Does 4 have an infinate number of significant digits?

Answers

Answer 1
4 is Significant! It doesn’t have 0’s

Related Questions

When CO2(g) is put in a sealed container at 730 K and a pressure of 10.0 atm and is heated to 1420 K , the pressure rises to 24.1 atm . Some of the CO2 decomposes to CO and O2.

Calculate the mole percent of CO2 that decomposes.
Express your answer using two significant figures.

Answers

Answer:

48%

Explanation:

Based on Gay-Lussac's law, the pressure is directly proportional to the temperature. To solve this question we must assume the temperature increases and all CO2 remains without reaction. The equation is:

P1T2 = P2T1

Where Pis pressure and T absolute temperature of 1, initial state and 2, final state of the gas:

P1 = 10.0atm

T2 = 1420K

P2 = ?

T1 = 730K

P2 = 10.0atm*1420K / 730K

P2 = 19.45 atm

The CO2 reacts as follows:

2CO2 → 2CO+ O2

Where 2 moles of gas react producing 3 moles of gas

Assuming the 100% of CO2 react, the pressure will be:

19.45atm * (3mol / 2mol) = 29.175atm

As the pressure rises just to 24.1atm the moles that react are:

24.1atm * (2mol / 19.45atm) = 2.48 moles of gas are present

The increase in moles is of 0.48 moles, a 100% express an increase of 1mol. The mole percent that descomposes is:

0.48mol / 1mol * 100 = 48%

A solution of carbon tetrachloride and acetic acid (CH3COOH) that is 50% carbon tetrachloride by mass is boiling at 98.6 °C. The vapor is collected and cooled until it condenses to form a new solution. Calculate the percent by mass of carbon tetrachloride in the new solution.

Answers

Answer:

The percent by mass of carbon tetrachloride in the new solution is 72.6

Explanation:

Molecular weight of Carbon Tetrachloride is 154 g/mol

Molecular weight of CH3COOH is 60g/mol

Mass fraction of CCl4 is 0.5

Mass fraction of CCl4 is (0.5/154)/{(0.5/154) + (0.5/60)}

Mass fraction of CCl4 is X = 0.2803 and Y = 1-X

As per Raoul’s law

Y Pt = X * P1

Pt = X * P1 + YP2

Pt = 0.2803 * 1377 + (1-0.2803) * 519

Pt = 759.557 torr

Substituting the given values we get  

Y1 = X1P1/Pt

Y1 = 0.2803 * 1377/759.557

Y1 = 0.508

Mass fraction  

(0.508)(154)/{( (0.508)(154)) + (1-0.508)(60)}

= 0.726 = 72.6 %

Determine the packing efficiency of a simple cubic unit cell that contains one atom with a metallic radius of 175 pm.

Answers

Answer:

the packing efficiency is 52.36%

Explanation:

Given the data in the question;

simple cubic unit cell that contains one atom with a metallic radius of 175 pm;

we know that;

Edge length of Simple cubic (a) is related to radius of atom (r) as follows;

a = 2r

since radius r = 175 pm

we substitute

a = 2 × 175 pm

a = 350 pm

Now we get the volume unit;

Volume of unit cell = a³ = ( 350 pm ) = 42875000 pm³

Next we get Volume of sphere;

Volume of Sphere = [tex]\frac{4}{3}[/tex]πr³

Volume occupied by 1 atom = [tex]\frac{4}{3}[/tex] × π × ( 175 pm )³

=  [tex]\frac{4}{3}[/tex] × π × 5359375 pm³

= 22449297.5 pm³

Now, the packing efficiency = ( Volume occupied by 1 atom / Volume of unit cell ) × 100

we substitute;

packing efficiency = ( 22449297.5 pm³ / 42875000 pm³ ) × 100

= 0.523598 × 100

= 52.36%

Therefore, the packing efficiency is 52.36%

Calculate the volume, in liters, occupied by 0.775 mol of oxygen gas at STP.

Answers

Answer:

17.4 L

Explanation:

Step 1: Given data

Moles of oxygen (n): 0.775 molPressure of the gas (P): 1 atm (standard pressure)Temperature of the gas (T): 273.15 K (standard temperature)

Step 2: Calculate the volume occupied by 0.775 moles of oxygen at standard temperature and pressure (STP)

At STP, 1 mole of an ideal gas occupies 22.4 L.

0.775 mol × 22.4 L/1 mol = 17.4 L

wwwwwwwwwwwwwwwwwwwwwwwweweewewwewweewweeweeweeweweweeeweew

Answers

Explanation:

Simply multiply the # of moles of O2 by a molar ratio to give the # of moles of MgO:

#moles O2 × (2 mol MgO/1 mol O2) = # moles of MgO

where the quantity inside the parenthesis is the molar ratio between MgO and O2.


Plzzzzzzzzz help

It's your 16th birthday. You've been given 1 penny every second since you were born. You want to use all that money to buy gold to make rings for your classmates. How many rings can you make? Useful information: 1 ring = 1.3 mL of gold, 1 gram of gold = $58, density of gold is 19.3 grams/mL

Answers

Explanation:

Since you're 16, you have to calculate how many seconds you've lived.

16 years × 31,536,000= 504,576,000 pennies.

504,576,000÷58 (for the amount of gold) = 8699586.2069 grams

Then go on from there. Hope that helped!

Hello I need help please

Answers

Answer:

The concentration of an acid in a solution can be determined by making an acid-base titration. To do this, a known volume of the acid solution is gradually added alkali solution whose concentration is known, until a neutral pH is reached.

Explanation:

This is an riddle.

I’m lighter than what I am made of and more of me is hidden than is seen. What am I?

Whoever answers correctly gets brainly.

Answers

Answer: The answer is Iceberg

Answer:

Is it an iceberg?

Explanation:

it floats in water

and you can only see the tip of an iceberg

Hope this helps! :)

Have a great weekend!!

it refers to the length of the entire path the object travelled

Answers

Answer:

Path length is the overall distance traveled following the path of where the object travel. ... Displacement is the distance from the starting point of the object to its final point irregardless where it travels.

if 9.2 g of calcium react completely with excess aluminum chloride how many grams of aluminum would be produced?
Ca + AlCl3 -> CaCl2 + Al

Answers

Explanation:

3Ca(s) + 2AlCl3(aq) -> 3CaCl2(aq) + 2Al(s)

According to the question, Ca is the limiting reactant.

Therefore, we equate Ca to Aluminium which is the product whose mass we want to find

Molar mass of Ca- 40g/mol

". ". of Al- 27g/mol

3Ca --> 2Al

3×40 --> 2×27

9.2 --> x

x = 9.2×2×27= 496.8÷120=4.14

How many hydrogen atoms are in 89.5 g of
C6H6 ?
Answer in units of atoms.

Answers

Solution :

Molar mass of [tex]C_6H_6[/tex] is :

M = 6×12 + 6×1 g

M = 78 g

78 gram of [tex]C_6H_6[/tex] contains [tex]6.022 \times 10^{23}[/tex] molecules.

So, 89.5 gram of [tex]C_6H_6[/tex] contains :

[tex]n = 6.022 \times 10^{23} \times \dfrac{89.5}{78}\\\\n = 6.91 \times 10^{23}[/tex]

Now, from the formula we can see that one molecule of [tex]C_6H_6[/tex] contains 2 hydrogen atom . So, number of hydrogen atom are :

[tex]h = 2\times 6.91 \times 10^{23}\\\\h = 1.38 \times 10^{22}\ atoms[/tex]

Hence, this is the required solution.

CH3 – CH2 – CH2 – CH2 – OH

Answers

Answer:

IUPAC name is butanol

I hope it's helps you

What are the characteristics of acids and bases, and some examples of each? (20%)

Answers

Answer:

Acid :

1) they are sour in taste

2) if we put litmus paper in an acid they turn blue litmus to red and ( red litmus paper colour doesn't change )

3) acids use to react with metals

4) it releases hydrogen (H+) when dissolved in water

5) example : Hydrochloric acid , sulphuric acid , nitric acid etc..

base :

1) they are bitter in taste

2) and the red litmus paper trunes to blue and ( red litmus paper colour doesn't change )

3) it doesn't react with metals

4) it releases hydroxide (OH+) when dissolved in water

5 example : sodium hydroxide, potassium hydroxide etc...

3. The speed of a reaction can be increased by increasing reactant concentration or decreasing
particle size. *
(1 Point)
True
False

Answers

Answer:

true

because with the both states we increase the surface of reaction

It would probably be true

ILL GIVE BRAINLY PLEASE HELP!
One of the main components of an airbag is the gas that fills it. As part of the design process, you need to determine the exact amount of nitrogen that should be produced. Calculate the number of moles of nitrogen required to fill the airbag. Show your work. Assume that the nitrogen produced by the chemical reaction is at a temperature of 495°C and that nitrogen gas behaves like an ideal gas. Use this fact sheet to review the ideal gas law.

Answers

Answer: airbags generally vary between 35 and 60 liters in volume and for the airbag system to activate, it takes about 20 Kgf/cm² of pressure; with this data taken from literature and knowing the temperature of reaction (495 °C), we determine the moles of nitrogen needed from the ideal gas law.

Explanation:

Draw the most stable form of the organic products formed in the reaction of ethyl acetate and ethyl benzoate. Ethanol can be excluded from the answer.

Answers

Answer:

Please find the solution in the attached file.

Explanation:

Matter is never created or destroyed.

Lesson 5.04

Question 7 options:
True
False

Answers

I believe it is true!

Chem. Question! Which would be the correct asnwer?

Answers

The valence shells of the atom are over lapping

Answer:

The valence shells of the atoms are overlapping.

Explanation:

Have a great day

Fill in the blank: The bonds in an ionic compound________
electrons.

Answers

Answer:

Ionic bonding is the complete transfer of valence electron

Explanation:

In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion.

The correct answer is "transferred; unequally shared; equally shared". Explanation: Ionic bonding occurs when a positively charged atom (cation) interacts with a negatively charged atom (anion). In ionic bonding, the cation transfers its electron to the anion

In the reaction A+B → C + D, what are the reactants?

Answers

Answer:

A and B

Explanation:

structural formula for alkene with double bond st carbon 2 that shows no trans -cis isomerism C6H12​

Answers

Answer:

Explanation:

Read up on this:

https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Book%3A_The_Basics_of_GOB_Chemistry_(Ball_et_al.)/13%3A_Unsaturated_and_Aromatic_Hydrocarbons/13.02%3A_Cis-Trans_Isomers_(Geometric_Isomers)

I think the answer is going to structure of 2-methyl-2-pentene.

If 45.6 g of Fe2O3 reacts with excess water, how much heat is required?

Answers

Explanation:

I

have not yet learnt chemistry so sorry

Answer:

350

Explanation:

Rachard is studying a sample of a substance. The sample is in a large, triangle-shaped flask. Rachard moves the sample to a small, rectangular container. Both containers are closed. Below is an image of the containers used by Rachard. She notices that the shape and the volume of the substance both change when the sample is moved. In which state of matter is the substance?

Answers

There’s no image for me to look at.

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Answers

??????????????,??????

Which type of fuel uses combustion to produce energy?
O A. Hydroelectric
B. Nuclear
O C. Biomass
D. Geothermal

Answers

Answer:

nuclear im not sure but the chances of the answer getting correct is high

Answer:

Nuclear

Explonation

If 50mL of 0.15M calcium sulfide is added to 30mL of 0.35M ammonium carbonate, how many grams of precipitate will form

Answers

Answer:

0.750 g

Explanation:

The reaction that takes place is:

CaS (aq) + (NH₄)₂CO₃ (aq) → CaCO₃ (s) + (NH₄)₂S (aq)

First we calculate how many moles of each reactant were added, using the given volumes and concentrations:

CaS ⇒ 50 mL * 0.15 M = 7.5 mmol CaS(NH₄)₂CO₃ ⇒ 30 mL * 0.35 M = 10.5 mmol (NH₄)₂CO₃

Given that they react in a 1:1 ratio, and that there are less CaS moles than (NH₄)₂CO₃ moles, CaS is the limiting reactant.

7.5 mmoles of CaS will produce 7.5 mmoles of CaCO₃.

We now convert 7.5 mmol CaCO₃ into mg, using its molar mass:

7.5 mmol * 100 mg/mmol = 750 mg

Finally we convert 750 mg to g:

750 mg / 1000 = 0.750 g

An empirical formula calculation gives a molar ratio of 1.0 oxygen, 4.8 hydrogen, 4.1 carbon and 1.8 nitrogen. If the molecular mass is approximately 200 amu, what is the molecular formula

Answers

Answer:

[tex]C_8H_{10}O_2N_4[/tex]

Explanation:

Hello there!

In this case, according to the given information about the empirical formula of this compound, we can infer that these mole ratios can be rounded to the following whole numbers in order to find the empirical formula:

[tex]C_4H_5ON_2[/tex]

Whose molar mass is 97.09 amu and thus, the ratio of the molecular to the empirical molar mass is:

[tex]200/97.09=2.1[/tex]

Which is almost a factor of 2; and therefore, the resulting molecular formula is:

[tex]C_8H_{10}O_2N_4[/tex]

Regards!

The chemical structures of eugenol and iso eugenol differ in what way?

a)Alkene location on aliphatic chain

b)Alkene geometry on aliphatic chain

c)Substitutions on the aromatic ring

d)These compounds are diastereomers of one another.​

Answers

Option = D ———————> is the correct answer! I think

Will Mark Brainliest.



1. Analysis of a hydrate of iron(III) chloride revealed that in a 10.00g sample of hydrate, 6.00 g is anhydrous iron(III) chloride and 4.00 g is water. Determine the formula and the name of the hydrate.

Answers

Answer:

FeCl₃ . 6H₂O, BRAINLIST PLZ

Explanation:

1) The chemical formula of iron(III) chloride is FeCl₃ (the oxidation number of Fe is 3+, and the oxidation number of Cl is 1-).

2) The formula that you are lookin for the hydrate is of the type FeCl₃ . n H₂O, where n is the number of water molecules per each unit formula of Fe₂O₃.

3) Find the mass of anhydrous FeCl₃ by difference:

mass of FeCl₃ = mass of the sample - mass of the water in the sample

mass of FeCl₃ = 5.49g - 2.20 g = 3.29 g

4) Convert the mass of FeCl₃ in number of moles

number of moles = mass in grams / molar mass

molar mass of FeCl₃ = 55.845 g/mol + 3×35.453 g/mol = 162.204 g/mol

number of moles = 3.29 g / 162.204 g/mol = 0.0203 mol FeCl₃

5) Convert the mass of water in number of moles:

molar mass of water = 18.015 g/mol

number of moles of water = mass in grams / molar mass = 2.20 g / 18.015 g/mol = 0.122 moles H₂O

6) Find the mole ratio of water to iron chloride:

0.122 mol water / 0.0203 mol iron chloride = 6.01 ≈ 6

Therefore, the complete formula of the hydrate is FeCl₃ . 6H₂O,

Please help! Virtual Chemical vs Physical changes

Answers

Answer:

Sometimes, it can be difficult to tell if a chemical or physical change is taking place. In the video, Dr. Jeff and the team explore a few different reactions to determine if they are chemical or physical changes, by figuring out if the material made after the reaction was present before the reaction. Chopping a banana.

Explanation:

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