Given here is the price list of vegetables shown at a Mother Dairy vegetable Booth.

Mrs. Khanna brought the following vegetables:

potatoes
[tex]2 \frac{1}{2} [/tex]


onions
[tex]3 \: kg[/tex]


Peas
[tex]1 \frac{1}{2} kg[/tex]


Carrots

[tex]1 \frac{1}{2} kg[/tex]
She Gave a 500 - Rupee note to the man at the counter. How Much balance did she get?​

Answer:

C.  3

Step-by-step explanation:

Perpendicular lines have slopes that are negative inverses of the other.

This inverse of -1/3 is -3.  The negative of -3 is 3.

The slope of the perpendicular line is 3.

Answer:

A: 39.1304348% OR 39%

B: 33.3%

Step-by-step explanation:

Part A:

find the total amount of children: 90+20+80+40=230

90-20=50

i got this from taking away the amount that like watching tv and not reading so from this you know 50 of those 90 that like watching tv also like tv and reading.

80-40=40

(same explanation as 90-20=50)

then do 50 +40 which equals 90

now you need to turn it into a percentage.

90/230=

9/23

=39.1304348%

if you need round it, do so!

Part b:

40+20=60

20/60= 2/6

=1/3

=33.3%

Answer:

x = 1/3 , y = 10/3

Step-by-step explanation:

Solve the following system:

{y = x + 3 | (equation 1)

y = 7 x + 1 | (equation 2)

Express the system in standard form:

{-x + y = 3 | (equation 1)

-(7 x) + y = 1 | (equation 2)

Swap equation 1 with equation 2:

{-(7 x) + y = 1 | (equation 1)

-x + y = 3 | (equation 2)

Subtract 1/7 × (equation 1) from equation 2:

{-(7 x) + y = 1 | (equation 1)

0 x+(6 y)/7 = 20/7 | (equation 2)

Multiply equation 2 by 7/2:

{-(7 x) + y = 1 | (equation 1)

0 x+3 y = 10 | (equation 2)

Divide equation 2 by 3:

{-(7 x) + y = 1 | (equation 1)

0 x+y = 10/3 | (equation 2)

Subtract equation 2 from equation 1:

{-(7 x)+0 y = -7/3 | (equation 1)

0 x+y = 10/3 | (equation 2)

Divide equation 1 by -7:

{x+0 y = 1/3 | (equation 1)

0 x+y = 10/3 | (equation 2)

Collect results:

Answer: {x = 1/3 , y = 10/3

Answer:

[tex]\boxed{x=\frac{1}{3} }[/tex]

[tex]\boxed{y=\frac{10}{3} }[/tex]

Step-by-step explanation:

[tex]y=x+3\\y=7x+1[/tex]

Plug y as x+3 in the second equation.

[tex]x+3=7x+1\\7x-x=3-1\\6x=2\\x=\frac{1}{3}[/tex]

Plug x as 1/3 in the second equation.

[tex]y=7(\frac{1}{3} )+1\\y=\frac{7}{3}+1\\y=\frac{10}{3}[/tex]

Answer:

option c is the right answer

Answer:

64° aka D

Step-by-step explanation:

∠J + ∠L + ∠LKJ = 180°

58° + 58° + ∠LKJ = 180°

116° + ∠LKJ = 180°

∠LKJ = 180° - 116°

=  64°

hope i helped

-lvr

Answer:

The length of longest piece is 105 cm.

Step-by-step explanation:

Given:

Rope is 245 cm long.

Ratio of lengths of first to second piece = 2:3.

Ratio of lengths of second to third piece = 4:5.

To find:

Length of longest piece = ?

Solution:

We are given the ratio of first and second pieces AND

ratio of second and third pieces.

Common link is second piece.

We need to make the ratio of second piece equal in both the ratio to find the ratio of all three pieces.

2:3

  4:5

Multiply 1st ratio by 4 and 2nd ratio by 3:

Now, the ratio becomes:

8:12 and 12:15

And the ratio of three pieces can be represented as:

8: 12: 15, this ratio is the first piece: second piece: third piece

[tex]\Rightarrow 8x+12x+15x = 245\\\Rightarrow 35x = 245\\\Rightarrow x = \dfrac{245}{35}\\\Rightarrow x = 7[/tex]

So, the pieces lengths will be

First piece = [tex]8 \times 7 = 56[/tex] cm

Second piece = [tex]12 \times 7 = 84[/tex] cm

Third piece = [tex]15 \times 7 = 105[/tex] cm

So, the length of longest piece is 105 cm.

Confidence interval for mean, when population standard deviation is unknown:

[tex]\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}[/tex]

, where [tex]\overline{x}[/tex] = sample mean

n= sample size

s= sample standard deviation

[tex]t_{\alpha/2}[/tex] = Critical t-value for n-1 degrees of freedom

We assume the population has a normal distribution.

Given, n= 19 , s= 3.8 , [tex]\overline{x}=22.4[/tex]

[tex]\alpha=1-0.99=0.01[/tex]

A) Critical t value for [tex]\alpha/2=0.005[/tex] and degree of 18 freedom

[tex]t_{\alpha/2}[/tex] = 2.8784

B) Required confidence interval:

[tex]22.4\pm ( 2.8744)\dfrac{3.8}{\sqrt{19}}\\\\=22.4\pm2.5058\\\\=(22.4-2.5058,\ 22.4+2.5058)=(19.8942,\ 24.9058)\approx(19.9,\ 24.9)[/tex]

Lower bound = 19.9 years

Uppen bound = 24.9 years

C) Interpretation: We are 99% confident that the true population mean of lies in (19.9, 24.9) .

Answer:

[tex] \theta = 210^\circ [/tex] or [tex] \theta = 330^\circ [/tex]

Step-by-step explanation:

[tex] 4 \sin \theta - 1 = -3 [/tex]

[tex] 4 \sin \theta = -2 [/tex]

[tex] \sin \theta = \dfrac{-2}{4} [/tex]

[tex] \sin \theta = -0.5 [/tex]

For sin θ = 0.5, the reference angle is θ = 30 deg.

[tex] \sin 30^\circ = 0.5 [/tex]

[tex] \theta = 210^\circ [/tex] or [tex] \theta = 330^\circ [/tex]

Answer:

A

Step-by-step explanation:

First, let's label the variables:

[tex]\text{Let }x \text{ represent Kaylee's number of pens,}\\\text{Let }L \text{ represent Lou's number of pens,}\\\text{And let }I \text{ represent Ilene's number of pens.}[/tex]

The first and second sentence, Kaylee at the start has x pens. She gave half to Lou, who started out with two fewer than Kaylee.

In other words, the total Lou now has is:

[tex]L=(\frac{1}{2}x )+(x-2)[/tex]

The first term represents what Kaylee gave to Lou. The second term represents what Lou had originally (two fewer than Kaylee [x]).

Simplifying, we get:

[tex]L=\frac{3}{2}x-2[/tex]

Third sentence. Lou give half of his new total to Ilene, who started out with three fewer pens than Lou. Lou, remember, started with three fewer than Kaylee (x-2). In other words:

[tex]I=(\frac{1}{2}(\frac{3}{2}x-2) )+((x-2)-3)[/tex]

The left represents what is given to Ilene: one-third of Lou's new total. The right represents Ilene's original total: three fewer than Lou: or five fewer than Kaylee. Simplifying gives:

[tex]I=(\frac{3}{4} x-1)+(x-5)\\I=\frac{7}{4}x-6[/tex]

Finally, Ilene gives a third of this new amount to Kaylee, and Kaylee's final amount is 37. Thus:

[tex]37=x-\frac{1}{2}x+\frac{1}{3}(\frac{7}{4}x-6)[/tex]

The first term represents what Kaylee originally started with. The second term represents what she gave to Lou. And the third term represents what Ilene gave to Kaylee. Simplify:

[tex]37=\frac{1}{2}x+\frac{7}{12}x-2\\39=\frac{6}{12}x+\frac{7}{12}x \\39=\frac{13}{12}x\\ 468=13x\\x=36[/tex]

Answer:

Matched pairs design

Step-by-step explanation:

Looking at the options;

-It's not a completely randomized design because a randomized design will assign all individuals to a group which in this case it doesn't.

- It's not a randomized block design because randomized block design will group the subjects in question into 2 or more blocks which have a common characteristic and will then randomly assign subjects in each of the blocks.

-It's a matched pair because every individual/subject undergoes measurements both before and after being treated with the drugs.

Thus, the correct option is matched pairs design.

Answer:

7 batches

Step-by-step explanation:

Answer:  243 cm²

Step-by-step explanation:  If the diameter is 18, the radius is 9. Each square is  9×9, so 81 cm² for each.   Multiply:  81×3 = 243

Or take the length times width  to get area  27×9= 243

Step-by-step explanation:

Here,

7x-6=5x+10 (as it has given already that alternate exterior angle are equal.

now, simplifying,

or,7x-5x = 10+6.

or, 2x=16

or, x=16/2

Therefore the value of x is 8.

i hope it helps.....

Answer:

You just need to demonstrate that the expression is not equivalent. To do that, we just need to evaluate the expression with a specific number.

[tex]\frac{3}{8}x+2 \neq \frac{3}{2}x+5[/tex]

For [tex]x=0[/tex], we have

[tex]\frac{3}{8}(0)+2 \neq \frac{3}{2}(0)+5\\2 \neq 5[/tex]

Notice that the answer is true because 2 is not equivalent to 5.

Therefore, the expression is actually non-equivalent.

Answer:

C

Step-by-step explanation:

The abscissa is the value of the x- coordinate and the ordinate is the value of the y- coordinate.

Since the point is in the second quadrant then x- coordinate will be negative and the y- coordinate positive.

C is the only point which meets this condition and

- 3 = 2(1) - 5 = 2 - 5 = - 3 ( 5 less than twice the ordinate) → C

Answer:

HCF is b since we take the least value. That's it. When the two numbers have same base, the LCM will be the base with greater power. So the answer is LCM = b^2

HOPE THIS HELPS AND PLS MARK AS BRAINLIEST

THNXX :)

HCF is b since we take the least value. That's it. When the two numbers have same base, the LCM will be the base with greater power. So the answer is LCM = b^2.

Complete Question:

Identify the type of sampling used​ (random, systematic,​ convenience, stratified, or cluster​ sampling) in the situation described below;

A researcher selects every 890th social security number and surveys the corresponding person. Which type of sampling did the researcher ​use?

Answer:

Systematic sampling.

Step-by-step explanation:

In Statistics, sampling can be defined as a process used to collect or select data (objects, observations, or individuals) from a larger statistical population using specific procedures.

There are various types of sampling used by researchers and these are;

1. Random sampling.

2. Convenience sampling.

3. Stratified sampling.

4. Cluster sampling.

5. Systematic sampling.

A systematic sampling is a type of probability sampling method which involves the researcher selecting or collecting data from a larger population.

Under systematic sampling method, samples are selected from an ordered (fixed) sample population at periodic interval. Therefore, numbers are assigned to every member of the population and then, the "nth" member are selected by the researcher after choosing a fixed starting point.

In this scenario, the researcher selects every 890th social security number and surveys the corresponding person.

Hence, the type of sampling used by the researcher ​is systematic sampling.

Answer:

False.

Step-by-step explanation:

If you multiply both sides by 1/2, you will get 1/4 at the right side.

So the correct way, to solve h, you have to divide both sides by 1/2.

Answer:

1. The amount of ice needed = 18 m²

2. The amount of fabric needed to manufacture the umbrella is 0.76 m²

3. The height of the cone, is 3.75 cm

4. The dimensions of the deck are;

Width = 28/3 m, breadth = 28/3 m

The area be 87.11 m²

5.   The dimensions of the optimal design for setting the storage area at the corner, we have;

Width = 10m

Breadth = 10 m

The dimensions of the optimal design for setting the storage area at the back of their building are;

Width = 7·√2 m

Breadth = 7·√2 m

Step-by-step explanation:

1. The amount of ice needed is given by the volume, V, of the pyramid given by V = 1/3 × Base area × Height

The base area = Base width × Base breadth = 3 × 5 = 15 m²

The pyramid height = 3.6 m

The volume of the pyramid = 1/3*15*3.6 = 18 m²

The amount of ice needed = 18 m²

2. The surface area of the umbrella = The surface area of a cone (without the base)

The surface area of a cone (without the base) = π×r×l

Where:

r = The radius of the cone = 0.4 m

l = The slant height = √(h² + r²)

h = The height of the cone = 0.45 m

l = √(0.45² + 0.4²) = 0.6021 m

The surface area = π×0.4×0.6021 = 0.76 m²

The surface area of a cone (without the base) = 0.76 m²

The surface area of the umbrella = 0.76 m²

The amount of fabric needed to manufacture the umbrella = The surface area of the umbrella = 0.76 m²

3. The volume, V, of the cone = 1/3×Base area, A, ×Height, h

The volume of the cone V = 150 cm³

The base area of the cone A = 120 cm²

Therefore we have;

V = 1/3×A×h

The height of the cone, h = 3×V/A = 3*150/120 = 3.75 cm

4. Given that the deck will have railings on three sides, we have;

Maximum dimension = The dimension of a square as it is the product of two  equal maximum obtainable numbers

Therefore, since the deck will have only three sides, we have that the length of each side are equal and the fourth side can accommodate any dimension of the other sides giving the maximum dimension of each side as 28/3

The dimensions of the deck are width = 28/3 m, breadth = 28/3 m

The area will then be 28/3×28/3 = 784/9 = [tex]87\frac{1}{9}[/tex] =87.11 m²

5. The optimal design for setting the storage area at the corner of their property with four sides is having the dimensions to be that of of a square with equal sides of 10 m each as follows;

Width = 10m

Breadth = 10 m

The optimal design to have the storage area at the back of their building having a fence on only three sides, is given as follows;

Storage area specified = 98 m²

For optimal use of fencing, we have optimal side size of fencing = s = Side length of a square

s² = 98 m²

Therefore, s = √98 = 7·√2 m

Which gives the width = 7·√2 m and the breadth = 7·√2 m.

Answer:

99,290

Step-by-step explanation:

99,200 + 10(18/2)

= 99,200 + 10(9)

= 99,200 + 90

= 99,290

Answer:

The required fraction is 3/5

Answer:  3/5

Step-by-Step Explanation:

Let x represent the denominator of the fraction, then we have [tex]\dfrac{x-2}{x}[/tex]

Now add 3 to the numerator and 5 to the denominator and set it equal to 3/5:

[tex]\dfrac{(x-2)+3}{(x)+5}=\dfrac{3}{5}\\\\\\\text{Simplify:}\\\dfrac{x+1}{x+5}=\dfrac{3}{5}\\\\\\\text{Cross Multiply and solve for x:}\\5(x+1)=3(x+5)\\5x+5=3x+15\\2x=10\\x=5[/tex]

Substitute x = 5 into the original fraction:

[tex]\dfrac{(5)-2}{(5)}\quad =\large\boxed{\dfrac{3}{5}}[/tex]

Answer:

  0.92

Step-by-step explanation:

Each year, the value declines. This eliminates choices A and D.

The decline from 33000 to 30360 is slightly less than 10%, so the multiplier from one year to the next is slightly more than 1 -10% = 90%. The only choice in range is ...

  0.92 . . . . the third listed choice

Answer:

The third one.

Step-by-step explanation:

The last bar graph is skewed to the right, since the values of its fourth and fifth bars are way smaller than the values of its first, second, and third graphs. The drastically smaller values pull down the mean of the last bar graph, making it be more different from the median.

Comparatively, bar graphs one and two have approximately symmetrical distributions of numbers on both sides of the central bar. This means that their mean is balanced out on both sides and that neither of them is significantly skewed left or right.

A bar graph. The horizontal axis is unnumbered. The vertical axis is numbered 0 to 50. The first bar is 38. The second bar is 43. The third bar is 21. The fourth bar is 5. The fifth bar is 1 is data distribution would most likely have a mean and median that are not close in value.

We have to determine, which data distribution would most likely have a mean and median that are not close in value.

According to the question,

The mean and the median both reflect the skewing, but the mean reflects it more.

The last bar graph is skewed to the right since the values of its fourth and fifth bars are way smaller than the values of its first, second, and third graphs.

The drastically smaller values pull down the mean of the last bar graph, making it be more different from the median.

The mean and the median are the same. This example has one mode (unimodal), and the mode is the same as the mean and median.

Bar graphs one and two have approximately symmetrical distributions on both sides of the central bar.

This means that their mean is balanced out on both sides and that neither of them is significantly skewed left or right.

Hence, The horizontal axis is unnumbered. The vertical axis is numbered 0 to 50. The first bar is 38. The second bar is 43. The third bar is 21. The fourth bar is 5. The fifth bar is 1.

To know more about Probability click the link given below.

https://brainly.com/question/23044118

Answer:

The ratios are;

[tex]\dfrac{BC}{AB} = \dfrac{3}{5}[/tex]

[tex]\dfrac{AC}{AB} = \dfrac{4}{5}[/tex]

[tex]\dfrac{BC}{AC} = \dfrac{3}{4}[/tex]

[tex]\dfrac{DE}{AD} = \dfrac{3}{5}[/tex]

[tex]\dfrac{AE}{AD} = \dfrac{4}{5}[/tex]

[tex]\dfrac{DE}{AE} =\dfrac{3}{4}[/tex]

Step-by-step explanation:

Given that the lengths of the sides are;

[tex]\overline {AB}[/tex]  = 20

[tex]\overline {BC}[/tex]  = 12

[tex]\overline {AC}[/tex]  = 16

[tex]\overline {AD}[/tex]  = 10

[tex]\overline {DE}[/tex]  = 6

[tex]\overline {AE}[/tex]  = 8

The ratios are;

[tex]\dfrac{Length \ opposite \ \angle A}{Hypothenus} = \dfrac{BC}{AB} = \dfrac{12}{20} = \dfrac{3}{5}[/tex]

[tex]\dfrac{Length \ adjacent\ \angle A}{Hypothenus} = \dfrac{AC}{AB} = \dfrac{16}{20} = \dfrac{4}{5}[/tex]

[tex]\dfrac{Length \ opposite \ \angle A}{Length \ adjacent \ \angle A} = \dfrac{BC}{AC} = \dfrac{12}{16} = \dfrac{3}{4}[/tex]

[tex]\dfrac{Length \ opposite \ \angle A}{Hypothenus} = \dfrac{DE}{AD} = \dfrac{6}{10} = \dfrac{3}{5}[/tex]

[tex]\dfrac{Length \ adjacent\ \angle A}{Hypothenus} = \dfrac{AE}{AD} = \dfrac{8}{10} = \dfrac{4}{5}[/tex]

[tex]\dfrac{Length \ opposite \ \angle A}{Length \ adjacent \ \angle A} = \dfrac{DE}{AE} = \dfrac{6}{8} = \dfrac{3}{4}[/tex]

Answer:

Step-by-step explanation:

x = 108

y = 36

z = 72

=============================================================

Explanation:

Check out the diagram below. I have added letters of x, y and z in places to help find the values of y and z. Note the triangle on top is isosceles (since a regular polygon has all sides equal; therefore the triangle on top has the top diagonal sides equal).

Before we find either y or z, let's find x.

For any regular polygon, the interior angles are all the same measure. They sum to 180(n-2). In this case, n = 5, so the angles sum to 180(5-2) = 540. Each individual interior angle is 540/n = 540/5 = 108 degrees

x = 108

Another way to find this interior angle is to first find the exterior angle. For any convex polygon (regular or not), the exterior angles always add to 360. When we talk about regular polygons, each individual exterior angle is 360/n. So in this case, we have 360/5 = 72 as one exterior angle. The adjacent interior angle is therefore x = 180-72 = 108. So there are two ways to find the measure of an interior angle.

--------

Referring to the diagram, specifically the isosceles triangle on top, we can see that it has angles of x, y and y. They add to x+y+y = x+2y. Set this equal to 180, plug in x = 108 and solve for y

x+2y = 180

108+2y = 180

2y = 180-108

2y = 72

y = 72/2

y = 36

--------

The bottom most triangle is a congruent copy of the triangle on top. We have another isosceles triangle with the same side lengths as before. This triangle also has x, y and y as mentioned above.

Notice the adjacent angles of y and z in the bottom left corner. They must add to 108 as this was the measure of the interior angle of a regular pentagon. So,

y+z = x

36+z = 108

z = 108-36

z = 72

Answer:

4a) 110 square centimetres

4b) 127 square centimetres

6) 292 square centimetres

8) 800 tiles

Step-by-step explanation:

4. We need to find the area of the large rectangle and then deduct the area of the unshaded part:

a) The large rectangle has dimensions 12 cm by 15 cm. Its area is:

A = 12 * 15 = 180 square centimetres

The unshaded part has a length of 15 - (3 + 2) cm i.e. 10 cm and a width of 7 cm. Its area is:

a = 10 * 7 = 70 square centimetres

Therefore, the area of the shaded part is:

A - a = 180  - 70 = 110 square centimetres

b) The large rectangle has dimensions 13 cm by 11 cm. Its area is:

A = 13 * 11 = 143 square centimetres

The unshaded part has dimensions 8 cm by 2 cm. Its area is:

a = 8 * 2 = 16 square centimetres

Therefore, the area of the shaded part is:

A - a = 143 - 16 = 127 square centimetres

6. The background area of the space not covered by the photograph is the area of the frame minus the area of the photograph.

The frame has dimensions 24 cm by 18 cm. Therefore, its area is:

A = 24 * 18 = 432 square centimetres

The photograph has dimensions 14 cm by 10 cm. Therefore, its area is:

a = 14 * 10 = 140 square centimetres

Therefore, the background area of the space not covered by the photograph is:

A - a = 432 - 140 = 292 square centimetres

8) The floor has dimensions 8 m by 4 m. The area of the floor is:

A = 8 * 4 = 32 square centimetres

Each square tile has dimensions 20 cm by 20 cm. In metres, that is 0.2 m by 0.2 m. The area of each tile is:

a = 0.2 * 0.2 = 0.04 square metres

The number of tiles that are needed is the area of the floor divided by the area of each tile:

A / a = 32 / 0.04 = 800 tiles

Answer:

c.

Step-by-step explanation:

90 degrees clockwise is (x,y)-(y,-x)

Answer:

The answer is A

Step-by-step explanation:

Took the test

Answer:

D.

A. x ≤ 1

Step-by-step explanation:

Well for the first question we need to simplify the inequality.

4x + 3 < x - 6

-x to both sides

3x + 3 < -6

-3 to both sides

3x < -9

Divide 3

x < -3

So if x is less than -3 than it goes to the left starting at -3.

So D. is the answer.

So to solve the floowing inequality we simplify, distribute, and combine like terms.

3(2x - 5) + 3 ≤ -2(x + 2)

6x - 15 + 3 ≤ -2x -4

6x -12 ≤ -2x - 4

8x - 12 ≤ -4

+12

8x ≤ 8

8/8

x ≤ 1

Hence the answer is A. x ≤ 1

Answer:

The equation of the graph after translating one unit to the left is;

[tex]y = \left | \dfrac{x}{2} - \dfrac{3}{2} \right |+3[/tex]

Step-by-step explanation:

The given equation is [tex]y = \left | \dfrac{1}{2}\cdot x - 2 \right |+3[/tex]

We note that minimum value of y = 3, where 1/2·x - 2 = 0 and x = 4

Therefore, in moving one unit to the left, we have at the y-intercept where slope of the graph has become inverted (reflection of the real graph) we add one to the x value as follows;

[tex]y = \left | \dfrac{1}{2}\cdot (x+1) - 2 \right |+3 = \left | \dfrac{x}{2} + \dfrac{1}{2} - 2 \right |+3 = \left | \dfrac{x}{2} - \dfrac{3}{2} \right |+3[/tex]

The equation of the graph becomes;

[tex]y = \left | \dfrac{x}{2} - \dfrac{3}{2} \right |+3[/tex].

Answer:

A right scalene triangle would have a 90 degree angle and 3 non congruent sides

Step-by-step explanation: