Does Kerri's dot plot match the data in the tally
table?
Use Kerri's dot plot to complete the statements.
_classmates spent 3 hours at the park.
_classmates spent 4 hours at the park.
_classmates spent 5 hours at the park.
_classmates spent 6 hours at the park.

Answer:

angle C = 38 degrees

Step-by-step explanation:

Refer to attached figure (sorry, forgot to attach earlier)

Given

AIB = 109

Let

CAX = XAB = x

CBY = YBA = y

XIB = YIA = x+y    ........exterior angles

XIB = YIA = 180-109 = 71   ............ sum of angles on a line

=>

x+y = 71

ACB = 180 - 2x -2y  ................. sum of angles of a triangle

= 180 - 2(x+y)

= 180 - 2(71)

= 180 - 142

= 38

Answer:

it is the inches milimeters meters

Answer:

Step-by-step explanation:

Given,

Volume of cone ( v ) = 27 π

Radius ( r ) = 3 cm

Height of cone ( h ) = ?

Now, let's find the height of cone:

Volume of cone = [tex] \frac{\pi {r}^{2}h }{3} [/tex]

plug the values

[tex]27\pi = \frac{\pi \: {3}^{2} \: h \: }{3} [/tex]

Evaluate the power

[tex]27\pi = \frac{\pi \times 9 \times h}{3} [/tex]

Divide 9 by 3

[tex]27\pi = 3\pi \: h[/tex]

Divide both sides of the equation by 3π

[tex] \frac{27\pi}{3\pi} = \frac{3\pi \: h}{3\pi} [/tex]

Calculate

[tex]9 = h[/tex]

Swipe the sides of the equation

[tex]h = 9[/tex] cm

Hope this helps..

Best regards!!

Answer: [tex]\dfrac{60}{143}[/tex]

Step-by-step explanation:

Given,  A class has five boys and nine girls.

Total students = 5+9=14

Number of ways to choose 6 students out of 14= [tex]^{14}C_6[/tex]  [Using combinations]

Number of ways to choose 4 girls out of 6 (4 girls + 2 boys = 6 ) = [tex]^{9}C_4\times\ ^{5}C_2[/tex]

If the teacher randomly picks six students, then the probability that he will pick exactly four girls:-

[tex]\dfrac{^{9}C_4\times \ ^{5}C_2}{^{14}C_6}[/tex]

[tex]=\dfrac{\dfrac{9!}{4!5!}\times\dfrac{5!}{2!3!}}{\dfrac{14!}{6!8!}}\\\\=\dfrac{1260}{3003}\\\\=\dfrac{60}{143}[/tex]

hence, the required probability = [tex]\dfrac{60}{143}[/tex] .

Answer:

Step-by-step explanation:

If  x and y be real numbers satisfying 2/x=y/3=x/y, then any two of the equation are equated as shown;

2/x = y/3 ... 1 and;

y/3 = x/y... 2

From equation 1, 2y = 3x ... 3

and from equation 2; y² = 3x ... 4

Equating the left hand side of equation 3 and 4 since their right hand sides are equal, we will have;

2y = y²

2 = y

y = 2

Substituting y = 2 into equation 3 to get the value of x;

2y = 3x

2(2) = 3x

4 = 3x

x = 4/3

The value of x³ will be expressed as (4/3)³ = 4*4*4/3*3*3 = 64/27

Answer:

Yes

Step-by-step explanation:

Let s be the price of snickers, g the price of galaxy and k the price of kitkat.

●For Mariam the equation will be:

8 s + 3 g + 3k = 8

●For Zainab the equation will be:

4 s + 9 g + 4 k = 10.9

Take the first equation and divide both sides by 4 to make it easier.

You get:

● 2s + 0.75 g + 0.75k = 2

Take the second equation and divide both sides by 2 to make easier.

You get:

● 2s + 4.5g + 2k = 5.45

The new system of equation is:

● 2s +0.75g + 0.75k = 2

● 2s + 4.5g + 2k = 5.45

Express s in the first equation using the other variables.

● 2s +0.75g +0.75k = 2

● 2s + 0.75(g+k) = 2

● 2s = 2-0.75(g+k)

● s = 1- 0.325 (g+k)

Replace s by the new expression in the second equation:

●2 [1-0.325(g+k)] +4.5 g +2k = 5.45

●2-0.75(g+k) +4.5g + 2k = 5.45

●2- 0.75g -0.75k +4.5 g +2k = 5.45

●2+ 3.75g + 1.25k = 5.45

● 3.75g +1.25k = 3.45

We have eliminated one variable (s)

We will keep (3.75g+1.25k=3.45) and use it.

Now that we eliminated in the second equation do it again in the first one.

You will get a system of equations with two variables.

Solve it and replace g and k with the solutions.

Finally solve the equation and find s.

Answer:

here,

A=2×22÷7×17/2×21

A=22×17×3

A=1122 sq.cm

Answer:

0

Step-by-step explanation:

The t-intercept here is what's khown as the x-intercept wich is given by C(t)=0

● C(t) = 2t^4-8t^3+6t^2

● 0 = 2t^4-8t^3+6t^2

Factor using t

● t(2t^3-8t^2+6t^1) = 0

Wich means that t=0

Answer:

3

Step-by-step explanation:

3

Answer:

9 years = 12 grams

Step-by-step explanation:

0 years = 96 grams

After 3 years , the amount left is 1/2 of what you started with

3 years = 1/2 *96 = 48 grams

After 3 years , the amount left is 1/2

6 years = 1/2 (48) = 24 grams

After 3 years , the amount left is 1/2

9 years = 1/2 ( 24) = 12 grams

Answer:

Hey there!

A=1/2bh

14=1/2(28)h

14=14h

h=1

Hope this helps :)

Answer:

Step-by-step explanation:

Area of a triangle is

[tex] \frac{1}{2} \times b \times h[/tex]

where b is the base

h is the height

From the question

Area = 14in²

b = 14 inches

So we have

[tex]14 = \frac{1}{2} \times 28 \times h[/tex]

which is

[tex]14 = 14h[/tex]

Divide both sides by 14

That's

[tex] \frac{14}{14} = \frac{14h}{14} [/tex]

We have the final answer as

h = 1

Therefore the height is 1 inch

Hope this helps you

Answer:

5 games

Step-by-step explanation:

To find how many games the team scored at least 70 points, we need to look at the 7 on the stem side. The 7 means 70, and we add the digits on the leaf side. For example, 7 | 2 is 72. The numbers on the leaf side are: 1, 1, 2, and 3.

There are no points for the 8 on the stem side, but on 90, there is one digit on the leaf side: 1. So, the points they scored over 70 are 71, 71, 72, 73, and 91, which equals to five games.

Answer:

[tex]\boxed{\mathrm{5 \ games}}[/tex]

Step-by-step explanation:

At least 70 points makes it 70 and more. It should be at least 70 and at most anything above then 70.

So, In 5 games, the team scored at least 70. (71,71,72,73 and 91)

Answer:

[tex]Range = 16[/tex]

[tex]Inter\ Quartile\ Range = 6.75[/tex]

[tex]Variance = 20.44[/tex]

[tex]Standard\ Deviation = 4.52[/tex]

Step-by-step explanation:

Given

4, 17, 12, 9, 6, 10, 1, 5, 9, 3

Calculating the range;

[tex]Range = Highest - Lowest[/tex]

From the given data;

Highest = 17 and Lowest = 1

Hence;

[tex]Range = 17 - 1[/tex]

[tex]Range = 16[/tex]

Calculating the Inter-quartile Range

Inter quartile range (IQR) is calculates as thus

[tex]IQR = Q_3 - Q_1[/tex]

Where

Q3 = Upper Quartile and Q1 = Lower Quartile

Start by arranging the data in ascending order

1, 3, 4, 5, 6, 9, 9, 10, 12, 17

N = Number of data; N = 10

---------------------------------------------------------------------------------

Calculating Q3

[tex]Q_3 = \frac{3}{4}(N+1) th\ item[/tex]

Substitute 10 for N

[tex]Q_3 = \frac{3}{4}(10+1) th\ item[/tex]

[tex]Q_3 = \frac{3}{4}(11) th\ item[/tex]

[tex]Q_3 = \frac{33}{4} th\ item[/tex]

[tex]Q_3 = 8.25 th\ item[/tex]

Express 8.25 as 8 + 0.25

[tex]Q_3 = (8 + 0.25) th\ item[/tex]

[tex]Q_3 = 8th\ item + 0.25 th\ item[/tex]

Express 0.25 as fraction

[tex]Q_3 = 8th\ item +\frac{1}{4} th\ item[/tex]

[tex]Q_3 = 8th\ item +\frac{1}{4} (9th\ item - 8th\ item)[/tex]

From the arranged data;

[tex]8th\ item = 10[/tex] and [tex]9th\ item = 12[/tex]

[tex]Q_3 = 8th\ item +\frac{1}{4} (9th\ item - 8th\ item)[/tex]

[tex]Q_3 = 10 +\frac{1}{4} (12 - 10)[/tex]

[tex]Q_3 = 10 +\frac{1}{4} (2)[/tex]

[tex]Q_3 = 10 +0.5[/tex]

[tex]Q_3 = 10.5[/tex]

Calculating Q1

[tex]Q_1 = \frac{1}{4}(N+1) th\ item[/tex]

Substitute 10 for N

[tex]Q_1 = \frac{1}{4}(10+1) th\ item[/tex]

[tex]Q_1 = \frac{1}{4}(11) th\ item[/tex]

[tex]Q_1 = \frac{11}{4} th\ item[/tex]

[tex]Q_1 = 2.75 th\ item[/tex]

Express 2.75 as 2 + 0.75

[tex]Q_1 = (2 + 0.75) th\ item[/tex]

[tex]Q_1 = 2nd\ item + 0.75 th\ item[/tex]

Express 0.75 as fraction

[tex]Q_1 = 2nd\ item +\frac{3}{4} th\ item[/tex]

[tex]Q_1 = 2nd\ item +\frac{3}{4} (3rd\ item - 2nd\ item)[/tex]

From the arranged data;

[tex]2nd\ item = 3[/tex] and [tex]3rd\ item = 4[/tex]

[tex]Q_1 = 3 +\frac{3}{4} (4 - 3)[/tex]

[tex]Q_1 = 3 +\frac{3}{4} (1)[/tex]

[tex]Q_1 = 3 +0.75[/tex]

[tex]Q_1 = 3 .75[/tex]

---------------------------------------------------------------------------------

Recall that

[tex]IQR = Q_3 - Q_1[/tex]

[tex]IQR = 10.5 - 3.75[/tex]

[tex]IQR = 6.75[/tex]

Calculating Variance

Start by calculating the mean

[tex]Mean = \frac{1+3+4+5+6+9+9+10+12+17}{10}[/tex]

[tex]Mean = \frac{76}{10}[/tex]

[tex]Mean = 7.6[/tex]

Subtract the mean from each data, then square the result

[tex](1 - 7.6)^2 = (-6.6)^2 = 43.56[/tex]

[tex](3 - 7.6)^2 = (-4.6)^2 = 21.16[/tex]

[tex](4 - 7.6)^2 = (-3.6)^2 = 12.96[/tex]

[tex](5 - 7.6)^2 = (-2.6)^2 = 6.76[/tex]

[tex](6 - 7.6)^2 = (-1.6)^2 = 2.56[/tex]

[tex](9 - 7.6)^2 = (1.4)^2 = 1.96[/tex]

[tex](9 - 7.6)^2 = (1.4)^2 = 1.96[/tex]

[tex](10 - 7.6)^2 = (2.4)^2 = 5.76[/tex]

[tex](12 - 7.6)^2 = (4.4)^2 = 19.36[/tex]

[tex](17 - 7.6)^2 = (9.4)^2 = 88.36[/tex]

Sum the result

[tex]43.56 + 21.16 + 12.96 + 6.76 + 2.56 + 1.96 + 1.96 + 5.76 + 19.36 + 88.36 = 204.4[/tex]

Divide by number of observation;

[tex]Variance = \frac{204.4}{10}[/tex]

[tex]Variance = 20.44[/tex]

Calculating Standard Deviation (SD)

[tex]SD = \sqrt{Variance}[/tex]

[tex]SD = \sqrt{20.44}[/tex]

[tex]SD = 4.52[/tex] (Approximated)

Assuming angle A is opposite to side a, B is the opposite to side b, and angle C is the opposite to side c.

Answer:

The right triangle has the following angles:

A = 48.31º, B = 41.69º and C = 90º.

The sides are:

[tex] \\ a = 37.26[/tex], [tex] \\ b = 33.12[/tex] and c = 49.9.

Step-by-step explanation:

The inner sum of a triangle = 180º.

A=48.31º,

C=90º

A + B + C = 180º

48.31º+ B + 90º = 180º

B = 180º - 90º - 48.31º

B = 41.69º

We can apply the Law of Sines to solve for unknown sides:

[tex] \\ \frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}[/tex]

We know that sin(90º) = 1.

[tex] \\ \frac{a}{sin(48.31)} = \frac{b}{sin(41.69)} = \frac{49.9}{1}[/tex]

Then, a is:

[tex] \\ \frac{a}{sin(48.31)} = \frac{49.9}{1}[/tex]

[tex] \\ a = 49.9*sin(48.31)[/tex]

[tex] \\ a = 49.9*0.7467[/tex]

[tex] \\ a = 37.26[/tex]

Thus, b is:

[tex] \\ \frac{b}{sin(41.69)} = \frac{49.9}{1}[/tex]

[tex] \\ b = 49.9*sin(41.69)[/tex]

[tex] \\ b = 33.12[/tex]

Answer:

We conclude that the true average stopping distance exceeds this maximum value.

Step-by-step explanation:

We are given the following observations that are on stopping distance (ft) of a particular truck at 20 mph under specified experimental conditions.;

X = 32.1, 30.9, 31.6, 30.4, 31.0, 31.9.

Let [tex]\mu[/tex] = true average stopping distance

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \leq[/tex] 30      {means that the true average stopping distance exceeds this maximum value}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > 30      {means that the true average stopping distance exceeds this maximum value}

The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;

                              T.S.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean stopping distance = [tex]\frac{\sum X}{n}[/tex] = 31.32 ft

            s = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex] = 0.66 ft

            n = sample size = 6

So, the test statistics =  [tex]\frac{31.32-30}{\frac{0.66}{\sqrt{6} } }[/tex]  ~  [tex]t_5[/tex]

                                    =  4.898

The value of t-test statistics is 4.898.

Now, at 0.01 level of significance, the t table gives a critical value of 3.365 at 5 degrees of freedom for the right-tailed test.

Since the value of our test statistics is more than the critical value of t as 4.898 > 3.365, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the true average stopping distance exceeds this maximum value.

The correct answer is 45.5 km

Explanation:

The total distance from the locksmith to the hotel, located in the east of the graph is not directly given; however, this distance can be calculated by considering the partial distances given. This includes the distance from the locksmith to the furniture store (18.3 km), and the distance between the furniture and the hotel (27.2) as the total distance = distance from the locksmith to the furniture store + distance from the furniture store to the hotel. Thus, the total distance is 18.3 km + 27.2 km which is equal to 45.5 km.

Answer:

Max area is 16

Step-by-step explanation:

If A² + B² = C², then A² + B² = 64. The largest triangle area is when both A² and B² are equal to 32, so 32 + 32 = 64.

So equal side of the triangle is √32 or about 5.6568. The area of the triangle is then 1/2(5.6568 × 5.6568) or 16.

The maximal area of a right triangle is 90.496

Derivative of a function of a real variable measures the sensitivity to change of the function value with respect to a change in its argument. Derivatives are a fundamental tool of calculus.

Given:

let the perpendicular be 'x'

and base be 'y'

Using Pythagoras theorem

x² + y² = 8²

x² + y² = 64

y²= 64- x²

y = √64-x²

Now, Area of triangle

= 1/2* base* height

=xy/2

=x *√64-x²*1/2

On differentiating both side

A' = 64-2x²/√64-x²*1/2

Setting derivative function equal to zero,

64= 2x²

32=x²

x=5.656

So, Area of triangle = x *√64-x²*1/2

= 90.496

Learn more about differentiation here:

https://brainly.com/question/24898810

#SPJ2

Answer:

[tex]\boxed{y\leq 6}[/tex]

Step-by-step explanation:

[tex]y-8 \leq -2[/tex]

Adding 2 to both sides

[tex]y \leq -2+8[/tex]

[tex]y \leq 6[/tex]

Answers:

sin a=12/15=4/5

step by step explanation:

AB=9, and BC=12

find c: hyp.=√12²+9²=c²

c=15

sin a=opp/hyp.=12/15=4/5 ( convert to degrees)

a=41.10

Answer:

[tex] f(x) = 6x^2 +2 , -6 <x<9[/tex]

[tex] f(x) = 12 , 9 \leq x <13[/tex]

And we want to evaluate f(x=9)

And for this case the answer would be:

[tex] f(9)= 12[/tex]

Best answer:

O 12

Step-by-step explanation:

For this problem we have the following function given:

[tex] f(x) = 6x^2 +2 , -6 <x<9[/tex]

[tex] f(x) = 12 , 9 \leq x <13[/tex]

And we want to evaluate f(x=9)

And for this case the answer would be:

[tex] f(9)= 12[/tex]

Best answer:

O 12

Question:

Diners frequently add a​ 15% tip when charging a meal to a credit card. What is the price of the meal without the tip if the amount charged is ​$20.70? How much was the​ tip?

Answer:

Price of meal = $18

Tip price = $2.70

Step-by-step explanation:

Let the price of the meal be y;

Let the tip be t

From the question;

15% of y is the tip charge (t). i.e

t = 15%y

=> t = 0.15y          --------(i)

The total amount charged is $20.70  (This means that the sum of the price of the meal and the tip is $20.70)

=> y + t = 20.70            [substitute the value of t=0.15y from equation (i)]

=> y + 0.15y = 20.70

=> 1.15y = 20.70

=> y = [tex]\frac{20.70}{1.15}[/tex]

=> y = $18

Therefore the price of the meal, y, is $18.

From equation (i),

t = 0.15y           [substitute the value of y = $18]

t = 0.15(18)

t = $2.70

Therefore the tip was $2.70

Answer:

h = 7.1 cm

Step-by-step explanation:

To find the height of the triangle, we can first find the area of the triangle using the Heron's formula:

[tex]S = \sqrt{p(p-a)(p-b)(p-c)}[/tex]

Where a, b and c are the sides of the triangle and p is the semi perimeter of the triangle:

[tex]p = \frac{a+b+c}{2} = \frac{15 + 8 + 17 }{2} = 20\ cm[/tex]

So the area of the triangle is:

[tex]S = \sqrt{20(20-15)(20-8)(20-17)}[/tex]

[tex]S = 60\ cm^2[/tex]

Now, to find the height, we can use the following equation for the area of the triangle:

[tex]S = base * height/2[/tex]

The height draw in the figure is relative to the side of 17 cm, so this side is the value of base used in the formula. So we have that:

[tex]60 = 17 * h/2[/tex]

[tex]h = 120/17[/tex]

[tex]h = 7.06\ cm[/tex]

Rounding to the nearest tenth, we have h = 7.1 cm

Answer:

7.1 cm

Step-by-step explanation:

:D

Answer:

x=3

Step-by-step explanation:

To solve this problem, we should check the x coordinate of the point where both graphs intersect. Based on both graphs, they intersect at the point (3,-1). So, the input value for which both graphs have the same value is x=3.

Answer:

its x=-2

Step-by-step explanation:

cause i got it wrong and it said the answer was x=-2

Answer:

  growth rate = 0.1733 per day, or 17.33% per day

Step-by-step explanation:

Since the doubling time is 4 days, the growth factor over a period of t days is ...

  2^(t/4)

Then the growth factor for 1 day is

  2^(1/4) ≈ 1.189207

The instantaneous growth rate is the natural log of this:

  ln(1.189207) ≈ 0.1733 . . . per day

Answer:

0.40

Step-by-step explanation:

The computation of the probability for the second student be sophomore and the first is a freshman is shown below:

Let us assume

Sophomore = S

Freshman = F

Based on this assumption, the probability is as follows

So,

[tex]= \frac{P(S\cap F)}{P(F)} \\\\ = \frac{P(S) \times P(F)}{P(F)} \\\\ = \frac{16}{40}[/tex]

= 0.40

Hence, the probability for the second student be sophomore and the first student be freshman is 0.40

Answer: 53.1ft

Step-by-step explanation:

We can draw a triangle rectangle.

Where the distance between the man and the tree is one cathetus, (the vertex is on the man's eyes)

The tree itself is the other cathetus, and the line that connects the man's eyes and the tip of the tree is the hypotenuse.

We know that:

The angle at the vertex of the man's eyes is 67°

And the adjacent cathetus, the distance between the man and the tree, is 20ft.

Then using the relation:

Tan(A) = (opposite cathetus)/(adjacent cathetus)

We can find the height of the treee:

Tan(67°) = X/20ft

Tan(67°)*20ft = X = 47.1ft

But remember that this is measured from the mans eye's, and the man's eyes are 6ft away from the ground.

Then the height of the tree is 47.1ft + 6ft = 53.1ft

Answer:

the answer is 1.00

Step-by-step explanation:

pls mark me as the brainliest and tell me thanks

Answer:

This is skewed torwards the right. Or in other words positively skewed distribution.

Step-by-step explanation:

All of the values are fairly close together torwards the lower range. While 50.20 is more of an outlier, so this graph would gradualy skew to the right.

Answer:

1,880.82

Step-by-step explanation:

The complete question is;

The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 8.9 minutes and a standard deviation of 2.5 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.)

(a) less than 10 minutes

(b) longer than 5 minutes

(c) between 8 and 15 minutes

Answer:

A) P (x < 10) = 0.6700

B) P (x > 5 ) = 0.9406

C) P (8.0000 < x < 15.0000) = 0.6332

Step-by-step explanation:

A) we are given;

Mean;μ = 8.9 minutes

Standard deviation;σ = 2.5 minutes

Normal random variable;x = 10

So to find;P(x < 10) we will use the Z-score formula;

z = (x - μ)/σ

z = (10 - 8.9)/2.5 = 0.44

From z-distribution table and Z-score calculator as attached, we have;

P (x < 10) = P (z < 0.44) = 0.6700

B) similarly;

z = (x - μ)/σ =

z = (5 - 8.9)/2.5

z = -1.56

From z-distribution table and Z-score calculator as attached, we have;

P (x > 5 ) = P (z > -1.56) = 0.9406

C)between 8 and 15 minutes

For 8 minutes;

z = (8 - 8.9)/2.5 = -0.36

For 15 minutes;

z = (15 - 8.9)/2.5 = 2.44

From z-distribution table and Z-score calculator as attached, we have;

P (8.0000 < x < 15.0000) = P (-0.36 < z < 2.44) = 0.6332

Answer:

1 x 3

Step-by-step explanation:

The order of the first matrix is 1 × 3

The order of the second matrix is 3 × 3

that is (1 × 3 ) × (3 × 3 )

The bold values at the ends of the orders give the order of the product, that is

1 × 3