Answer:
Prokaryotic Bacteria
Explanation:
Pls solve the first question for me
Answer:
which question
Explanation:
please explain better
alex is pushing a heavy box.The force he exerts is represented by the white arrow. In order to make his task easier in which direction should an additional force be applied?
Answer:
The other arrow/force should be in the same direction that Alex is pushing the heavy box.
Explanation:
If Alex is pushing the heavy box to the right, then another person helping him that is also pushing the heavy box to the right would lessen the amount that he has to push.
Determine the distance Covered by a body is 5 Second, if it initial velocity is 30mls and acceleration 5. om/s
The form of energy found in moving objects is ___??
Answer:
kinetic energy
Explanation:
It is kinetic energy because it is an energy in motion. In order words it is an energy which the body or object moves.
Two 20 kg buckets of water are being lowered into a well. There is a rope attached to the top bucket and a rope attaching the two buckets. If the acceleration is 0.025 m/s squared downwards, what is the tension in each rope?
I need help fast hurry
Sound waves are mechanical waves. They need a medium for propagation. In air the sound waves will travel smoothly and we can get it. Whereas in vacuum, no medium is there and the sound waves cannot propagate.No sound can be produced there.
What is mechanical waves?Mechanical waves are waves propagating through a medium such as air, water etc. There are two types of mechanical waves namely transverse wave and longitudinal waves.
In transverse waves, the vibration of particles is in a direction perpendicular to the wave whereas, in longitudinal waves, both are in one direction. Sound wave is a longitudinal wave.
Unlike electromagnetic waves mechanical waves cannot be travelled in vacuum. Hence if we try to produce sound in space or vacuum,no effect will be there but in air and water sound waves can be propagated.
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A box is dropped out of a moving airplane. The airplane is traveling at 50 m/s
East. The box is dropped from rest with respect to the airplane. The box travels a
vertical distance of 40 m before landing on a trampoline. The airplane continues
traveling at a constant speed after the box is dropped and the wind resistance on
the falling box is negligible.
Choose the option that correctly identifies the missing terms, in order of their
appearance in the sentences.
The box has an initial horizontal velocity of
of
m/s. The box takes
seconds to reach the ground. The box experiences an acceleration
m/s2. The box will land directly
the airplane.
The options that correctly identifies the missing terms, in order of their
appearance in the sentences are as follows:
The box has an initial horizontal velocity of 50m/s.The box takes 2.86 seconds to reach the ground.The box experiences an acceleration of 9.8 m/s².The box will land directly 143 m from the airplane.What is the initial horizontal velocity of the box dropped from the airplane?The initial horizontal velocity of the box dropped from the airplane is equal to the horizontal velocity of the airplane.
The velocity of the airplane is 50 m/s
Hence, the horizontal velocity of the box is also 50m/s.
The box falls freely under the effect of gravity. Hence, the acceleration in the vertical direction will be equal to the acceleration due to gravity.
The time taken by the box to reach the ground is calculated from the formula below as follows:
t = √(2h/g)
where;
t is the time taken to reach the ground
h is the vertical height above the ground = 40 m
g is the acceleration due to gravity = 9.8 m/s²
t = √(2 * 40 / 9.8)
t = 2.86 seconds
The horizontal distance traveled by the box = 2.86 s * 50 m/s
The horizontal distance traveled by the box = 143 m
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According to the law of universal gravitation, all objects exert gravitational forces on each other. Which statement best describes the information you need to calculate the gravitational force?
The mass of each object and the distance between the two objects
The mass of the larger object and the distance between the two objects
The distance between the objects and the electrical charge of each object
The weight of the objects and the distance between the two objects
Option -a is correct. The two objects' respective masses and distances from one another.
Which of the following statements about objects in gravitational pull on one another is always true?In other words, a line connecting the two masses is where the force vectors we could depict on each mass lie. When two objects pull on one another due to gravity, this is always true. The lines of those attractional forces run between the centers of mass of the two objects.
Any particle of matter in the universe will gravitate toward any other with a force that varies directly as the product of the masses and inversely as the square of the distance between them, according to Newton's law of gravitation.
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What is the approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s?
The approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s is 5.34 m/sec.
What is speed?
The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
Given in the question an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s, tangential speed is ,
v = [tex]2\pi*r[/tex]/t
v = 2*3.14*1.8*108/2.2*104
v = 5.34 m/sec.
The approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s is 5.34 m/sec.
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A child can throw a baseball at 20 mph. Some professional ball players can throw a baseball at 100 mph, which is five times as fast. How much more energy does the pro ball player give to the faster ball?
The ball is 25 times more energetic when it is thrown by the professional then when it is thrown by the child.
What is the ratio of the energy?Basically we ought to be reminded that the kinetic energy of the object is the energy that is possessed by the object by virtue of the fact that the object is in motion.
We have to recall that the kinetic energy is given by;
KE = 1/2 mv^2
m = mass of the object
v = velocity of the object
Since the mass of the object is held the same let us take note of the speed with which the ball is thrown by the student and the professional respectively
Speed of the student = 20 mph or 8.9 m/s
Speed of the professional = 100 mph or 44.7 m/s
Energy of the ball by the student = 0.5 * m * (8.9)^2
Energy of the ball by the professional = 0.5 * m * (44.7)^2
We now have;
0.5 * m * (44.7)^2/0.5 * m * (8.9)^2
25 times
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A ball is projected with an initial velocity 50m/s at an angle 30 degree from the top of a tower 55m high.calculate the total time the ball was on the air and the maximum horizontal distance
Time of flight = 1.6 s
Horizontal distance = 64 m
What is a projectile motion?Projectile motion is the form of motion experienced by an object or particle projected into a gravitational field, such as from the surface of the Earth, and moves along a curvilinear path only under the action of gravity.
For the given case,
h = vt + ¹/₂gt²
h = height of tower
v = initial velocity
t = time of flight
55 = 50sin30t + ¹/₂9.8t²
55 = 25t + 4.9t²
4.9t² + 25t - 55 = 0
t = 1.6 s
X = vₓt
X = horizontal distance
vₓ = horizontal velocity
t = time of flight
X = (50 x cos30) x 1.6
X = 64 m
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A car accelerated uniformly from rest and attained a velocity of 8m/s. it then travels with the uniform velocity of for the next 22 seconds and later brought to rest in 5 seconds
(a )draw the velocity time graph
(b.) calculate the total distance covered (c.) calculate the distance covered after 25 seconds.
Answer:
See below
Explanation:
See diagram below
8 seconds to 60 m/s then 60 m/s for 22 seconds then to 0 m/s in 5 seconds
12. Water spinning in a turbine has
(1 Point)
Water spinning in a turbine has Kinetic energy.
What is kinetic energy?
We must exert force on an object to accelerate it. We have to put up the effort to use force. Energy is transmitted when work is done on an object, and the thing then moves at a new, constant speed. The energy that is transported is referred to as kinetic energy, and it is influenced by the mass and speed attained.
In physics, kinetic energy is described as follows:
The amount of labor an object can accomplish through motion is measured by its kinetic energy.
As a scalar quantity, kinetic energy can only be fully defined by its magnitude.
Water spinning in a turbine has kinetic energy which is used to produced electric energy.
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I need this answer, urgently
A detailed graph of angular velocity versus time is shown. What is the angular displacement, in radians, during the time interval from 0.75 s to 14.2 s?
0.116 rad/s is the angular speed in radians, during the time interval from 0.75 s to 14.2 s
ω=Δθ/Δt
Δθ= 90° = 1.571rad
Δt=13.45
ω=1.571/13.45
ω=0.116 rad/s
The rate of change of angular displacement, or the angle a body travels along a circular path, is the definition of angular speed. Calculating angular speed involves dividing the quantity of rotations or revolutions made by a body by the amount of time required. Omega is a Greek letter that represents angular speed. The SI's angular speed unit is rad/s.
As is well known, angular speed is determined by dividing the rate of displacement change by the time. As a result, the angular speed equation is = /t. Despite the procedure stated above, a different and more well-liked formula is used to determine angular speed in competitive testing. As ω = θ/t
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Honey is a technology company that provides online coupons to its subscribers. Honey's analytics staff has developed a classification method to predict whether a customer who has been sent a coupon will apply the coupon toward a purchase. For a sample of customers, the following table lists the classification model's estimated coupon usage probability for a customer. For this particular campaign, suppose that when a customer uses a coupon, Honey receives $1 in revenue from the product sponsor. To target the customer with the coupon offer, Honey incurs a cost of $0.05. Honey will offer a customer a coupon as long as the expected profit of doing so is positive. Using the equation
Expected Profit of Coupon Offer = P(coupon used) × Profit if coupon used + (1 - P(coupon used)) × Profit if coupon not used
determine which customers should be sent the coupon.
Customer Probability of Using Coupon
1 0.44
2 0.34
3 0.24
4 0.11
5 0.06
Determine the expected profit for each customer. Round your answers to the nearest cent. Enter negative value as negative number, if any.
Customer Expected Profit
1 $
2 $
3 $
4 $
5 $
The expected profit is positive for customers (Select your answer: 2 and 3, 4 and 5, 1, 2, and 33, 4, and 5, 1, 2, 3, and 4, 1, 2, 3, and 5, 2, 3, 4, and 5, 1, 2, 3, 4, and 5) so these customers (Select your answer: should be offered or should not be offered) the coupon.
The expected profit is positive for the customers 1, 2, 3, 4, 5.
What is expected profit?This is the term that is used to refer to the gain that would be expected to be gotten based on the fact that a person has engaged in a business.
We have 1 - 0.05 = 0.95 profit if the coupon is used
-0.05 is the profit if the coupon is not used
for consumer 1
the probability = 0.44
expected profit = 0.44 x 0.95 - 0.05 x 0.56
= 0.418 - 0.028
= 0.39
for consumer 2
the probability = 0.34
expected profit = 0.34 x 0.95 - 0.05 x 0.66
= 0.323 - 0.033
= 0.29
For consumer 3
the probability = 0.24
expected profit = 0.24 x 0.95 - 0.05 x 0.76
= 0.228 - 0.038
= 0.19
For consumer 4
the probability = 0.11
expected profit = 0.11 x 0.95 - 0.05 x 0.89
= 0.1045 - 0.0445
= 0.06
For consumer 5
the probability = 0.06
expected profit = 0.06 x 0.95 - 0.05 x 0.94
= 0.057 - 0.047
= 0.01
The expected profits can be listed as:
0.390.290.190.060.01The expected profits are positive for all of 1, 2, 3, 4, and 5, hence these customers can purchase the coupon.
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A television uses a current of 1.5A at 120V. The television is used for 2 hours. Calculate
the power used in kW and the energy used in kWh.
Answer:
the power used is 0.18kW and the energy used is 0.36kWh
Explanation:
from power= current × voltage
power= 1.5A × 120V
power= 180W or 0.18kW
energy used = power × time
= 0.18kW ×2h
energy used = 0.36kWh
IF B is added to Ã, under what Condition does the resultant vector have magnitude equal to A + B ?
Answer:
its b and a
Explanation:
A student throws a baseball vertically upward and then catches it. What would that graph look like?
Find the wave length of 100.2khz
The wavelength of a wave with frequency of 100.2Khz is 2.99 × 10³m.
How to calculate wavelength?Wavelength is the length of a single cycle of a wave, as measured by the distance between one peak or trough of a wave and the next.
The wavelength is often designated in physics as λ, and corresponds to the velocity of the wave divided by its frequency as follows:
λ = v/f
Where;
λ = wavelengthv = velocityf = frequencyAccording to this question, the frequency of a wave is 100.2KHz, which is equivalent to 1.002 × 10⁵Hz.
λ = 3 × 10⁸ ÷ 1.002 × 10⁵
λ = 2.99 × 10³m
Therefore, 2.99 × 10³m is the wavelength of the wave.
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a race car is traveling in a uniform circular motion around a race track what happends to the radial aceleration of the car if the velocity is dobled and the radio od the circel is half
A race car is traveling in a uniform circular motion around a race track, the radial acceleration of the car when the velocity is doubled and the radius of the circle is halved will increase by a factor of 8 (Option D)
What is radial acceleration?To arrive at the above conclusion, we must recall that radial acceleration is defined by:
Ac = v²/r; where
Ac - is the magnitude of radial acceleration
v - is the linear or tangential speed
r - is the radius of the circular path
A′c - is the new magnitude of the radial acceleration.
Given that the linear velocity is duplicated and simultaneously the radius is split in two, then the new radial acceleration increases by a factor of 8, according to the following calculation:
A'c = (2v²)/(0.5r)
= 4v²/(0.5r)
= 8 · (v²/r)
= 8 · Ac
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Full Question:
A race car is traveling in a uniform circular motion around a race track what happens to the radial acceleration of the car if the velocity is doubled and the radius of the circle is halfed?
A. It remains the same.
B. It increases by a factor of 2.
C. It increases by a factor of 4.
D. It increases by a factor of 8.
E. It decreases by a factor of 2.
The design of a new road includes a straight stretch that is horizontal and flat but that suddenly dips down a steep hill at 18°. The transition should be rounded with what minimum radius so that cars traveling 95 km/h will not leave the road
Answer:
74.7 m
Explanation:
You want the minimum radius of curvature of a vertical circular arc so that vehicles traveling 95 km/h making the transition from horizontal to an 18° down grade will not leave the road.
AccelerationThe acceleration due to gravity on the vehicle at the point it is traveling 18° down is ...
g·cos(18°) ≈ (9.8 m/s²)·0.95106 ≈ 9.32 m/s²
RadiusThe radius of an arc and the speed of travel are related to the normal acceleration by ...
r = v²/a
where v is the speed along the arc, and 'a' is the normal acceleration required to make an object follow the circular curve.
The speed of 95 km/h can be translated to m/s by ...
(95 km/h) · (1000 m/(1 km)) · (1 h)/(3600 s) = 95/3.6 m/s ≈ 26.389 m/s
RadiusUsing the above relation to find the radius, we get ...
r = (26.389 m/s)²/(9.32 m/s²) ≈ 74.72 m
The minimum radius of the vertical circular arc should be 74.7 meters to prevent vehicles from becoming airborne.
__
Additional comment
In actual roadway design, factors of sight distance and stopping distance come into play. Sight distance over this crest would be about 25 m. It would need to be more than 6 times that distance for the roadway to be safe at 95 km/h.
An 18° down grade is about 3 times the usual maximum for roadway design, which will severely increase stopping distance. The vertical arc described here would leave the car with no normal force on the roadway at the end of the arc, so braking would be impossible. Passengers would be feeling weightless, too.
Roadway curves are generally parabolic (not circular), so they have a constant rate of change of slope with horizontal distance.
In each of three trials of an investigation, a single force is applied to a mobile. Each time, the mobile acquires a different acceleration. The table shows the relationship between the acceleration and the acting force.
Which phrase best describes a graph that would represent the relationship shown in the table?
O a downward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis
B) a downward-sloping line drawn on a graph with acceleration shown on the x-axis and force shown on the y-axis
C) an upward-sloping line drawn on a graph with acceleration shown on the x-axis and force shown on the y-axis
D) an upward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis
The best representation of the graph is an upward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis. Option D
What is the relationship between the force and the acceleration?
We know that there is a direct relationship between the force and the acceleration of the object. According to the Newton second law, when force is applied to an object. The object would acquire an acceleration. In order words, the force that acts on the body is able to increase the speed of the object.
If we look at the table that was shown in the question that we have attached here, you would notice that as the force that acted on the object was increased, there was a commensurate increase in the acceleration of the object as seen.
This goes on to buttress that the relationship between the force and the accaleration is a direct relationship. This also tell us that we will have a graph that runs upwards and not downwards!
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A truck has a speed of 14 m/s. How far will the truck go in 3 minutes? O a 18,650 meters 42 meters 4.7 meters 1640 meters 2520 meters
Answer:2,520
Explanation: The truck goes 14 meters per second
Since it is traveling for 3 minutes which is 180 seconds, all you need to do is times the 180 seconds with the 14 meters. :)
Motion is a change in ____. Question 6 options: time speed velocity position
Answer:
Motion is a change in Position.
Explanation
1. Change in time cannot be a motion, because time can change without any movement of an object.
2. speed and velocity are parts of motion but change in speed and motion is an acceleration (refer from acceleration formula), which means motion is not only change in speed or velocity but it is change in position.
Because change in position can be referred as speed and accerelation
4. A 0.7 kg object has a momentum of 15 kg m/s. What is the object's speed?
Answer:
21.4 m/s
Explanation:
Momentum = m * v
15 kg m/s = .7 * v
v = 15/.7 = 21.4 m/s
what sources of motion does a shake flashlight harness
Answer:
The power for the LED stems from the movement of a magnet through a coil of wire on a tube. Each time the magnet moves through the coil of wires, the magnet generates a pulse of electricity. This is what happens when you shake the flashlight. A capacitor allows you to use the flashlight without continuously shaking it.
An unknown radioactive element decays into non-radioactive substances. It's 520the radioactivity of a sample decreases by 60 percent.
a) What is the half-life of the element?
b) How long will it take a 100 mg sample to break down to 92 mg?
The half life of the sample is 393.4 days while it would take 47.3 days for 100 mg sample to break down to 92 mg.
What is the half-life of the element?We know that the half life has to do with the time that it takes for only half of the number of the radioactive atoms in the sample to remain. We have in this case that;
N/No = (1/2)t/[tex]t_{\frac{1}{2} }[/tex]
No = Number of radioactive atoms originally present
N = Number of atoms at time t
t = time taken
[tex]t_{\frac{1}{2} }[/tex] = half life
Then we are told that the sample decreases by 60 percent thus 40 percent is left.
We have;
0.4No/No = (1/2)^520/[tex]t_{\frac{1}{2} }[/tex]
0.4 = (1/2)^520/[tex]t_{\frac{1}{2} }[/tex]
ln0.4 = 520/[tex]t_{\frac{1}{2} }[/tex] ln 0.5
520/[tex]t_{\frac{1}{2} }[/tex] = ln0.4 /ln 0.5
[tex]t_{\frac{1}{2} }[/tex] =520/ ln0.4 /ln 0.5
= 393.4 days
Then
Using;
92/100 = (1/2)^t/ 393.4
0.92 = (1/2)^t/ 393.4
ln 0.92 = t/ 393.4 ln 0.5
t = ln 0.92/ ln 0.5 * 393.4
t = 47 days
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In the lab downstairs physics majors use a rotating mirror to measure the speed of light within a few percent of the actual value they switch the mirror from rotating clockwise at 115 rad/s to counter clockwise at 115 rad/s over the course of 85 seconds. Assume constant angular acceleration.
QUESTION: how many revolutions does the rotating mirror go through when it gets to a 0 angular velocity along the way to new speed. SHOW WORKING OUT
The number of complete cycles the rotating mirror goes through before the angular velocity gets to zero is approximately 1166.8 revs
What is angular velocity?Angular velocity is the ratio of the angle turned to the time taken.
The kinematic equation for angular velocity are presented as follows;
ω = ω₀ + α·t
θ = θ₀ + ω₀·t + 0.5·α·t²
Where;
θ₀ = The initial angle turned = 0
ω₀ = The initial angular velocity of the mirrors = 115 rad/s clockwise
α = The angular acceleration = (115 - (-115))rad/s/(85 s) = -46/17 m/s²
t = The duration of the motion;
When the angular velocity, ω is zero, we get;
0 = 115 - 46/17·t
t = 85/2
Which indicates;
θ = 0 + 115× (85/2) + 0.5×(46/17) ×(85/2)² = 7331.25
θ = 7331.25 radians
θ = 7331.25/(2×π) ≈ 1166.8 rev
The mirrors would have turned through approximately 1166.8 revolutions when the angular gets to zero
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Two forces, F1=(1.65i−0.90j+1.15k) N F2=(−1.00i+1.20j) N are applied on a moving object of mass 0.20 kg. The displacement vector produced by the two forces is d=(10.0i+8.8j+5.1k)m. What is the work done by the two forces?
I need help with this question. please
Answer:
I don't Know espero que le entiendas