Which of the following is NOT an example of convection?
Answer:
HEAT?
Explanation:
A person gets a suntan on a beach is not an example of convection. Therefore, the correct option is option C.
What is convection?The process of convection involves the movement of such a heated fluid, including such air or water, in order to transfer heat. Natural convection is caused by the fact that most fluids have a propensity to expand when heated, becoming less dense and rising due to the increased buoyancy.
Natural convection is caused by the fact that most fluids have a tendency to expand when heated, becoming less dense and rising due to the increased buoyancy. The air inside a heated room or the water inside a kettle are heated uniformly thanks to circulation brought on by this effect. A person gets a suntan on a beach is not an example of convection.
Therefore, the correct option is option C.
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Your question is incomplete but most probably your full question was,
Which one of the following is not an example of convection?
a) Smoke rises above a fire.
b) An eagle soars on an updraft of wind.
c) A person gets a suntan on a beach.
d) Spaghetti is cooked in water.
e) An electric heater warms a room.
How Negative Points Works
btw help me with this
How much does the sky weigh?
Answer:
it weighs 237469812734t7162341873498273417234321476281736481273648123764812736481723648273648137468127364872364 million pounds :)
Explanation:
Answer:
This is a dumb question.
Explanation:
The 'sky' does not weigh anything.
PLEASE HELP URGENT 1. You put 1 gram of salt into 1 liter of water and stir. The resulting liquid is an example of
A. A pure substance.
B. a homogeneous mixture.
C. a heterogeneous mixture.
D. an immiscible mixture.
1. A car has a mass of 400 kg and is driving down a hill at 2 m/s/s. What is the force of the car?
Answer:
l think the right answer is 4720
One of the largest pipe organs is in the auditorium organ in the Fox Theatre. The pipe is 32 ft. Long and produces a sound with a wavelength of about 8.8m. If the speed of sound in air is 346 m/s what is the frequency of this sound? What is the period? Show all work and explain your answer.
Explanation:
length of pipe= 32 ft
wavelength of wave λ= 8.8 m
let f be frequency
we know velocity of wave v=λf
therefore, f=v/λ = 346/8.8 = 39.31 per second or hertz
time period = 1/f = 1/39.31 = 0.02543 seconds
The frequency of this sound will be 39.31-sec⁻¹or Hz. While the time period will be 0.02543 sec.
What is the frequency?Frequency is defined as the number of repetitions of waves occurring in 1 second. Frequency is also defined as the number of cycles completed in 1 second. SI unit of frequency is Hz.
The given data in the problem is;
L is the length of pipe= 32 ft
λ is the wavelength of wave= 8.8 m
f is the frequency=?
T is the time period=?
The frequency is fine as the ratio of the speed of wave and wavelength.,
[tex]\rm f= \frac{v}{\lambda} \\\\ \rm f= \frac{346}{8.8}\\\\ \rm f= 39.31 \ Hz[/tex]
The time period is guven as the inverse of the time period.
[tex]\rm T = \frac{1}{f} \\\\ \rm T = \frac{1}{39.31} \\\\ \rm T = 0.02543\ sec[/tex]
Hence the frequency of this sound will be 39.31-sec⁻¹or Hz. While the time period will be 0.02543 sec.
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Suggest a measure that a government can take to reduce a country's energy use
Answer:
Using alternative sources of energy like solar power,wind powermake aware people about using less energyconduct more hydroelectricity projectsWhich of the following is extrusive? Lava, Magma, Laccolith, Batholith.
Answer:
lava
Explanation:
Clara's grandfather is a captain of a cargo ship. He prefers to navigate his ship through the moderate neap tides. At these times, the line between Earth and the sun is at a right angle to the line between Earth and the moon. Which phase or phases of the moon describe this alignment?
Answer:
The phases are the first and third quarters.
Explanation:
During the first quarter of the moon phases, the line between Earth and the Sun is at a right angle to the line between Earth and the moon. At this time the moon has completed the first quarter of its orbit around the earth. At this point, half of the moon is fully reflecting light from the sun.
Also during the third quarter which is the last quarter, the line between the earth and the sun is at a right angle to the line between the earth and the moon. This is the time when the second half of the moon which was not illuminated during the first quarter becomes completely illuminated.
F = m x a. A ball of mass 0.35kg rolls on a smooth surface hits another object at rest and of mass 7kg. The second object gets an acceleration of 1.5m/s2. What acceleration does the ball get? Use newton’s third law.
Please show the working and thankyouu!!
Answer:
The acceleration the ball gets = 30 m/s²
Explanation:
The given parameters are;
The mass of the first ball that hits an object, m₁ = 0.35 kg
The mass of the object hit by the ball, m₂ = 7 kg
The acceleration given to the second object, a₂ = 1.5 m/s²
Let the a₁ represent the acceleration the ball gets
Newton's third law states that action and reaction are equal and opposite, therefore, the force exerted on a body A by a body B is equal to the force exerted on the body B by the body A;
Therefore, we have;
The force exerted on the object, F₂ = m₂ × a₂ = 7 × 1.5 = 10.5 N
The force the ball exerts on the object = F₁ = m₁ × a₁ = 0.35 × a₁
By Newton's third law, F₁ = F₂, which gives;
m₁ × a₁ = m₂ × a₂
0.35 × a₁ = 10.5
a₁ = 10.5/0.35 = 30
The acceleration the ball gets = a₁ = 30 m/s².
B. A car is moving 4.0 m/s to the right. The car begins to accelerate at a rate of 1.5 m/s/s, to the right. After
10 seconds, what will be the velocity of the car? For credit, show work in detail
Which of the following is not an example of acceleration?
A) A person jogging at 3 m/s along a winding path
B) A car stopping at stop sign
C) A cheetah running 27 m/s east
D) a plane taking off
John is a runner. He runs the 100m sprint in 10.6s. What speed did he travel at? (in m/s)
The answer you are looking for is approximately 9.4 m/s.
Solution/Explanation:
First, writing out the formula for the speed of an object, encompassing distance and time, in meters per second, or m/s,
S=D/T.
"S" stands for "Speed."
"D" stands for "Distance."
"T" stands for "Time."
Speed (S)=????
Distance (D)=100m.
Time (T)=10.6s.
Substituting the given values of the variables,
S=100m/10.6s.
100÷10.6=9.43396226415≈9.4.
So, therefore, the final answer is approximately 9.4 m/s.
I hope that this has helped answer your question. Good day to you.
The SI unit of measurement for mass is the
Answer:
m/s is answer for your questions
A baseball is thrown at an angle of 22◦ relative to the ground at a speed of 24.8 m/s. The ball is caught 43.5518 m from the thrower. The acceleration due to gravity is 9.81 m/s^2
How long is it in the air?
Answer in units of s.
How high is the tallest spot in the ball’s path?
Answer in units of m
Answer:
12 seconds in the air
2.5
very high
132
Explanation:
URGENT ANSWER ASAP PLEASE
What is the relationship between memory and learning? Memory and learning are the same process. Memory is more important than learning. Memory is the foundation of all learning. Memory outlasts learning
Answer:
learning and memory are very closely related concept . Learning is the acquisition of silk or knowledge, while memory is the expression of what you've acquired.Another difference is the speed with which the two things happen if you acquire the new skill or knowledge slowly and laboriously, that's learning
Answer: I took a test that had this question and the answer was Memory is the foundation of all learning. I hope this helps
A Red-Tailed Hawk leaves its nest and flies 100.0 meters across the sky in 20 seconds, when it spots a garter snake on the ground below. It then flies 50.0 meters in 5.0 seconds to catch the snake. What was the hawk's average speed over his entire journey?
Answer:
7.5 m/s
Explanation:
A red tailed hawk leaves its nest and flies 100 meters across the sky in 20 secs
Speed 1= distance/time
= 100/20
= 5m/s
When it spots a garter snake on the ground it flies 50 meters in 5 secs
Average speed= distance /time
= 50/5
= 10 m/s
Therefore the average speed of the hawk over the entire journey can be calculated as follows
= 10+5/2
= 15/2
= 7.5 m/s
Which statements about carbon-14 dating are true? Check all that apply. Carbon-14 decays into nitrogen-14. Carbon-14 has a longer half-life than potassium-40. Once a living thing dies, it no longer takes in carbon. Carbon-14 dating is used to date very old volcanic rock. Carbon-14 dating works for fossils as old as 50,000 years.
Answer:
135
Explanation:
A person, of weight mg, is standing on a scale in an elevator. What will the
scale read when the elevator accelerates upward?
A. More than mg
B. Less than mg
C. Equal to mg
D. Cannot tell what the scale will read.
more than mg
Explanation:
the pressure
A car traveling at 50 m/s comes to a stop in 5 seconds. What is the
acceleration of this car?
Answer:10
Explanation:
You have to do speed divided by time so your answers 10
How many molecules of water are found in this formula--6H2O?
Answer:
6 the number infront of H2O is the amount of molecules it is
Explanation:
How much longer would it take to travel a
distance of 600 km at a speed of 50 kmhr-1
than it would at a speed of 60 kmhr-1?
Explanation:
Time=distance/speed
=600/50
=12
=600/60=10
==12-10=2 hours
How much resistance allows 6V battery to produce a current of 0.006 amps?
Answer:
It produces 1000Ω.
Explanation:
You have to apply Voltage formula, V = I × R :
V = I × R
6 = 0.006 × R
R = 6 ÷ 0.006
R = 1000Ω
We have that from the Question"How much resistance allows 6V battery to produce a current of 0.006 amps?" it can be said that How much resistance that allows 6V battery to produce a current of 0.006 amps is
R=1000 ohms
From the Question we are told
How much resistance allows 6V battery to produce a current of 0.006 amps?
Generally the equation for Resistance mathematically given as
[tex]R=\frac{V}{I}\\\\\Therefore\\\\R=\frac{V}{I}\\\\R=\frac{6}{0.006}\\\\[/tex]
R=1000 ohms
Therefore
How much resistance that allows 6V battery to produce a current of 0.006 amps is
R=1000 ohms
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how does the electric force between two charged particles change if the distance between them is decreased by a factor of 3?
Answer:
F' = 9F
Explanation:
The electric force between charges is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
It means,
[tex]F\propto \dfrac{1}{r^2}[/tex]
If distance decreased by a factor of 3, r' = r/3
Net force will become,
[tex]F'=\dfrac{kq_1q_2}{r'^2}\\\\=\dfrac{kq_1q_2}{(\dfrac{r}{3})^2}\\\\=9\dfrac{kq_1q_2}{r^2}\\\\=9\times F[/tex]
It means new force will become 9 times that of the initial force.
Answer:
it is increased by a factor of 9
Explanation:
just took the test
100 points to whoever can help, please
A 52-kg snow skier is at the top of a 245-m-high hill. After she has gone down a vertical distance of 112 m, what is her total energy?
a. 125 kJ
b. 1430 kJ
Selected: c. 570 kJThis answer is incorrect.
d. 13 kJ
Answer:
A) 1.2x10^5 J
Explanation:
A car accelerates from rest at a rate of 4 m/s’2 . How many seconds will it take the car to reach a final speed of 16m/s
Answer:
t = 4 [s]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f}=v_{o}+a*t[/tex]
where:
Vf = final velocity = 16 [m/s]
Vo = initial velocity = 0
a = acceleration = 4 [m/s²]
t = time [s]
Now replacing:
[tex]16=0+4*t\\t = 16/4\\t = 4[s][/tex]
properties can be used to distinguish and separate substances.
Answer:
true
Explanation:
What is the voltage required to move 3A through three resistors (2ohms, 3ohms & 5ohms)?
A skateboarder is trying to skate horizontally off a building and jump over a pool as shown! The pool is 25.0m wide and the roof of the building is 32.0m above where he will land. Neglect drag.
How long will the skateboarder remain in the air?
With what initial speed (in given units) does the skateboarder need to barely clear the pool?
Would the skateboarder clear the pool if he skated off the building with an initial speed of 27mph?
Answer:
a) t = 2.55s
b) [tex]v_{0x} = 9.80 m/s[/tex]
c) yes
Explanation:
In order to solve this problem, we can start by drawing a sketch of the situation so we can better visualize what the problem is about (see attached picture).
a)
For the first question. We are talking about a movement in two dimensions. So on the first question they are asking us for vertical movement. It will be uniformly accelerated, so we can use the following formula:
[tex]y_{f}=y_{0}+V_{0y}t+\frac{1}{2}at^{2}[/tex]
We know the following:
[tex]y_{f}=0[/tex]
[tex]y_{0} = 32m[/tex]
[tex]V_{0y}=0[/tex]
t=?
[tex]a=-9.81 m/s ^{2}[/tex]
With this data, we can simplify our equation, so we end up with:
[tex]y_{0}+\frac{1}{2}at^{2}=0[/tex]
so we can now substitute the data we know and solve for t:
[tex]32m-\frac{1}{2}(9.81 m/s^{2})t^{2}=0[/tex]
[tex](-4.905 m/s^{2})t^{2}=-32m[/tex]
[tex]t^{2} = \frac{-32m}{-4.905 m/s^{2}}[/tex]
[tex]t=\sqrt{6.52s^{2}}[/tex]
t = 2.55 s
b)
For part b, since we are talking about horizontal movement and we are neglecting drag, this means that his horizontal speed will be constant. So we can use the following formula:
[tex]V_{x}=\frac{x}{t}[/tex]
we know he most move a horizontal distance of 25 meters in a time of 2.55s so we get:
[tex]V_{x} = \frac{25m}{2.55s}[/tex]
[tex]V_{x}=9.80 m/s[/tex]
c) for part c, we can do the conversion between miles per hour to meters per second like this:
[tex]\frac{27mi}{1hr}*\frac{1hr}{3600s}*\frac{5280ft}{1mi}*\frac{0.3048m}{1ft}[/tex]
so the given initial speed is equivalent to:
12.07 m/s
this is greater than the minimum 9.80 m/s we need, so the skater will clear the pool at this speed.
(a) The time spent in air by the skateboarder is 2.56 s
(b) The initial speed needed by the skateboarder to clear the pool is 9.77 m/s.
(c) The skateboarder with given initial speed of 27 mph will clear the pool since it is greater than minimum initial velocity required.
The given parameters;
width of the pool, d= 25 mheight of the building, h = 32 mThe time spent in air by the skateboarder is calculated as follows;
[tex]h = v_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\gt^2 = 2h\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 32}{9.8} } \\\\t =2.56 \ s[/tex]
The initial speed needed by the skateboarder to clear the pool is calculated as;
[tex]v = \frac{d}{t} \\\\v = \frac{25}{2.56} \\\\v = 9.77 \ m/s[/tex]
The initial speed of the skateboarder is m/s;
[tex]27 \ \frac{mile}{hour} \times \frac{1609.3 \ m}{1 \ mile} \times \frac{1 \ hr}{3600 \ s} = 12.07 \ m/s[/tex]
Thus, the skateboarder with given initial speed of 27 mph will clear the pool since it is greater than minimum initial velocity required.
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A dog walks a distace of 100 ft in 20 s of time. What is the dogs speed in feet per second
Answer:
5 sec
Explanation:
A particle is launched at an angle of 37° from horizontal. If the horizontal velocity component is 7.65 meters/second, what is the resultant velocity of the particle?
Answer:
R = 9.58 m/s
Explanation:
cos(37) = (7.65 m/s)/R
R = (7.65 m/s)/cos(37)
R = 9.58 m/s