Can you help me solve this problem please?

Answer:

a)

(4a - 3b + 4) + (a + 3b - 1) =

4a - 3b + 4 + a + 3b - 1 =

5a + 3

b)

(2x^2 - 3x - 3) + (-x^2 - 6x + 8) =

2x^2 - 3x - 3 - x^2 - 6x + 8  =

x^2 - 9x + 5

c)

(3m^2 + 5m - 6) + (-m^2 - 4n + 5) =

3m^2 + 5m - 6 - m^2 - 4n + 5 =

m^2 + 5m - 4n -1

d)

(4x^3 - 3xy^2) + (x^3 - 5xy^2 - 5y^2) =

4x^3 - 3xy^2 + x^3 - 5xy^2 - 5y^2 =

7x^3 - 8xy^2 - 5y^2

e)

(5m + 2lm) + (l^2 - 3m^2 - 2lm) =

5m + 2lm + l^2 - 3m^2 - 2lm =

5m + l^2 - 3m^2

Answer:

Jaime is _48_years old, and Savannah is _32_ years old.

Step-by-step explanation:

Jaime is 16 years older than Savannah

Ten years ago, the sum of ages = 60.

(60-16)=22

Ten years ago, Jaime=22+16=38y but now Jaime is 48 (38+10)

Ten years ago, Savannah = 22y but now Savannah is 32y (22+10)

hope this helps

Answer:

I think that it would be -4.5

Step-by-step explanation:

Have a great day!

Answer:

-4.5

Step-by-step explanation:

yeahhhhhhh

Answer:

a=55%

b=190%

c=54 pounds

Step-by-step explanation:

ok

a.

33/60=0.55

55%

b.

114/60=1.9

or 190%

c

60/100=0.6

0.6=1 percent

54

Answer:

a=55%

b=190%

c=54 pounds

Step-by-step explanation:

Answer:

Step-by-step explanation:

3x+2

Answer:

90

Step-by-step explanation:

Answer:

Step-by-step explanation:

1/18

9514 1404 393

Answer:

Step-by-step explanation:

Let e represent the number of pounds of expensive chocolate in the bag. Then (3-e) is the amount of the other chocolate. The total cost of the bag will be ...

  6.00e +4.50(3 -e) = 15.00

  1.50e = 1.50 . . . . . . collect terms, subtract 13.50

  e = 1 . . . . . . . . . . . . .divide by 1.50

1 pound of expensive chocolate is used; 2 pounds of other chocolate is used.

Answer:

[tex] \frac{1} {2^{-1}}[/tex]

Step-by-step explanation:

[tex] \huge \frac{1}{ {8}^{ - \frac{1}{3} } } \\ \\ = \huge \frac{1}{ {( {2}^{3} )}^{ - \frac{1}{3} } } \\ \\ = \huge \frac{1}{ {{2} }^{ - 3 \times \frac{1}{3} } } \\ \\ = \huge \frac{1}{ {{2} }^{ - 1 } } [/tex]

Answer:

12

Step-by-step explanation:

Answer:

m, p

Step-by-step explanation:

Answer:

x^4-3x^3-14x^2+12x+40 =0

Step-by-step explanation:

Answer:

Step-by-step explanation:

3000

Answer:

46

Step-by-step explanation:

Calculate in calculator

Answer:

D

Step-by-step explanation:

the answer os 60% of 20 is 12

Answer:7 foot i think

Step-by-step explanation: bottom is 4 foot side is 7 foot that means other side is 7 foot

Answer:

8.08 %

Step-by-step explanation:

Let us denote : [tex]X=[/tex] score X follows a normal distribution with mean [tex]=24[/tex] and standard deviation [tex]=1.5[/tex]

Step 2

The probability that someone scored 21.9 or less is :

[tex]\mathrm{P}(\mathrm{X} \leq 21.9)[/tex]

[tex]=\mathrm{P}\left(\mathrm{Z} \leq \frac{21.9-24}{1.5}\right)[/tex]

[tex]=\mathrm{P}(\mathrm{Z} \leq-1.4)[/tex]

[tex]=0.0808[/tex]

[tex]=8.08%[/tex]

Answer : [tex]8.08 %[/tex]

Answer:

y = (0,4)

x=(6,0)

(6,4)

Step-by-step explanation:

Answer:

the answer is 0.375

Step-by-step explanation:

hope this helps

Answer:

No values of x- Any whole number that is not 8

All values of x: 8

Just one Value of x: There could be many possibilites but all of them have to be some value of x. One answer is:x

Step-by-step explanation:

3x + 8 = 3x + x, which has one solution at x=8.

The given equation is 3x+8=3x+ ____.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

If 3x + 8 = 3x + 7 has no solutions

If 3x + 8 = 3x + 8 has infinite solutions

If 3x + 8 = 3x + x is equal to 3x + 8 = 4x, which has one solution at x=8

Therefore, 3x + 8 = 3x + x, which has one solution at x=8.

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Answer:

3060 ducks

Step-by-step explanation:

There are 2 possibilities here. We can plug in 15 for n since 2025 is 15 years after 2010, or we can graph it and find the value.

If we do the first method, we have

[tex]P=200*1.02(15)\\P=3060[/tex]

So the population in 2025 is 3060 ducks.

We can check our answer by graphing on a calculator. If we enter the equation and then use calc>value we can see that when x=15, y=3060.

Hope this helps!

Look at the values on the axes of the graph.

Step-by-step explanation:

Domain can be found by looking at the x-axis of a graph. Range can be found by looking at the y-axis of a graph. You have to find at what point on the axis is the graph stopping.

For example, if I wanted the domain of y=x, I would say it is all real numbers. Why? Because when we look along the x-axis, from left to right, we can see that it continues going until infinity. That means that there are no stopping points in the graph of y=x.

Answer:

9 + 6.2x = y

Step-by-step explanation:

x - Gallons per minute

y - Total gallons

So, your answer would be:

9 + 6.2x = y

Could also be written as:

y = 9 + 6.2x

Hope this helps :)

Answer:

Expression: [tex] \frac{40}{y - 16} [/tex]

When y = 20, the value of the expression is 10.

Step-by-step explanation:

The expression for the phrase "difference of a number, y, and 16" is (y - 16).

Therefore, the quotient of 40 and the "difference of a number, y, and 16" would be written as:

[tex] \frac{40}{y - 16} [/tex]

Let's evaluate the expression when y = 20.

Substitute y = 20 into [tex] \frac{40}{y - 16} [/tex].

Thus:

[tex] \frac{40}{20 - 16} [/tex]

[tex] = \frac{40}{4} = 10 [/tex]

Answer:m = 5/4  b=2 and  y=5/4x +2

Step-by-step explanation:

m = 5/4  b=2 and  y=5/4x +2

Answer:

B) △DEF ~ △GHI

E) △JKL ~ △ABC

Step-by-step explanation:

i just did the assignment

The  pairs of triangles are similar

△DEF ~ △GHI and △JKL ~ △ABC.

If two triangles have an equal number of corresponding sides and an equal number of corresponding angles, then they are comparable. Similar figures are described as items with the same shape but varying sizes, such as two or more figures.

Given:

AC = 14

BC = 20

DF = 8

FE= 10

HI = 15

IG = 12

KL = 10

LJ = 7

As, In Right Triangle we can use Pythagoras theorem

AB = √14²+ 20² = 24.41

DE= √8²+10²= 12.8

HG= √15²+ 12² = 19.2

KJ= √10² + 7² = 12.2

Then, from the ratio of Corresponding sides we get

△DEF ~ △GHI and △JKL ~ △ABC.

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