Determine if the sequence is geometric. If it is, find the common ratio. ( -4, 12, -36, 108, ... )

Answer:

38

Step-by-step explanation:

Answer:

Student 2 and Student 3

Step-by-step explanation:

Student 2

-(5r - 3s + 1)

= - 5r +3s - 1

Student 3

= - 5r +3s - 1

Answer:

x>9

Step-by-step explanation:

Tamika already has $55, which will stay the same independent of how much time passes. Since she deposits $5 per week, we can assign weeks a variable x. The amount of money in her account after x weeks is equal to 55+5x. If she must save over $100, we can create an inequality to solve for how many weeks must pass: 55+5x>100.

The question also asks to solve the inequality:

This solution tells us that Tamika must save for more than nine weeks to have more than $100 in her account.

lmk if i made an error, hope this helps!!

9514 1404 393

Answer:

  m = 1/3

Step-by-step explanation:

Step 1. Pick a line of the table to use as (x1, y1).

Step 2. Pick a different line of the table to use as (x2, y2).

Step 3. Use the slope formula:

  m = (y2 -y1)/(x2 -x1)

Step 4. Simplify the result.

__

Here are these steps for this problem.

1, 2. use (x1, y1) = (-9, -5) and (x2, y2) = (-3, -3)

3. m = (-3 -(-5))/(-3 -(-9)) = 2/6

4. m = 1/3

Answer:

1. 6cm , 8cm , 10cm

2. 3cm , 4cm , 5cm

Step-by-step explanation:

Given:

In a triangle, side x has a length of 15 cm and side y has a length of 4 cm.

To find:

The possible value of side z.

Solution:

In a triangle, the sum of two smaller sides must be greater than the largest side otherwise the triangle is not possible.

Case I: Let x be the largest side, then

[tex]y+z>x[/tex]

[tex]4+z>15[/tex]

[tex]z>15-4[/tex]

[tex]z>11[/tex]               ...(i)

It is clear that [tex]y<x[/tex]. So, y cannot be a largest side.

Case II: Let z be the largest side, then

[tex]x+y>z[/tex]

[tex]15+4>z[/tex]

[tex]19>z[/tex]               ...(ii)

From (i) and (ii), we get

[tex]11<z<19[/tex]

It means the value of z lies between 11 and 19.

From the given options, only 17 is the value which lies between 11 and 19. So, the possible length of side z is 17 cm.

Therefore, the correct option is C.

Answer:

There were 343 children and 197 adults.

Step-by-step explanation:

In order to solve this problem, you can use an equation after identifying the important information, like that there were 540 people, the cost for a child is $1.25, the cost for an adult is $2.00, and admission fees totaled $822.75:

where c = number of children, and a = number of adults,

c + a = 540

1.25c + 2a = 822.75

Now, you need to solve this system of equations by isolating one of the variables. I'll isolate c by multiplying the first equation by 2 since it's easier:

  2c + 2a = 1080

- 1.25c + 2a = 822.75

= .75c           = 257.25

Now, you can multiply both sides by 4/3 to find c:

c = 257.25 × 4 ÷ 3

c = 343

So there were 343 children. Now you can find the number of adults by substituting 343 for c in the first equation:

where c + a = 540 and c = 343,

343 + a = 540

a = 197

So, there were 197 adults.

Answer:

200.96

Step-by-step explanation:

64x3.14=200.96

Answer:

A= 200.96in2

Step-by-step explanation:

8×8=64

64×3.14=200.96

Given:

The equations of circle are

4. [tex]\left(x+\dfrac{2}{3}\right)^2+(y+1)^2=24[/tex]

5. [tex](x-1)^2+(y+2)^2=28[/tex]

6 .[tex](x+12)^2+y^2=\dfrac{3}{64}[/tex]

To find:

The center and radius for the given circles.

Solution:

The standard form of a circle is:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Where, [tex](h,k)[/tex] is center and [tex]r[/tex] is the radius of the circle.

4.

The equation of the circle is

[tex]\left(x+\dfrac{2}{3}\right)^2+(y+1)^2=24[/tex]

The standard form of this circle is

[tex]\left(x-(-\dfrac{2}{3})\right)^2+(y-(-1))^2=(\sqrt{24})^2[/tex]

[tex]\left(x-(-\dfrac{2}{3})\right)^2+(y-(-1))^2=(2\sqrt{6})^2[/tex]

Therefore, the center of the circle is [tex]\left(-\dfrac{2}{3},-1\right)[/tex] and the radius of the circle is [tex]2\sqrt{6}[/tex].

5.

The equation of the circle is

[tex](x-1)^2+(y+2)^2=28[/tex]

The standard form of this circle is

[tex](x-1)^2+(y-(-2))^2=(\sqrt{28})^2[/tex]

[tex](x-1)^2+(y-(-2))^2=(2\sqrt{7})^2[/tex]

Therefore, the center of the circle is [tex]\left(1,-2\right)[/tex] and the radius of the circle is [tex]2\sqrt{7}[/tex].

6.

The equation of the circle is

[tex](x+12)^2+y^2=\dfrac{3}{64}[/tex]

The standard form of this circle is

[tex](x-(-12))^2+(y-0)^2=(\sqrt{\dfrac{3}{64}})^2[/tex]

[tex](x-(-12))^2+(y-0)^2=\dfrac{\sqrt{3}}{8}[/tex]

Therefore, the center of the circle is [tex]\left(-12,0\right)[/tex] and the radius of the circle is [tex]\dfrac{\sqrt{3}}{8}[/tex].

Answer:

3 5/7

Step-by-step explanation:

Answer:

First option: 336

Step-by-step explanation:

To find the answer, separately solve for each of the shapes.

1. The base is the square so length times width is the formula:

12 x 12 = 144

144 is the area of the square

Next, find the 4 triangles which are congruent(the same).

Triangle area formula: Base x Height divided by 2.

So, the area of 1 triangle is 12 x 8 =96

96/2 = 48

Area =48

Because there are 4 triangles, do 48 x 4=192.

Finally, add the area together and you should get 192+144 =336 ft^2

Surface area = 336 ft^2

50×100÷110=45.454545r6

Answer:

See below, please!

Step-by-step explanation:

We know that 6z-31+something is going to be equal to 180 degrees, because it is supplementary. But what is that something? We see 67 degrees. Do you think this is a corresponding angle to the something that we need to find? Yes, it is! So we know that 6z-31+67 is equal to 180. So, z is 24. Now, since we know the value of the something (67 degrees because of corresponding angles) we can find yet another pair of supplementary angles. 67+x=180! Kind of neat, huh? So, x is equal to 113.

Hope this helped!

Answer:

Step-by-step explanation:

Given,

Marks of the four exams = 65, 80, 76, 68

Let the mark for the fifth exam be = x

Mean of the five exams = 70

Therefore,

By the problem,

[tex] = > \frac{65 + 80 + 76 + 68 + x}{5} = 70[/tex]

[tex] = > \frac{289 + x}{5} = 70[/tex]

=> 289 + x = 70 × 5

=> 289 + x = 350

=> x = 350 - 289

=> x = 61

Hence,

Marks of the fifth exam is 61 (Ans)

Answer:

5°C

Step-by-step explanation:

Given:

The expression is

[tex]3x^4-81x[/tex]

To find:

The product of prime polynomials which is equivalent to the given expression.

Solution:

We have,

[tex]3x^4-81x[/tex]

Taking out the common factors, we get

[tex]=3x(x^3-27)[/tex]

It can be written as

[tex]=3x(x^3-3^3)[/tex]

[tex]=3x(x-3)(x^2+3x+3^2)[/tex]        [tex][\because a^3-b^3=(a-b)(a^2+ab+b^2)][/tex]

[tex]=3x(x-3)(x^2+3x+3^2)[/tex]

[tex]=3x(x-3)(x^2+3x+9)[/tex]

Therefore, the correct option is B.

Answer:

It's B

Step-by-step explanation:

Answer:

The probability of not spinning a 3 is [tex]\frac{8}{9}[/tex]

Step-by-step explanation:

The probability of spinning a 3 is 1/9. What is the probability of not spinning a 3?

Spinning a 3 and not spinning a 3 are complementary events, which means that the sum of their probabilities is decimal 1. So

[tex]\frac{1}{9} + p = 1[/tex]

[tex]p = 1 - \frac{1}{9} = \frac{9}{9} - \frac{1}{9} = \frac{8}{9}[/tex]

The probability of not spinning a 3 is [tex]\frac{8}{9}[/tex]

Answer:

44°

Step-by-step explanation:

8x - 4 = 6x + 8 (This is because they are corresponding angles)

8x - 6x = 8 + 4

2x = 12

x = 12 ÷ 2

x = 6

6x + 8 = angle 1 (Vertically opposite angles are equal)

Substitute the value of x in the equation '6x +8' to get the size of the angle.

6 × 6 + 8

36 + 8 = 44°

Angle 1  =  44°

Answer:

15

Step-by-step explanation:

Apply absolute rule: | a | = a, a ≥ 0

| 13 | = 13

= 13 + | -2 |

| -2 | = 2

= 13 + 2

= 15

Answer:

The discount takes $25 dollars off

Step-by-step explanation:

So yes, he'll pay $100 after the discount is applied

Answer:

25 dollars

Step-by-step explanation:

125 - 100= 25

Answer:

13/15

Step-by-step explanation:

The fraction of the cookies that are chocolate chip can be determined by solving this equation

1 - ([tex]\frac{4}{12}[/tex] - [tex]\frac{1}{5}[/tex])

1 - [tex]\frac{20 - 12}{60}[/tex]

1 - [tex]\frac{8}{60}[/tex]

[tex]\frac{60}{60}[/tex] - [tex]\frac{8}{60}[/tex] = [tex]\frac{52}{60}[/tex] = 13/15

Answer:

angle B = 66.42

Step-by-step explanation:

cos-1 B = [tex]\frac{adjacent}{hypotenuse}[/tex]

cos-1 B = [tex]\frac{2}{5}[/tex]

cos-1 B = 0.40

cos-1 of 0.40 is 66.4218

round to the nearest hundreth = 66.42

angle b = 66.42

Answer: to get range you subtract the largest and smallest numbers. so 18-3= 15 therefor, 15 is the range.

Hope this helps :)

#'s 9-14

Base info:   40% are red, 30% are white, 20% are blue, and 10% are green

9) 40% chance to get red, 10% chance to get green. 50% chance to get one of either.

10) getting red: 40%

Getting blue: 20%

11) 80%  (100% - 20% = 80%)

1/8 = 12.5%

12) 12.5% chance

13) 25% chance

14) 12.5 x 5 = 62.5  

62.5% chance

Answer:

Step-by-step explanation:

r=4, w=3, b=2, g=1, t=(4+3+2+1)=10

9) P(r or g)=4/10+1/10=5/10= 1/2

10) P(r or b)=4/10+2/10=6/10= 3/5

11) P(!b)=P(r or w or g)=4/10+3/10+1/10=8/10= 4/5

12) There are six numbers and only one six, P(6)= 1/6

13) The only even numbers less than 5 are 2 and four so

P(e<5)=2/6= 1/3

14) The primes on a die are 2,3,5 so three primes out of six numbers

P(!)=3/6= 1/2

15) 2,3,4,6 are multiples of 2 and three

P(2n or 3n)=4/6= 2/3

16) We want a one half probability so

P(W)=(3+x)/(3+4+2+x)=1/2

(3+x)/(9+x)=1/2

2(3+x)=9+x

6+2x=9+x

x=3

So 3 white marbles have to be added.

17) (3+x)/(9+x)=2/3

3(3+x)=2(9+x)

9+3x=18+2x

x=9

So nine whites need to be added.

Answer:

y ≥ 1

since the graph starts at 1 and doesn't come below that

Answer:

I hoped this helped :))

Answer:

I think answer is C. 4

Step-by-step explanation:

8:2=4

Answer:

Kindly check explanation

Step-by-step explanation:

To test for Difference in mean times

Null hypothesis, H0 will be, there is no difference in mean times ; m1 = m2

Alternative hypothesis, there is difference in mean times ; m1 ≠ m2

Decision region :

When p value < α ; reject the Null

Here. ;

Pvalue = 2% = 0.02

α = 1% = 0.01

Pvalue > α

0.02 > 0.01

Since, Pvalue > α ; we do not reject the Null ;

Hence, conclusion should be, there is no difference in mean times of bus and car