Choose all of the zeros of the function f(x) = 2x² + 5x – 3.
-3, -0.5, 0.5, 1, 3 << those are the answer choices.

Answer:

≈ 0.52

Step-by-step explanation:

P( head ) = 2/3 , P( tail ) = 1/3

when a head is tossed ; Gambler A wins $1

when a tail is tossed : Gambler B wins $1

Determine the P( Gambler A wins the game ) if he starts with I dollars

Assuming I = $1

n = 5

p ( head ) = P( winning ) = 0.66

p( losing ) = 0.33

applying the conditional probability in Markov which is ;

Pₓ = pPₓ₊₁ + (1 - p) Pₓ₋₁

P( 1) = 0.66P₂ + 0.33P₀

resolving the above using with Markov probability

P( 1 ) = 0.51613

hence the probability of Gambler A winning the game if he starts with $1

≈ 0.52

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

1/48 + 5/6    

The LCD of 48 and 6 is 48 so we have:

1/48 + 40/48

= 41/38

Answer:

41/48

Step-by-step explanation:

Answer:

Here is the picture

Step-by-step explanation:

The number lies between x-values 4 and 6 and y-values 6 and 9.

Coordinates are a pair of integers (Cartesian coordinates), or occasionally a letter and a number, that identify a certain place on a grid, often referred to as a coordinate plane.

Given that scatter plot lies in quadrant 1 of a coordinate plane, and the 14 points are plotted in the first quadrant.

We need to find the range of x and y values for this scatter plot.

The x values of the 14 points are given as;

2, 4, 4,1, 5, 5, 5, 5, 6, 6, 7, 8, 9.5, 9.5

The y values of the 14 points are given as;

5, 6, 9, 7.2, 6, 6.8, 8, 9, 7, 8.5, 10, 10.5, 9.5, 11.4

We can conclude that that most of the points are clustered between x-values 4 and 6 and y-values 6 and 9.

Therefore, the points are clustered between the x-values 4 and 6 and y-values 6 and 9.

To learn more about the coordinates;

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The complete question is

Select the correct answer. Scatter plot in quadrant 1 of a coordinate plane. 14 points are plotted at (2, 5), (4, 6), (4, 9), (4.1, 7.2), (5, 6), (5, 6.8), (5, 8), (5, 9), (6, 7), (6, 8.5), (7, 10), (8, 10.5), (9.5, 9.5), and (9.5, 11.4). Between which x-values and y-values does the cluster in this scatter plot lie? A. It lies between x-values 2 and 4 and y-values 4 and 6. B. It lies between x-values 4 and 6 and y-values 9 and 10. C. It lies between x-values 4 and 6 and y-values 6 and 9. D. It lies between x-values 7 and 9 and y-values 10 and 11.

Answer:

13 minutes

Step-by-step explanation:

The reason why it is 13 minutes is because you subtract 10:41 AM from 10:28 AM and you get 13 minutes.

Answer:

13

Step-by-step explanation:

41-28= 13

the hours don't change so you just need to subtract the minutes

Answer:Center =(-5,-7)

Step-by-step explanation:

Answer:

value for X

3x-4 =41

3x =41+4

3x =45

x =15

Answer:

42+106=x

148=x

Step-by-step explanation:

Answer:

B. All real numbers

Step-by-step explanation:

I calculated it logically

Answer:

I believe it is all real numbers

Answer:

He can lift 160 pounds

Step-by-step explanation:

125 (from last year) + 35 (more pounds) = 160 (total pounds)

125 + 35 = 160

Answer:

B

Step-by-step explanation:

i know this already from another

Answer:

Step-by-step explanation:

First,

7 times 8 = 7 × 8 = 56

Then,

The product divided by 2 = 56 ÷ 2 = 28

Hence,

The required answer is 28

Answer: D is correct

Step-by-step explanation:

Answer:

C.   x > 0 and x ≤ 3

Step-by-step explanation:

0 < x ≤ 3

when  0 < x then x > 0

Example: 0 < 2 then 2> 0

Therefor

x > 0 and x ≤ 3

Answer:

Subject : Tomato plant

Explanatory variables : Watering condition ; Fertilizer addition

Treatment : daily watering ; half fertilizer ; full fertilizer

Response variable = Number of tomato picked

Step-by-step explanation:

Subjects are the individuals, animals or plants upon which treatment is applied. The subject here are the tomato plants

The Explanatory variables are the independent variables upon which we want base the variation of the dependent variable. The Independent variables are the watering condition a d the amount of fertilizer added.

Treatment : These are the actual changes made or applied on the subject, they include, daily watering, full or half fertilizer application.

Response variable : The number of tomatoes picked. This is also called the dependent variable, it is the outcome which may be due to the effect of the independent variable.

Answer:

98?

Step-by-step explanation:

Given:

The given sum is:

[tex]\sum _{k=4}^9(5k+3)[/tex]

To find:

The expanded form and find the sum.

Solution:

We have,

[tex]\sum _{k=4}^9(5k+3)[/tex]

The expanded form of given sum is:

[tex]\sum _{k=4}^9(5k+3)=(5(4)+3)+(5(5)+3)+(5(6)+3)+(5(7)+3)+(5(8)+3)+(5(9)+3)[/tex]

[tex]\sum _{k=4}^9(5k+3)=(20+3)+(25+3)+(30+3)+(35+3)+(4+3)+(45+3)[/tex]

[tex]\sum _{k=4}^9(5k+3)=23+28+33+38+43+48[/tex]

[tex]\sum _{k=4}^9(5k+3)=213[/tex]

Therefore, the correct option is C.

Answer:

a.

Approximately [tex]24.7\; \rm in[/tex].

b.

While there are three diagonals in a box (a rectangular prism,) all three diagonals goes through the same point- the centroid of this box.  

For a maximum-length poster to fit in this box, it would have to be on one of the main diagonals of this box. Hence, any maximum-length poster that fits in this box would go through the centroid of this box.

It's not possible to force more than one posters to go through the same point (i.e., the centroid) in space. Hence, it would not be possible to fit a second maximum-length poster into this box.

This argument does not apply to  [tex]21.5\; \rm in[/tex] posters. These posters are shorter than the diagonal of this box; they could fit inside the box without having to go through a particular point in space.

Step-by-step explanation:

The longest poster that could be fit into this box (a rectangular prism) would be as long as the longest line segment in this box. That line segment would be one of the three diagonals of this box.

Apply the Pythagorean theorem twice to find the length of that diagonal.

Start by finding calculating the diagonal of the base of this box. The base of this box is a rectangle with width [tex]8\; \rm in[/tex] and length [tex]10\; \rm in[/tex]. The length of its diagonal would be [tex]\sqrt{8^2 + 10^2}[/tex] inches.

Combine that with the height of this box to find the length of the diagonal of this box.

[tex]\begin{aligned}& \sqrt{{\left(\sqrt{8^2 + 10^2}\right)}^2 + 12^2 \\ &= \sqrt{8^2 + 10^2 + 12^2} \\ &\approx 24.7 \end{aligned}[/tex].

Answer:

x = 2 , 1

Step-by-step explanation:

Answer:

2.5 or 3.5

Step-by-step explanation:

The quadratic formula is [tex]x = -b +/- \frac{\sqrt{b^2 + 4ac}}{2a}[/tex] .

a, b, and c are determined by the terms in the formula ax^2 + bx + c

They gave you the equation x^2 - 3x - 2, which fits that formula. a is 1, b is -3, and c is -2. So plug those values into the equation:

[tex]x = -(-3) +/- \frac{\sqrt{(-3)^2 + 4(1)(-2)}}{2(1)}[/tex]

[tex]x = 3 +/- \frac{\sqrt{9 -8}}{2}[/tex]

[tex]x = 3 +/- \frac{\sqrt{1}}{2}[/tex]

[tex]x = 3 +/- \frac{1}{2}[/tex]

So x is 3 plus or minus -1/2. 3 plus -1/2 is 2.5

3 minus -1/2 is 3.5

So the 2 possible x values are 2.5 and 3.5.

sum of observations

no. of observations

50+55+58+90+58+92+99 502

7 7

awnser is 71.7

Answer:

4 to 1

Step-by-step explanation:

The greatest common factor between 8 and 2 is 2. So 2 will go into 8, 4 times. And 2 will go into 2, 1 time. So simplified the equivalent ratio is 4:1.

Answer:

I think it's 18

Step-by-step explanation:

because I'm looking at 12/8 to be a ratio, that means that the size of the bigger figure had decreased by 12/8 or 1.5

then I divided the 27 by 1.5 to get the area of the small one which was 18.

Answer:

A

Step-by-step explanation:

This can be rearranged as 4^3 * 1/(4^6)

or (4^3)/(4^6)

This can be changed to:

(4^3)/((4^3)*(4^3)

Which is equal to 1/(4^3)

or

4^(-3)

Answer:

its not loading

Step-by-step explanation:

Answer:

I DONT SEE TRIANGLES

Step-by-step explanation:

Answer:

2, 3, 4 (up to down)

Step-by-step explanation:

Rational: can be terminating, repeating, in a fraction

Irrational: Not terminating (ending), doesn't repeat (o.33333....), and you can't put it in a fraction

Hope this helps!!

p.s. brainliest plz

Answer:

The nth term is 27 - 30(n-1) or can be simplified to 57 - 30n.

Step-by-step explanation:

This is an arithmetic sequence (ie. each term equals the previous term with a constant value added (or subtracted from it)

T1 = 27

T2 = -3 = T1 - 30 = 27 - 30

T3 = -33 = T2 -30 = 27 -30 - 30=27-30X(2)

T4= -63 = T3 - 30 =27-30X(2)-30=27-30X(3)

In general, the nth term of this sequence:

S(n) = 27 - 30X(n-1)

Answer:

[tex](a)\ Pr = \frac{2}{5}[/tex]

[tex](b)\ Pr = \frac{9}{20}[/tex]

[tex](c)\ E(Orange) = 100[/tex]

[tex](d)\ E(Orange) = 62.5[/tex]

Step-by-step explanation:

Solving (a): Theoretical probability of green or yellow

Here, we consider the spinner itself

From the attached image, we have:

[tex]n= 5[/tex] --- i.e. 5 sections

[tex]Yellow = 1[/tex]

[tex]Green = 1[/tex]

So, the probability is:

[tex]Pr = P(Yellow)\ or\ P(Green)[/tex]

[tex]Pr = \frac{Yellow}{n} + \frac{Green}{n}[/tex]

[tex]Pr = \frac{1}{5} + \frac{1}{5}[/tex]

Take LCM

[tex]Pr = \frac{1+1}{5}[/tex]

[tex]Pr = \frac{2}{5}[/tex]

Solving (b): Experimental probability of green or yellow

Here, we consider the result of the experiment

From the attached image, we have:

[tex]n= 40[/tex] --- i.e. 40 spins

[tex]Yellow = 12[/tex]

[tex]Green = 6[/tex]

So, the probability is:

[tex]Pr = P(Yellow)\ or\ P(Green)[/tex]

[tex]Pr = \frac{Yellow}{n} + \frac{Green}{n}[/tex]

[tex]Pr = \frac{12}{40} + \frac{6}{40}[/tex]

Take LCM

[tex]Pr = \frac{12+6}{40}[/tex]

[tex]Pr = \frac{18}{40}[/tex]

Simplify

[tex]Pr = \frac{9}{20}[/tex]

Solving (c): Expectation of orange outcomes in a spin of 500 times, theoretically.

Here, we consider the spinner itself

From the attached image, we have:

[tex]n= 5[/tex] --- i.e. 5 sections

[tex]Orange = 1[/tex]

So, the probability of having an outcome of orange in 1 spin is:

[tex]Pr = P(Orange)[/tex]

[tex]Pr = \frac{Orange}{n}[/tex]

[tex]Pr = \frac{1}{5}[/tex]

In 500 spins, the expectation is:

[tex]E(Orange) = Pr * 500[/tex]

[tex]E(Orange) = \frac{1}{5} * 500[/tex]

[tex]E(Orange) = 100[/tex]

Solving (c): Expectation of orange outcomes in a spin of 500 times, base on experiments.

Here, we consider the spinner itself

From the attached image, we have:

[tex]n= 40[/tex] --- i.e. 40 spins

[tex]Orange = 5[/tex]

So, the probability of having an outcome of orange is:

[tex]Pr = P(Orange)[/tex]

[tex]Pr = \frac{Orange}{n}[/tex]

[tex]Pr = \frac{5}{40}[/tex]

[tex]Pr = \frac{1}{8}[/tex]

In 500 spins, the expectation is:

[tex]E(Orange) = Pr * 500[/tex]

[tex]E(Orange) = \frac{1}{8} * 500[/tex]

[tex]E(Orange) = 62.5[/tex]