Find the measure of <0

You find the intersection point of the two lines, which is (3, -2).

It is what the question meant when it asked for "solution".

These two lines are y = mx + c, which is another form of linear equations with two variables you are likely familiar with

x+y=20

x-y=10

Hope this clears up your confusion.

Answer:

10

Step-by-step explanation:

20 divided by 4 = 5 and times it from there

Answer:

-1

Step-by-step explanation:

-5x – 15 > 10 + 20x

-5x -20x > 10+15

-25x > 25

x < -1

Answer:

x=130 I believe

Step-by-step explanation:

28+8+14+x=180

50+x=180

x=130

Answer: the slope is 3/4.

y=mx+b and m is always the slope.

Answer:

the slope is 3/4

Step-by-step explanation:

y = mx + b

y = slopex + y intercept

y = 3/4x - 1

slope = 3/4

y intercept = -1

Answer:

75 !!

Step-by-step explanation:

you would add <2 and <3 (105), then subtract that from 180... since the highlighted spot (look at image) is congruent to 5 !! (because its alternate interior !!)

i hope this helped and made sense !

Answer:

i did dude.may God bless you.sorry.l

Answer: 875

Step-by-step explanation:

You can set up proportions so it’s like: 1/350=2.5/x and then solve for x

Answer:

to this question is it is 1.01

Answer:

You have to fine the number that matches with the "X" so the answer would be 126 divided by 43 which is 2.9. 2.9 is closer to 3 than 2 so the "x" is 3

Step-by-step explanation:

Answer:

30% increase or decrease

Step-by-step explanation:

Because every mile is 3% and according to the question it is reduced 90 miles

Answer:

we all need help sometimes

Step-by-step explanation:

Answer:

i cant see it

Step-by-step explanation:

Answer:

2.6315789473

Step-by-step explanation:

Hope this helps!

Answer:

26wb trial corp Cisco soap

Answer:

See answers below

Step-by-step explanation:

Using the coordinates from the table (0, 12) and (1, 14)

m = 14-12/1-0

m = 2/0

m = 2

Hence the slope of the table is 2

y intercept occurs at x = 0

Substitute m = 2 and (0,12) into the equation y = mx+c

12 = 2(0) + b

12 = b

b = 12

Hence the y-intercept is 12

Get the equation

Recall that y = mx+c

y = 2x + 12

Hence the required equation is y = 2x+12

ill give you 50 pints for a brainliest

Answer:

Its good and yours? ill try to answer ur question i might not know lol

Step-by-step explanation:

Answer:

hello

Step-by-step explanation:

Answer:{ x,y } = { - 2, - 3 }

Step-by-step explanation: 4x = 2y - 2                                                                      

x = y/2 - 1/2                  

3. (y   /2 -  1/2 ) + 2y  =  - 12  

7y/2 =  - 21/2  

7y =   -  21    

x =   y/2 - 1/2  

   y =  - 3    

x = (/2) ( - 3 ) - 1/2 = - 2

The area of the circle will be 3.14 feet .

Find the area of a circle with a diameter of 2 feet. Use 3.14 for π.

★Given,

→ Diameter = 2 feet

→ Circumference = 2/2 = 1 feet

★Now,

→Area of a circle = πr²

→ = 3.14 × 1 × 1

→ = 3.14 feet

Hence , the circumference is 3.14 feet.

Answer:

62?

Step-by-step explanation:

I just subtracted 76 and 14, I don't know if i'm right

Answer:

HA , LJ , and IK contain the center of dilation. Line segments that contain the center of dilation in the preimage also contain the center of dilation in the image. GF , HI , and KL do not contain the center of dilation. Line segments that do not contain the center of dilation in the pre image are mapped onto distinct lines parallel to the original, corresponding line segment. HL does not contain the center of dilation either but it does lie on a line that passes through the center of dilation. Line segments that lie on lines passing through the center of dilation in the preimage lie on the same lines in the image.

Step-by-step explanation:

Plato’s Answer

Answer:

Step-by-step explanation:

HA , LJ , and IK contain the center of dilation. Line segments that contain the center of dilation in the preimage also contain the center of dilation in the image. GF , HI , and KL do not contain the center of dilation. Line segments that do not contain the center of dilation in the pre image are mapped onto distinct lines parallel to the original, corresponding line segment. HL does not contain the center of dilation either but it does lie on a line that passes through the center of dilation. Line segments that lie on lines passing through the center of dilation in the preimage lie on the same lines in the image.

Answer: = cos 4x

[tex]\frac{tan2x}{tan4x-tan2x}\\\\=\frac{tan2x}{\frac{2tan2x}{1-tan^{2}2x }-tan2x }\\\\=\frac{tan2x(1-tan^{2}2x) }{2tan2x-tan2x(1-tan^{2}2x) }\\\\=\frac{tan2x(1-tan^{2}2x) }{tan2x(2-1+tan^{2}2x) }\\\\=\frac{1-tan^{2}2x }{1+tan^{2}2x } \\\\=\frac{1-\frac{sin^{2}2x }{cos^{2}2x } }{1+\frac{sin^{2}2x }{cos^{2}2x } }\\\\=\frac{cos^{2}2x-sin^{2}2x }{cos^{2}2x+sin^{2}2x } \\\\=\frac{cos4x}{1}\\\\=cos4x[/tex]

Step-by-step explanation:

Answer: The solution is (3, -2)

This means that x = 3 and y = -2 pair up together.

=====================================================

Explanation:

The solution is where the two lines cross. Note if we started at the origin (0,0) and moved to the right 3 units, and then down 2 units, we would arrive at the location (3, -2).

-----------------

As a way to check, we can plug x = 3 into each equation. We should get y = -2 as a result for each equation

y = (-5/3)x + 3

y = (-5/3)*3 + 3

y = -5+3

y = -2

The first equation is confirmed. Let's check the second equation

y = (1/3)x - 3

y = (1/3)*3 - 3

y = 1 - 3

y = -2

Both equations have the y value equal -2 when x = 3. Therefore, the overall solution is confirmed.

Answer: $13.11

Step-by-step explanation:

hope this helps!

Incomplete question: Options

(a) Each triangular part and each rectangular part represents 1/2 the area of one square.

(b) Each triangular part has an area that is greater than the area of each rectangular part.

(c) Each triangular part and each rectangular part represents 1/4 the area of one square

(d) Each rectangular part has an area that is greater than the area of each triangular part.

See attachment for squares

Answer:

(a) Each triangular part and each rectangular part represents 1/2 the area of one square.

Step-by-step explanation:

Given

See attachment

Required

Which statement is true

Before the division, the area of both squares is:

[tex]Area = l * w[/tex]

After the division:

The area of the triangle is:

[tex]Area = \frac{1}{2} * base * height[/tex]

[tex]A_1 = \frac{1}{2} * l * w[/tex]

Substitute Area for l * w

[tex]A_1 = \frac{1}{2} *Area[/tex]

This equals half the area of the square

The area of the rectangle is:

[tex]Area = length * width[/tex]

The length of the rectangle is now half the length of the original square.

So, we have:

[tex]A_2 = \frac{1}{2} l * w[/tex]

Substitute Area for l * w

[tex]A_2 = \frac{1}{2} *Area[/tex]

From the values of A1 and A2, we can conclude that (a) is true

Answer:

12.8

Step-by-step explanation: