Answer:
The example of the nonlinear element is a diode and some of the nonlinear elements are not there in the electric circuit is called a linear circuit. Some other examples of the non-linear elements are transistors, vacuum tubes, other semiconductor devices, iron core inductors, and transformers.
Explanation:
Define the following terms in your own words:
- Energy
- Kinetic energy
- Potential energy
- Work
- Friction
Answer:
Energy: The ability to do work
Kinetic energy: Kinetic energy is the energy an object has due to its motion
Potential energy: potential energy is the energy that is stored in an object
Work: Work is the transfer of energy by a force acting on an object as it is displaced
Friction: Friction acts as a resisting force which is generated , when two solid surfaces slide against one another
To measure the internal diameter of a beaker one would reliably use______.
Answer:
Vernier calipers is used to measure the internal diameter of a beaker
A solenoid that is 69.3 cm long has a cross-sectional area of 24.0 cm2. There are 1260 turns of wire carrying a current of 8.78 A. (a) Calculate the energy density of the magnetic field inside the solenoid. (b) Find the total energy in joules stored in the magnetic field there (neglect end effects).
Answer:
a) 34.17J/m^3
b) 0.0468 J
Explanation:
a) Calculate the energy density of the magnetic field inside the solenoid as follows:
[tex]u_{B} &=\frac{U}{A l} \\ &=\frac{L I^{2}}{2 A l} \quad\left(U=\frac{1}{2} L I^{2}\right) \\ &=\frac{\mu_{0} N^{2} A I^{2}}{2 A l^{2}} \quad\left(L=\frac{\mu_{0} N^{2} A}{l}\right) \\ &=\frac{\mu_{0} N^{2} I^{2}}{2 l^{2}}[/tex]
Substitute the corresponding values in the above equation.
[tex]u_{B} &=\frac{4 \pi\left(10^{-7}\right)(1260)^{2}(8.78)^{2}}{2(0.693)^{2}} \\
&=34.17 \mathrm{~J} / \mathrm{m}^{3}[/tex]
b) Calculate the total energy stored in the solenoid as follows:
[tex]U &=u_{B} A l \\ &=(34.17)\left(24 \times 10^{-4}\right)\left(69.3 \times 10^{-2}\right) \\ &=0.0468 \mathrm{~J}[/tex]
It has been shown that the half-life for this radioactive isotope is 20 years. In the year 2000, an archaeology team unearths pottery and is using this isotope for radiometric dating to place the age of the pottery. It is shown that 95% of the nuclei have decayed. How much mass has decayed? How much mass is left?
I'd prefer to be shown a step-by-step on how to solve for these questions. I do better with seeing the step-by-step, and can retain the information better.
Answer:
(1/2)*n = .05 by the definition of half-life where n is the number of half-lives
n ln .5 = ln .05
n = ln .05 / ln .5 = 4.32 number of half-lives
So 4.32 * 20 = 86.4 years has passed
Actually, they only want the mass left. However, all that has changed is that
95% of the original radioactive atoms have changed to a different form of about the same amount of mass. The amount of mass remaining would be about the same. Also, one doesn't know the percentage of radioactive atoms
that formed the original mass.
What determines the precision of a measurement?
Answer:
Precision is determined by a statistical method called a standard deviation To determine if a value is precise find the average of your data, then subtract each measurement from it
1 gram of radium is reduced by 3.1 mg in 5 years by alpha decay.
Calculate the half-life of radium.
Answer:
1 gm = 1000 mg
N = No e^-y t where y = lambda the decay constant
N / N0 = .9969
ln .9969 = - y t
-.00310 = - 5 y
y = .00310 / 5 = .000621
So the half-life = .693 / y
T^1/2 = .693 / .000621 = 1116 or about 1120 yrs
What is the energy of an electromagnetic wave that has a frequency of 5.0 * 10^5 Hz? Use the equation E=hf, where h=6.626 * 10^-34 J*s.
I will mark brainliest!!! :)
Answer:
3.3*10^-28j
Explanation:
A P E X
The energy of an electromagnetic wave that has a frequency of 5.0 * 10^5 Hz is 3.3 * 10 ^ -28 J
What is Electromagnetic waves ?Electromagnetic waves are the waves that are created as a result of vibration between an electric field and a magnetic field . They are composed of oscillating magnetic and electric field
Energy of Electromagnetic waves can be calculated by
Energy = h * f where h = plank's constant = 6.626 * 10^-34 J s.
f = frequency of electromagnetic waves
given : h = 6.626 * 10^-34 J s.
frequency = 5.0 * 10^5 Hz
Energy of electromagnetic waves = (6.626 * 10^-34 J s) *( 5.0 * 10^5 Hz)
= 33.13 * 10 ^ -29 J
= 3.3 * 10 ^ -28 J
correct answer is c)3.3 * 10 ^ -28 J
Learn more about electromagnetic waves
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A circular loop of radius 13 cm carries a current of 13 A. A flat coil of radius 0.94 cm, having 58 turns and a current of 1.9 A, is concentric with the loop. The plane of the loop is perpendicular to the plane of the coil. Assume the loop's magnetic field is uniform across the coil. What is the magnitude of (a) the magnetic field produced by the loop at its center and (b) the torque on the coil due to the loop
Answer:
[tex]6.28\times 10^{-5}\ \text{T}[/tex]
[tex]1.92\times 10^{-6}\ \text{Nm}[/tex]
Explanation:
[tex]\mu_0[/tex] = Vacuum permeability = [tex]4\pi 10^{-7}\ \text{H/m}[/tex]
[tex]I_l[/tex] = Current in circular loop = 13 A
[tex]r_l[/tex] = Radius of circular loop = 13 cm
[tex]N[/tex] = Number of turns = 58
[tex]r_c[/tex] = Radius of coil = 0.94 cm
[tex]I_c[/tex] = Current in coil = 1.9 A
[tex]\theta[/tex] = Angle between loop and coil = [tex]90^{\circ}[/tex]
Magnitude of magnetic field in circular loop
[tex]B_l=\dfrac{\mu_0I_l}{2r_l}\\\Rightarrow B_l=\dfrac{4\pi 10^{-7}\times 13}{2\times 13\times 10^{-2}}\\\Rightarrow B_l=6.28\times 10^{-5}\ \text{T}[/tex]
The magnetic field produced by the loop at its center is [tex]6.28\times 10^{-5}\ \text{T}[/tex].
Torque is given by
[tex]\tau=\pi NI_cr_c^2B_l\sin\theta\\\Rightarrow \tau=\pi 58\times 1.9\times (0.94\times 10^{-2})^2\times 6.28\times 10^{-5}\sin90^{\circ}\\\Rightarrow \tau=1.92\times 10^{-6}\ \text{Nm}[/tex]
The torque on the coil due to the loop [tex]1.92\times 10^{-6}\ \text{Nm}[/tex].
A 4 kg particle moves at a constant speed of 2.5 m/s around acircle of radius 2 m. What is its angular momentum about the center of the circle? Answerin units of kg · m2/s. What is its moment of inertia about an axis through the center ofthe circle and perpendicular to the plane of the motion? Answer inunits of kg · m2. What is t
Explanation:
Given that,
Mass of the particle, m = 4 kg
Speed of the particle, v = 2.5 m/s
The radius of the circle, r = 2 m
We need to find the angular momentum about the center of the circle. The formula for the angular momentum is given by :
[tex]L=mvr[/tex]
Substitute all the values,
[tex]L=4\times 2.5\times 2\\\\L=20\ kg{\cdot}m^2s[/tex]
So, the angular momentum of the particle is 20 kg-m² s.
Please do not round the numbers
Answer:
1) λ = 24.7 cm, 2) f = 13.88 Hz, 3) L = 117.3 cm
Explanation:
1) This is a resonance process, that is, the wave going downwards will interfere with the wave going upwards.
This is a tube with one end closed and the other open, at the closed end there is a node and at the open end a belly, so the resonances are
L = λ / 4
λ = 4L 1st harmonic
λ = 4L / 3 third harmonic
λ = 4L / 5 fifth harmonic
λ = 4L / n ’ n’ odd number n ’= (2n +1)
the wavelength is requested for the eighth resonance n = 8, the corresponding prime number is
n ’= 2 8 +1
n ’= 17
we substitute
λ = 4 105/17
λ = 24.7 cm
2) the speed of the wave is related to the wavelength and frequency
v = λf
f = v /λ
f = 343 / 24.7
f = 13.88 Hz
3) the next resonance occurs for n = 9, so the prime number is
n ’= 2 9 +1
n ’= 19
L = n’ λ / 4
L = 19 λ / 4
We must suppose a value for the wavelength, if the wavelength is present in the tube and the length of the column increases, the resonance number increases
L = 19 24.7/4
L = 117.3 cm
When two trains, going in opposite directions, are passing on tracks that are laid out close together, the train cars can often be seen to be leaning in toward one another where they are in proximity. How might the air passing through the narrow gap separating the two trains contribute to the observed attraction between their cars?
4. A 100-kg soldier in the Arctic is coasting on his ice skates at a speed of 3.0 m/s. He fires 35 bullets directly forward from his 10.0-kg machine gun. Each bullet has a mass of 60 g and a speed of 500 m/s. What is his final velocity?
Answer:
The gunner must apply 240 N to the gun to stop it from moving back.
Explanation:
In a laser cutting process of aluminum plates of 1mm thick, a through hole is to be drilled, followed by melting-dominated cutting. If the focused laser beam is 0.25 mm in diameter (assuming it is the same of the cut width w), (a) In order to drill a hole through the plate in 1 ms, determine the laser power required. (b) In the cutting, the laser power is adjusted to be 1,500W. Determine the cutting velocity V achievable.
Answer:
a) P = 118.4 W, b) t = 7.9 10⁻⁵ s
Explanation:
a) Let's analyze this interesting exercise a bit, we suppose that all the laser
energy is used to heat the aluminum, we should calculate the energy necessary to bring the solid aluminum to the melting temperature and add the energy to carry out the change of solid state to liquid,
let's use the calorimeter equation
Q₁ = m c_e ΔT
and the energy of change of these solid to liquid (fusion process)
Q₂ = m L
the energy required to create the hole is
Q_ {total} = Q₁ + Q₂
if there are no losses this is the laser energy
E = Q_ {total}
The aluminun data c_e =9000 J/kgC, L = 322 103 J/kg, ρ = 2.7 103 kg/m3 , T₂ = 660C, T₀= 25C
Let's find the mass of the hole, which we approximate by a cylinder of diameter d = 0.25 mm = 0.25 10⁻³ m and a thickness of e = 1 mm = 1 10⁻³ m
let's use the concept of density
ρ = m / V
the volume of a cylinder is
V = π r² e = π (d²/4) e
we substitute
m = [tex]\rho \pi \frac{d^2 e}{4}[/tex]
let's calculate
m = π/4 2.7 10³ (0.25 10⁻³)² 1 10⁻³
m = 1,325 10⁻⁷ kg
we calculate the energy
E = 1,325 10⁻⁷ 900 (660 - 25) + 1,325 10⁻⁷ 322 10³
E = 7.57 10⁻² + 4.27 10⁻²
E = 1.184 10⁻¹ J
Let's use the power ratio
P = E / t
P = 0.1184 /1 10⁻³
P = 118.4 W
b) In this part they indicate that the laser power is P = 1500 W, find the time to deposit the energy to melt the aluminum
P = E / t
t = E / P
t = 0.1184 / 1500
t = 7.9 10⁻⁵ s
Question 10 of 10
Which of the following is an example of a surface wave?
Answer:
gravity wave
Explanation:
What is Compression?
Answer:
Compression, decrease in volume of any object or substance resulting from applied stress. Compression may be undergone by solids, liquids, and gases and by living systems.
Explanation:
| Britannicahttps://www.britannica.com
A block of wood and a block of aluminum have been sitting out for a while. How do their temperatures compare?
Answer:
Block of aluminum
Explanation:
The block of aluminum because of the conductivity, and is a metal, so it gets hotter faster
The temperature of wood and the aluminium will depend upon thier thermal coductivity.
What is thermsal conductivity?The thermal conductivity of any material is defined as the amount of heat from a material can flow in a unit area per unit degree centigrade for a unit distance.
The thermal conductivity of wood is around 0.90 to 0.197 w/mk and that of aluminium is around 88 to 251 w/mk.
We can see that the aluminium block will absorb much amount of heat as compared to the wood block. Because the thermal conductivity of aluminium is much higher then the wood.
Hence temperature of wood and the aluminium will depend upon thier thermal coductivity.
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If the force of gravity changes what will happen and what would cause it to change?
g n diffraction, the formula for minima is given by a times s i n (theta )equals m lambda, where a is the width of the slit, theta is the angle of dispersion, m is the order, and lambda is the wavelength. For a wavelength of 630 nm, m equals 3, and a equals 5 times 10 to the power of negative 6 end exponent m. Calculate the angular spread in Degrees. Enter only the numerical value (i.e. omit the unit abbreviations when inputting your answer into Blackboard).
Answer:
θ = 22.2
Explanation:
This is a diffraction exercise
a sin θ = m λ
The extension of the third zero is requested (m = 3)
They indicate the wavelength λ = 630 nm = 630 10⁻⁹ m and the width of the slit a = 5 10⁻⁶ m
sin θ = m λ / a
sin θ = 3 630 10⁻⁹ / 5 10⁻⁶
sin θ = 3.78 10⁻¹ = 0.378
θ = sin⁻¹ 0.378
to better see the result let's find the angle in radians
θ = 0.3876 rad
let's reduce to degrees
θ = 0.3876 rad (180º /π rad)
θ = 22.2º
A car of mass 1800000 g, going 150 km/h rear ends a truck, 5500 kg going 100000 m/h. What are their velocities after an elastic collision in one dimension?
Answer:
v = 2099.5 km/h, v' = -618.8 km/h
or
v =-1996.6 km/h, v' = 721.7 km/h
Explanation:
From the law of conservation of momentum,
Total momentum before collision = Total momentum after collision
For elastic,
mu+m'u' = mv+m'v'..................... Equation 1
Total kinetic energy before collision is equal to total kinetic energy after collision
mu²+m'u'² = mv²+m'v'²............. Equation 2
Where m and m' are the mass of the car and truck respectively, and u and u' are the initial velocity of the car and the truck respectively, v and v' are the final velocity of the car and the truck respectively.
Given: m = 1800000 g = 1800 kg, m' = 5500 kg, u = 150 km/h, u' = 100000 km/h
Substitute these values into equation 1 and 2
1800(150)+5500(100000) = 1800v+5500v'
1800v+5500v' = 375500................... Equation 3
1800(150²) +5500(100000²) = 1800v²+5500v'²...................... Equation 4
Solving equation 3 and 4 simultaneously,
v = 2099.5 km/h, v' = -618.8 km/h
or
v =-1996.6 km/h, v' = 721.7 km/h
What is Kirchoff law
Answer:
.
Kirchhoff's circuit laws are two equalities that deal with the current and potential difference (commonly known as voltage) in the lumped element model of electrical circuits. They were first described in 1845 by German physicist Gustav Kirchhoff.[1] This generalized the work of Georg Ohm and preceded the work of James Clerk Maxwell. Widely used in electrical engineering, they are also called Kirchhoff's rules or simply Kirchhoff's laws. These laws can be applied in time and frequency domains and form the basis for network analysis.
Both of Kirchhoff's laws can be understood as corollaries of Maxwell's equations in the low-frequency limit. They are accurate for DC circuits, and for AC circuits at frequencies where the wavelengths of electromagnetic radiation are very large compared to the circuits.
Question is in the image
Answer:
thank you
Explanation:
a force acting on a body of mass 24 kg produces an acceleration of 12ms ^-2 . what acceleration will the same force produce in a body of 10 kg
please give answers if they are right and you know how to do it
Answer: a = 28,8
Explanation:
[tex]F = ma[/tex]
m = 24 , a = 12
[tex]F=ma\\\\F = 24 x12\\\\F=288[/tex]
Same force :
m = 10
a = ?
F = 288
[tex]F = ma \\\\288 = 10xa \\\\28,8=a[/tex]
How least count determine the precision of a measurement?
Explanation:
The least count of the normal scale is 1mm whereas the least count of vernier calliper is 0.01 mm
The definition that best describes invention is:
Your answer:
Invention is the first product produced on an assembly line
Invention is having a desired goal to achieve something
Invention is changing the size of an existing product
Invention is a process of turning ideas into devices or systems
Answer: Invention is a process of turning ideas into devices or systems.
Explanation:
Invention is a process of turning ideas into devices or system. Invention, simply has to do with bringing of ideas together so as to create something unique.
It should be noted that without creativity, invention can't take place. Examples of invention include the light bulb, fans etc. They are products that were designed based on the ideas that someone had Wich was turned into a device.
Which statement best describes how resources are distributed?
according to it's nature
It is 32 degrees F outside. What is this in Kelvin?
Answer:
273.15
Explanation:(32°F − 32) × 5/9 + 273.15 = 273.15K
What is the motion of an apple when it falls from a tree ? a)Constant b)accelerating c)decelerating d)zero
The motion of an apple when it falls from a tree is
b) Accelerating
The motion of apple is when it falls from a tree is the case of free fall.
During free fall , the initial velocity of the apple or any object is zero but it gains some velocity due to gravitatonal acceleration .
A student is provided with a rubber cylinder and a patch of synthetic fur. The rubber cylinder and the patch are electrically neutral. The student rubs the cylinder back and forth along the fur. A short time later, after the cylinder and fur have been placed on insulating stands, the student determines that the fur has a net negative electric charge. Before the patch of fur attained its net negative charge, it was considered to be electrically neutral. Which of the following claims, with appropriate evidence, is correct about the distribution of charge in the patch of fur before the charging process?
a. It is an isolated system.
b. It is a closed system.
c. It is an open system.
d. The type of system cannot be determined unless information is known about the net force exerted on the system at any given time.
Answer:
Option b ( It is a closed system) is the appropriate answer.
Explanation:
The mass transfer isn't made on a platform. There seems to be no mass transfer, the mechanism can't be separated as power lines will interfere beyond the physical boundaries including its fur patch.The mechanism can't however be separated and, while the mass transfer is indeed not present, several field lines will communicate well outside the mechanism.The other options are not linked to the situation in question. Thus, the answer is correct.
Which of the following should you do to improve your fitness level and increase your assessment scores by the end of the semester?
OA Watch a lot of TV
B.
Perform cardiovascular exercise
OC. Eat a diet high in fat and sugar
OD
All of the above
It’s Not Lhysics It’s Pe btw
Question 3 of 15
Which process is often used to determine what coefficients to use to balance
an equation?
A. Trial and error
B. Neutral numbers
C. Roundabout
D. Lavoisier's
Help?
Answer:
A. Trial and error
Explanation:
Trial and error method is a method adopted when trying to solve a quadratic equation. This equation is mostly the balancing of the right hand side and the left hand side in-order to form a unique point or to equate to zero when one is subtracted from the other. In trail and error method, the coefficients is used to determine when the actual equation is balanced and the likely answer it should be if the equation is expanded through multiplication method.