Could somebody answer c i and ii

Answer:

Explanation:

Using the formula

v = fλ

v is the speed

f is the frequency

λ is the wavelength

Given the following

v = 332m/s

Frequency is the number of oscillation completed in one second. Since 332 waves passes through a medium in one second, hence the frequency us 222 Hertz

From the formula

λ = v/f

λ = 332/332

λ = 1m

Hence the wavelength is 1m

Answer:

0.21486 mm

Explanation:

The formula for the maximum intensity is given by;

I = I_o•cos²(Φ/2)

Now,we are not given Φ but it can be expressed in terms of what we are given as; Φ = πdy/(λL)

Where;

y is the distance from the central maximum

d is the distance between the slits

λ is the wavelength

L is the distance to the screen

Thus;

I = I_o•πdy/(λL)

We are given;

d = 0.05 mm = 0.5 × 10^(-3) m

λ = 540 nm = 540 × 10^(-9) m

L = 1.25 m

I/I_o = 50% = 0.5

From earlier, we saw that;

I = I_o•πdy/(λL)

We have I/I_o = 0.5

Thus;

I/I_o = πdy/(λL)

Plugging in the relevant values;

0.5 = (π × 0.5 × 10^(-3) × y)/(540 × 10^(-9) × 1.25)

Making y the subject, we have;

y = (0.5 × 540 × 10^(-9) × 1.25)/(π × 0.5 × 10^(-3))

y = 0.00021486 m

Converting to mm, we have;

y = 0.21486 mm

Answer:

The direction of partlcle movement is perpendicular to the direction of movement of energy of the wave.

Answer:

The range is 17.32 m

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 30°

Initial velocity (u) = √2g

Acceleration due to gravity (g) = 10 m/s²

Range (R) =?

The range can be obtained as follow:

R = u²Sine2θ /g

R = (√2g)²Sine 2θ / g

R = 2g² × Sine (2×30) / g

R = 2g × Sine 60

R = 2 × 10 × 0.8660

R = 17.32 m

Therefore, the range is 17.32 m

Answer:

vz vc

Explanation:

v b

Answer:

40 Kpa

Explanation:

150 cm2 = 0.015 m2

[tex]p \: = \frac{mg}{ a} = 40000[/tex]

Answer:

C. a small charged particle.

Explanation:

typically beta radiation emits an electron which is a small negativity charged particle.

hope it helps. :)

Answer:

A small charged particle.

Explanation:

Answer:

speed of light: 299,792,458

what does light travel fasted through?: Light will have the fastest velocity when it travels through the air. Light will have the slowest velocity when it travels through gelatin. Why? Light slows down when passing through different transparent materials. The more it slows down, the more it bends when it hits a medium made of that material

Answer:

The building are not getting farther and farther away, road signs, exits, other cars

Explanation:

Answer:

The tesla is the SI unit for the magnetic field (T). One tesla is the magnetic field in which a charge of one coulomb travelling perpendicular to the magnetic field at a velocity of 1 m/s receives a force of one newton.

OAmalOHopeO

Answer:

I would choose A. and B

Explanation:

The parent and daughter elements are different and the number of atoms is not conserved.

Answer:

Length of Orbit

Explanation:

The surface temperatures decreases with increasing distance from the sun. Venus is an exception because its dense atmosphere acts as a greenhouse and heats the surface to above the melting point of lead, about 880 degrees Fahrenheit (471 degrees Celsius).

Hopefully this helps!

Answer:

Option B is correct

Explanation:

Here the

Mass number of carbon is 11 and that of boron is 11. While the atomic number varies by a a unit 1 value.

Thus, on the right hand side, a particle with atomic number 1 and mass number 0 is released

Thus, option B is correct

Answer:

a) El trabajo realizado es de 274,680 J

b) La potencia de la carretilla elevadora es de 4578 Watts.

c) La energía cinética del montacargas es de 3.888.[tex]\overline 8[/tex] J

d) La energía potencial del montacargas es de 274.680 Joules.

e) La energía mecánica de la carretilla elevadora 278,568.[tex]\overline 8[/tex] J

Explanation:

a) Los parámetros dados son;

La velocidad de la carretilla elevadora, v = 12 km / h = 10/3 m / s

La masa que debe levantar la carretilla elevadora, m = 700 kg

La altura a la que se levantará la masa, h = 40 m

El trabajo realizado, W = Fuerza, F × Distancia, h

 La fuerza, F aplicada = El peso de la carga = Masa, m × Gravedad, g

Donde 'g' es la aceleración debida a la gravedad ≈ 9,81 m / s²

∴ Trabajo realizado, W = 700 kg × 9,81 m / s² × 40 m = 274,680 J

b) El tiempo que se tarda en subir 40 m = 1 minuto = 60 segundos

∴ Potencia = Trabajo / tiempo

Por lo tanto, la potencia del montacargas, P = 274,680 J / (60 s) = 4578 Watts

c) Energía cinética, K.E. = 1/2 · m · v²

La energía cinética de la carretilla elevadora, K.E. se da como sigue;

Carretilla elevadora K.E. = 1/2 × 700 kg × (10/3 m / s) ² = 3.888.[tex]\overline 8[/tex] J

d) La energía potencial del montacargas a 40 m, P.E. = m · g · h

∴ P.E. = 700 kg × 9,81 m / s² × 40 m = 274,680 Julios

e) La energía mecánica, M.E. = P.E. + K.E.

∴ M.E. = 3.888.[tex]\overline 8[/tex] J + 274,680 J = 278,568.[tex]\overline 8[/tex] J

La energía mecánica de la carretilla elevadora, M.E.= 278,568.[tex]\overline 8[/tex] J.

Answer:

T

Explanation:

I did sme answer

Answer:

1. Mike was riding in the wagon when it had the most acceleration because his light weight compared to Tim's weight required the least effort to move

2. Mike

Explanation:

According to Newton's second law of motion, force is proportional to te rate of change of momentum produced

Mathematically, we can write the above law as follows;

F = m × a

Where;

F = The force acting on the object

m = The mass of object in motion

a = The acceleration of the object

1. The given parameters in the question are;

The weight of Tim = 311 Newtons (70 lbs.)

The weight of Mike = 50 Newtons (50 lbs.)

The minimum force required to pull the wagon to constant speed = The weight of the wagon

With the assumption that the wagon has very little weight, we have

Therefore, when Tim gets in the wagon, the force, 'F' applied by Mike to pull the wagon to constant speed = Mass of Tim, m × Acceleration of the cart, a

Given that mass is proportional to weight, we can write;

Force from mike, Tim on the wagon F₁ = 311 N × a₁

Similarly when they switched places, we have;

Force from Tim, Mike on the wagon  = F₂ = 50 N × a₂

Therefore, for the same force, F₁ = F₂ = F, we have;

a₁ = F₁/(311 N) = F/(311 N)

a₂ = F₂/(50 N) = F/(50 N)

By fraction of numbers, F/(50 N) > F/(311 N) > N), therefore, a₂ > a₁

The acceleration of the wagon when Mike was on the wagon will be more than the acceleration of the wagon when Tim gets in the wagon because for the same applied force, the weight of Mike offer less resistance to move

2. Given that Sare and Mike have the same weight of 50 N each let F₃ represent the force with which she pulls Mike in the wagon, and F₁ represent the force with which Mike pulls her while she is on the wagon, we  are also given that F₃ > F₁

By Newton's second law of motion, we have;

a₃ = F₃/(50 N) and a₁ = F₁/(50 N)

From F₃ > F₁, we have;

F₃/(50 N) > F₁/(50 N)

Therefore;

a₃ > a₁

The acceleration of the wagon when Mike is being pulled by Sare, a₃, is greater than the acceleration of the wagon when Sare is pulled by Mike

Therefore, Mike is on the wagon when it has the greatest acceleration.

Answer:

Using V= IR

I= 0.2307 Ampere

Answer:

B i believe

Explanation:

Answer:

One of the most common is to use pH strips.

Explanation:

Answer:

oof

Explanation:

oof

Answer:

I think a Kinetic energy of an object is the measure of the work an object can do by the virtue of its motion.”

Hope this help!:)

Answer:

9.8kW

Explanation:

Given data

Mass= 60kg

Hieght= 4m

Time= 4.2seconds

We know that the energy possessed is given as

PE=mgh

PE=60*9.81*4

PE= 2354.4 Joulse

Also, the expression for power is

Power=Energy*Time

Power= 2354.4*4.2

Power=9888.48 watt

Power= 9.8kW

Answer:

The total force is [tex]F_{tot}=4.29\: N[/tex]

The direction is [tex]\omega=32.43^{\circ}[/tex]

Explanation:

First, we need to find the angle with respect to the horizontal, of the force between q2 (-2 μC) and q3 (3 μC).

Let's use the tangent function.

[tex]tan(\alpha)=\frac{2}{1.5}[/tex]

[tex]\alpha=53.13^{\circ}[/tex]  

Now, let's find the magnitude of the force F(12).

[tex]|F_{12}|=k\frac{q_{1}q_{2}}{d_{12}}[/tex]

Where:

[tex]|F_{12}|=9*10^{9}\frac{3*10^{-6}*2*10^{-6}}{0.015}[/tex]

[tex]|F_{12}|=3.6\: N[/tex]

The magnitude of the force F(23) will be:

[tex]|F_{23}|=k\frac{q_{2}q_{3}}{d_{23}}[/tex]

The distance between these charges is:

[tex]d_{23}=\sqrt{1.5^{2}+2^{2}}[/tex]

[tex]d_{23}=2.5\: m[/tex]

[tex]|F_{23}|=9*10^{9}\frac{2*10^{-6}*4*10^{-6}}{0.025}[/tex]

[tex]|F_{23}|=2.88\: N[/tex]

So, we have the force F(12) in the second quadrant and F(23) in the second quadrant too but with 53.13 ° with respect to the horizontal.

We just need to add these two forces (vectors) and get the total force acting on q2.

Total force in x-direction:

[tex]F_{tot-x}=-F_{12}-F_{23}cos(53.13)[/tex]

[tex]F_{tot-x}=-3.6-2.88cos(53.13)[/tex]

[tex]F_{tot-x}=-5.33\: N[/tex]

Total force in y-direction:

[tex]F_{tot-y}=F_{23}sin(53.13)[/tex]

[tex]F_{tot-y}=2.88sin(53.13)[/tex]

[tex]F_{tot-y}=2.3\: N[/tex]

Therefore, the magnitude of the total force will be:

[tex]|F_{tot}|=\sqrt{(-3.62)^{2}+(2.3)^{2}}[/tex]

[tex]|F_{tot}|=4.29\: N[/tex]

and the direction is:

[tex]tan(\omega)=\frac{2.30}{3.62}[/tex]

[tex]\omega=32.43^{\circ}[/tex]

I hope it helps you!

Answer:

Kinectic

Explanation:

kinetic energy can be regarded as the energy that is been posses by a body as a result of motion, it can be reffered to as work that is required in accelerating a body having a given mass from rest up to a particular velocity. Once this energy is gained during acceleration, the Kinectic energy is maintained by the body unless there is change in speed.

Formula

K.E= 1/2 mv^2

Where m= mass of the object

v= velocity

Therefore, the energy of a semi-truck doing 100 kph on the kighway is a " Kinectic energy"

Answer:

Intensity, 1. Option

Explanation:

brainliest?

The correct answer is intensity.

Answer:

Thrust = 200 N

Explanation:

The engine thrust can be found by using the following formula:

[tex]Thrust = mv[/tex]

where,

m = mass flow rate of the fuel = 0.05 kg/s

v = velocity of ejected gases = 4000 m/s

Therefore, using the given values in the equation, we get:

[tex]Thrust = (0.05\ kg/s)(4000\ m/s)[/tex]

Thrust = 200 N

Answer:

3) D: 31 m/s

4) D: 84.84 metres

Explanation:

3) Initial velocity along the x-axis is;

v_x = v_o•cos θ

Initial velocity along the y-axis is;

v_y = v_o•sin θ

Plugging in the relevant values, we have;

v_x = 31 cos 60

v_x = 31 × 0.5

v_x = 15.5 m/s

Similarly,

v_y = 31 sin 60

v_y = 31 × 0.8660

v_y = 26.85 m/s

Thus, magnitude of the initial velocity is;

v = √(15.5² + 26.85²)

v ≈ 31 m/s

4) Formula for horizontal range is;

R = (v² sin 2θ)/g

R = (31² × sin (2 × 60))/9.81

R = 84.84 m

Explanation:

hope it is helpful to you