GEOMETRY QUESTION NEED HELP ASAP 20 POINTS ​

Proof:-

In ∆XYZ and ∆VWZ

[tex]\because\sf\begin{cases}\sf XZ\cong VZ(Given)\\ \sf YZ\cong WZ(Given)\\ \sf <XZY\cong <WZV(Opposite angles)\end{cases}[/tex]

Hence

∆XYZ[tex]\cong[/tex](Side-Angle-Side)

Given that √2 = 1.414

The value of (1/2)√(16200)

16200 can be written as

16200 = 2×8100

16200 = 2×2×4050

16200 = 2×2×2×2025

16200 = 2×2×2×5×405

16200 = 2×2×2×5×5×81

16200 = 2×2×2×5×5×3×27

16200 = 2×2×2×5×5×3×3×9

16200 = 2×2×2×5×5×3×3×3×3

√16200 = √(2×2×2×5×5×3×3×3×3)

√16200 = √2×(2×2)×(5×5)×(3×3)×(3×3)

√16200 = 2×5×3×3√2

√16200 = 90√2

Now,

(1/2)√16200

⇛(1/2)×90√2

⇛90√2/2

⇛45√2

⇛45×1.414

⇛63.63

Answer: Hence, value of (1/2)√(16200) is 63.63

also read similar questions: if √2=1.414 and√3=1.732,find the value of 1/√2+√3..

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If √2 = 1.414 then the value of 5+√2 / 5-√2 is..

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The value of 1/2√16200 given the value of √2 = 1.414 is 63.63

Prime factorization of √16200

= 3 × 3 × 5 × √2

= 90√2

Given:

1/2√16200

= 1/2 × 90√2

= 90√2 / 2

= 45√2

= 45 × √2

= 45 × 1.414

= 63.63

Therefore, the value of 1/2√16200 is 63.63

Learn more about prime factorization:

https://brainly.com/question/9523814

Answer:

\mathrm{X\:Intercepts}:\:\left(-\frac{431}{26},\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:43.1\right)

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

you can break the 78 into 70 and 8, and multiply them separately by 6 and then add the two answers to get 468

Answer: y = 115 and x = 78

Step-by-step explanation:

y = 115 because it is parallel with the angle 115 and parallel are congruent, for x find the angle beside the angle 102 and that angle is parallel with the angle x and that will be 180 - 102 = 78 which is x  

Answer:

5

7

..................

Answer:

y equals -2x -7

y equals 3/4 x plus 2 1/2

Answer:

A pencil is about 19 centimeters long

Answer:

if 100 inches=254 centimeters

then 10 inches=x

100x=2540

x=2540/100

x=25.4 centimeters

Answer:

when the coefficient of x^2 is negative

Step-by-step explanation:

Answer:

Hence 27 cubes can be obtained.

Step-by-step explanation:

Volume occupied by one cube of side 2cm = 2*2*2 = 8cm^3

Volume of cube of side 6cm = 216cm^3

Number of cubes of side 2cm which would fit in a cube of side 6cm = 216/8 = 27 cubes

Answer:

11:18

Step-by-step explanation:

Hope this helped!

Answer:

False.

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Calculus

Differentiation

Derivative Rule [Basic Power Rule]:

Derivative Rule [Product Rule]:                                                                             [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify.

[tex]\displaystyle \frac{d}{dx}[x^3e^x][/tex]

Step 2: Differentiate

∴ [tex]\displaystyle \frac{d}{dx}[x^3e^x] \neq x^3e^x(3x + 2)[/tex]  but  [tex]\displaystyle \frac{d}{dx}[x^3e^x] = (x^3 + 3x^2)e^x[/tex].

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Answer:

2/3

Step-by-step explanation:

The answer is simple; the number of non-red marbles over the number of total marbles.

Answer:

  (b)  {-8, 2}

Step-by-step explanation:

The given equation

  x³ +6x -16 = 0

cannot be factored in integers. It has one irrational real root near x=1.759, and two complex roots.

__

Perhaps you want to factor ...

  x² +6x -16 = 0

  (x +8)(x -2) = 0

This has solutions x = -8 and x = 2 that make the factors be zero.

_____

Additional comment

"Cubed" refers to an exponent of 3.

Answer:

Option b] (2,-8)

Step-by-step explanation:

⇒ x³ + 6x - 16 = 0

♦ the value of one root is irrational and other two are complex roots.

⇒ x² + 6x - 16 = 0

⇒ (x + 8)(x - 2) = 0

⇒ x = 2 , -8

Answer:

[tex](x-2)(x-3)[/tex]

Step-by-step explanation:

[tex]x^2-5x+6[/tex]

[tex]x^2-3x-2x+6[/tex]

[tex]x(x-3)-2(x-3)[/tex]

[tex](x-2)(x-3)[/tex]

That would probably be zero for the answer, because if a number or an equation subtracts the same number or equation it will cancel itself out. Thus giving us zero.

Hope this help :D.

Answer:

Step-by-step explanation:

Dilation does not affect angles or the direction of lines. The lines of a dilated figure will be parallel to the original, unless they go through the center of dilation.

Line CD does not go through P, so C'D' is distinct and parallel to it (True).

Angles B and B' are congruent. (True)

Using the histogram, the mean of the data-set is estimated to be of 31.

In this problem, the intervals and relative frequencies are:

Hence, the mean is:

[tex]E(X) = 23\frac{4}{30} + 28\frac{8}{30} + 33\frac{14}{30} + 38\frac{4}{30} = \frac{23(4) + 28(8) + 33(14) + 38(4)}{30} = 31[/tex]

For more on mean of histograms, you can check https://brainly.com/question/24651197

Answer: x = 3 and y = 5

Step-by-step explanation:

Answer:

answer is  

A.21,369 or  D. 56,783

Step-by-step explanation:

am  not sure but am mostly sure it is D but i dont know i think is A to but am

99% is D

hope it helps

Answer:

Your answer is C 48,618

Step-by-step explanation:

if you add the sum up of all of the digits it is divisible by both three and nine.

can i plz get brainliest.

Answer:6 . 625 or 6 5/8

Step-by-step explanation

10 + (-3 3/8)         (adding a negative is like subtracting a positive)

10 - 3 3/8

6 5/8

Step-by-step:

Use slope formula to find the slope. (y - y)/(x - x)

Make sure the x and y in front of the minus is a pair that goes together, as well as the x and y behind the minus sign. So

8 - -4 goes on top, that's 12

0 - -1 goes under, thats 1

12/1 is the slope which is just 12. Use either point to fill in the second x and the second y in the point-slope equation. m is the slope.

y - y = m(x - x)

y - 8 = 12(x - 0)

y - 8 = 12x

Answer:

x=1+sqr57,1-sqr57

Step-by-step explanation:

Answer:

  x = -6.5, x = 8.5

Step-by-step explanation:

The given equation ...

  x^2 -4x -31 = -2x +25

can be rewritten to a form that facilitates completing the square:

  x^2 -2x = 56 . . . . . add 2x+31

  x^2 -2x +1 = 57 . . . add 1 to complete the square

  (x -1)^2 = 57 . . . . . write the left side as a square

  x -1 = ±√57 . . . . . take the square root

  x = 1 ±√57 ≈ {-6.5, 8.5} . . . . . add 1, evaluate

Solutions are near x = -6.5 and x = 8.5.

======================================================

Explanation:

Solve the inequality for x.

5x + 4 < 29

5x < 29-4

5x < 25

x < 25/5

x < 5

I subtracted 4 from both sides (step 2). Then I divided both sides by 5 to fully isolate x (step 4). The inequality sign stays the same the entire time.

Since x < 5, this means the original set {3,4,5,6} becomes {3,4} since these values make x < 5 a true statement. In other words, we erase 5 and 6 because something like 6 < 5 is false.

That's why {3, 4} is the final answer.

---------------

An alternative method is to go through the set {3,4,5,6} and plug those items one by one into the original inequality. If you get a true result, then it's part of the answer.

Let's try x = 3

5x + 4 < 29

5(3) + 4 < 29

15+4 < 29

19 < 29

We get a true statement at the end, so x = 3 is part of the solution set. A similar story happens for x = 4 as well.

If we tried x = 5, then,

5x + 4 < 29

5(5) + 4 < 29

25 + 4 < 29

29 < 29

which is false. No number is bigger than itself (or smaller than itself). Therefore, x = 5 is crossed out of the original set. You should get a false statement for x = 6, which means we'll kick this value out as well.

Answer: yes they are perpendicular

The zeros of

y = x(x + 2)(x + 5)y=x(x+2)(x+5)

are

x=0,x=-2,x=-5x=0,x=−2,x=−5

EXPLANATION

The given function is

y = x(x + 2)(x + 5)y=x(x+2)(x+5)

To find the zeros of the above function, we just have to equate the function to zero and solve for x.

x(x + 2)(x + 5) = 0x(x+2)(x+5)=0

This implies that,

x = 0 \: \: or \: x + 2 = 0 \:or \: x + 5 = 0x=0orx+2=0orx+5=0

x = 0 \: \: or \: x = - 2\:or \: x = - 5x=0orx=−2orx=−5

To graph the above function, we need to consider the multiplicity.

We can see that the multiplicity of the roots are odd. This means that, the graph crosses the x-axis at each x-intercept.

We also need to consider the position of the graph on the following intervals,

x < - 5x<−5

When

x = - 10x=−10

y = - 10( - 8)( - 5) \: < \: 0y=−10(−8)(−5)<0

The graph is below the x-axis.

- 5 \: < \: x \: < \: - 2−5<x<−2

When

x = - 3x=−3

y = - 3(2)( - 1) \: > 0y=−3(2)(−1)>0

The graph is above the x-axis.

- 2 \: < \: x < \: 0−2<x<0

when

x = - 1x=−1

y = -1(1)(4) \: < \: 0y=−1(1)(4)<0

The graph is below the x-axis.

Finally the interval,

x \: > \: 0x>0

when

x = 1x=1

y = 1(3)(6) \: > \: 0y=1(3)(6)>0

The graph is above the x-axis.

We can now use the above information to sketch graph as shown in the diagram above