Evaluate the expression when a=4 and y=-6.
-a+3y
a.
hi​

Answers

Answer 1

Answer:

- 22

Step-by-step explanation:

Given,

a = 4

y = -6

Now,

[tex] - a + 3y[/tex]

Plug the values

[tex] = - 4 + 3 \times ( - 6)[/tex]

Multiply the numbers

[tex] = - 4 + ( - 18)[/tex]

When there is a (+) in front of an expression in parentheses, the expression remains the same.

[tex] = - 4 - 18[/tex]

Calculate

[tex] = - 22[/tex]

Hope this helps..

Best regards!!

Answer 2

Answer:

14

Step-by-step explanation:

-4 + 3(6)

-4+18

14


Related Questions

Which represents the solution of the graphed system of equations, y=x^2-2x and y=-2x-1

Answers

Answer:

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

Step-by-step explanation:

The solution to the system of equations is at the point where they intercept each other.

y1 = y2

For the given equation;

y=x^2-2x and y=-2x-1

To get the where they intercept, we will equal both equations;

y=x^2-2x = -2x-1

x^2 - 2x = -2x - 1

x^2 - 2x + 2x + 1 =0

x^2 +1 = 0

x^2 = -1

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

These are the weekly wages paid to staff in a hotel. £245 £140 £525 £163 £195 £174 £140 What is the range of these wages? £ What is the mean wage?

Answers

Answer:

Range of wages is £140 to £525.

Mean wage = £226

Step-by-step explanation:

Given:

Weekly wages paid to the staff are :

£245, £140, £525, £163, £195, £174 and £140.

To find:

Range of these wages = ?

Mean wage = ?

Solution:

First of all, let us learn about the range of wages and mean wage.

Range of wages has a minimum pay and a maximum pay.

Here, if we have a look £140 is the minimum pay and

£525 is the maximum pay.

So, range of wages is £140 to £525.

Mean wage means the average of all the wages given to the staff.

Mean is defined as the formula:

[tex]\text{Average/Mean =} \dfrac{\text{Sum of all the observations}}{\text{Number of observations}}[/tex]

Here, Sum of all observations mean sum of the wages of all the staff members.

Number of observations mean the number of staff members i.e. 7 here.

Applying the formula:

[tex]\text{Average/Mean =} \dfrac{\text{245+140+525+163+195+174+140}}{\text{7}} \\\Rightarrow \text{Average/Mean =} \dfrac{\text{1582}}{\text{7}}\\\Rightarrow \text{Average/Mean =} 226[/tex]

So, the answer is:

Range of wages is £140 to £525.

Mean wage = £226

A student earned grades of​ B, B,​ A, C, and D. Those courses had these corresponding numbers of credit​ hours: 4,​ 5, 1,​ 5, 4. The grading system assigns quality points to letter grades as​ follows: A=​4, B=​3, C=​2, D=​1, and F=0. Compute the grade point average​ (GPA) and round the result to two decimal places.

Answers

Answer:

Computation of Grade Point Average (GPA):

GPA = Total Weighted Points divided by total credit hours

= 45/19

= 2.37 on 4.00 Grade Average

Step-by-step explanation:

a) Data and Computations:

Courses  Grade Letters  Credit Hours  Quality Points  Weighted Points

1                        B                     4                        3                      12

2                       B                     5                        3                      15

3                       A                     1                         4                       4

4                       C                     5                        2                     10

5                       D                     4                        1                       4

Total                                       19 credit hours                         45 Points

b) GPA = Total Weighted Points divided by total credit hours

= 45/19

= 2.37

c) The GPA for this student is the total weighted points (which is a product of the credit hours (loads) and the quality point) expressed as a ratio of the total credit hours for the courses she took.  The grade point average ensures that the each point used in calculating the GPA is weighed by the credit hours allocated to the course.  The resultant figure of 2.37 implies that out of 4.00 grade points, the student scored 2.37, translating to about 59%.

what is the measure of SR?

Answers

Answer:

RS = 8

Step-by-step explanation:

Given:

Secant QU = internal secant segment PU + external secant segment PQ = 7 + 9 = 16

Secant QS = internal secant segment RS + external secant segment RQ = (3x - 5) + 8

To find the measure of RS, we need to find the value of x.

Thus, recall the "Two Secant Theorem"

According to the theorem,

(RS + RQ)*RQ = (PU + PQ)*PQ

Thus,

[tex] (3x - 5 + 8)*8 = (7 + 9)*9 [/tex]

[tex] (3x + 3)*8 = (16)*9 [/tex]

[tex] 24x + 24 = 144 [/tex]

Subtract 24 from both sides

[tex] 24x + 24 - 24 = 144 - 24 [/tex]

[tex] 24x = 120 [/tex]

Divide both sides by 24

[tex] \frac{24x}{24} = \frac{120}{24} [/tex]

[tex] x = 5 [/tex]

Plug in the value of x into (3x - 5) to find the measure of RS

RS = 3(5) - 5 = 15 - 7

RS = 8

Emma buys 3 and two-thirds yards of blue fabric and some yellow fabric at a store. She buys a total of 5 and one-third yards of fabric. The equation 5 and one-third = 3 and two-thirds + y can be used to represent this situation, where y is the number of yards of yellow fabric she buys. How much yellow fabric does she buy?

Answers

Answer:

A) 1  2/3 yards

Step-by-step explanation:

Hope this helped

Answer:

The answer is A

Let me finish the quiz then upload a picture to this answer showing you the correct answer is A

Step-by-step explanation:

Need help solving hi

Answers

Answer:

See below.

Step-by-step explanation:

[tex]2 \ln(x+2)=6[/tex]

[tex]\ln (x+2)=3[/tex]

[tex]e^{\ln(x+2)}=e^3[/tex]

[tex]x+2=e^3[/tex]

[tex]x=e^3-2[/tex]

[tex]x\approx 18. 09[/tex]

What is the Greatest Common Factor GCF between two expressions?

Answers

Answer:

The GCF is the largest expression that is factor of all expressions

Answer:

The GCF of two expressions is the greatest expression that is a factor of both the expressions.

Step-by-step explanation:

For example 7x² and 14x.

7x² = 1, 7, x, x

14x = 2, 7, x

The greatest common factor of the two expressions is 7x.

What is 4sqrt7^3 in exponential form?

Answers

Answer:

[tex]\boxed{7^{\frac{3}{2} } \times 4}[/tex]

Step-by-step explanation:

[tex]4 (\sqrt{7} )^3[/tex]

Square root can be written as a power.

[tex]4(7^{\frac{1}{2} })^3[/tex]

Multiply the exponents.

[tex]4(7^{\frac{3}{2} })[/tex]

Answer:

A (7^3/4)

Step-by-step explanation:

ed 2020

Trigonometry Dilemma

Answers

Answer:

17.1

Step-by-step explanation:

The missing side is x

tan 25° = [tex]\frac{opposite }{adjacent }[/tex] tan 25° = [tex]\frac{8}{x}[/tex]                  

switch tan 25° and x

x = [tex]\frac{8}{tan 25}[/tex] x= 17.15≈17.1

Can someone help me with this one

Answers

Answer:

b^2

------

2a

Step-by-step explanation:

-6ab^3          10b

-------------- * -----------

5a                   -24 ab^2

Rewriting

-6ab^3          10b

-------------- * -----------

 -24 ab^2      5a

Canceling like terms

b                  2b

-------------- * -----------

 4                a

Canceling the 2 and 4

b                  b

-------------- * -----------

 2                a

b^2

------

2a

Answer:

b²/2a

Step-by-step explanation:

[(-6ab³)/5a]*[(10b)/(-24ab²)]

-60ab^4/-120a²b²= ( when divide ,subtract the exponents)

b²/2a

An infinite population has a standard deviation of 10. A random sample of 100 items from this population is selected. The sample mean is determined to be 60. At 80% confidence, the margin of error is

Answers

Answer:

1.28

Step-by-step explanation:

Margin of error is also called confidence interval, and it shows how much the results from sample reflects the characteristics of the larger population.

The following steps are used to calculate margin of error.

- obtain population standard deviation (σ) and sample size (n)

- divide standard deviation by square root of sample size

- multiply result by z score consistent with the given confidence. In this case confidence is 80% and z score for it is 1.28

Margin of error= z * (σ ÷ √n)

Margin of error = 1.28 * (10 ÷ √100)

Margin of error= 1.28 * (10 ÷ 10) = 1.28

43.
Some of the ingredients used by a baker for making 1 dozen
normal sponge cakes are listed below:
225g unsalted butter; 4 eggs; 125ml milk;
2 tsp vanilla extract; 264g plain flour
To make fully vegetarian cakes, the baker replaces each egg
with an additional 30g of plain flour.
The baker got an order for 100 normal cakes and 60 vegetarian
cakes. How much kilograms of flour would the baker need to
complete the order?​

Answers

Answer:

4.12 kg

Step-by-step explanation:

Regular cakes:

1 dozen normal sponge cakes: 264 g plain flour

Vegetarian cakes:

1 dozen cakes: 264 g plain flour

4 eggs are replaced by 4 * 30 g of flour = 120 g flour

total flour for 1 dozen vegetarian cakes = 264 g + 120 g = 384 g

Proportion for regular cakes:

12 cakes to 264 g flour = 100 cakes to x grams flour

12/264 = 100/x

12x = 26400

x = 2200

2200 g flour for 100 regular cakes

Proportion for vegetarian cakes:

12 cakes to 384 g flour = 60 cakes to y grams flour

12/384 = 60/y

12y = 384 * 60

12y = 23040

y = 1920

1920 g flour for 60 vegetarian cakes

Total flour needed:

2200 g + 1920 g = 4120 g

4120 g * 1 kg/(1000 g) = 4.12 kg

Answer: 4.12 kg

what is 3141 times X. x=5783978

Answers

Answer:

18167474898

Step-by-step explanation:

I used a calculator.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

express 3.222......in p/q form​

Answers

Answer:

3.22222......  = [tex]\frac{29}{9}[/tex]

Step-by-step explanation:

In this question we have to convert the number given in recurrent decimals into fraction.

Recurrent decimal number is 3.22222.......

Let x = 3.2222.........   -------(1)

Multiply this expression by 10.

10x = 32.2222........... -------(2)

Now subtract the expression (1) from (2),

10x = 32.22222.....

   x = 3.22222.......

9x = 29

x = [tex]\frac{29}{9}[/tex]

Therefore, recurrent decimal number can be written as [tex]\frac{29}{9}[/tex] which is in the form of [tex]\frac{p}{q}[/tex].

The temperature, T^0Celcius, of an object, t minutes after it is removed from a head source, is given byT=55e^((-0.1t) )+15. Find the temperature of the object at the instant it is removed from the heat source.

Answers

Answer:

60°C

Step-by-step explanation:

This is a great example of a problem that looks really complicated, but can be broken down and easily understood!

First, we want to know the temperature the instant it is removed from the heat source. In that case, the time that has elapsed after it has been removed is 0, so we're looking for:

[tex]T(0)=55e^{-0.1(0))}+15=55e^{0}+15[/tex]

Now, any number raised to to the power of zero is 1, so this becomes:

[tex]T(0)=55(1)+15=60[/tex]

For more information on why any number raised to the zero power is 1, I highly recommend researching if it interests you. One of the most intuitive ways is to think of the pattern of exponents:

[tex]3^{3}=3*3*3=27[/tex]

[tex]3^{2}=3*3=9[/tex]

[tex]3^{1}=3[/tex]

You might notice that with each decrease in power, it can be read as dividing the expression by three, so following that pattern gives:

[tex]3^{0}=\frac{3}{3}=1[/tex]

And if we follow the division pattern, we do end up going into negative exponents correctly:

[tex]3^{-1}=\frac{1}{3^{1}}[/tex]

[tex]3^{-2}=\frac{1}{3^{2}}=\frac{1}{9}[/tex]

[tex]3^{-3}=\frac{1}{3^3}=\frac{1}{27}[/tex]

Jacob needs to know if the volume of a storage bin is under 3,000 cubic feet. The
dimensions of the bin are 17 ft. X 15 ft. x 10 ft.
a. Is the bin under 3,000 cubic ft.?
b. If yes, by how much?

Answers

Answer:

It is less  than 3000 ft^3 by 450 ft^3

Step-by-step explanation:

The volume of the bin

V = l*w*h

V = 17*15*10

V =2550 ft^3

If it less than 3000 ft^3

V = 3000- 2550 =450 ft^3

If is less by 450 ft^3

Answer:

Let’s first multiply all the numbers given

Since it wants the volume we need to use the formula

LxWxH

17x15x10=2,550

Part A: yes the bin is under 3,000

Part B: by 450 more because if you subtract 3,000 and 2,550 you will get 450

Hope this helps! :)

Mitch mixes 5 parts white paint to 9 parts blue paint. If he has 4 qt of white paint, how much blue paint would he need?
He would need
qt of blue paint

Answers

Answer:

7.2 qt

Step-by-step explanation:

1. Determine how much blue paint is needed in comparison to white paint

9 ÷ 5 = 1.8

For every 1 part of white paint, 1.8 times that amount of blue paint is needed.

2. Multiply the 4 qt of white paint by 1.8

4 · 1.8 = 7.2

The number of blue paints Mitch will need given the proportion of white and blue paints is 7.2qt

Given:

Blue paints = 9

White paints = 5

Ratio of blue paints to white paints = 9 : 5

If Mitch has 4 qt of white paint

Number of blue paints needed is x

Ratio of blue paints to white paints = x : 4

Equate the ratio

9 : 5 = x : 4

9/5 = x/4

cross product

9 × 4 = 5 × x

36 = 5x

x = 36/5

x = 7.2 qt

Learn more about ratio:

https://brainly.com/question/1781657

In the diagram, line a is the perpendicular bisector of KM. Line a is a perpendicular bisector of line segment K M. It intersects line segment K M at point L. Line a also contains point N. Line segment K L is 6 x + 4. Line segment K N is 9 x minus 5. Line segment N M is 7 x + 7. What is the length of KM? 22 units 40 units 44 units 80 units

Answers

Answer:

D. 80    :)

Step-by-step explanation:

The solution is : The value of segment LM is 9x + 5.

What is an angle?

In Plane Geometry, a figure which is formed by two rays or lines that shares a common endpoint is called an angle. The two rays are called the sides of an angle, and the common endpoint is called the vertex.

here, we have,

Consider the image below.

A perpendicular bisector is a line segment that bisects another line segment into two equal parts and is perpendicular to this line segment.

So from the diagram below we know:

KL = LM

line a is ⊥ to KM

∠NLK = 90°

Since the angle measure of ∠NKL is not provided we cannot determine the value of x.

So, the value of segment LM is 9x + 5.

To learn more on angle click:

brainly.com/question/28451077

#SPJ7

Complete question:

Line a is a perpendicular bisector of line segment K M. It intersects line segment K M at point L. Line a also contains point N. Line segment K L is 9 x +5. Line segment K N is 14 x minus 3. What is the length of segment LM? units

please help me out with these questions. Its trigonometry.

Find the value of the lettered angles
In case the pic's not clear;
[tex] \cos \alpha = \sin(50 + \alpha ) [/tex]

Answers

Answer:  i) θ = 30°, 60°, 210°, & 240°

              ii) θ = 20° &  200°

Step-by-step explanation:

i) sin (2θ) = cos 30°

[tex]\sin(2\theta)=\dfrac{\sqrt3}{2}\\\\.\quad 2\theta=\sin^{-1}\bigg(\dfrac{\sqrt3}{2}\bigg)\\\\.\quad 2\theta=60^o\qquad 2\theta=120^o\\\\.\quad \theta=30^o\qquad \theta=60^o[/tex]

To include all of the solutions for one rotation, add 360/2 = 180 to the solutions above.   θ = 30°, 60°, 210°, 240°

If you need ALL of the solutions (more than one rotation), add 180n to the solutions.   θ = 30° + 180n   &   60° + 180n

*********************************************************************************************

ii) cos α = sin (50 + α)

Use the Identity: cos α = sin (90 - α)

Use Transitive Property to get:   sin (50° + α) = sin (90° - α)

50° + α = 90° - α

50° + 2α = 90°

        2α = 40°

          α = 20°

To find all solutions for one rotation, add 360/2 = 180 to the solution above.

α = 20°, 200°

If you need ALL of the solutions (more than one rotation), add 180n to the solution. α = 20° + 180n





























































































Item 25
The linear function m=45−7.5b represents the amount m (in dollars) of money that you have after buying b books. Select all of the values that are in the domain of the function.

0

1

2

3

4

5

6

7

8

9

10





















































































Item 25
The linear function m=45−7.5b represents the amount m (in dollars) of money that you have after buying b books. Select all of the values that are in the domain of the function.

0

1

2

3

4

5

6

7

8

9

10

Answers

Answer:

5

Step-by-step explanation:

which formula would be used to find the measure of angle 1

Answers

Answer:

Option (4)

Step-by-step explanation:

By the Angle of intersecting secants,

"If two lines intersect outside a circle, then the measure of the angle between these lines or secants will be one half of the difference between the intercepted arcs."

From the picture attached,

Angle between the secants = ∠1

Measure of intercepted arcs are a° and b°.

By this theorem,

m∠1 = [tex]\frac{1}{2}(a-b)[/tex]

Option (4) will be the answer.

A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed of the film and believes that this can be achieved by reducing the thickness of the film to 20 mils. Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured. For the 25-mil film, the sample data result is: Mean Standard deviation 1.15 0.11 For the 20-mil film the data yield: Mean Standard deviation 1.06 0.09 *Note: An increase in film speed would lower the value of the observation in microjoules per square inch. We may also assume the speeds of the film follow a normal distribution. Use this information to construct a 98% interval estimate for the difference in mean speed of the films. Does decreasing the thickness of the film increase the speed of the film?

Answers

Answer:

A 98% confidence interval estimate for the difference in mean speed of the films is [-0.042, 0.222].

Step-by-step explanation:

We are given that Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured.

For the 25-mil film, the sample data result is: Mean Standard deviation 1.15 0.11 and For the 20-mil film the data yield: Mean Standard deviation 1.06 0.09.

Firstly, the pivotal quantity for finding the confidence interval for the difference in population mean is given by;

                     P.Q.  =  [tex]\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex]  ~  [tex]t__n_1_+_n_2_-_2[/tex]

where, [tex]\bar X_1[/tex] = sample mean speed for the 25-mil film = 1.15

[tex]\bar X_1[/tex] = sample mean speed for the 20-mil film = 1.06

[tex]s_1[/tex] = sample standard deviation for the 25-mil film = 0.11

[tex]s_2[/tex] = sample standard deviation for the 20-mil film = 0.09

[tex]n_1[/tex] = sample of 25-mil film = 8

[tex]n_2[/tex] = sample of 20-mil film = 8

[tex]\mu_1[/tex] = population mean speed for the 25-mil film

[tex]\mu_2[/tex] = population mean speed for the 20-mil film

Also,  [tex]s_p =\sqrt{\frac{(n_1-1)s_1^{2}+ (n_2-1)s_2^{2}}{n_1+n_2-2} }[/tex] = [tex]\sqrt{\frac{(8-1)\times 0.11^{2}+ (8-1)\times 0.09^{2}}{8+8-2} }[/tex] = 0.1005

Here for constructing a 98% confidence interval we have used a Two-sample t-test statistics because we don't know about population standard deviations.

So, 98% confidence interval for the difference in population means, ([tex]\mu_1-\mu_2[/tex]) is;

P(-2.624 < [tex]t_1_4[/tex] < 2.624) = 0.98  {As the critical value of t at 14 degrees of

                                             freedom are -2.624 & 2.624 with P = 1%}  

P(-2.624 < [tex]\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] < 2.624) = 0.98

P( [tex]-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] < [tex]2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] <  ) = 0.98

P( [tex](\bar X_1-\bar X_2)-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] < ([tex]\mu_1-\mu_2[/tex]) < [tex](\bar X_1-\bar X_2)+2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] ) = 0.98

98% confidence interval for ([tex]\mu_1-\mu_2[/tex]) = [ [tex](\bar X_1-\bar X_2)-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] , [tex](\bar X_1-\bar X_2)+2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] ]

= [ [tex](1.15-1.06)-2.624 \times {0.1005 \times \sqrt{\frac{1}{8}+\frac{1}{8} } }[/tex] , [tex](1.15-1.06)+2.624 \times {0.1005 \times \sqrt{\frac{1}{8}+\frac{1}{8} } }[/tex] ]

 = [-0.042, 0.222]

Therefore, a 98% confidence interval estimate for the difference in mean speed of the films is [-0.042, 0.222].

Since the above interval contains 0; this means that decreasing the thickness of the film doesn't increase the speed of the film.

One number is 2 more than another. The difference between their squares is 52. What are the numbers?

Answers

The numbers are 12 and 14.

Answer:

The aprox, numbers:

4.1633   and    8.3266

Step-by-step explanation:

a = 2b

a² - b² = 52

then:

(2b)² - b² = 52

4b² - b² = 52

3b² = 52

b² = 52/3

b² = 17.333

√b² = √17.333

b = 4.1633        aprox.

a = 2b

a = 2*4.1633

a = 8.3266

Check:

8.3266² - 4.1633² = 52

69.333 - 17.333 = 52

A movie earned $438 million at the box office in
2013. That is 24% more than book of the same
name earned. Estimate how much the book
earned?
Round your answer to the nearest hundredth of
a million dollars.

Answers

Answer:

332.88 million

Step-by-step explanation:

you do the thing

331.36 is the answer.
You can take 76% of 438 to find the answer

solve the inequality -2/11 j _< 8

Answers

Answer:

j ≥ -44

Step-by-step explanation:

-2/11 j ≤ 8

Multiply each side by -11/2 to isolate j.  Flip the inequality since we are multiplying by a negative

-11/2 * -11/2 j ≥ 8 * -11/2

j ≥ -44

Answer:

[tex]j\geq -44[/tex]

Step-by-step explanation:

The inequality given is:

[tex]\frac{-2}{11}j\leq 8[/tex]

To solve the inequality, we must get the variable j by itself.

j is being multiplied by -2/11. To reverse this, we must multiply by the reciprocal of the fraction.

Flip the numerator (top number) and denominator (bottom number) to find the reciprocal.

[tex]\frac{-2}{11} --> \frac{-11}{2}[/tex]

Multiply both sides of the equation by -11/2.

[tex]\frac{-11}{2} *\frac{-2}{11} j \leq 8*\frac{-11}{2}[/tex]

[tex]j\leq 8*\frac{-11}{2}[/tex]

Since we multiplied by a negative number, we must flip the inequality sign.

[tex]j\geq 8*\frac{-11}{2}[/tex]

Multiply 8 and -11/2

[tex]j\geq 8*-5.5[/tex]

[tex]j\geq -44[/tex]

The solution to the inequality is: [tex]j\geq -44[/tex]

surface area of a equilateral by hand

Answers

surface area of a equilateral by hand a 140.4 cm and 9cm

What is the slope of the line x = 4?

Answers

Answer:

slope is undefined

Step-by-step explanation:

x = 4 is the equation of a vertical line parallel to the y- axis.

The slope of a vertical line is undefined

Answer:

Undefined

Step-by-step explanation:

If the line is strait up like x = 4 that means it is undefined.

PLZ IM ON THE CLOCK!!!!! A sports memorabilia store makes $6 profit on each football it sells and $5.50 profit on each baseball it sells. In a typical month, it sells between 35 and 45 footballs and between 40 and 55 baseballs. The store can stock no more than 80 balls total during a single month. What is the maximum profit the store can make from selling footballs and baseballs in a typical month? $457.50 $460.00 $462.50 $572.50

Answers

Answer:

460

Step-by-step explanation:

Answer:

460

Step-by-step explanation:

Which of the following is an exterior angle of triangle BHE? Yes or no​

Answers

Answer:

Im not 100% sure, but I think it is:

No

No

No

Yes

Find the total area of the prism.

Answers

Answer:

A=1,728

Step-by-step explanation:

To find the area of a prism, you must find the area of one side, then multiply it by so it would be Width*Hight*Depth, W*H*D.

The width is 12, the hight is 12, and the depth is 12 so you can write

A=12*12*12

Multiply 12 by 12

A=144*12

Multiply 12 by 144 to get your final total area

A=1,728

Hope this helps, feel free to ask follow-up questions if confused.

Have a good day! :)

A=1728 if u multiply and u will get it answer
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