Find the LCM of 14 and 18 using prime factorizations.

2000-200 = 1800

1800-180 = 1620

1620 - 162 = 1458

1458- 148.8 = 1309

1309 - 130.9 = 1178

1178- 117.8 = 1060.2

1060 - 106 = 954

= 7 years

The value of the car is $956.5938 after 7 years and this can be determined by using arithmetic operations.

Given :

The following steps can be used in order to determine the total number of years will the computer have a value of less than $1,000:

Step 1 - The 10% of $2000 is $200. So, the value of the car after 1 year is $1800.

Step 2 - The 10% of $1800 is $180. So, the value of the car after 2 years is $1620.

Step 3 - The 10% of $1620 is $162. So, the value of the car after 3 years is $1458.

Step 4 - The 10% of $1458 is $145.8. So, the value of the car after 4 years is $1312.2.

Step 5 - The 10% of $1312.2 is $131.22. So, the value of the car after 5 years is $1180.98.

Step 6 - The 10% of $1180.98 is $118.098. So, the value of the car after 6 years is $1062.882.

Step 7 - The 10% of $1062.882 is $106.2882. So, the value of the car after 7 years is $956.5938.

Therefore, the correct option is C).

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Answer:

48%

Step-by-step explanation:

24 is almost 25 which is half of 50 you it would be 48%, hope this helps!:)

Answer: yes !!

Step-by-step explanation:

first we have to simplify

25:5 = 5:1

10:2 = 5:1

yes, they are

When two ratios are in proportion the ratios are said to be equivalent.

The ratios 25:5 and 10:2 are equivalent because they are in proportion.

It is the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity.

We have,

25:5 and 10:2

The ratio must be in proportion to be equivalent.

25:5 = 25/5 = 5 / 1

10:2 = 10/2 = 5/1

25:5 = 10:2

25/5 = 10/2

(5x5) / 5 = (5x2) / 2

5/1 = 5/1

We see that the ratio is equivalent.

Thus,

The ratios 25:5 and 10:2 are equivalent because they are in proportion.

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#SPJ2

Answer:

2.5

Step-by-step explanation:

Answer:

-45

Step-by-step explanation:

I think one way you could do it is:

1. –3(–5) = 15

2. (–1)(3)​ = -3

3. (15) (-3) = -45

I used a calculator pls let me know if im incorrect

Answer:

x≤30

Step-by-step explanation:

he can spend no more than $30 a week

Answer:

7

Step-by-step explanation:

basically just subtract 10-3=7 then to check 3+7=10

Answer:

x = 7

Step-by-step explanation:

3 + x = 10

-3         -3

x = 7

you subtract by 3 on both sides (because the opposite property of addition is subtraction) to cancel it out and isolate the x.

The value of given expression when x=-4 and y=4 is 1250.

The expression is missing in the question which is [tex]\dfrac{x^6-x}{4y}[/tex].

We have to solve it for x= -4 and y = 4.

Now putting the value of x and y we get,

[tex]\dfrac{x^6-x}{4y}=\dfrac{(-4)^6-(-4)}{4}[/tex]

[tex]\dfrac{x^6-x}{4y}=\dfrac{4096+4}{4}[/tex]

[tex]\dfrac{x^6-x}{4y}=1250[/tex]

Hence the value of given expression when x=-4 and y=4 is 1250.

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Answer:your mom

Step-by-step explanation:

[tex]\huge \bf༆ Answer ༄[/tex]

Any value multiplied by Zero gives Zero, therefore ~

Answer:2508

Step-by-step explanation:

Answer:

Divide the no. by three

Step-by-step explanation:

153÷3 = 51

so, 51+51+51 = 153

Answer:

an odd number can be expressed as 2n+1 (2n would be even, add 1 = odd)

first number = 2n+1

second number = 2n+3 -> skip + 2 because it would make it even

third number = 2n+5

2n+1+2n+3+2n+5=153

6n+9=153

6n=144

n=24

24*2+1=48+1=49

24*2+3=48+3=51

24*2+5=48+5=53

the numbers are 49, 51, and 53.

The approximate value of q in the equation is [tex]0.774[/tex]

The equation is given as:

[tex]q\log_2(6) = 2[/tex]

Divide both sides of the equation by [tex]\log_2(6)[/tex].

So, we have:

[tex]q= \frac{2}{\log_2(6) }[/tex]

Determine log(6) base 2

[tex]q= \frac{2}{2.585}[/tex]

Divide 2 by 2.585

[tex]q= 0.774[/tex]

Hence, the approximate value of q in the equation is [tex]0.774[/tex]

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Using the t-distribution, it is found that:

a) Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that significantly more electricity is used at the student center, on average, on weekdays than weekend days.

b) The 95% confidence interval for the difference in mean electricity use at the student center between weekdays and weekend days is (3.56, 33.18).

Item a:

At the null hypothesis, it is tested if there is no difference, that is, the subtraction is at most 0, hence:

[tex]H_0: \mu_1 - \mu_2 \leq 0[/tex]

At the alternative hypothesis, it is tested if there is difference, that is, the subtraction is positive, hence:

[tex]H_1: \mu_1 - \mu_2 > 0[/tex]

The standard errors are given by:

[tex]s_1 = \frac{32.07}{\sqrt{60}} = 4.14[/tex]

[tex]s_2 = \frac{43.29}{\sqrt{30}} = 7.9[/tex]

The distribution of the difference has mean and standard deviation given by:

[tex]\overline{x} = \mu_1 - \mu_2 = 112.63 - 94.26 = 18.37[/tex]

[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{4.14^2 + 7.9^2} = 8.92[/tex]

The standard deviation are given for the samples, hence, the t-distribution is used.

The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{s}[/tex]

In which [tex]\mu = 0[/tex] is the value tested at the hypothesis.

Hence:

[tex]t = \frac{\overline{x} - \mu}{s}[/tex]

[tex]t = \frac{18.37 - 0}{8.92}[/tex]

[tex]t = 2.06[/tex]

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05 and 30 + 60 - 2 = 88 df is [tex]t^{\ast} = 1.66[/tex]

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that significantly more electricity is used at the student center, on average, on weekdays than weekend days.

Item b:

The interval is:

[tex]\overline{x} \pm t^{\ast}s[/tex]

Hence:

[tex]\overline{x} - t^{\ast}s = 18.37 - 1.66(8.92) = 3.56[/tex]

[tex]\overline{x} + t^{\ast}s = 18.37 + 1.66(8.92) = 33.18[/tex]

The 95% confidence interval for the difference in mean electricity use at the student center between weekdays and weekend days is (3.56, 33.18).

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Answer:

5:36

Step-by-step explanation:

12 inches = 1 foot, so 6 feet = 72 inches

10:72, reduces to 5:36

Answer:

84mm

Step-by-step explanation:

square = LxW = 6x6 =36

triangle = bxh/2 = 6x8/2 =24

add together 24x2+36=84

Answer:

30

Step-by-step explanation:

15x30 = 450

Answer:

She purchased 30 shirts.

Step-by-step explanation:

She paid only $400 Dollars, because she got a discount of $50.

So the total before getting the discount was $450.

If you divide $450 by $15 (the price for 1 shirt) you come up with 30.

450/15 = 30

Answer:

The prime factorization of 110 is: 2 x 5 x 11.

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Answer: B Stan has $42 and Cory has $108.

Step-by-step explanation:

The awnser is Stan has $42 and Cory has $108 and $108 + $42 = $150.

                            CAN YOU PLEASE MARK ME BRAINLY.

Answer:

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

96

Step-by-step explanation:

C=πd

C=?

π=3

d=32

C=3×32

Therefore C=96

Answer:

The third option, 1/2..

Answer:

okkkkkkkkkkkkkkkkkkkkkkkkkkk

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Sum of angles of a pentagon is ~ 540°

Therefore,

Value of x = 95°

Answer:

Axis interception points of -52 :

Y intercepts : (0,-52 )

I think its the third one but im not completly sure

Answer:

-t-5>-1.5

Step-by-step explanation:

Just ask.

Hope this helps! :)

Answer:

X=7

Step-by-step explanation:

Answer:

Step-by-step explanation:

Conclusion:

Therefore

Hoped this helped.

[tex]GeniusUser[/tex]

The sum of the square of the constants is 3/4

Given the equation [tex]\frac{1}{a+1} +\frac{1}{b+1} +\frac{1}{c+1} =2[/tex]

The partial form of the equation is given as:

Solve for the constant "a"

[tex]\frac{1}{a +1} = 2\\a+1 = \frac{1}{2} \\a = \frac{1}{2} - 1\\a =-\frac{1}{2}[/tex]

Hence [tex]a=b=c=-\frac{1}{2} \\[/tex]

Taking the square of the constant, we will have:

[tex]a^2 + b^2 + c^2 =(-1/2)^2 +(-1/2)^2+(-1/2)^2\\a^2 + b^2 + c^2 =1/4 + 1/4 + 1/4\\a^2 + b^2 + c^2 =3/4[/tex]

Hence the sum of the square of the constants is 3/4

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Answer -the sum of the square of the consonants is 3/4