Compare and contrast chemical reactions and nuclear reactions in terms of particles involved . Select all the statements that apply Both chemical and nuclear equations are written with equal signs. Nuclear reactions create a difference in the number of protons, neutrons, and electrons after the reaction. A chemical reaction is the rearranging of atoms to form new substances. E=mc^ aleph 2 applies to both chemical and nuclear reactions. In a nuclear reactionparticles can transmute into others. Chemical reactions produce energy on levels comparable to nuclear reactions The total number of protons, neutrons, and electrons stay the same throughout the chemical reaction.

Answer: B

G v = 60 cm/s λ = 15 cm E f = V / λ S f = 4 Hz U f = ? S f = (60 cm/s) / 15 cm 5.

Explanation:

Explanation:

I think its a option pascal's principal

Answer:

c

Explanation:

Just took the quiz

Answer:

[tex]0.000835\ \text{m}[/tex]

Explanation:

d = Distance between plates = 2 mm

V = Potential difference = 500 V

v = Velocity of proton = [tex]2\times 10^5\ \text{m/s}[/tex]

a = Acceleration

m = Mass of proton = [tex]1.67\times 10^{-27}\ \text{kg}[/tex]

Electric field is given by

[tex]E=\dfrac{V}{d}\\\Rightarrow E=\dfrac{500}{2\times 10^{-3}}\\\Rightarrow E=250000\ \text{V/m}[/tex]

Force balance is given by

[tex]ma=qE\\\Rightarrow a=\dfrac{qE}{m}\\\Rightarrow a=\dfrac{1.6\times 10^{-19}\times 250000}{1.67\times 10^{-27}}\\\Rightarrow a=2.395\times 10^{13}\ \text{m/s}^2[/tex]

We have the relation

[tex]v^2=u^2+2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{(2\times 10^5)^2-0}{2\times 2.395\times 10^{13}}\\\Rightarrow s=0.000835\ \text{m}[/tex]

The farthest distance from the negative plate that the proton reaches is [tex]0.000835\ \text{m}[/tex].

The farthest distance from the negative plate that the proton reaches will be s=0.000835 m

The electric field is defined as the force across the charged particles which attract or repel the other charged particles.

Now it is given in the question that

d = Distance between plates = 2 mm

V = Potential difference = 500 V

v = Velocity of proton =   [tex]2\times 10^5\ \dfrac{m}{s}[/tex]

a = Acceleration

m = Mass of proton = [tex]1.67\times10^{-27} kg[/tex]

The Electric field will be calculated as

[tex]E=\dfrac{V}{d}[/tex]

[tex]E=\dfrac{500}{2\times10^{-3}} =250000\ \frac{V}{m}[/tex]

Force balance is given by

[tex]ma=qe[/tex]

[tex]a=\dfrac{qE}{m}[/tex]

[tex]a=\dfrac{1.6\times10^{-19}\times250000}{1.67\times10^{-27}}[/tex]

[tex]a=2.395\times 10^{13}\frac{m}{s^2}[/tex]

Now from equation of motion

[tex]v^2=u^2+2as[/tex]

[tex]s=\dfrac{v^2-u^2}{2a}[/tex]

[tex]s=\dfrac{(2\times10^5)^2-0}{2\times 2.395\times 10^{13}}[/tex]

[tex]s=0.000875 m[/tex]

Thus the farthest distance from the negative plate that the proton reaches will be s=0.000835 m

To know more about Electric field follow

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Answer:

Acceleration = 0.0282 m/s^2

Distance = 13.98 * 10^12 m

Explanation:

we will apply the energy theorem

work done = ΔK.E ( change in Kinetic energy )  ---- ( 1 )

where :

work done = p * t

                  = 15 * 10^6 watts * ( 1 year ) = 473040000 * 10^6 J

( note : convert 1 year to seconds )

and ΔK.E = 1/2 mVf^2   given ; m = 1200 kg  and initial V = 0

back to equation 1

473040000 * 10^6  = 1/2 mv^2

Vf^2 = 2(473040000 * 10^6 ) / 1200

∴ Vf = 887918.92 m/s

i) Determine how fast the rocket is ( acceleration of the rocket )

a = Vf / t

  = 887918.92 / ( 1 year )

  = 0.0282 m/s^2

ii) determine distance travelled by rocket

Vf^2 - Vi^2 = 2as

Vi = 0

hence ; Vf^2 = 2as

s ( distance ) =  Vf^2 / ( 2a )

                     = ( 887918.92 )^2 / ( 2 * 0.0282 )

                    = 13.98 * 10^12 m

Answer:

image distance = -8.47 cm

diameter of the image = 0.769 cm

Answer:

Yes, warming up is necessary before intense exercise, work-out or sports because they help regulate temperatures of your body. Warming up also makes your muscles ready for intense physical activities and prevents muscle cramps.

Explanation:

Answer:

45.864N

Explanation:

Using the formula

F = nR

n is the coefficient of friction

R is the normal reaction

R = mg

F = nmg

F = 0.78 * 6 * 9.8

F = 45.864N

Hence the amount of force with which the hand pushes the box is 45.864N

Answer:

Bowl will have maximum potential energy

Explanation:

It is the bowl that will have maximum potential energy.

It is because potential energy is high when both height and mass of the object is high.

Here in this case the bowl has maximum weight with maximum height except the tea cup but the potential weight of cup will not make much impact as its weight is very low.

Answer:

yabarrow

Explanation:

i think thats the name

Answer:

a = 6.25 m/s/s

d = 50 m

Explanation:

Given:

v1 (initial velocity)= 0 m/s (cz its at rest)

v2 (final velocity)= 25 m/s

t = 4s

a = ?

d = ?

to determine  acceleration

a = (v2 - v1)/ t

= (25m/s - 0m/s)/4s

= 6.25 m/s/s

to determine distance traveled

d = 1/2(v1 + v2)t

=1/2(0m/s+25m/s)(4s)

=50 m

Answer:

Answer in explanation.

Explanation:

Using Equation

[tex]v = u + at[/tex]

where v is the final velocity

u is initial velocity

a is acceleration

t is time taken

given u = 0, v = 25, t = 4,

[tex]25 = 0 + 4a \\ 4a = 25 \\ a = 6.25 \frac{m}{ {s}^{2} } [/tex]

Now, using equation

[tex]v {}^{2} = {u}^{2} + 2as[/tex]

where v and u remains the same, a = 6.25 and s is the distance,

[tex](25) {}^{2} = \: {0}^{2} + 2(6.25)s \\ 12.5s = 625 \\ s = \frac{625}{12.5} \\ s = 50m[/tex]

Answer:

I hate to say it is a bit of the holiday but

Answer:

a) the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]

b) the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]

c) the magnitude of the net momentum is 54102.5 kgm/s

Explanation:

Given the data in the question;

a) x-component of the net momentum of this system.

the second vehicle ( sedan ) doesn't have momentum along x-axis, the momentum along x-axis is strictly contributed by the pick up

so;

Px = 2600 kg × 17.0 m/s [tex](-x)[/tex]

Px = 44200 kgm/s [tex](-x)[/tex]

Therefore, the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]

b) y-component of the net momentum of this system

Also, momentum along y-axis is entirely provided by the sedan

Py = 1300 kg × 24.0 m/s [tex](y)[/tex]

Py = 31200 kgm/s [tex](y)[/tex]

Therefore, the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]

c) magnitude of the net momentum?

magnitude of the net momentum P = √( Px² + Py² )

so we substitute  

P = √( (44200)² + (31200)² )

P = √( 2927080000 )

P = 54102.5 kgm/s

Therefore, the magnitude of the net momentum is 54102.5 kgm/s

Answer:

0.01 mm

Explanation:

The least count of the screw gauge = pitch/number of divisions on circular scale

Pitch = 1 mm and number of divisions = 100

Substituting the values of the variables into the equation, we have

least count of the screw gauge = pitch/number of divisions on circular scale =  1 mm/100 = 0.01 mm

Answer: 50.7 J

Explanation:

Given

mass of lion is  [tex]m=2.6\ kg[/tex]

The initial speed of the lion is [tex]v_1=5\ m/s[/tex]

increased speed of lion is [tex]v_2=8\ m/s[/tex]

Initially, its kinetic energy is [tex]K_1=\frac{1}{2}mv_1^2[/tex]

Final kinetic energy [tex]k_2=\frac{1}{2}mv_2^2[/tex]

work did by lion after speed up is [tex]k_2-k_1[/tex]

[tex]\Rightarrow W=\dfrac{1}{2}\times 2.6[8^2-5^2]\\\\\Rightarrow W=1.3\times [39]=50.7\ J[/tex]

Explanation:

it has no energy when considered with respect to earth ,as it has neither height (i e potential energy) nor velocity (i.e kinetic energy).

Explanation:

Consider the two-slit Interference experiment. Electromagnetic radiation passes through the two slits that are a distance 0.0287 mm apart. The path to the fourth-order bright fringe on the nearby screen forms an angle with the horizontal. What is the wavelength of the light? (1 point) O 655 nm O 570 nm O 164 nm O 409 nm

COMPANY

i think so it is frequency

Answer:

C. both A and B

Explanation:

Sana nakatulong

Answer:

5

Explanation:

From the question given above, the following data were obtained:

Proton number = 2

Neutron number = 3

Mass number =.?

The mass number of a given atom is simply the sum of the protons and neutrons in the nucleus of the atom. Mathematically, it is expressed as:

Mass number = proton + neutron

With the above formula, we can obtain the mass number of the atom as follow:

Proton number = 2

Neutron number = 3

Mass number =.?

Mass number = proton + neutron

Mass number = 2 + 3

Mass number = 5

Thus, the mass number the atom is 5.

Answer:

A. The bus has more kinetic energy than the car.

Explanation:

As we know that

Kinetic energy is the amount of energy possessed by the body at the time when it is in motion.  

Also,

Kinetic energy = 1 ÷ 2mv²

Here m denotes the mass of the body

and v denotes the velocity of the body.

So it would be based on the mass & velocity of the body

As if the passenger bus contains more kinetic energy as compared to the car because of the big mass

Hence, the first option is correct

Answer:

Primary Succession is defined as the type of ecological succession, which occurs or start from the barren, uninhabited and unoccupied areas, such as the newly formed pond, rock, dunes, etc., while such kind of succession, which occurs in the area where there was the existence of life previously but got abandoned due to natural disturbances like deforestation, natural calamities (flood, earthquake, tsunami), the field with no vegetation is known as Secondary Succession

Explanation:

Some examples of primary succession include the formation of a new ecosystem after a volcano, glacier outbursts, or a nuclear explosion. Some examples of secondary succession include succession after fire, harvesting, logging, or abandonment of land or the renewal after a disease outbreak

i hope this answer helps :)

Answer:

a) 17.086m

b) 0.1671 m

Explanation:

Given data: speed of water through the hose  = 1.81 m/s

through the nozzle = 18.3 m/s

We know that maximum height of an object with upward velocity v is given by,

a) H = v^2/2g

where H is the maximum height water emerges  

= 18.3^2/(2×9.8) = 17.086 m answer

b) Again,  

H = v^2/2g

= 1.81^2/(2×9.8) = 0.1671 m

Answer:

hello your question has some missing information attached below is the missing information

answer : q3 = 0.300 nC

Explanation:

Given that Eay is in the Y axis ( upward ) , E3 will be downward and this will make the sign on the the charge ( q3 ) to be positive

E3 = Eay.   ( for an electric field to be neutral/zero the electric field in the opposite direction will have same magnitude )

To calculate the value of q3 we will apply the relation below

 K*q3/( 15 - 12 )^2  = 0.300

           = (9 * 10^9) * (q3 / 9 ) = 0.300

∴ q3 = 0.300 / 10^9

        = 0.300 nC

Note : The value of Eay is been calculated outside this solution as it is not part of the question asked  

Answer:

two least important criteria are A and B.

Explanation:

In an industrial production process there are criteria on the location of the production plants. Among the most important criteria we have that a good quantity is produced from the producer and that the process is cost-beneficial - cats to increase the profit of the company.

There are other desirable but minor criteria

A) The size of the city is of minor importance

b) Finding raw material locally is interesting, but its importance is less, the raw material can be sent from other locations.

Consequently the two least important criteria are A and B.

Answer:

A. The process should be located in a major city.

B. The process should use local, organic reactants.

Explanation:

ap.ex

Answer:

The speed of the knife after passing through the target is 9.33 m/s.

Explanation:

We can find the speed of the knife after the impact by conservation of linear momentum:

[tex] p_{i} = p_{f} [/tex]

[tex] m_{k}v_{i_{k}} + m_{t}v_{i_{t}} = m_{k}v_{f_{k}} + m_{t}v_{f_{t}} [/tex]

Where:

[tex] m_{k}[/tex]: is the mass of the knife = 22.5 g = 0.0225 kg

[tex] m_{t}[/tex]: is the mass of the target = 300 g = 0.300 kg

[tex] v_{i_{k}}[/tex]: is the initial speed of the knife = 40.0 m/s

[tex] v_{i_{t}} [/tex]: is the initial speed of the target = 2.30 m/s

[tex]v_{f_{k}}[/tex]: is the final speed of the knife =?

[tex] v_{f_{t}} [/tex]: is the final speed of the target = 0 (it is stopped)

Taking as a positive direction the direction of the knife movement, we have:

[tex] m_{k}v_{i_{k}} - m_{t}v_{i_{t}} = m_{k}v_{f_{k}} [/tex]  

[tex] v_{f_{k}} = \frac{m_{k}v_{i_{k}} - m_{t}v_{i_{t}}}{m_{k}} = \frac{0.0225 kg*40.0 m/s - 0.300 kg*2.30 m/s}{0.0225 kg} = 9.33 m/s [/tex]

Therefore, the speed of the knife after passing through the target is 9.33 m/s.

I hope it helps you!              

Answer:its 2kg

Explanation: