. 2

coefficient 8

third term

degree 3

coefficient -5

fourth term

degree 4

coefficient -5

fifth term

degree 0

coefficient -5

Answer:

Option C is the correct answer.

Comment for explaination

Answer:

Where's the cone at and I might be able to help

Step-by-step explanation:

Answer: Please put a picture of the cone underneath the question!

Step-by-step explanation:

Answer:

The answer is 6

Step-by-step explanation:

[tex]\lim_{x \to 4} \frac{x^3 - 64}{x^2 - 16} \\\\= \lim_{x \to 4} \frac{x^3 - 64}{(x + 4)(x - 4)} \\\\=\lim_{x \to 4} \frac{(x^2 + 4x + 16)(x - 4)}{(x + 4)(x - 4)} \\\\= \lim_{x \to 4} \frac{(x^2 + 4x + 16)}{(x + 4)} \\\\= (16 + 16 + 16) / 8\\= 48 / 8\\= 6[/tex]

Answer: 285

Step-by-step explanation:

Jared = 194

Matthew=(194)(3)=582

Gary=582-297=285

Fewer means Substraction

Gary will sell 285 chocolate bars

Answer:

5

Step-by-step explanation:

To find the distance between two points, subtract the two values and find the absolute value. So in this question, our equation would be |-2-3| which equals |-5| which then solves to 5.

Step-by-step explanation:

1) Your problem → (4x^2 - 17x^3 + 9) - (x^2 + 9x + 23x^2 + 11)

(-17x^3+4x^2+9)-(x^2+23x^2+9x+11)

=-17x^3+4x^2+9-x^2-23x^2-9x-11

=-17x^3+4x^2-x^2-23x^2-9x+9-11

=-17x^3-20x^2-9x-2

2) Your problem → 0 - 19.73 - 25x^2 - 12x - 3

=0-19.73-25x2-12x-3

=-25x^2-12x-22.73

3) - 10.x^3 – 162x^2 – 24x - 4

4) Your problem → 17x^3 - 20x^2 - 9x^2

=17x^3-20x^2-9x^2

=17x^3-29x^2

5) -16x^3 – 243x^2 – 12x – 3

Answer:

The answer is 1 time

Step-by-step explanation:

If you subtract 60 from 72 you come out with 12. Which is not enough for you to subtract 60 again so the answer is 1.

Answer:

1 equals two of 1/2 which means you get the equation 1/3 x 2 for the answer

Answer:

4 1/3(b-21) im pretty sure

Answer:

23.10

Step-by-step explanation: Each large necklace is 4.10 There are only 1 largfe necklace he sold so we multiply 4.10 by 1 which is 4.10. A small necklace is 3.80 and he sold 5 of them so we multiply 5 by 3.80. 3.80 times 5 is 19. Then we add the large and small necklace product.

19+ 4.10=23.10

Answer:

23.1

Step-by-step explanation:

(4.10*1)+(3.80*5)

4.10*1=4.10

3.80*5=19

4.10+19=$23.1

Answer:

x=-5

Step-by-step explanation:

x/12-1=-6

  12-1

x/11=-6

 -11  -11

========

  x=-5

Hope that helps

Answer:

What are you asking? Whats the problem?

Answer:

sin 102 cant be put into standard position its already in standard position if you want to covert to rectangular it would be sin (102).

Step-by-step explanation:

Answer:

60° is answer.it is right.thank you

Answer: Tuesday

April 20,2021

Answer: No because 1/2 is equal to 6/12 because 1 x6=6 and 2x6 =12 which makes 1/2 equivalent to 6/12 not 7/12

Answer:

no this is false

Step-by-step explanation:

7 is not half of 12

Answer: 1/1024

Step-by-step explanation:

m^-n=4^(-5)

=1/(4^5)

=1/1024

Answer:

Equation :---

[tex] {m}^{ - n} [/tex]

where m=4, n=5 and p=-2

[tex] {4}^{ - 5} = \frac{1}{ {4}^{5} } = \frac{1}{1024} \\ [/tex]

Answer:

The equation is y = (2/3)x + (4/3).

Step-by-step explanation:

First, you have to change the equation into slope-intecept formula to find its gradient (slope) :

[tex]3x + 2y = 12[/tex]

[tex]2y = - 3x + 12[/tex]

[tex]y = - \frac{3}{2}x + 6[/tex]

Given that when a line is perpendicular to the other line, their slope value multiplied, will form -1. Next, we have to find the slope for line :

[tex]m1 \times m2 = - 1[/tex]

[tex] - \frac{3}{2} \times m2 = - 1[/tex]

[tex]m2 = - 1 \div - \frac{3}{2} [/tex]

[tex]m2 = \frac{2}{3} [/tex]

Lastly, we have to subatitute the x and y values into the equation, to find its intercept value :

[tex]y = \frac{2}{3}x + b[/tex]

[tex]let \: x = 1,y = 2[/tex]

[tex]2 = \frac{2}{3} (1) + b[/tex]

[tex]b = 2 - \frac{2}{3} [/tex]

[tex]b = \frac{4}{3} [/tex]

[tex]y = \frac{2}{3} x + \frac{4}{3} [/tex]