explain translatory motion and give examples of various types of translatory motion
Answers
Answer:
Translatory Motion:
The motion of a body along a line is called Translatory Motion. The line may be straight or curved. There are three types:
1) Linear Motion:
Straight line motion of a body is called Linear Motion.
E.g. Movement of a car on a straight road.
2) Circular Motion:
Motion of a body along a circle is called circular motion.
E.g. Movement of a toy train along its circular track.
3) Random Motion:
The irregular motion of a body is called random motion.
E.g. Movement of a bee.
.......Hope it helps :)........
Related Questions
A mass of 1.15 kg of air at 111 kPa and 27 C is contained in a gas-tight, frictionless piston cylinder device. The air is now compressed to a final pressure of 0.84 MPa. During this process, heat is transferred from the air such that the temperature inside the cylinder remains constant. Calculate the work input (in kJ) during this process.
Answers
Answer:
Work input W = -200.39 KJ
Explanation:
From the question, we are given;
m = 1.15 kg
Constant temperature T1 = T2 = 27 + 273 = 300k
Since the temperature is constant, we can say that the process is isothermal
P1 = 111 KPa
P2 = 0.84 MPa = 0.84 * 1000 KPa = 840 KPa
Now what we want to calculate is W1-2
Mathematically, for isothermal process;
W1-2 = mRTlnP1/P2
where R can be obtained from table and it is equal to 0.287 KJ/kg.k
Hence;
W1-2 = (1.15)(0.287)(300)(ln 111/840)
W1-2 = 99.015 * -2.023871690525 = -200.39 KJ
Kindly note that the value of the work is negative because work is done on the system and not by the system
how can i solve density
Answers
Answer:
p=m÷v
Explanation:
that is the formula for it. now, using your numbers p=density,m=mass and v= volume. you just divide it.
after you measurement would be in cm/3
Answer:
You can simply find density by using formula
[tex]d = \frac{m}{v} [/tex]
where m represents mass of an object and v represents volume of an object.
hope it helps..
What must be the tension of a string 202 cm long and 3 x 10-2 Kg / m per unit length (µ) for it to emit a sound of 78 Hz?
Answers
Answer:
2980 N
Explanation:
The fundamental frequency of a string is:
f₁ = √(T/µ) / (2L)
78 Hz = √(T / (0.03 kg/m)) / (2 (2.02 m))
315.12 m/s = √(T / (0.03 kg/m))
99,300 m²/s² = T / (0.03 kg/m)
T = 2980 N
What rule should be used to transform a table of data to represent the
reflection of f(x) over the yaxis?
Answers
Answer:
Multiply the x values with -1.
Explanation:
By multiplying the numbers by one, you are changing them to be the opposite of their original state.
You multiply the numbers that are in the x-value column because you are reflecting the image over the y-axis.
Hope this helped and good luck!
Answer:
Multiply each x-value in the table by -1
Explanation:
explain why the term Nano is used to describe nanotechnology
Answers
Answer:
Nanotechnology means working with materials at the scale of one billionth of a metre.
Explanation:
The prefix “nano” refers to one billionth: it’s part of the scientific scale of measurement. Its science, engineering, and technology are conducted at the nanoscale, which is about 1 to 100 nanometers. Nanoscience and nanotechnology are the study and application of extremely small things. Thus, this describes why the term nano is used to describe nanotechnology.
I hope this helps :)
Answer:
Nanotechnology is technology that is about a nanometer in size, or between 1 nm and 100 nm.
Explanation:
its the sample response on edge 2021
Diagram 7 shows the velocity-time graph of an
object for 12 s.
When is the object at a distance of one-quarter of
the total distance travelled in the 12 s?
A 3 s
B 4 s
C 5 s
D 6 s
*The answer is D but can anyone tell me the solving steps? Or perhaps the answer is wrong?*
Answers
Answer:
t = 6
Explanation:
Displacement is equal to the area under a velocity vs time graph.
In this case, the area is a triangle. At time t, the base of the triangle is t. The height of the triangle can be found with similar triangles:
h / t = 8 / 12
h = ⅔ t
So the distance traveled at time t is:
d = ½ (t) (⅔ t)
d = ⅓ t²
The distance traveled at time 12 is:
D = ½ (12) (8)
D = 48
We want to find when d = D/4.
d = D/4
⅓ t² = 48/4
⅓ t² = 12
t² = 36
t = 6
Alternatively, since the acceleration is constant here, we could use a constant acceleration equation.
Δx = v₀ t + ½ at²
Given v₀ = 0 m/s and a = ⅔ m/s²:
Δx = (0) t + ½ (⅔) t²
Δx = ⅓ t²
When t = 12, Δx = 48.
⅓ t² = 48/4
t = 6
Please help me with this question ASAP.
In a a potentiometer circuit, a 1m long potentiometer wire PQ of resistance 10 ohms is connected in series with a cells of e.m.f. 9V with internal resistance 3 ohms Calculate:
i The p.d. across PQ
ii. The e.m.f. of a cell which has a balance point of 75cm.
Answers
Answer:
i. 6.923 V
ii. The e.m.f. = 22.5 V
Explanation:
i. The given parameters are;
Length of potentiometer = 1 m
The resistance of the potentiometer = 10 Ω
The e. m. f. of the attached cell = 9 V
The current, I flowing in the circuit = e. m. f/(Total resistance)
The current, I flowing in the circuit = 9 V/(10 + 3) = 9/13 A
The potential difference, p.d. across the 1 m potentiometer wire = I × Resistance of the potentiometer wire
The p.d. across the potentiometer wire = 9/13×10 = 90/13 = 6.923 V
ii) Given that the 1 m potentiometer wire has a resistance of 10 Ω, 75 cm which is 0.75 m will have an e.m.f. given by the following relation;
[tex]\dfrac{E}{R_{balance}} = \dfrac{V}{R_{cell}}[/tex]
Where:
E = e.m.f. of the balance point cell
[tex]R_{balance}[/tex] = Resistance of 75 cm of potentiometer wire = 0.75×10 = 7.5 Ω
[tex]R_{cell}[/tex] = Resistance of the cell in the circuit = 3 Ω
V = e.m.f. attached cell = 9 V
[tex]\dfrac{E}{7.5} = \dfrac{9}{3}[/tex]
E = 7.5*3 = 22.5 V
The e.m.f. = 22.5 V
A hollow circular shaft made of 304 stainless steel uniformly tapers from an outer diameter of 3.0 cm to an outer diameter of 4.0 cm over a length of 2 meters. The inner diameter of 1.0 cm is constant over the length of the shaft. The shaft is subjected to an applied torque of 500 Nm. Determine the maximum shear stress in the shaft.
Answers
Answer:
maximum shear stress = τ(max) = 95.49 × 10⁶N/m²
Explanation:
given
outer diameter at one end(D₁) = 3.0cm
outer diameter at the other end(D₂) = 4.0cm
inner diameter(d₁) = 1.0cm
torque applied(T) = 500Nm
maximum shear stress will occur at lower outer diameter
the formula is τ/r = T/J
τ= T × r/J
where r is radius
T is the torque
J is the polar 2nd M of area
attached is the calculation of the question
The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volume of the balloon? (Hint: n and P are constant) (Unit= m^3)
Answers
Answer:
[tex]\boxed{ V_{2}= 0.03189 m^3}[/tex]
Explanation:
According to Charles Law
=> [tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]
Where [tex]V_{1}[/tex] = 0.0279 m³, [tex]T_{1}[/tex] = 280 K and [tex]T_{2}[/tex] = 320 K
=> [tex]\frac{0.0279}{280} = \frac{V_{2}}{320}[/tex]
=> [tex]V_{2}[/tex] = 0.03189 m³
The power source provides a current of 1.86 A at a potential difference of 3.90 V. Calculate the power of the power source. Use the equation:
power = potential difference × current
Choose the correct unit from the box below
C W J
Answers
Answer:
W
Explanation:
The unit for Power which is (Volt X Current) is Watts. and the symbol for Watts is W.
A stone is dropped from a height of 49m and simultaneously another ball is thrown upward from the ground with a speed of 40m/s. when and where do the two stone meet
Answers
Answer:
S1 = 1/2 g t^2 distance stone falls in time t
S2 = Vy t - 1/2 g t^2 distance thrown stone rises in time t
H = 49 = S1 + S2 = Vy t
t = 49 / 40 sec time when stones meet
Check:
Stone 1 falls: 1/2 g t^2 = 1/2 * 9.8 * (49 / 40)^2 = 7.35 m
Stone 2 rises : 40 * (49 / 40) - 1/2 * 9.8 (49 / 40)^2 = 41.65 m
Two men, Joel and Jerry, each pushes an object that are identical on a horizontal frictionless floor starting from rest. Joel and Jerry are using the same force F. Jerry stops after 10 min, while Joel is able to push for 5.0 min longer. Compare the work they do.
Answers
Answer:
The work done by Joel is greater than the work done by Jerry.
Explanation:
Let suppose that forces are parallel or antiparallel to the direction of motion. Given that Joel and Jerry exert constant forces on the object, the definition of work can be simplified as:
[tex]W = F\cdot \Delta s[/tex]
Where:
[tex]W[/tex] - Work, measured in joules.
[tex]F[/tex] - Force exerted on the object, measured in newtons.
[tex]\Delta s[/tex] - Travelled distance by the object, measured in meters.
During the first 10 minutes, the net work exerted on the object is zero. That is:
[tex]W_{net} = W_{Joel} - W_{Jerry}[/tex]
[tex]W_{net} = F\cdot \Delta s - F\cdot \Delta s[/tex]
[tex]W_{net} = (F-F)\cdot \Delta s[/tex]
[tex]W_{net} = 0\cdot \Delta s[/tex]
[tex]W_{net} = 0\,J[/tex]
In exchange, the net work in the next 5 minutes is the work done by Joel on the object:
[tex]W_{net} = W_{Joel}[/tex]
[tex]W_{net} = F\cdot \Delta s[/tex]
Hence, the work done by Joel is greater than the work done by Jerry.
Suppose a piece of food is on the edge of a rotating microwave oven plate. Does it experience nonzero tangential acceleration, centripetal acceleration, or both when: (a) The plate starts to spin
Answers
Answer:
the only acceleration it has is radial (centripetal)
Explanation:
The microwaves plate rotates at a constant speed after a very short period of acceleration.
Therefore we can apply Newton's second law
F = m a
where the acceleration is centripetal
a = v2 / r = w2 r
therefore as it rotates constant speed it cannot have a tangential acceleration since it changes the modulus of the speed.
Consequently the only acceleration it has is radial (centripetal)
How did Niels Bohr change the atomic model based on his experimental
results?
A. He described the atom as a sea of positive charge sprinkled with
electrons,
B. He placed positive material in the atom's center,
C. He placed electrons in orbits around the nucleus.
D. He described electrons as being in clouds outside the nucleus.
Answers
Answer:
C. He placed electrons in orbits around the nucleus
Explanation:
Answer:
He placed electrons in orbits around the nucleus.
Explanation:
A refrigerator recieves 240 V of electricity. If it use 32 A of current, what is the resistance of the refrigerator?
Answers
Answer:
7.5 Ω
Explanation:
Voltage = Current x Resistance
(V = IR)
240 = 32 R
R = 240 / 32
= 7.5 Ω
A river flows with a speed of 3km/h in still water. A man who can swim with a speed of 5km/h wishes to reach a point on the other bank just opposite to the starting point. In which direction should he put his strokes and how long will he take to cross the river of width 1.2km? Please try to provide a diagram and step by step explanation.
Answers
Answer:
Explanation:
Let the angle required be θ with direction opposite to current .
cos θ = 3 / 5
θ = 53° .
Resultant velocity towards the opposite side
= √ ( 5 ² - 3²)
= 4 km /h
distance covered = 1.2 km
time taken = 1.2 / 4 = .3 h
= 18 min .
Earthquake damage causes two rabbits to be separated from the rest of the rabbits in their large habitat. They have no way to get back to their original habitat. The two rabbits mate with each other. Over time, all the offspring in the new habitat are descendants of the original two rabbits. What are the outcomes of this situation? A.The rabbits in the new habitat will have lower genetic variation than the rabbits in the original habitat. B. The rabbits in the new habitat will have a higher risk of random genetic mutations than the rabbits in the original habitat. C. The rabbits in the original habitat have a greater likelihood of choosing an unrelated mate than the rabbits in the new habitat. D.The rabbits in the original habitat will be less likely to reproduce than the rabbits in the new habitat.
Answers
Answer:
A.The rabbits in the new habitat will have lower genetic variation than the rabbits in the original habitat.
Explanation:
If two animals of opposite sex are isolated from a larger group of animal, and made to reproduce. They will produce offspring with similar genetic makeup. If this offspring still remain isolated, and continue to interbreed within themselves for a number of consecutive generations, their offspring will all be very closely related genetically. Situations like this just as with the two rabbits in the question leads to a lower genetic variation within the offspring of the two animals.
Animals need to reproduce within a larger group in order to increase genetic variation. Increasing genetic variation reduces the risk of been sucked into a gene pool. A lower genetic variation reduces the fitness of the animals involved. It is only an advantage in cases in which the the original pair are resistant to a deadly disease. In this case all the offspring also develop this immunity. Mostly the effects of a lower genetic variation leaves negative impacts, and animals try to avoid this by preferring to interbreed with unrelated partner
Answer:
I got this and got the answer correct.
Explanation:
Hope it helps :)
How do you find the rest mass (kg) of a 3.1 eV electron?
Answers
Answer:
Explanation:
The rest energy of any substance is defined by the Einstein's mass energy equivalence relation. Thus the rest mass of a electron is 9.11x10^-31 kg. The speed of light is 299,792,458 m/s. Thus multiplying the square of speed of light with the rest mass of electron gives the rest energy of the electron.
What does addition of two vectors give you?
Answers
Answer:
Explanation:
To add or subtract two vectors, add or subtract the corresponding components. Let →u=⟨u1,u2⟩ and →v=⟨v1,v2⟩ be two vectors. The sum of two or more vectors is called the resultant. The resultant of two vectors can be found using either the parallelogram method or the triangle method .
Light travels 300 000 000 m/s and one year has approximately 32 000 000 second a light year is the distance light travels in one year
Answers
Explanation:
It is given that,
Speed of light, [tex]v=300 000 000\ m/s=3\times 10^8\ m/s[/tex]
Seconds in 1 year, [tex]t=32 000 000=32\times 10^6\ s[/tex]
We need to find the distance traveled by light in one year. Speed of an object is given by :
[tex]v=\dfrac{d}{t}[/tex]
So,
[tex]d=v\times t\\\\d=3\times 10^8\times 32\times 10^6\\\\d=9.6\times 10^{15}\ m[/tex]
Since,
[tex]1\ \text{light year}=9.46\times 10^{15}\ m\\\\1\ m=\dfrac{1}{9.46\times 10^{15}}\ \text{ly}\\\\9.6\times 10^{15}\ m=\dfrac{9.6\times 10^{15}}{9.46\times 10^{15}}\\\\d=1.01\ \text{ly}[/tex]
So, the distance covered by light is 1.01 light years.
identify the motion when a car is moving with constant speed along a curve
Answers
Answer:
Uniform circular motion
Explanation:
When a car is moving with constant speed along a curve, it will said to have uniform circular motion. The speed of the car remains constant in this case. But its velocity keeps on changing. The velocity can be calculated by drawing the tangent on the circle. Hence, the motion of the car is uniform circular motion.
Answer:
Uniform motion
Explanation:
The motion when a car is moving with constant speed along a curve is an example of uniform motion.
A car moving at constant speed covers equal distances in equal intervals of time. The average speed remains the same in uniform motion.
The curve defines the path of the motion and the speed remains constant.
Suppose the position of an object moving in a straight line is given by s (t )equals 5 t cubed minus 2 t squared plus 9. Find the instantaneous velocity when tequals7.
Answers
Answer:
Explanation:
s(t) = 5t³-2t²+9
Instantaneous velocity v = ds / dt
v = ds/dt = 15t²-4t
Putting t = 7
v = 15 x 7² - 4 x 7
= 707
Instantaneous velocity at t = 7
is 707 unit .
Why is hydraulic jack used ? Write.
Answers
Answer:
it is used because
It occupies less spaceheavy loads are easily movedminimum of effort is usedit is a bit lighter than screw jacks.They are also less likely to jam due to rust in the screw thread.
Hydraulic jacks are often used to lift elevators in low and medium rise buildings.
A hydraulic jack uses a liquid that is forced into a cylinder by a pump plunger.
How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 22.0 cmcm in diameter to produce an electric field of 1340 N/CN/C just outside the surface of the sphere?
Answers
Answer:
1.125x10^-10 electrons
Explanation:
Pls see attached file
Which of the following would cause the force of static friction to increase?
Answers
Answer:
Answer B) An increase in [tex]\mu_S[/tex]
Explanation:
Since we are talking about the force of static friction, due to its definition as the product between the normal force to the surface times the coefficient of static friction, the only two ways such force could increase is due to an increase in the normal force, or an increase in the coefficient of static friction [tex]\mu_S[/tex].
So the only valid answer is answer B)
Which of the following statements describes nucleons?
A. Nucleons are the particles that make up a nucleus.
B. Nucleons are the particles in an atom that are neutral.
C. Nucleons are the particles that make up an atom.
D. Nucleons are the particles in an atom that have a charge.
Answers
Answer: nucleons are the particles that make up in nucleus
Explanation:
Nucleons are the particles that make up a nucleus, and they include protons and neutrons.
What are nucleons?Nucleons are particles that make up nucleus of an atom. They include either proton or neutron, or both found in atomic nucleus.
Generally, nucleons are subatomic particles found within nucleus of an atom.
Therefore, we can conclude that, nucleons are the particles that make up a nucleus.
Learn more about nucleons here: https://brainly.com/question/12582292
#SPJ2
Suppose you are testing a new amusement park roller coaster with an empty car with a mass of 100 kg. One part of the track is a vertical loop with a radius of 12.0 m. At the bottom of the loop (point A), the car has a speed of 25.0 m/s and at the top of the loop (point B), it has a speed of 8.00 m/s. As the car rolls from point A to point B, how much work is done by friction? Use 9.81 m/s2 for the acceleration due to gravity.
Answers
Answer:
Explanation:
Gain of kinetic energy + work done by friction = loss of potential energy
= 1 / 2 m ( 25² - 8² ) + work done by friction = m x 9.8 x ( 12 + 12 )
= .5 x 100 x ( 625 - 64 ) + work done by friction = 100 x 9.8 x 24
28050 + work done by friction = 23520
work done by friction = -4530 J
Salt compounds are commonly used to melt ice that forms on sidewalks in the winter. A common chemical that is used to melt sidewalk ice is calcium chloride, CaCl2(s). When calcium chloride dissolves into solution is releases thermal energy which aides in melting
the ice.
The molar mass of water is 18.02 g/mol
The thermal energy, in kilojoules (kJ) that must be released from the calcium chloride,
CaCl2(s), to melt 10.0 kg of ice, expressed in scientific notation is a.bc x 104 k).
46
55
The values of a, b, c, and d.
Answers
Answer:
The values of a, b, c and d are
a = 3, b = 3, c = 4 and d = 3
Explanation:
The quantity of heat needed to melt the ice is given by Q = mL where m = mass of ice and L = latent heat of fusion of ice = 334 kJ/kg. This quanity of heat is also the thermal energy needed to be released by the calcium chloride, CaCl₂
Now, the mass of ice = 10 kg. So,
Q = mL
Q = 10 kg × 334 kJ/kg
Q = 3340 kJ
In scientific notation,
Q = 3.34 × 10³ kJ
So the thermal energy needed to be released by the calcium chloride is 3.34 × 10³ kJ
Comparing Q = 3.34 × 10³ kJ with a.bc × [tex]10^{d}[/tex] kJ
So, a = 3, b = 3, c = 4 and d = 3
The values of a, b, c and d are
a = 3, b = 3, c = 4 and d = 3
How much work is done when 0.0042 C is moved through a potential difference of 12.0 V? Use W = qV A. 0.050 J B. 0.00035 J C. 2900 J D. 12 J
Answers
Answer:
Work done by charge (W) = 0.050 (Approx)
Explanation:
Given:
Charge (q) = 0.0042 C
Potential difference(V) = 12.0 V
Find:
Work done by charge
Computation:
Work done(W) = qV
Work done by charge (W) = (0.0042)(12)
Work done by charge (W) = 0.0504
Work done by charge (W) = 0.050 (Approx)
Answer:
Work done by charge (W) = 0.050 (Approx)
Explanation:
Charge (q) = 0.0042 C
Potential difference(V) = 12.0 V
Find:
Work done by charge
Computation:
Work done(W) = qV
Work done by charge (W) = (0.0042)(12)
Work done by charge (W) = 0.0504
Work done by charge (W) = 0.050 (Approx)
When you urinate, you increase pressure in your bladder to produce the flow. For an elephant, gravity does the work. An elephant urinates at a remarkable rate of 0.0060 m3 (a bit over a gallon and a half) per second. Assume that the urine exits 1.0 m below the bladder and passes through the urethra, which we can model as a tube of diameter 8.0 cm and length 1.2 m. Assume that urine has the same density as water, and that viscosity can be ignored for this flow.
1) What is the speed of the flow? It is 1.2 m/s
2) If we assume that the liquid is at rest in the bladder (a reasonable assumption) and that the pressure where the urine exits is equal to atmospheric pressure, what does Bernoulli's equation give for the pressure in the bladder? (In fact, the pressure is higher than this; other factors are at work. But you can see that no increase in bladder pressure is needed!)
Answers
Answer:
1) v = 1.19 m / s , 2) P₁ = 9.308 10⁴ Pa
Explanation:
In this exercise we will simulate the emission of urine as a fluid mechanics system
1) they indicate the urine flow rate Q = 0.0060 m³ / s, they also give the diameter of the tube 8.0 cm, they ask us the speed.
Let's use the continuity equation
Q = v A
The area of a cycling tube is
A = π r² = π d² / 4
we substitute
Q = v π d² / 4
v = 4Q / π d²
let's calculate
v = 4 0.006 / (π 0.08²)
v = 1.19 m / s
2) they ask to find the pressure in the bladder, for this we use the Bernoulli equation, where the index is for the bladder and the index 2 is for the exit point
P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂
in the exercise it indicates that the outlet pressure is equal to the atmospheric pressure P₂ = 1,013 10⁵ Pa, the velocity of the liquid in the bladder is v₁ = 0 and the height difference 1.0 m
P₁ = P₂ + ½ ρ v₂² + ρ g (y₂-y₁)
let's calculate
P₁ = 1.013₁ 10⁵⁵ + ½ 1000 1.19 + 1000 9.8 (0-1)
P₁ = 1.013 105 + 595 - 9800
P₁ = 9.308 10⁴ Pa