Find the slope of the line passing through the points D(10, 8) and E(-4, 4).

Answer:

4107 cells

Step-by-step explanation:

From the question, we have the following values:

Day 1 : 113 cells

Number of cells increases by day by 82%

Hence,

Day 2

113 × 82% = 92.66cells

Hence, Total number of bacteria cells for Day 2 = 113 + 92.66 = 205.66cells

Day 3

205.66 × 82% = 168.6412 cells

Hence, Total number of bacteria cells for Day 3 = 168.6412 + 205.66 = 374.3012 cells

Day 4

374.3012 × 82% = 306.926984 cells

Hence, Total number of bacteria cells for Day 4 = 306.926984 + 374.3012 = 681.228184 cells

Day 5

681.228184 × 82% = 558.60711088 cells

Hence, Total number of bacteria cells for Day 5 = 558.60711088 + 681.228184 = 1239.8352949 cells

Day 6

1239.8352949 × 82% = 1016.6649418 cells

Hence, Total number of bacteria cells for Day 5 = 1016.6649418 + 1239.8352949 = 2256.5002367 cells

Day 7

2256.5002367 × 82% = 1850.3301941 cells

Hence, Total number of bacteria cells for Day 7 = 1850.3301941 + 2256.5002367 = 4106.8304308 cells

Approximately to nearest whole number, the total number of bacteria cells that would be present after 7 days = 4107 cells

Answer:

C.  6√5

Step-by-step explanation:

√20 +√80= √4*5 + √16*5 = 2√5 + 4√5 = 6√5

Answer:

second option

Step-by-step explanation:

Answer:

poop

Step-by-step explanation:

Using the standard calculation, the expected value is 46/11.

Answer:

A, B, E

Step-by-step explanation:

I attached everything that I thought it would help you.

Hope this helps ;) ❤❤❤

Answer:

A) a=25

B) b=14

Step-by-step explanation:

A) a/5+3=8

First you need to subtract 3 from both sides.

(a/5+3)-3=(8)-3

Then simplify

a/5=5

Multiply both sides by 5

(a/5)*5=(5)*5

Then simplify

a= 25

B )3b/7-1=5

First you need to add 1 to both sides

(3b/7-1)+1=(5)+1

Simplify

3b/7=6

Multiply both sides by 7

(3b/7)*7=(6)*7

Simplify

3b=42

Divide both sides by 3

(3b)/3=(42/3)/3

Simplify

b= 14

(Brainliest???) :P

Answer: it is =4176000000000000

Step-by-step explanation:

(2.9)(100000)(7.2)(10^2)

5(10^−8)

=

(290000)(7.2)(10^2)

5(10^−8)

=

2088000(10^2)

5(10^−8)

=

(2088000)(100)

5(10^−8)

=

208800000

5(10^−8)

=

208800000

5(1/100000000)=

208800000/1

20000000

=4176000000000000

hope i helped

-lvr

Answer:

15%

Step-by-step explanation:

Question:

The price of a jacket was slashed from Rs.960 to Rs.816.Then the rate of discount offered is​

Solution

Original price= Rs.960

Discount price= Rs.816

Difference in price=Original price - discount price

=Rs. 960 - Rs. 816

=Rs. 144

Percentage discount= Difference in price / Original price × 100

=Rs. 144 / Rs. 960 × 100

=0.15 × 100

=15%

The percentage discount =15% NOT 10% as you have written

Answer:

6

Step-by-step explanation:

From the table given defining a function, the values of "x" on the table represents the input of the function, which gives us an output, f(x), which can be labelled as "y" in some instances.

Thus, the value of f(0), is simply the output value we would get, given an input value of "0".

So therefore, f(0) = 6. That is, at x = 0, f(x) = 6.

Answer: 6

Step-by-step explanation:

Answer:

The coordinates are;

For reflection over the x-axis

A'(-8, 2)

B'(-4, 3)

C'(-2, 8)

D'(-10, 6)

For reflection over the y-axis;

A''(8, 2)

B''(4, 3)

C''(2, 8)

D''(10, 6)

Step-by-step explanation:

When a point (x, y) is reflected over the x, axis, we have;

Coordinates of the pre-image = (x, y)

Coordinates of the image after reflection = (x, -y)

Therefore, for the points A, B, C, D we have;

Pre-image A(-8, -2), Image A'(-8, 2)

Pre-image B(-4, -3), Image B'(-4, 3)

Pre-image C(-2, -8), Image C'(-2, 8)

Pre-image D(-10, -6), Image D'(-10, 6)

When a point (x, y) is reflected over the y, axis, we have;

Coordinates of the pre-image = (x, y)

Coordinates of the image after reflection = (-x, y)

Therefore, for the points A', B', C', D' we have;

Pre-image A'(-8, 2), Image A''(8, 2)

Pre-image B'(-4, 3), Image B''(4, 3)

Pre-image C'(-2, 8), Image C''(2, 8)

Pre-image D'(-10, 6), Image D''(10, 6).

Answer:

[tex]p=- \frac{15}{2}[/tex]

[tex]p=2[/tex]

Step-by-step explanation:

[tex]2p^2+11p=30[/tex]

Subtract 30 on both sides.

[tex]2p^2+11p-30=30-30[/tex]

[tex]2p^2+11p-30=0[/tex]

Factor left side of the equation.

[tex](2p + 15)(p-2)=0[/tex]

Set factors equal to 0.

[tex]2p+15=0[/tex]

[tex]2p=-15[/tex]

[tex]p=\frac{-15}{2}[/tex]

[tex]p-2=0[/tex]

[tex]p=2[/tex]

Answer:

The area of △ABC is equal to the area of △DEF

Step-by-step explanation:

On a coordinate plane, triangles A B C and D E F are shown. Triangle A B C has points (4, 2), (7, 2), (4, 6). Triangle D E F has points (negative 2, negative 1), (4, negative 3), and (4, negative 1).

How do the areas of triangle ABC and DEF compare? The area of △ABC is 1 square unit less than the area of △DEF. The area of △ABC is equal to the area of △DEF. The area of △ABC is 1 square unit greater than the area of △DEF. The area of △ABC is 2 square units greater than the area of △DEF.

Answer: The length of the sides of the triangle ABC are given below:

[tex]AB=\sqrt{(7-4)^2+(2-2)^2} =3\ unit\\\\BC=\sqrt{(4-7)^2+(6-2)^2} =5\ unit\\\\AC=\sqrt{(4-4)^2+(6-2)^2} =4\ unit[/tex]

The area of triangle ABC is given as:

Area = 1/2 × base × height = 1/2 × 3 × 4 = 6 unit²

The length of the sides of the triangle DEF are given below:

[tex]DE=\sqrt{(4-(-2))^2+(-3-(-1))^2} =\sqrt{40} \ unit\\\\EF=\sqrt{(4-2)^2+(-1-(-3))^2} =2 \ unit\\\\DF=\sqrt{(4-(-2))^2+(-1-(-1))^2} =6 \ unit[/tex]

The area of triangle DEF is given as:

Area = 1/2 × base × height = 1/2 × 2 × 6 = 6 unit²

The area of triangle ABC is equal to 6 unit² and the area of triangle DEF is equal to 6 unit² , therefore The area of △ABC is equal to the area of △DEF

Answer:

b

Step-by-step explanation:

edge exam

Answer:

Below

Step-by-step explanation:

Coterminal angles are angles with same terminal angles

Mathematically speaking these angles should have the same coordinates in a trigonomitrical circle

●●●●●●●●●●●●●●●●●●●●●●●●

Angles like 0° and 360° are coterminal since to we made a spin from 0° to 360°

For two angles A and B to be coterminal they should verify this relation :

A = B + k*360° with k an integer

So A-B = k*360°

●●●●●●●●●●●●●●●●●●●●●●●●

7) :

35° and 395°

395° -35° = 360°

360° is a multiple of 360° so these angles are coterminal

8) :

140° and 860°

860° - 140° = 720°

720° is a multiple of 360°

720 = 360° × 2

9) :

350° and -710°

350 -(-710) = 350+ 710 = 1060°

1060° isn't a multiple of 360°

So these angles aren't coterminal

10) :

130° and -230°

130 -(-230) = 130+230 = 360°

So these angles are coterminal

11) :

30° and -690°

30 -(-690) = 30+ 690 = 720°

720 is a multiple of 360 so these angles are coterminal

12) :

210° and 10°

210-10 = 200

200 isn't a multiple of 360 so these angles aren't coterminal

Answer:

SAA or AAS

Step-by-step explanation:

∠BAC = ∠BCA   Given

∠BDA = 90° and ∠BDC = 90°   Given

∠BDA = ∠BDC All 90° angles are congruent

BD = DB Reflexive property

ΔADB = ΔCDB   SAA

Answer:

f(x) = 8(x-3)

Step-by-step explanation:

F^ -1 ( x) = x/8 +3

Let y = x/8+3

To find the inverse

Exchange x and y

x = y/8+3

Solve for y

x-3 = y/8+3-3

x-3 = y/8

Multiply each side by 8

8(x-3) = y/8 * 8

8(x-3) = y

The inverse of the inverse is the function so

f(x) = 8(x-3)

Answer:

[tex]\boxed{f(x) = 8(x-3)}[/tex]

Step-by-step explanation:

[tex]y=\frac{x}{8} +3[/tex]

Switch variables.

[tex]x=\frac{y}{8} +3[/tex]

Make y as subject.

Subtract 3 from both sides.

[tex]x-3=\frac{y}{8}[/tex]

Multiply both sides by 8.

[tex]8(x-3)=y[/tex]

a. true

b. false ( angles should equal 180 125+65=190)

c. true

d. true

e. true

Answer:

[tex]\boxed{\mathrm{view \: explanation}}[/tex]

Step-by-step explanation:

a. True (vertically opposite angles are equal)

b. False (angles on a straight line add up to 180 degrees)

c. True (corresponding angles are equal)

d. True (supplementary angles are angles that add up to 180 degrees)

e. True (alternating interior angles are equal)

Answer:

The correct option is;

[tex]h(x) = \sqrt[3]{x + 2}[/tex]

Step-by-step explanation:

Given that h(x) is a translation of f(x) = ∛x

From the points on the graph, given that the function goes through (-1, 1) and (-3, -1) we have;

When x = -1, h(x) = 1

When x = -3, h(x) = -1

h''(x) = (-2, 0)

Which gives  

d²(∛(x + a))/dx²= [tex]-\left ( \dfrac{2}{9} \cdot \left (x + a \right )^{\dfrac{-5}{3}}\right )[/tex], have coordinates (-2, 0)

When h(x) = 0, x = -2 which gives;

[tex]-\left ( \dfrac{2}{9} \cdot \left (-2 + a \right )^{\dfrac{-5}{3}}\right ) = 0[/tex]

Therefore, a = (0/(-2/9))^(-3/5) + 2

a = 2

The translation is h(x) = [tex]\sqrt[3]{x + 2}[/tex]

We check, that when, x = -1, y = 1 which gives;

h(x) = [tex]\sqrt[3]{-1 + 2} = \sqrt[3]{1} = 1[/tex] which satisfies the condition that h(x) passes through the point (-1, 1)

For the point (-3, -1), we have;

h(x) = [tex]\sqrt[3]{-3 + 2} = \sqrt[3]{-1} = -1[/tex]

Therefore, the equation, h(x) = [tex]\sqrt[3]{x + 2}[/tex] passes through the points (-1, 1) and (-3, -1) and has an inflection point at (-2, 0).

Answer: B

Step-by-step explanation:

Answer:

$39.15

Step-by-step explanation:

We can find that Steve started with $39.15, by adding the price he has now and the price he paid for the pizza.

35.86+3.29=$39.15

Answer:

$39.15

Step-by-step explanation:

$35.86 + $3.29 = $39.15

hOpEfUlLy ThIs HeLpEd!! :33

Answer:

0.9168

Step-by-step explanation:

From the data given:

Mean = 110

standard deviation = 5

Let consider a random sample n =49 which have a mean between 109 and 112.

The test statistics can be computed as:

[tex]Z_1 = \dfrac{x- \bar x}{\dfrac{\sigma}{\sqrt{n}}}[/tex]

[tex]Z_1 = \dfrac{109- 110}{\dfrac{5}{\sqrt{49}}}[/tex]

[tex]Z_1= \dfrac{-1}{\dfrac{5}{7}}[/tex]

[tex]Z_1[/tex]  = -1.4

[tex]Z_2= \dfrac{x- \bar x}{\dfrac{\sigma}{\sqrt{n}}}[/tex]

[tex]Z_2 = \dfrac{112- 110}{\dfrac{5}{\sqrt{49}}}[/tex]

[tex]Z_2 = \dfrac{2}{\dfrac{5}{7}}[/tex]

[tex]Z_2 =2.8[/tex]

Thus; P(109  <  [tex]\overline x[/tex]  <  112) = P( - 1.4 < Z < 2.8)

= P(Z < 2.8) - P( Z < -1.4)

= 0.9974 - 0.0806

= 0.9168

Answer:

E

Step-by-step explanation:

i guess the dotted lines outline a square

so get the area of the square which is 6×6=36

then don't focus on the shaded part but unshaded you'll see two right angled triangles

[tex]a = 1 \div2b \times h[/tex]

you will get a total for both as 21

then get the area of the square 36-21=15

so the area becomes 15

Answer:

      $5 and 50 units

Step-by-step explanation:

Answer:

[tex]3x^2+2x+1[/tex]

Step-by-step explanation:

Sum means to add and second power means that the exponent is "2". So, the expression is:

=> [tex]3x^2+2x+1[/tex]

It cannot be simplified further.

Answer:

6.09

Step-by-step explanation:

in ADB

[tex]a ^{2} + b^{2} = c ^{2} [/tex]

to get hypotenuse=8.96

this is height of ABC so use tan

[tex] tan(55.8)= 8.96 \x[/tex]

x=6.09

Answer:

D

Step-by-step explanation:

To find x, we first to to find the line between A&B.

Use the pythagoram theorem to do this A^2+B^2=C^2

4.9^2+7.5^2=C^2

80.26=C^2

square root each side

Side AtoB=8.958

We now know the side length of the opposite and adjacent for the angle C. So according to SohCahToa we need to use Tangent.

So Tan(55.8)=(8.958/x)

We you solve for x, the answer is 6.088

[tex]-6w-16>44[/tex]

Add both sides by 16

[tex]-6w>60[/tex]

Divide both sides by -6 (Note: Since we're dividing by a negative number, the inequality symbol needs to be reversed)

[tex]w<-\dfrac{60}{6}[/tex]

[tex]w<10[/tex]

This is the solution to the inequality. Let me know if you need any clarifications, thanks!

Answer:

9

Step-by-step explanation:

x − 3y

Let x =3 and y = -2

3 -3(-2)

3 + 6

9

Answer:

864.36 boxes

Step-by-step explanation:

In the question above, we are given the following values,

Confidence interval 95%

Since we know the confidence interval, we can find the score.

Z score = 1.96

σ , Standards deviation = 15mm

Margin of error = 1 mm

The formula to use to solve the above question is given as:

No of boxes =[ (z score × standard deviation)/ margin of error]²

No of boxes = [(1.96 × 15)/1]²

= 864.36 boxes

Based on the options above, we can round it up to 97 boxes.

Answer:

n = -15 and n = 9. n = -15 is not reasonable because you can't have negative boxes or negative units of measurement.

Step-by-step explanation:

8(n + 2)(n + 4) = 1,144

(n + 2)(n + 4) = 143

n^2 + 2n + 4n + 8 = 143

n^2 + 6n - 135 = 0

(n + 15)(n - 9) = 0

n + 15 = 0

n = -15

n - 9 = 0

n = 9

I got two solutions: n = -15 and n = 9. Only one is reasonable because you cannot have a negative number of boxes or negative weight.

Hope this helps!

Simplify the equation, and set it equal to zero to prepare for factoring.

Multiply the two factors in parentheses using the distributive property:

8(n2 + 2n + 4n + 8) = 1,144

Combine like terms inside the parentheses:

8(n2 + 6n + 8) = 1,144

Multiply the terms inside the parentheses by 8 using the distributive property:

8n2 + 48n + 64 = 1,144

Set the equation equal to zero by subtracting 1,144 from each side:

8n2 + 48n − 1,080 = 0

Factor out the GCF, which is 8:

8n2 + 48n − 1,080 = 0

8(n2 + 6n − 135) = 0

Divide both sides of the equation by 8:

n2 + 6n − 135 = 0

Compare the equation with the standard form ax2 + bx + c = 0, and get a, b, and c:

a = 1, b = 6, c = -135

The leading coefficient of the equation is 1. So, find two numbers that have a sum of 6 and a product of -135:

6 = -9 + 15

-135 = -9 • 15

The two numbers are -9 and 15. Use the two numbers to write the factors of the quadratic expression:

(n − 9)(n + 15) = 0

Use the zero product property, and solve for n:

n − 9 = 0 or n + 15 = 0

n = 9 or n = -15

There are two solutions for n. But since n represents the width of the helmet box, it can’t be negative. Therefore, the only reasonable solution is n = 9

Answer:

$2,500 was invested in the first account while $7,500 was invested in the second account

Step-by-step explanation:

Here in this question, we want to find the amount which was invested in each of the accounts, given their individual interest rates and the total amount that was accorded as interest from the two investments

Now, since we do not know the amount invested , we shall be representing them with variables.

Let the amount invested in the first account be $x and the amount invested in the second account be $y

Since the total amount invested is $10,000, this means that the summation of both gives $10,000

Mathematically;

x + y = 10,000 ••••••(i)

now for the $x, we have an interest rate of 5%

This mathematically translates to an interest value of 5/100 * x = 5x/100

For the $y, we have an interest rate of 6% and this mathematically translates to a value of 6/100 * y= 6y/100

The addition of both interests, gives 575

Thus mathematically;

5x/100 + 6y/100 = 575

Multiplying through by 100, we have

5x + 6y = 57500 •••••••••(ii)

From 1, we can have x = 10,000-y

let’s substitute this into equation ii

5(10,000-y) + 6y = 57500

50,000-5y + 6y = 57500

50,000 + y = 57500

y = 57500-50,000

y = 7,500

Recall;

x = 10,000-y

so we have;

x = 10,000-7500 = 2,500