Answer:
2x - 2
Step-by-step explanation:
Here is the completer question
lim as Δx → 0 [(x + Δx)²- 2(x + Δx) + 3 - (x² - 2x + 3)]/Δx
Solution
lim as Δx → 0 [(x + Δx)²- 2(x + Δx) + 3 - (x² - 2x + 3)]/Δx
Expanding the brackets, we have
lim as Δx → 0 [(x² + 2xΔx + (Δx)²- 2x - 2Δx + 3 - x² + 2x - 3)]/Δx
Collecting like terms. we have
lim as Δx → 0 [(x² - x² + 2xΔx - 2Δx + (Δx)²- 2x + 2x + 3 - 3)]/Δx
Simplifying, we have
lim as Δx → 0 [(0 + 2xΔx - 2Δx + (Δx)² + 0 + 0)]/Δx
lim as Δx → 0 [2xΔx - 2Δx + (Δx)²]/Δx
Dividing through by Δx, we have
lim as Δx → 0 [2x - 2 + (Δx)]
Inserting Δx = 0, we have
= lim as Δx → 0 (2x -2 + 0)
= 2x -2
So lim as Δx → 0 [(x + Δx)²- 2(x + Δx) + 3 - (x² - 2x + 3)]/Δx = 2x -2
Find the total surface area.
The pyramid consists of 4 congruent triangular faces, and 1 square base.
Area of 1 triangular face:
1/2 * (5 in)/2 * (5.6 in) = 7 in^2
Area of base:
(5 in)^2 = 25 in^2
Then the total surface area is
4 * (7 in^2) + 25 in^2 = (28 + 25) in^2 = 53 in^2
The roof of a cabin is to be shingles at a cost of $70 of a square ( a square, shingling, is a region with an area of 100 sq. ft.) Find the cost of the shingling the roof shown, assuming the roof is symmetrical
Answer:
Just multiply 2 by (36*15) which equals 1080
Than divide 1080 by 100
1080/100
Which would give us 10.8 10.8 * 70 = $756.00
So, the answer is $756.00
Step-by-step explanation:
What is the length of the line?
Answer:
[tex]\boxed{\sf B. \ \sqrt{61} }[/tex]
Step-by-step explanation:
The line can be made into a hypotenuse of a right triangle.
Find the length of the base and the height of the right triangle.
The base (leg) is 6 units.
The height (leg) is 5 units.
Apply Pythagorean theorem.
[tex]\sf c=\sqrt{a^2 +b^2 }[/tex]
[tex]\sf c=\sqrt{6^2 +5^2 }[/tex]
[tex]\sf c=\sqrt{36+25 }[/tex]
[tex]c=\sqrt{61}[/tex]
Answer:
[tex] \sqrt{61} [/tex]Option B is the correct option
Step-by-step explanation:
Assuming center of co-ordinate axes at lower left corner at the line. So end points are:
( x1 , y1 ) = ( 0 , 0 ) and ( x2 , y2 ) = ( 6 , 5 )
Distance between two points is given by formula:
D [tex] = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } [/tex]
[tex] = \sqrt{ {6 - 0)}^{2} + {(5 - 0)}^{2} } [/tex]
[tex] = \sqrt{ {6}^{2} + {5}^{2} } [/tex]
[tex] = \sqrt{36 + 25} [/tex]
[tex] = \sqrt{61} [/tex]
Hope this helps..
Best regards!!
Simplify [tex]$\frac{2\sqrt[3]9}{1 + \sqrt[3]3 + \sqrt[3]9}.$[/tex] $\frac{2\sqrt[3]9}{1 + \sqrt[3]3 + \sqrt[3]9}.$
Answer:
[tex]3 -\sqrt[2]3[/tex]
Step-by-step explanation:
Given
[tex]\frac{2\sqrt[3]{9}}{1 + \sqrt[3]{3} + \sqrt[3]{9}}[/tex]
Required
Simplify
Rewrite the given expression in index form
[tex]\frac{2 * 9 ^\frac{1}{3}}{1 + 3^{\frac{1}{3}} + 9^{\frac{1}{3}}}[/tex]
Express 9 as 3²
[tex]\frac{2 * 3^2^*^\frac{1}{3}}{1 + 3^{\frac{1}{3}} + 3^2^*^{\frac{1}{3}}}[/tex]
[tex]\frac{2 * 3^\frac{2}{3}}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}}}[/tex]
Multiply the numerator and denominator by [tex]1 - 3^{\frac{1}{3}}[/tex]
[tex]\frac{2 * 3^\frac{2}{3}}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}}} * \frac{1 - 3^{\frac{1}{3}}}{1 - 3^{\frac{1}{3}}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) (1 - 3^{\frac{1}{3}})}{(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})(1 - 3^{\frac{1}{3}})}[/tex]
Open the bracket
[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{2}{3})(3^{\frac{1}{3}})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
Simplify the Numerator using Laws of Indices
[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{2+1}{3})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
Further Simplify
[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{3}{3})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3^1)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]
Simplify the denominator
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - (3^{\frac{1}{3}})(3^{\frac{1}{3}}) - (3^{\frac{1}{3}})(3^{\frac{2}{3}})}[/tex]
Further Simplify Using Laws of Indices
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - (3^{\frac{1+1}{3}}) - (3^{\frac{1+2}{3}})}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3^{\frac{3}{3}}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3^1}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3}}[/tex]
Collect Like Terms
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 - 3+ 3^{\frac{1}{3}} - 3^{\frac{1}{3}}+ 3^{\frac{2}{3}} - 3^{\frac{2}{3}} }}[/tex]
Group Like Terms for Clarity
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{(1 - 3) + (3^{\frac{1}{3}} - 3^{\frac{1}{3}}) + (3^{\frac{2}{3}} - 3^{\frac{2}{3}} )}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{(- 2)+ (0) + (0)}}[/tex]
[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{-2}}[/tex]
Divide the fraction
[tex]-(3^\frac{2}{3}) + (3)[/tex]
Reorder the above expression
[tex]3 -3^\frac{2}{3}[/tex]
The expression can be represented as
[tex]3 -\sqrt[2]3[/tex]
Hence;
[tex]\frac{2\sqrt[3]{9}}{1 + \sqrt[3]{3} + \sqrt[3]{9}}[/tex] when simplified is equivalent to [tex]3 -\sqrt[2]3[/tex]
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions.
Answer:
4x-2
Step-by-step explanation:
4x(3x+5)-2(3x+5)
(4x-2)(3x+5)
you can see that 4x-2 is a factor
50. At a booth at the school carnival in past years, they've found that 32% of students win a stuffed toy ($3.25), 10% of students win a jumprope ($1.70), and 8% of students win a t-shirt ($7.80). The remaining students do not win a prize. If 200 students play the game at the booth, how much money should the carnival committee expect to pay for prizes for that booth
Answer:
The expected amount to be paid by the carnival committee for prices would be $366.80
Step-by-step explanation:
Hello!
Here, we want to calculate the amount of money the carnival committee is expected to pay for the prizes for that booth
From the question, we have 3 categories of prices to be won
To calculate for people that won’t win anything , we simply subtract the percentages of all from 100
That would be 100-32-10-8 = 100-50 = 50%
So now let’s calculate the number of people out of 200 that will win each category based on the percentages
For stuffed toy
32/100 * 200 = 64
Jump rope
10/100 * 200 = 20
For t-shirt
8/100 * 200 = 16
So total price paid for stuffed toy= 3.25 * 64 = $208
For jump rope, we have 1.7 * 20 = $34
For t-shirt , we hav 16 * 7.8 = $124.8
So the total value spent on prices by the committee would be;
124.8 + 34 + 208 = $366.80
find the value of x. 43°
Answer: x = 137°
Step-by-step explanation:
When a quadrilateral is inscribed in a circle, the opposite angles are supplementary.
x + 43° = 180°
x = 137°
The value of x is 137°.
What is inscribed quadrilateral?The quadrilateral whose all 4 vertices lie on the circumference of the circle is called an inscribed quadrilateral.
In inscribed quadrilateral opposite angles are supplementary i.e. sum of those opposite angles is 180°.
Here given in the picture that the measurements of the two opposite angles in the inscribed quadrilateral in the circle are 43° and x°.
So as we know in the inscribed quadrilateral opposite angles are supplementary.
So sum of those opposite angles in the quadrilateral is 180°.
so we can write x+43°= 180°
⇒ x = 180°- 43°
⇒ x = 137°
Therefore the value of x is 137°.
Learn more about inscribed quadrilateral
here: https://brainly.com/question/26690979
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a box of tickets has an average of 100, and an SD of 20. Four hundred draws will be made at random with replacement from this box. a) Estimate the chance that the average of the draws will be in the range 80 to 120. b) estimate the chance that the average of the draws will be in the range 99 to 101
Answer:
(a) The probability that the average of the draws will be in the range 80 to 120 is 1.
(b) The probability that the average of the draws will be in the range 99 to 101 is 0.6827.
Step-by-step explanation:
According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.
Then, the mean of the sample means is given by,
[tex]\mu_{\bar x}=\mu[/tex]
And the standard deviation of the sample means is given by,
[tex]\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}[/tex]
As the sample selected is quite large, i.e. n = 400 > 30, then the sampling distribution of sample means will be approximately normally distributed.
Compute the mean and standard deviation of sample mean as follows:
[tex]\mu_{\bar x}=\mu=100\\\\\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{20}{\sqrt{400}}=1[/tex]
So, [tex]\bar X\sim N(100, 1)[/tex]
(a)
Compute the probability that the average of the draws will be in the range 80 to 120 as follows:
[tex]P(80<\bar X<120)=P(\frac{80-100}{1}<\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}<\frac{120-100}{1})[/tex]
[tex]=P(-20<Z<20)\\\\=P(Z<20)-P(Z<-20)\\\\=(\approx1)-(\approx0)\\\\=1[/tex]
Thus, the probability that the average of the draws will be in the range 80 to 120 is 1.
(b)
Compute the probability that the average of the draws will be in the range 99 to 101 as follows:
[tex]P(99<\bar X<101)=P(\frac{99-100}{1}<\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}<\frac{101-100}{1})[/tex]
[tex]=P(-1<Z<1)\\\\=P(Z<1)-P(Z<-1)\\\\=0.6827[/tex]
Thus, the probability that the average of the draws will be in the range 99 to 101 is 0.6827.
The volume of the Sun is about 1.41 x 10^18 cubic kilometers. The volume of Earth is about 1.09 x 10^12 cubic kilometers. The number of Earths that can fit inside the Sun can be found by dividing the Sun's volume by Earth's volume. Find this quotient and express the answer in scientific notation.
Answer:
1290000
Step-by-step explanation: Given that
The volume of the Sun is about = 1.41 x 10^18 cubic kilometers.
The volume of Earth is about 1.09 x 10^12 cubic kilometers.
The number of Earths that can fit inside the Sun can be found by dividing the Sun's volume by Earth's volume.
= Volume of Sun ÷ Volume of the Earth
= 1.41 x 10^18 cubic km/1.09 x 10^12 cubic km
= 1.41 x 10^18/1.09 x 10^12
=(1.42/1.09)× 10^18-12
= 1.29×10^6
n is 1.29×10^6.
Hence the number of Earth that can be fitted in the Sun is 1290000
Find all values of x, giving your answer to 3 significant figures where necessary, for 0 is equal or smaller than x and 2 pi is equal or larger than x.
a) 3 sin x + 2tan x = 0
Triangle ABC is rotated about the origin by 270° to form the triangle A′B′C′, then translated upward 10 units to form triangle A″B″C″. Which of the following statements is true for ΔABC and ΔA″B″C″? A)There isn't enough information to identify whether ΔABC and ΔA″B″C″ are congruent or similar. B)ΔABC and ΔA″B″C″ are neither similar nor congruent. C)ΔABC and ΔA″B″C″ are similar triangles. D)ΔABC and ΔA″B″C″ are congruent triangles.
Answer:
The correct answer is option:
D) ΔABC and ΔA″B″C″ are congruent triangles.
Step-by-step explanation:
Given
ΔABC is first rotated about the origin by 270° to form the triangle A′B′C′.[tex]\triangle A'B'C'[/tex] is then translated upwards 10 units to form [tex]\triangle A''B''C''[/tex]To find: The true statement among the given options.
Solution:
Let the triangle be situated in 1st quadrant.
It is rotated about the origin by [tex]270^\circ[/tex].
Now, it moves towards quadrant 2 if it is rotated clockwise. It is termed as
[tex]\triangle A'B'C'[/tex].
It is given that now it is translated 10 units upwards. i.e. 10 units added to x coordinate of each vertex to form [tex]\triangle A''B''C''[/tex].
Now, we can see that there is no change in the dimensions of the triangle. We are just changing the location of the triangle.
So, all its angles will be equal to each other and all the sides will be equal to each other.
i.e.
[tex]\angle A = \angle A''\\\angle B = \angle B''\\\angle C = \angle C''\\Side\ AB = Side\ A''B''\\Side\ BC = Side\ B''C''\\Side\ AC = Side\ A''C''[/tex]
Hence, the correct option is:
D)ΔABC and ΔA″B″C″ are congruent triangles.
Answer:A-B
Step-by-step explanation:
Express 429 as a product of its prime factors
Answer:
The answer is 429 = 3×11×13.
Step-by-step explanation:
You have to divide by prime number :
429 ÷ 3 = 143
143 ÷ 11 = 13
13 ÷ 13 = 1
Answer:
3×11×13
Step-by-step explanation:
Start dividing by prime numbers. Since the number is even two won't work so next is three. If you divide 429 by 3 you get 143. You continue doing this with primes going up (5, 7, 11, 13, etc.) until you get to the final prime. 5 and 7 don't work if you try dividing them by 143 individually so next up is 11. If you divide 11 by 143 you get 13 which is also a prime number. Therefore, 3×11×13 is a product of prime factors.Help me plz? Plllzzzz?
3) The Buendorf family has agreed to let their children get some animals. The kids said they
want chickens and goats, so the parents told them the number of chickens could be four
times that of the number of goats. They are allowed to have no more than 30 total animals.
What are the possible number of chickens and goats?
Answer:
The possible number of goats is 6 and the possible number of chicken is 24
Step-by-step explanation:
Let
chicken=c
Goat=g
the number of chickens could be four times the number of goats
c=4g
Total number of animals=30
c+g=30
Recall, c=4g
So,
c+g=30
4g+g=30
5g=30
Divide both sides by 5
5g/5=30/5
g=6
Recall,
c+g=30
c+6=30
c=30-6
=24
c=24
The possible number of goats is 6 and the possible number of chicken is 24 making a total of 30 animals
Find the vertical asymptote of f(x)=2x^2+3x+6/x^2-1 I'm having trouble with this one, seems simple tho I just don't want to make a stupid mistake,,, And here are the choices:
Answer:
x = - 1, x = 1
Step-by-step explanation:
Given
f(x) = [tex]\frac{2x^2+3x+6}{x^2-1}[/tex]
The denominator cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.
x² - 1 = 0 ← difference of squares
(x - 1)(x + 1) = 0
x - 1 = 0 ⇒ x = 1
x + 1 = 0 ⇒ x = - 1
x = - 1 and x = 1 are vertical asymptotes
The incorrect work of a student to solve an equation 2(y + 4) = 4y is shown below: Step 1: 2(y + 4) = 4y Step 2: 2y + 6 = 4y Step 3: 2y = 6 Step 4: y = 3 Which of the following explains how to correct Step 2 and shows the correct value of y? The equation should be y + 4 = 4y after division by 2; y = 5 The equation should be y + 4 = 4y after division by 2; y = 2 2 should be distributed as 2y + 8; y = 4 2 should be distributed as 2y + 8; y = 2
Answer:
2 should be distributed as 2y + 8; y = 4
Step-by-step explanation:
Step 2 is wrong.
2(y + 4) = 4y
The step to solve is to expand brackets or distribute 2, not divide both sides by 2.
2y + 8 = 4y
Subtract both sides by 2y.
8 = 2y
Divide both sides by 2.
4 = y
Find the perimeter of the shaded figure. Please help,thanks!
Answer:
I believe its 40
Step-by-step explanation:
Answer:
Hey there!
The perimeter can be expressed as 10+7+2+2+6+2+2+7, or 38.
Hope this helps :)
Ans ASAP.. In pic with steps.. Plz tysm 1rst one BRAINLIEST
Answer:
The expression for the shaded region is 10x² + 12x .
Step-by-step explanation:
First, you have to find the area of both rectangles using the formula :
[tex]area = length \times height[/tex]
Small rectangle,
[tex]area = x \times (5x - 2)[/tex]
[tex]area = 5 {x}^{2} - 2x[/tex]
Large rectangle,
[tex]area = (3x + 2) \times 5x[/tex]
[tex]area = 15 {x}^{2} + 10x[/tex]
In order to find the shaded region, you have to subtract the smaller from the larger one :
[tex]area \: of \: shaded = large - small[/tex]
[tex]area = 15 {x}^{2} + 10x - 5 {x}^{2} + 2x [/tex]
[tex]area = 10 {x}^{2} + 12x[/tex]
What is the 4th tearm to this?
b(n)=4−6(n−1)
Answer:
If you wish to find any term (also known as the {n^{th}}n
th
term) in the arithmetic sequence, the arithmetic sequence formula should help you to do so. The critical step is to be able to identify or extract known values from the problem that will eventually be substituted into the formula itself.
Step-by-step explanation:
find the value of x in the triangle shown below
Answer:
46°
Step-by-step explanation:
We can tell that this triangle is an isosceles triangle because 2 of it's sides are the same, therefore, two of it's angles are the same.
Looking at it, we can assume that the two angles not defined (x and the other one) are the two angles that are the same because they look similar.
Now, the angles of all triangles add up to 180°. So, we can subtract 88° from 180 to see what the two angles add up to.
[tex]180-88=92[/tex]
So both of these angles add up to 92 degrees. Since there are two, we divide 92 by 2.
[tex]92 \div 2 = 46[/tex]
Hope this helped!
Eight people are going for a ride in a boat that seats eight people. One person will drive, and only three of the remaining people are willing to ride in the two bow seats. How many seating arrangements are possible?
Answer:
720 seating arrangments
Step-by-step explanation:
There are eight people but driver is always the same so we only have to deal with combinations of the other 7 seats.
the combination of the five seats has 5! times 2 combinations for each of the 3 passengers willing to ride in the two boat seats thus the total number of different seating arrangements is 5! times 3! or 720
hope this helps :)
Using the Fundamental Counting Theorem, it is found that there are 5760 possible seating arrangements.
What is the Fundamental Counting Theorem?It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:
[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]
In this problem:
For the driver, there are 8 outcomes, hence [tex]n_1 = 8[/tex].For the bow seats, there are [tex]n_2 = 3 \times 2 = 6[/tex] outcomes.For the other 5 seats, there are [tex]n_3 = 5![/tex] possible outcomes.Hence:
[tex]N = 8 \times 6 \times 5! = 5760[/tex]
There are 5760 possible seating arrangements.
More can be learned about the Fundamental Counting Theorem at https://brainly.com/question/24314866
Find m
A. 82
B. 32
C. 98
D. 107
Answer: A. 82
Step-by-step explanation:
The measure of <BAD can be found by simply adding 25(<BAC)+57(<CAD) = 82.
[tex]\mathrm{BAD}=\mathrm{BAC}+\mathrm{CAD}=25^{\circ}+57^{\circ}=82^{\circ}[/tex].
Hope this helps.
Write each of the following expressions without using absolute value. |z−6|−|z−5|, if z<5
Answer: 6 - 5
Step-by-step explanation:
|z - 6| - |z - 5| ; z < 5
Since z < 5, then
|z - 6| will be the absolute value of a negative number. Replace the absolute value with a negative and parentheses:
-(z - 6) = -z + 6
|z - 5| will be the absolute value of a negative number. Replace the absolute value with a negative and parentheses:
-(z - 5) = -z + 5
Now subtract them without the absolute value signs:
-z + 6 - (-z + 5)
Distribute the negative sign:
-z + 6 + z - 5
-z + z = 0 which leaves:
6 - 5
Answer: 1
Step-by-step explanation: first you need to pretend that the absolute value bars are parentheses. Then substitute a with any number less that five, for example z=3
Now we can write our new equation: (3-6)-(3-5)
now we have to determine if the final answer inside the parentheses is positive or negative. In the first parentheses 3-6=-3 with is negative. In our second parentheses we have 3-5=-2 which is a also negative.
Knowing that both parentheses are negative results we can set up an equation using z instead of 3:
-(z-6)-(-(z-5)) is our new equation. If we simplify this equation we get 1 for an answer
Which could be used to solve this equation?
3 and one-fifth + n = 9
Subtract 3 and one-fifth from both sides of the equation.
3 and one-fifth minus 3 and one-fifth + n = 9 + 3 and one-fifth
Add 3 and one-fifth to both sides of the equation.
9 + 3 and one-fifth = 12 and one-fifth
Answer:
Subtract 3 and one-fifth from both sides of the equation
Step-by-step explanation:
Well to find n you gotta separate it.
3 1/5 + n = 9
-3 1/5
n = 5.8
Thus,
to seperate it you subtract 3 1/5 from both sides.
Answer:
Subtract 3 and one-fifth from both sides of the equation
Step-by-step explanation:
first correct answer gets best marks
Answer:
option three!!!!!
Step-by-step explanation:
its closed circle
on 6
and pointing left
Just need to know the elements of (A n B)
Answer:
{ 1,2}
Step-by-step explanation:
The ∩ means intersection, or what is in common for the two sets
The intersection of A and B is what is in the overlapping circles
The intersection of A and B is { 1,2}
Help please!! Thank you
Answer:
25 ( A)
pls mark me as BRAINLIEST
stay at home stay safe
and keep rocking
Answer:
A
Step-by-step explanation:
The first ten primes are
2,3,5,7,11,13,17,19,23,27
so the number is
2*3*5*7*11*13*17*23*27
so
2*11 is 22, so 22 divides the number
2*3 is 6, so 6 divides the number
2 is there so 2 divides the number
So the only one is 25.
If the area of the trapezoid below is 75 square units, what is the value of x? AB=17 DC=8
A. 1.5
B. 12
C. 6
D. 3
Diagram related to the question can be found in the attached picture below :
Answer: 6 units
Step-by-step explanation:
From the diagram attached to the question:
Length AB = 17
Length DC = 8
height (h) = x
Area of trapezium = 75sq units
The Area (A) of a trapezium is given by:
(1/2) × (a + b) × h
Where ;
a and b are the upper and base lengths of the trapezium
h = height of trapezium
A = (1/2) × (a + b) × h
75 = (1/2) * (17 + 8) * x
75 = 0.5*25*x
75 = 12.5x
x = 75 / 12.5
x = 6 units
calculate EG if a=5 and b=15
Point K is rotated 90°. The coordinate of the pre-image point K was (2, –6) and its image K’ is at the coordinate (−6, −2). Find the direction of the rotation. The direction of rotation was .
Answer:
Hello! The answer to your question will be below.
Step-by-step explanation:
The answer would be clockwise.
So point k was rotated 90 degrees clockwise.....
Review.....
Question:
Point K is rotated 90 degrees. The coordinate of the pre-image point K was (2,-6) and it’s image K’ is at the coordinate (-6,-2).Find the direction of the rotation.
THE DIRECTION OF THE ROTATION WAS CLOCKWISE.
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Answer:
clockwise.
So point k was rotated 90 degrees clockwise.....
Review.....
Question:
Point K is rotated 90 degrees. The coordinate of the pre-image point K was (2,-6) and it’s image K’ is at the coordinate (-6,-2).Find the direction of the rotation.
Step-by-step explanation: