Find the area of the parking space shown to the right

Answer:

Sum of angles of a polygon with one side less = (12-2)x180 = 1800

Sum of angles of a polygon with one side more​ = (14-2)x180 = 2160

Step-by-step explanation:

(n-2)x180 = 1980

n = 13

Sum of angles of a polygon with one side less = (12-2)x180 = 1800

Sum of angles of a polygon with one side more​ = (14-2)x180 = 2160

Step-by-step explanation:

As we can see it is a parallelogram so here the diagonals bisect so

6y + 1 = 4y + 9

6y - 4y = 9 - 1

2y = 8

y = 8 / 2

y = 4

2x - 5 =x + 7

2x + x = 7 + 5

3x = 12

x = 12 / 3

x = 4

Hope it will help :)

Answer:

≈ 18.3 m²

Step-by-step explanation:

The shaded area (A) is calculated as

A = area of sector - area of right triangle

area of sector = area of circle × fraction of circle

A = πr² × [tex]\frac{90}{360}[/tex]

   = π × 8² × [tex]\frac{1}{4}[/tex] = 64π × [tex]\frac{1}{4}[/tex] = 16π m²

area of triangle = [tex]\frac{1}{2}[/tex] × 8 × 8 = 4 × 8 = 32 m²

shaded area is then

A = 16π - 32 ≈ 18.3 m² ( to the nearest tenth )

Given:

The polynomial is

[tex]-x+5x^2+1[/tex]

To find:

The polynomial in the form [tex]ax^2+bx+c[/tex] and find the values of a, b and c.

Solution:

We have,

[tex]-x+5x^2+1[/tex]

Arranging the terms in descending order of their degrees, we get

[tex]=5x^2-x+1[/tex]

[tex]=(5)x^2+(-1)x+1[/tex]

On comparing this polynomial with [tex]ax^2+bx+c[/tex], we get

[tex]a=5,b=-1,c=1[/tex]

Therefore, the value of a is 5, the value of b is -1 and the value of c is 1.

Answer: 34

Step-by-step explanation:

D+F+E = 12+14+8=34

Answer:

17 in

Step-by-step explanation:

DE = 1/2(14) = 7

DF = 1/2(8) = 4

EF =1/2(12) = 6

7 + 4 + 6 = 17 in

Illustrations in reverce order

Explanations:

6. [tex]\displaystyle y = Atan(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{\pi}{\frac{1}{2}} \\ Amplitude \hookrightarrow N/A[/tex]

You can choose to figure the period out by looking at the distanse between each endpoint on the x-axis, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, ALL tangent, secant, cosecant, and cotangent functions have NO amplitudes, so you figure out what you want to put in the blank, but make sure it is not a numerical value. Not even ZERO can be plased there.

_______________________________________________

5. [tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{3}\pi \\ Amplitude \hookrightarrow 4[/tex]

You can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline.

_______________________________________________

4. [tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{2}{1}\pi \\ Amplitude \hookrightarrow 3\frac{1}{2}[/tex]

Again, you can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midine.

_______________________________________________

3. [tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow \frac{1}{2}[/tex]

Again, you can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline.

_______________________________________________

2. [tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{2}{4}\pi \\ Amplitude \hookrightarrow 1[/tex]

Again, you can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline.

_______________________________________________

1. [tex]\displaystyle y = Atan(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{\pi} \hookrightarrow \frac{\pi}{1} \\ Amplitude \hookrightarrow N/A[/tex]

Again, you can choose to figure the period out by looking at the distanse between each endpoint on the x-axis, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period.

I am delighted to assist you at any time.

*I also apologise for the sixth photograph not being present [exercise 1]. The system ALL OF A SUDDEN no longer allows me to display more than five photographs. You will have to see the graph somewhere elce.

Answer:

x=8

Step-by-step explanation:

a=8x-13

b=13x-65

a+b=90

8x-13+13x-65=90

21x=168

x=8

Answer

[tex]\frac{573}{400}[/tex]

step-by-step explanation:

[tex]\frac{1.4325}{1}[/tex] ×  [tex]\frac{10000}{10000}[/tex]  =  [tex]\frac{14325}{10000}[/tex]

Simplify

[tex]\frac{14325}{10000}[/tex] ÷[tex]\frac{25}{25}[/tex] = [tex]\frac{573}{400}[/tex]

Answer:

Rounded it's 46,000

Step-by-step explanation:

Answer: 167

Step-by-step explanation:

Because I just answered it

Answer: 10 km/ hr

Step-by-step explanation:

In the graph below, Diego's speed at various points during his 10 kilometer race is shown on the y axis while the distance is shown on the x axis.

Looking at the 1km mark on the x axis, Diego's speed on the y-axis is at 10km/ hr and this was the speed he started the race with. After the kilometer mark however, his speed changed and went on to increase to 11km/ hr by the second kilometer mark.

9514 1404 393

Answer:

  a) $15,779.70

  b) $13,679.70

  c) $210.92

Step-by-step explanation:

a) When tax is added, the total cost is ...

  total = price × (1 +tax rate)

  total = $14,775 × 1.068 = $15,779.70

__

b) The amount financed is the difference between the total cost and the down payment.

  financed = total - down35

  financed = $15,779.70 -2100 = $13,679.70

__

c) The monthly payment is found using the amortization formula. It can also be found using any of a number of financial calculators, spreadsheets, or apps.

  A = P(r/12)/(1 -(1 +r/12)^-n) . . . . annual rate r, n monthly payments, principal P

  A = $13,679.70(0.035/12)/(1 -(1 +0.035/12)^-72) ≈ $210.92

Answer: See explanation

Step-by-step explanation:

The number of comedy films will be:

= 6/(6+8+1) × 135

= 6/15 × 135

= 54 comedy films

The number of action films will be:

= 8/(6+8+1) × 135

= 8/15 × 135

= 72 action films

The number of horror films will be:

= 1/(6+8+1) × 135

= 1/15 × 135

= 9 horror films

Answer:

84 in^2

Step-by-step explanation:

Answer:

84in^2

Step-by-step explanation:

First we can calculate the rectangle which would be

6*11=66

then we can calculate the triangle

we know that the base is 6, so if we cut it in half we get two triangles which could get put back together in another rectangle so we would just need to do

6*3=18

then add them together

66+18=84

Answer:

The answer should be -5+7= 2

Answer:

2

Step-by-step explanation:

[tex]-5-(-7)\\\\-5+7\\\\\boxed{2}[/tex]

We would distribute the '-' into the '-7' to yield the second step.

Hope this helps.

QTR & TRS

.....................................

Answer:

triangle TQR to triangle TRS

AS angle QRT= angle RTS

QR=TS

and their height are same

hope it helps! :)

Answer: 108 degrees

Step-by-step explanation:

180 - 72 = 108

Answer:

15cmerote

Step-by-step explanation:

Answer:

[tex]V=\frac{45\sqrt{3} }{2}cm^{2}[/tex]

Step-by-step explanation:

Volume= Area*height

height: h=10cm

Area of isosceles triangle:

[tex]A=\frac{9\sqrt{3} }{4} cm^{2}[/tex]

Volume:

[tex]V=\frac{9\sqrt{3} }{4}*10\\\\V=\frac{90\sqrt{3} }{4}\\\\V=\frac{45\sqrt{3} }{2}cm^{2}[/tex]

Answer:

Helen is correct and Don is wrong

Step-by-step explanation:

Halen wrote the prodect 0.4 for the problem .5×.8. Don says that is not correct since when you multiply tenths by tenths the product will be in the hundreths. Is Don right?

.5 × .8 = 0.4

Helen is correct

Don is wrong because the zero(0) at the end of decimals are usually ignored

Such as: 0.10 ; it is usually written as 0.1

Same thing goes for 0.40 which is written as 0.4

Therefore, Helen is correct and Don is wrong

Answer:

X = 1 , 2

Y = -1 , 2

Z = -2 , -1

Answer:

B 21.50 dollars

Step-by-step explanation:

Answer:

this is to hard

Step-by-step explanation:

7, 8 ,9 ,0 10

9514 1404 393

Answer:

  (d)  (-2, 6)

Step-by-step explanation:

We can rewrite the function using vertex form.

  f(x) = (x^2 +4x) +10

  f(x) = (x^2 +4x +4) +10 -4 . . . . . . . add and subtract (4/2)^2

  f(x) = (x +2)^2 +6

Compare to vertex form:

  f(x) = (x -h)^2 +k

we see that (h, k) = (-2, 6) . . . . the vertex

_____

Additional comment

The value added and subtracted is the square of half the x-coefficient. Inside parentheses, that value "completes the square". Outside parentheses, that value ensures the overall function remains unchanged.

Answer:

No

Step-by-step explanation:

7 squared + 10 squared = 149

13 squared = 169

As you can see these two products are not equal. They have to be equal to be a right triangle.

So this triangle is not a right triangle.

Hope that helped you and have a great day!

Answer:

No it is not.

Step-by-step explanation:

Let h = 13, p = 10 and b =7

Using pythagoras theorem,

h² = p² + b²

13² = 10² + 7²

169 = 100 + 49

169 = 149

This is false so the triangle is not a right angled triangle.

Answer:

0.75

Step-by-step explanation:

Answer: i BELIEVE YOUR ANSWER IS

.....  

B

Step-by-step explanation:

Answer:

5x+(-3x+11)=21

2x+11=21

2x=21-11

2x=10 2x/2=10/2

x=5

Answer:

X = 5

Step-by-step explanation:

here's your solution

=> y= -3x + 11.

=> given equation = 5x + y = 21

=> by putting value of Y in given equation

=> 5x -3x + 11 = 21

=> 2x + 11 = 21

=> 2x = 21-10

=> x = 10/2

=> x = 5

hope it helps

Since 4 peaches x 2 =8, you would would only be able to buy 6 mangos since $1.25 x 6 mangos =$7.5 so it would be $7.5+$8=$15.5 and 6 mangos+4 peaches=10 in total. And he would also save $5.00! :)

Please mark brainliest!

Hope it helps!