Below are the solutions to the selected questions:
Concave #4AThe image distance is -7.5cm, the magnification is 0.5 and the image formed is a real upright image.
Workings :
f = -5.0 cm (since it is a concave mirror)
u = -15.0 cm (since the object is placed in front of the mirror)
Using the mirror formula,
1/f = 1/v - 1/u
Substituting the values, we get:
1/v = 1/f - 1/u
1/v = 1/-5.0 - 1/-15.0
1/v = -0.2 + 0.0667
1/v = -0.1333
Taking the reciprocal on both sides, we get:
v = -7.5 cm
The negative sign indicates that the image is formed behind the mirror, which means it is a real image.
Now, we can calculate the magnification using the formula:
m = -v/u
m = -(-7.5)/15.0
m = 0.5
Concave #3AThe image distance is -4.0cm, the magnification is 0.8 and the image formed is a virtual, upright and smaller than the object.
Given:
Radius of curvature, R = -20.0 cm (since it's a concave mirror)
Object distance, u = 5.0 cm
Using the mirror formula, 1/f = 1/u + 1/v, where f is the focal length and v is the image distance, we can find the image distance:
1/f = 1/u + 1/v
1/-20.0 = 1/5.0 + 1/v
-0.05 = 0.2 + 1/v
-0.25 = 1/v
v = -4.0 cm
Since the image distance is negative, the image is virtual and upright.
To find the magnification, we use the formula:
magnification, m = -v/u
m = -(-4.0 cm)/5.0 cm
m = 0.8
The magnification is positive, indicating an upright image. The magnitude of the magnification is less than 1, which means the image is smaller than the object.
Convex #1AThe image distance is -4.0cm, the magnification is 0.8 and the image formed is a virtual, upright and smaller than the object.
Workings:
For a convex mirror, the focal length is negative, and we can use the mirror equation:
1/f = 1/do + 1/di
where f is the focal length, do is the distance of the object from the mirror, and di is the distance of the image from the mirror.
We know that the center of curvature is 60.0 cm, so the focal length is:
f = R/2 = 60.0 cm/2 = 30.0 cm
Plugging in the values, we get:
1/30.0 = 1/10.0 + 1/di
Simplifying:
di = 15.0 cm
The magnification can be found using the magnification equation:
m = -di/do
where the negative sign indicates that the image is virtual and upright. Plugging in the values, we get:
m = -15.0 cm/10.0 cm = -1.5
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question 34 pts how do ambient sounds differ from sound effects?how are foley sounds different from sound effects?
The differences between ambient sounds, sound effects, and Foley sounds.
Ambient sounds, also known as background sounds or atmospheric sounds, are the continuous, subtle noises that help create a sense of atmosphere or location in a scene. They differ from sound effects in that sound effects are distinct, purposeful sounds added to emphasize specific actions or events in a scene.
Foley sounds, on the other hand, are a type of sound effect created manually by a Foley artist to match and enhance the actions happening on-screen. They are different from regular sound effects because they are typically recorded live in a studio using various objects and materials to create realistic, synchronized sounds for actions such as footsteps, clothing rustles, and object handling.
In summary:
1. Ambient sounds create a sense of atmosphere or location and are continuous and subtle.
2. Sound effects are distinct, purposeful sounds added to emphasize specific actions or events.
3. Foley sounds are a type of sound effect created manually by a Foley artist to match on-screen actions.
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After a person has made a change in their life, relapse is common.
A. True
B. False
Answer:
A true
Explanation:
because it is talking about drugs and alcohol
find the magnitude of a uniform electric field (in mv/m) with the same energy density as a 0.23-t magnetic field.
The magnitude of the uniform electric field which has the same energy density as a 0.23 t magnetic field is 86.68 V/m.
To find the magnitude of the uniform electric field with the same energy density as a 0.23 t magnetic field, we can use the equation for energy density:
Energy density (in J/m³) = 0.5 × μ × B²
where μ is the permeability of free space (4π × 10⁻⁷ Tm/A) and B is the magnetic field strength in teslas.
We know the energy density of the magnetic field, so we can rearrange the equation to solve for the electric field strength:
Electric field strength (in V/m) = √(2 * energy density / ε)
where ε is the permittivity of free space (8.85 x 10⁻¹² F/m).
Substituting the values given, we get:
Energy density = 0.5 × μ × B²
= 0.5 × 4π × 10⁻⁷ T*m/A * (0.23 T)²
= 3.325 × 10⁻⁸ J/m³
Electric field strength = √(2 × energy density / ε)
= √(2 × 3.325 × 10⁻⁸ J/m³ / 8.85 × 10⁻¹² F/m)
= 86.68 V/m
Therefore, the magnitude of the uniform electric field with the same energy density as a 0.23 t magnetic field is 86.68 V/m.
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recall the two variables that affect the density of water, temperature and salinity. which scenario would cause the water to be most dense?
If the two variables that affect the density of water are temperature and salinity then the scenario that would cause water to be most dense is when the water is at a low temperature and high salinity.
Salinity refers to the concentration of dissolved salts and other minerals in the water.
When the temperature is low, the molecules of water are more tightly packed, which results in higher density. Similarly, when the salinity is high, there are more dissolved particles in the water, which also results in a higher density. Therefore, the scenario that would cause the water to be most dense is when both the temperature is low and the salinity is high.
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at what speed, in m/s , would a moving clock lose 2.7 ns in 1.0 day according to experimenters on the ground? hint: use the binomial approximation.
The clock must be moving at a velocity of approximately 4.53 m/s relative to the observers on the ground in order to experience a time dilation of 2.7 ns over the course of one day.
According to Einstein's theory of relativity, time dilation occurs when an object moves at a constant velocity relative to an observer. This means that time appears to pass more slowly for an object in motion than for an observer at rest. The amount of time dilation depends on the relative velocity between the two objects.
In this problem, we are given that a clock moving at some velocity loses 2.7 nanoseconds (ns) over the course of one day, as measured by observers on the ground. We want to determine the velocity of the clock.
We can use the formula for time dilation, which states that the observed time interval (Δt') is related to the proper time interval (Δt) by:
[tex]$\Delta t' = \frac{\Delta t}{\sqrt{1 - \frac{v^2}{c^2}}}$[/tex]
where v is the velocity of the clock, c is the speed of light, and the square root is taken using the binomial approximation (since v << c).
We know that Δt' = Δt - 2.7 ns and Δt = 1 day = 86400 seconds. Substituting these values and simplifying, we get:
[tex]$86400 - 2.7 = \frac{86400}{\sqrt{1 - \frac{v^2}{c^2}}}$[/tex]
Squaring both sides and rearranging, we can solve for v:
[tex]$v = c \sqrt{1 - \left(\frac{2.7}{86400}\right)^2} \approx 4.53 \text{ m/s}$[/tex]
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in most applications the braking torque of the friction brakes should be?
In most applications, the braking torque of the friction brakes should be adequate enough to bring the vehicle to a complete stop within a reasonable distance.
This is important for safety reasons and to prevent accidents.
The braking torque required depends on several factors, including the weight of the vehicle, the speed at which it is traveling, and the road conditions.
To calculate the required braking torque, one can use the equation:
Braking torque = vehicle weight x deceleration x radius of the brake rotor
Deceleration is the rate at which the vehicle slows down, and the radius of the brake rotor is the distance from the center of the rotor to the point where the brake pads make contact.
Once the required braking torque is calculated, the brake system can be designed accordingly.
This may involve selecting the appropriate brake pad material, ensuring proper brake cooling, and selecting the right brake rotor size and design.
It is important to note that the braking torque should not be excessive, as this can cause premature wear of the brake components and reduce their effectiveness over time.
Additionally, excessive braking torque can lead to wheel lock-up and skidding, which can be dangerous.
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Describe what happens as the hair dryer takes in cool air from one end and blows out warm air from other end TYYYY
When the hair dryer is turned on, it draws in cool air from its back end and passes it over a heating element, which increases the temperature of the air.
What happens when a hair dryer intakes cool air from one end and expels warm air from the other?Cool air is taken in and is heated using a heating element as described. The heated air is then forced out through the front end of the dryer by a fan. As the warm air blows over the hair, it causes the water molecules in the hair to evaporate, thus drying the hair. The hair dryer also helps to style hair by blowing it in different directions, causing it to move and create volume.
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a particle of mass 2.6 kg moves under the influence of the force f(x) = 3 x n. if its speed at x = 3.0 m is v = 7.0 m/s, what is its speed (in m/s) at x = 8.0 m?
The speed of the particle at x = 8.0 m is 9.30 m/s.
We can solve this problem using the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy,
W_net = ΔK
Where W_net is the net work done by all forces acting on the object, and ΔK is the change in kinetic energy of the object.
In this case, the only force acting on the particle is F(x) = 3x N, which is a conservative force, so the net work done by this force can be expressed as the negative gradient of a potential energy function:
W_net = -ΔU
Where ΔU is the change in the potential energy of the particle.
Since F(x) = -dU/dx, we can integrate both sides with respect to x to find the potential energy function:
[tex]U(x) = -\int F(x) dx\\= -\int 3x dx[/tex]
= -1.5x² + C
where C is an arbitrary constant of integration. To determine the value of C, we can use the fact that U(x) is defined up to an arbitrary constant, so we can set U(3) = 0:
U(3) = -1.5(3)² + C = 0
C = 13.5
So the potential energy function is,
U(x) = -1.5x² + 13.5
Now we can use the conservation of energy to find the velocity of the particle at x = 8.0 m. At x = 3.0 m, the kinetic energy of the particle is,
K(3) = (1/2)mv² = (1/2)(2.6 kg)(7.0 m/s)² = 67.9 J
The potential energy at x = 3.0 m is:
U(3) = -1.5(3)² + 13.5 = 0 J
So the total energy of the particle at x = 3.0 m is:
E(3) = K(3) + U(3) = 67.9 J
At x = 8.0 m, the potential energy is:
U(8) = -1.5(8)² + 13.5 = -94.5 J
Therefore, the kinetic energy of the particle at x = 8.0 m is:
K(8) = E(3) - ΔU = 67.9 J - (-94.5 J) = 162.4 J
The velocity of the particle at x = 8.0 m can be found using the kinetic energy formula:
K = (1/2)mv²
v = √(2K/m) = √(2(162.4 J)/(2.6 kg)) = 9.30 m/s
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A system consists of two charges,
and 109. The force exerted on charge q has a magnitude
of F. Does the force exerted on the charge 10 q have a
magnitude that is greater than, less than or equal to F?
Explain.
The force exerted on the charge 10q has a magnitude that is greater than F.
The force between two charged particles is given by Coulomb's law:
F = k * q1 * q2 / r^2
If we consider the system of two charges, q and 10q, and assume that they are at the same distance from the test charge:
[tex]F = k * q * qtest / r^2[/tex]
where qtest is the charge of the test charge.
Similarly, the force on the test charge due to 10q is given by:
F' = k * (10q) * qtest / r^2
Dividing second equation by the first, we get:
F' / F =[tex](10q * qtest) / (q * qtest)[/tex] = 10
So the force exerted on the charge 10q has a magnitude that is greater than the force exerted on the charge q by a factor of 10.
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after an intense earthquake, the earth "rings" with a period of 54 minutes. what is the frequency (in hz) of this oscillation? Express your answer in hertz.
Frequency = the rate per second of a vibration constituting a wave, either in a material (as in sound waves), or in an electromagnetic field (as in radio waves and light).
The frequency is = 0.00030864 Hz
Solution - To find the frequency of the oscillation after an intense earthquake, we need to use the formula:
Frequency (f) = 1 / Period (T)
Given that the period of the Earth's oscillation is 54 minutes, we first need to convert this to seconds:
54 minutes * 60 seconds/minute = 3240 seconds
Now, we can find the frequency:
Frequency (f) = 1 / 3240 seconds ≈ 0.00030864 Hz
the frequency of the oscillation after the intense earthquake is approximately 0.00030864 Hz.
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what is an expression for x1(t) , the position of mass i as a function of time? assume that the position is measured in meters and time is measured in seconds.
The expression for x1(t) , the position of mass i as a function of time, is x1(t) = x1_0 + v1_0 * t + 0.5 * a1 * t²
To find an expression for x1(t), the position of mass 1 as a function of time, we need to consider the following terms:
1. Initial position (x1_0): The position of mass 1 at time t=0.
2. Initial velocity (v1_0): The velocity of mass 1 at time t=0.
3. Acceleration (a1): The constant acceleration acting on mass 1, if applicable.
Now, we can use the general equation for the position of an object as a function of time:
x1(t) = x1_0 + v1_0 * t + 0.5 * a1 * t²
Where x1(t) is the position of mass 1 at time t, x1_0 is the initial position, v1_0 is the initial velocity, a1 is the acceleration, and t is the time in seconds.
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what is the wavelength in meters of an electron (mass *9.11 * 10-28 g) that has been accelerated to a speed of2.1 * 107 m>s?
The wavelength of an electron with a mass of 9.11 x 10^-28 g that has been accelerated to a speed of 2.1 x 10^7 m/s is 1.23 x 10^-10 meters.
What is the wavelength of an electron (mass *9.11 * 10-28 g) that has been accelerated to a speed of2.1 * 107 m>s?To find the wavelength of an electron that has been accelerated to a speed of 2.1 x 10^7 m/s, we can use the de Broglie equation:
wavelength = h / mv
where h is Planck's constant (6.626 x 10^-34 J*s), m is the mass of the electron (9.11 x 10^-28 g), and v is the velocity of the electron (2.1 x 10^7 m/s).
First, we need to convert the mass of the electron from grams to kilograms:
m = 9.11 x 10^-28 g = 9.11 x 10^-31 kg
Now we can plug in the values into the equation:
wavelength = h / mv
wavelength = 6.626 x 10^-34 J*s / (9.11 x 10^-31 kg)(2.1 x 10^7 m/s)
wavelength = 1.23 x 10^-10 m
Therefore, the wavelength of an electron with a mass of 9.11 x 10^-28 g that has been accelerated to a speed of 2.1 x 10^7 m/s is 1.23 x 10^-10 meters.
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what would be the met-min per week if a 70 kg person is walking/jogging for 60 minutes per day, 3 days per week at the intensity of 6 mets?
A 70 kg person would burn about 527 MET-minutes per week if they exercised for 60 minutes each day, three days per week, at a moderate effort of 6 METs.
The energy expended during physical activity is measured in METs. The sum of the individual's oxygen intake (VO2) times their weight in kilogrammes and the number of minutes spent exercising is the total MET-minutes.
The formula 3.5 + (METs) can be used to calculate VO2 by multiplying METs by 0.1. People can track their physical activity and make sure they are following the advised exercise standards for maintaining good health by knowing the total MET-minutes of a session.
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met-min per week for this person would be 75,600.
To calculate the met-min per week for a 70 kg person who is walking/jogging for 60 minutes per day, 3 days per week at the intensity of 6 mets, we can use the following formula:
met-min per week = met value x weight in kg x minutes per week
First, we need to calculate the total minutes per week:
60 minutes per day x 3 days per week = 180 minutes per week
Next, we can plug in the values for the met value (6), weight in kg (70), and minutes per week (180):
met-min per week = 6 x 70 x 180
met-min per week = 75,600
Therefore, the met-min per week for this person would be 75,600.
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Show that the form of Newton’s second law is invariant under the Galilean transformation. According to Newton’s second law, the net force acting on an object is equal to the product of its mass and acceleration. Newton’s second law of motion is given by following expression:
Newton’s second law of motion states that the force F acting on an object of mass m produces an acceleration a in the object, and is given by, F = ma. The law s invariant under Galilean transformation.
The Galilean transformation is a set of equations that describe the relationship between two reference frames that are in relative motion with constant velocity. It has no effect on the form of Newton’s second law because it only involves a change of coordinates and time, which do not affect the physical laws.
To see this, consider two reference frames S and S', where S' moves with constant velocity v with respect to S. Let an object of mass m be at rest in S, and let F be the net force acting on it in S. According to Newton’s second law in S, we have:
F = ma
Now, let us apply the Galilean transformation to the equation. The position of the object in S' is given by:
x' = x - vt
where x is the position of the object in S, and t is time. Taking the derivative of x' with respect to t, we get:
v' = dx'/dt
= dx/dt - v
= v - v
= 0
This means that the velocity of the object is the same in both reference frames. Similarly, the acceleration is also the same in both reference frames, since it is the derivative of velocity,
a' = dv'/dt = da/dt = a
Therefore, we can write Newton’s second law in S' as,
F' = ma'
where F' is the net force acting on the object in S'. Substituting a' = a, we get:
F' = ma
which is the same form as in S. Thus, we see that the form of Newton’s second law is invariant under the Galilean transformation.
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what is the ultimate fate of an isolated pulsar? it will spin ever faster, becoming a millisecond pulsar. as gravity overwhelms the neutron degeneracy pressure, it will become a white dwarf. as gravity overwhelms the neutron degeneracy pressure, it will explode as a supernova. it will slow down, the magnetic field will weaken, and it will become invisible. the neutron degeneracy pressure will eventually overwhelm gravity and the pulsar will slowly evaporate.
The ultimate fate of an isolated pulsar is determined by a combination of various physical processes that act on it over time.
The ultimate fate of an isolated pulsar depends on various factors such as its mass, rotation speed, and magnetic field strength. If the pulsar has a low mass, it may eventually spin faster and become a millisecond pulsar.
However, if it has a high mass, it may explode as a supernova, releasing huge amounts of energy and leaving behind a neutron star or a black hole.
In some cases, if the magnetic field weakens and the pulsar slows down, it may become invisible. As the neutron degeneracy pressure overwhelms gravity, the pulsar may eventually transform into a white dwarf.
Alternatively, the neutron degeneracy pressure may eventually overwhelm gravity, and the pulsar will slowly evaporate.
Overall, the ultimate fate of an isolated pulsar is determined by a combination of various physical processes that act on it over time.
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A computer hard disk starts from rest, then speeds up with
an angular acceleration of 190 rad/s until it reaches its final
angular speed of 7200 rpm. How many revolutions has the disk
made 10. 0s after it starts up?
The final angular speed of the hard disk is 766.9 rad/s, and it takes 4.04 s to reach this speed with an angular acceleration of 190.0 [tex]rad/s^2[/tex].
To take care of this issue, we want to utilize the equation that relates the rakish removal of a pivoting object to its precise speed increase, time, and beginning rakish speed. The equation is given by:
θ = 1/2 * α * [tex]t^2[/tex] + ω0 * t + θ0
Where θ is the complete point pivoted by the plate, α is the precise speed increase, t is the time slipped by, ω0 is the underlying rakish speed, and θ0 is the underlying point.In this issue, the circle begins from rest, so ω0 = 0. The rakish speed increase of the plate is given as 190 [tex]rad/s^2[/tex], and the last precise speed is 7200 rpm.
We want to change the last precise speed from rpm over completely to rad/s by increasing it with 2π/60. In this manner, the last precise speed is 240π rad/s.We can now substitute these qualities into the recipe and compute the absolute point pivoted by the circle after 10.0 seconds:
θ = 1/2 * 190 [tex]rad/s^2[/tex] * [tex](10.0 s)^2[/tex] + 0 rad/s * 10.0 s + 0 rad
θ = 9500 rad
To change this point over completely to the quantity of insurgencies, we partition it by 2π, as one unrest compares to a point of 2π radians. Consequently:
θ in transformations = 9500 rad/(2π rad/unrest) = 1507 upheavals
Accordingly, the plate has made 1507 insurgencies after 10.0 seconds from its underlying state.
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The complete question is:
A computer hard disk starts from rest, then speeds up with an angular acceleration of 190.0 [tex]rad/s^{2}[/tex]until it reaches a final angular speed of 7300.0 rpm.
(a) What is the final angular speed in units of rad/s? rad/s.
(b) How long does it take for the disk to reach this angular speed? s
(c) How many revolutions (not radians) does it make in getting to the final angular speed? rev
(d) Once the disk reaches its final angular speed, it continues rotating at this same speed. How many revolutions has the disk made 10.0 s after it started up from rest?
a wheel of radius 15 cm has sa rotational inertia of 2.3 kg m^2. the wheel is spinning at a rate of 6.5 revolutions per second. a frictional force is applied tangentially to the wheel to bring it to a stop. the work done by the torque to stop the wheel is most nearly:
The work done by the torque to stop the wheel is -1918 J.
The given parameters are:
- Wheel radius (r): 15 cm = 0.15 m
- Rotational inertia (I): 2.3 kg·[tex]m^{2}[/tex]
- Angular velocity (ω): 6.5 revolutions per second = 6.5 * 2π rad/s ≈ 40.84 rad/s
To find the work done by the torque to stop the wheel, we can use the rotational work-energy theorem: W = 0.5 * I * (ω_[tex]f^{2}[/tex] - ω_[tex]i^{2}[/tex]), where W is the work done, ω_f is the final angular velocity (0 rad/s), and ω_i is the initial angular velocity.
Plugging in the given values:
W = 0.5 * 2.3 kg·[tex]m^{2}[/tex] * (0^2 - 40.84 rad/s^2)
W = 0.5 * 2.3 kg·[tex]m^{2}[/tex] * (-1667.86 rad^2/s^2)
W ≈ -1918.24 J
Since work is done against the frictional force to bring the wheel to a stop, the work done is negative. Therefore, the work done by the torque to stop the wheel is most nearly -1918 J.
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a spring gun shoots out a plastic ball at speed v. the spring is then compressed twice the distance it was on the first shot. by what factor is the ball's speed increased?
Answer:√4 = 2.
Explanation:
When the spring gun is fired for the first time, let's assume that the spring was compressed by a distance of x, and the plastic ball is shot out at a speed of v.
Now, the spring is compressed twice the distance it was on the first shot. Therefore, the new compression distance is 2x.
Let's assume that the speed of the plastic ball after the second shot is v'. We can use the principle of conservation of energy to relate the speed of the ball to the compression distance of the spring.
For the first shot, the energy stored in the spring (½kx², where k is the spring constant) is converted into the kinetic energy of the ball (½mv², where m is the mass of the ball). Therefore,
½kx² = ½mv²
For the second shot, the energy stored in the spring (½k(2x)² = 2kx²) is again converted into the kinetic energy of the ball (½mv'²). Therefore,
2kx² = ½mv'²
Dividing the second equation by the first equation, we get:
v'²/v² = 4
Therefore, the speed of the plastic ball is increased by a factor of √4 = 2. So, the ball's speed is increased by a factor of 2.
An astronaut of mass 75 kg is floating in space holding a 20 kg fire extinguisher. If she throws the extinguisher forward at a velocity of 3.5 m/s, what will be her resulting velocity?
Momentum is defined as mass multiplied by velocity, so the total momentum before the extinguisher is thrown is 70 kg*m/s.
What is Velocity?Velocity is a vector quantity that measures the rate of change of an object's position. It is determined by the displacement of an object over a given period of time, and is usually expressed in terms of distance over time.
The astronaut's resulting velocity will be the same as the fire extinguisher's velocity, 3.5 m/s.
This is because the astronaut and extinguisher have the same mass and momentum must be conserved.
Momentum is defined as mass multiplied by velocity, so the total momentum before the extinguisher is thrown is 75 kg * 0 m/s + 20 kg * 3.5 m/s
= 70 kg*m/s.
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type 1 cable consists of ? twisted pairs, each individually shielded with foil, with a braided outer shield surrounding the entire cable core and covered with a jacket.
Type 1 cable consists of a braided outer shield surrounding the entire cable core and covered with a jacket, the correct answer is c.
Type 1 cable is commonly used in high-frequency applications where signal interference is a concern. The braided shield provides excellent protection against electromagnetic interference (EMI) and radio frequency interference (RFI). It also helps to reduce signal loss and attenuation by keeping the signal within the cable and preventing it from escaping.
The jacket provides an additional layer of protection against environmental factors such as moisture, abrasion, and temperature extremes. Type 1 cable is a reliable and effective option for applications where signal integrity and protection against interference are critical factors, the correct answer is c.
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The complete question is:
Type 1 cable consists of ?
a. twisted pairs
b. each individually shielded with foil
c. with a braided outer shield surrounding the entire cable core and covered with a jacket.
A student is constructing a stream table to investigate how erosion by a meandering stream is affected by the slope of the land. The student uses the equipment shown.
What should the student vary for the different trials of the experiment?
Responses
A The number of blocks stacked beneath the tray The number of blocks stacked beneath the tray
B The sediment size of sand used in the stream table The sediment size of sand used in the stream table
C The volume of water that enters the stream table and collects in the bucket The volume of water that enters the stream table and collects in the bucket
D The size of the hole in the bottom of the container of water
A student is constructing a stream table to investigate how erosion by a meandering stream is affected by the slope of the land should vary, the number of blocks stacked beneath the tray. Option A
What is the purpose of the experiment?The purpose of the experiment is to investigate how the slope of the land affects erosion by a meandering stream. By varying the number of blocks stacked beneath the tray, the student can change the slope of the land and observe how this affects the behavior of the stream and the resulting erosion.
Varying the sediment size, the volume of water, or the size of the hole in the bottom of the container would not directly address the question of how slope affects erosion by a meandering stream.
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after the train passed, the pitch of the train whistle became lower. this change in sound would be represented by what change in the diagram below?
The change in sound of the train whistle from a higher pitch to a lower pitch after the train passes can be explained by the Doppler Effect.
Here is a step-by-step explanation:
1) The Doppler Effect is the change in frequency or pitch of a sound wave due to the relative motion of the sound source and the observer.
2) When the train is approaching the observer, the sound waves from the train are compressed and the frequency or pitch of the sound wave appears higher.
3) As the train passes the observer, the sound waves from the train are stretched and the frequency or pitch of the sound wave appears lower.
4) This change in frequency or pitch can be explained by the relative motion of the train and the observer.
When the train is approaching the observer, the sound waves from the train are "bunched up" and appear closer together, resulting in a higher frequency or pitch.
When the train is moving away from the observer, the sound waves are "stretched out" and appear further apart, resulting in a lower frequency or pitch.
5) The change in frequency or pitch of the train whistle can be represented by a graph showing the frequency of the sound wave over time.
Before the train passes, the frequency of the sound wave gradually increases as the train approaches the observer.
After the train passes, the frequency of the sound wave gradually decreases as the train moves away from the observer.
6) The change in frequency or pitch of the train whistle can also be calculated using the Doppler Effect equation, which relates the frequency of the sound wave, the speed of the sound wave, and the relative velocity of the train and the observer.
In summary, the change in sound of the train whistle from a higher pitch to a lower pitch after the train passes is due to the Doppler Effect, which is caused by the relative motion of the train and the observer.
The change in frequency or pitch can be represented by a graph or calculated using the Doppler Effect equation.
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the speed of sound in air is 332 m/s. humans have sensitivity to sound frequencies from 20 hz to 20,000 hz. a. what is the longest sound wavelength we can hear? (5 pts) b. what is the shortest sound wavelength we can hear? (5 pts)
The longest sound wavelength we can hear is 16.6 m while the shortest sound wavelength we can hear is 0.0166 m.
We can use the formula for the speed of sound to find the longest and shortest sound wavelengths humans can hear:
speed of sound = frequency × wavelength
Let's first solve for the longest wavelength (a):
a. Longest wavelength = speed of sound / lowest frequency
Longest wavelength = 332 m/s / 20 Hz
Longest wavelength = 16.6 m
Now, let's solve for the shortest wavelength (b):
b. Shortest wavelength = speed of sound / highest frequency
Shortest wavelength = 332 m/s / 20,000 Hz
Shortest wavelength = 0.0166 m (or 1.66 cm)
So, the longest sound wavelength humans can hear is 16.6 meters and the shortest sound wavelength we can hear is 0.0166 meters (1.66 centimeters).
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dheepthi started from point a in south direction. after walking for 4 m she turned to her right and walked 5 m. now she turned to her left and walked 3 m after which she turned to her right. now she walked 4 m and turned to her right again and walked 15 m. now finally she turned to her right and after walking for 7 m, she stopped at point b. what is the distance ab?
The distance traveled by Dheepthi from point A to B is 29.5m.
To find the distance AB, we need to use Pythagoras' theorem, which states that the square of the hypotenuse (the longest side) of a right triangle is equal to the sum of the squares of the other two sides.
In this case, we can break down Dheepthi's journey into a series of right triangles.
First, she walks 4m in the south direction from point A. Then, she turns right and walks 5m, forming a right triangle with legs of 4m and 5m.
Using Pythagoras' theorem, we can calculate the hypotenuse (her distance from point A) to be 6.4m.
Next, she turns left and walks 3m, forming another right triangle with legs of 1.6m (the remainder of her distance south) and 3m. Using Pythagoras' theorem again, we can calculate the hypotenuse of this triangle to be 3.4m.
Then, she turns right and walks 4m, forming a right triangle with legs of 1.6m and 4m. The hypotenuse of this triangle is 4.2m.
Finally, she turns right again and walks 15m, forming a right triangle with legs of 4.2m and 15m. The hypotenuse of this triangle is 15.5m.
Adding up all of these distances, we get a total distance of 6.4m + 3.4m + 4.2m + 15.5m = 29.5m. Therefore, the distance AB is 29.5m.
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a barometer indicates that the atmospheric pressure is actually 768.2 mm hg. what is the pressure in kpa? a. 1.011 b. 102.4 c. 7.784 x 104 d. 7.582 e. 14.85
The pressure in kPa is approximately 102.4 kPa, when a barometer indicates that the atmospheric pressure is actually 768.2 mm hg. The correct option is b.
To convert the atmospheric pressure from mmHg to kPa, we can use the following conversion formula:
1 mmHg = 0.133322 kPa.
Given that the barometer indicates the atmospheric pressure is 768.2 mmHg, we can find the pressure in kPa by multiplying the pressure in mmHg by the conversion factor.
Pressure in kPa = 768.2 mmHg * 0.133322 kPa/mmHg
Pressure in kPa ≈ 102.4 kPa
Therefore, the correct answer is (b) 102.4 kPa.
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What happens when thermal energy is applied to a substance q
When thermal energy is applied to a substance, the particles in the substance start to vibrate more rapidly, and the average kinetic energy of the particles increases.
What happens when thermal energy is applies to a substanceAs a result, the temperature of the substance increases. The amount of thermal energy required to increase the temperature of the substance by a certain amount is called the specific heat capacity of the substance.
The way the substance responds to the applied thermal energy also depends on its physical properties, such as its mass, density, and thermal conductivity. For example, a substance with a high thermal conductivity will transfer heat more rapidly to its surroundings, while a substance with a low thermal conductivity will retain heat more effectively.
If the applied thermal energy is sufficient, the substance may undergo a phase change, such as melting or boiling, as the increased kinetic energy overcomes the intermolecular forces holding the particles together.
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the geocentric model of the universe that was widely accepted in scientific and religious circles until the 16th century was that of
The geocentric model of the universe that was widely accepted in scientific and religious circles until the 16th century was that of Ptolemy, also known as the Ptolemaic system.
The geocentric model of the universe, widely accepted in scientific and religious circles until the 16th century, was based on the idea that Earth was at the center of the cosmos.
This model, also known as the Ptolemaic system, was developed by the ancient Greek astronomer Claudius Ptolemy in the 2nd century AD. According to this model, all celestial objects, including the Sun, Moon, and stars, revolved around the Earth in circular or epicyclical paths.
The geocentric model was dominant for over a thousand years due to its alignment with religious beliefs and its ability to explain astronomical observations.
However, the 16th-century work of Nicolaus Copernicus and later astronomers led to the acceptance of the heliocentric model, which placed the Sun at the center of the solar system and was a more accurate representation of the cosmos.
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at a given instant in time, an 8-kg rock that has been dropped from a high cliff, experiences an upward force of air resistance of 12 n.note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part.what is the gravitational force on the rock? use g
The gravitational force on the rock is 78.4 Newtons.
At the given instant, the 8-kg rock experiences a gravitational force which can be calculated using the formula:
F_gravity = m * g
where m is the mass of the rock (8 kg) and g is the acceleration due to gravity (approximately 9.8 m/s²).
F_gravity = 8 kg * 9.8 m/s² = 78.4 N
So, the gravitational force on the rock is 78.4 Newtons.his net force causes the rock to accelerate downwards.
The concept of gravitational force is an important one in physics, as it plays a significant role in many natural phenomena. The force of gravity is responsible for the motion of celestial bodies, and it is also a key factor in determining the weight of objects on earth.
Understanding the principles of gravitational force can help us understand the behavior of objects in motion and can also help us develop technologies that are based on these principles.
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duc 1. Define the term 'element. 2. If you break down each of the following, how many different atoms would you be able to recover? a) Mercury b) Sodium chloride c) Water d) Carbon dioxide e) Oxygen
part a.
An element is described as a pure substance that is composed of only one type of atom. Each element is characterized by a unique atomic number, which corresponds to the number of protons in the nucleus of its atoms.
part b.
a) Mercury - breaking down mercury would yield only mercury atoms.
b) Sodium chloride - Breaking down sodium chloride would yield sodium and chlorine atoms in their respective ratios.
c) Water -Breaking down water would yield hydrogen and oxygen atoms in their respective ratios.
d) Carbon dioxide : Breaking down carbon dioxide would yield carbon and oxygen atoms in their respective ratios.
e) Oxygen - breaking oxygen down would yield only oxygen atoms.
More about Elements?Some facts about elements includes;
Elements found on Earth and Mars are exactly the same.Hydrogen is the most common element found in the universe. Isotopes are atoms of the same element, with different numbers of neutrons.In ancient times the elements referred to fire, earth, water, and air.Learn more about elements at: https://brainly.com/question/20096027
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suppose the horns of all cars emitted sound at the same pitch or frequency. what would be the change in the frequency of the horn of a car moving toward ou? away from you?
The frequency of the horn of a car moving towards you would increase, while the frequency of a car moving away from you would decrease due to the Doppler effect.
The frequency of the sound waves an automobile makes will rise as it approaches you. This is due to the sound waves compression as the automobile draws closer to you, which causes them to have a shorter wavelength and a higher frequency. The Doppler effect is the name for this rise in frequency.
On the other hand, when an automobile pulls away from you, the sound waves' frequency will drop because they stretch, leading to a longer wavelength and a lower frequency. As a result, if all vehicles produce sound at the same frequency, you would hear a frequency rise for a vehicle travelling in your direction and a frequency drop for a vehicle driving away from you.
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If the car is moving towards you, the frequency of the horn will increase,moving away from you, the frequency will decrease
If the horns of all cars emitted sound at the same pitch or frequency, the frequency of the horn of a car moving toward you would appear to increase, as the sound waves are compressed and the wavelength is shortened due to the Doppler effect. Conversely, the frequency of the horn of a car moving away from you would appear to decrease, as the sound waves are stretched and the wavelength is lengthened due to the Doppler effect. This is because the observer perceives a higher frequency when the source is approaching and a lower frequency when the source is moving away.
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