Will give brainliest!! How would you write the direction of the vector above as a global angle?
Answer:
Assuming they're unit vectors (length of 1)
You simply add them together.
The vector pointing right can be described with X and Y
(1, 0).
The vector pointing down
(0, -1).
The numbers are taken from the axis in X and Y directions.
If you add them together you get a final vector.
(1, - 1)
This gives you -45° pointing South East.
Or 360°-45°=315°
Which example illustrates Newton's second law?
A. A wheelbarrow remains stationary when no one pushes on it.
B. More mass is added to a wheelbarrow, and a larger force is
required to move it.
C. A person pushes a wheelbarrow, causing it to move forward.
D. The force of a wheelbarrow on the ground is equal to the force of
the ground on the wheelbarrow.
Answer:B
Explanation:
Mass
More mass is added to a wheelbarrow, and a larger force is required to move it - illustrates Newton's second law.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Newton’s second law of motion states that “Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration."
Hence more mass is added to a wheelbarrow, and a larger force is required to accelerate, i.e., move it.
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What happens to the kinetic energy of a hot drink when an ice cube is put into the drink?
Answer:
Heat is kinetic energy -- the higher the temperature of a substance, the faster and farther its molecules move.
Explanation:
... Conversely, when heat transfers from your beverage to the ice and the temperature of the liquid drops, the molecules in the beverage slow down. When those molecules slow down, their kinetic energy decreases.
If a car manufacturer reduced the mass of a new car model, so that it took a force of 4000 N
to accelerate towards the barrier at 4 m/s2, what would be the mass of
the new car?
Answer:
1000 kg
Explanation:
Force = mass x acceleration, Hence, mass = Force/acceleration
mass = 4000/4 = 1000 kg
pls help me with this question pls
Explanation:
pls help me with this question pls
Two students are measuring the Gravitational Attraction between each other. One student weighs 120 kg. The other student weighs 108 kg. Calculate the gravitational pull they have on each other.
Answer:
[tex]F=8.64\times 10^{-9}\ N[/tex]
Explanation:
Given that,
Mass of student 1, m₁ = 120 kg
Mass of student 2, m₂ = 108 kg
Let they are at a distance of 10 m.
We need to find the gravitational pull they have on each other. The gravitational force acting between two objects is given by :
[tex]F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{120\times 108}{(10)^2}\\\\=8.64\times 10^{-9}\ N[/tex]
So, the gravitational pull between students is [tex]8.64\times 10^{-9}\ N[/tex].
Which has the most momentum?
Select one:
A. 100 kg at rest
B. 20 kg at 2 m/s
C. 5 kg at 50 m/s
D. 10 kg at 5 m/s
Answer: C
Explanation:
A: 100kg*0m/s (obviously not answer)
B: 20kg*2m/s (=40)
C: 5kg*50m/s (=250, safe bet this one is it)
D: 10kg*5m/s (=50)
5 kg at 50 m/s, with a momentum of 250 kg m/s has the most momentum.
Hence, the correct option is C.
To calculate momentum, we use the formula:
Momentum (p) = Mass (m) × Velocity (v)
Let's calculate the momentum for each option:
A. 100 kg at rest
Momentum = 100 kg × 0 m/s = 0 kg m/s
B. 20 kg at 2 m/s
Momentum = 20 kg × 2 m/s = 40 kg m/s
C. 5 kg at 50 m/s
Momentum = 5 kg × 50 m/s = 250 kg m/s
D. 10 kg at 5 m/s
Momentum = 10 kg × 5 m/s = 50 kg m/s
Therefore, 5 kg at 50 m/s, with a momentum of 250 kg m/s has the most momentum.
Hence, the correct option is C.
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can u plz help
Define: Medium
Answer:
Medium: something in a middle position, maybe in between sizes big or small, or in a situation it's not negative or positive it's just neutral. (I'm sorry if that wasn't helpful)
Explanation:
What is the net force on a bathroom scale when a 110 pound person stands on it? How do you know?
A ball that is out of play is called a __________________. 2. Volleyballs are made out of __________________ material. 3. A __________________ occurs when the server steps on or over the end line. 4. Contact of the ball by a player is called __________________. 5. The __________________ decides who will serve and the choice of playing area.
Answer:
1) Deadball
2) Leather
3) Foot Fault
4) Pass
5) Captain
Explanation:
1) In most sports when a ball is out of play or termed temporarily unplayable, it is said to be a Deadball.
2) Volleyballs are generally made of leather materials be it synthetic or genuine leather.
3) In volleyball, when a server steps on or over the end line, it is called foot fault.
4) The first contact of a ball by a player after a serve from a passer is usually called a pass.
5) In volleyball, the referee issues a coin toss in presence of both captains and the captain with the winning toss is the one that makes the choice of play area and the first server.
There is friction between the block and the
table.
The suspended 2 kg mass on the left is
moving up, the 4 kg mass slides to the right
on the table, and the suspended mass 4 kg on
the right is moving down.
The acceleration of gravity is 9.8 m/s
2
.What is the magnitude of the acceleration
of the system?
1. 1.67253
2. 1.9845
3. 1.75311
4. 2.47673
5. 2.1315
6. 2.058
7. 2.548
8. 1.33933
9. 1.5288
10. 2.03127
Answer in units of m/s
2
.
Answer:
5 no
Explanation:
actually the 4kg lying on table has no influence
it slides towards 4kg weight hung
as it has excess 2kg force
force=miu × m ×g
The magnitude of acceleration of the entire system is [tex]2.1315 \;\rm m/s^{2}[/tex]. Hence, option (5) is correct.
Given data:
The masses suspended from the table are, m = 2 kg and m' = 4 kg.
And the mass kept on the table is, m'' = 4 kg.
The frictional force will oppose the motion of mass 4 kg, kept on the table. Then the required value of frictional force is,
[tex]f = \mu \times m'' \times g\\\\f = 0.11 \times 4 \times 9.8\\\\f = 4.312 \;\rm N[/tex]
Since, the mass kept on the right side is more. Then at equilibrium,
-f + m''g + (m' +m)a = m'g
Here,
a is the magnitude of acceleration of the system.
Solving as,
-4.312+ 4(9.8) + (4 -2)a = 4(9.8)
2a = 4.312
[tex]a \approx 2.1315 \;\rm m/s^{2}[/tex]
Thus, we can conclude that the magnitude of acceleration of the entire system is [tex]2.1315 \;\rm m/s^{2}[/tex]. Hence, option (5) is correct.
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A weight lifter is trying to lift a 1,500 N weight but can apply a force of only 1,200 N on the weight. One of his friends helps him lift it at a constant velocity. What force was applied to the rope
Answer:
400N is applied to the rope
Answer:
300N
Explanation:
Assuming his friend didn't throw the box, they would need a total of 1,500N to lift it, if the first person is already applying 1,200N, the only other amount of force needed is 300N to make a total of 1,500N! Simple math problem :)
Hope this helps! <3
A man drops a penny V=0 off the top of the Golden Gate Bridge how fast will the penny be moving when it hits the ground? The golden hat bridge is 275 meters tall
Answer:
Vf = 73.4 m/s
Explanation:
This is the case of vertical motion where we have to find the final velocity of the penny when it hits the ground. We can use 3rd equation of motion to find the final velocity:
2gh = Vf² - Vi²
where,
g = 9.8 m/s²
h = height = 275 m
Vf = Final Velocity = ?
Vi = Initial Velocity = 0 m/s
Therefore,
2(9.8 m/s²)(275 m) = Vf² - (0 m/s)²
Vf = √5390 m²/s²
Vf = 73.4 m/s
The speed with penny dropped from the Golden Gate Bridge hits the ground is 73.4m/s.
Given the data in the question;
Since the penny was at rest before it was dropped
Initial velocity; [tex]u = 0[/tex]Height or distance of the golden hat bridge; [tex]s = 275m[/tex]Final velocity; [tex]v = \ ?[/tex]
To determine the speed with which the penny hits the ground, we use the Third Equation of Motion:
[tex]v^2 = u^2 + 2as[/tex]
Where v is the final velocity, u is the initial velocity, s is the height of the bridge and a is acceleration due to gravity ( since its under gravity; [tex]a = g = 9.8m/s^2[/tex] )
We substitute our values into the equation
[tex]v^2 = 0 + [ 2\ *\ 9.8m/s^2\ *\ 275m]\\\\v^2 = 5390m^2/s^2\\\\v = \sqrt{5390m^2/s^2}\\\\v = 73.4 m/s[/tex]
Therefore, the speed with penny dropped from the Golden Gate Bridge hits the ground is 73.4m/s.
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Un automóvil se mueve hacia el norte siguiendo una trayectoria rectilínea con una velocidad constante, recorre 195 Km cada 1.3 h. ¿Calcula la velocidad con que se mueve?
Answer:
La velocidad con la que se mueve el automóvil es 150 [tex]\frac{km}{h}[/tex]
Explanation:
La velocidad es una magnitud que expresa la relación entre el espacio recorrido por un objeto, el tiempo empleado para ello y su dirección.
Es decir, la velocidad se define como la relación que se establece entre la distancia recorrida y el tiempo transcurrido en el movimiento de un móvil.
Se puede calcular la magnitud de la velocidad utilizando la siguiente expresión:
[tex]velocidad=\frac{distancia}{tiempo}[/tex]
En este caso:
distancia= 195 kmtiempo= 1.3 hReemplazando:
[tex]velocidad=\frac{195 km}{1.3 h}[/tex]
Resolviendo:
velocidad=150 [tex]\frac{km}{h}[/tex]
La velocidad con la que se mueve el automóvil es 150 [tex]\frac{km}{h}[/tex]
A horse gallops for 3.5 minutes around the raceing track. During this time it changes velocity from 543 min to 628 min. Calculate the acceleration of the horse during this 3.5min interval
Answer:
The acceleration of the horse during this time interval is 24.286 m/min²
Explanation:
Given;
initial velocity of the horse during the gallop, u = 543 m /min
final velocity of the horse during the gallop, v = 628 m /min
time of motion, t = 3.5 minutes
The acceleration of the horse is given by the change in velocity per change in time;
[tex]a = \frac{v-u}{t}\\\\a = \frac{628-543}{3.5}\\\\a = 24.286 \ m/min^2[/tex]
Therefore, the acceleration of the horse during this time interval is 24.286 m/min²
Which quantities define momentum?
Answer:
velocity and mass
Explanation:
:) apek
If Chris throws the baseball 60 meters forward in 4.2 sec, what is the velocity of the ball? I need answer immediately
Answer:
14.3 m/s
Explanation:
velocity equation
v= d/t
v= 60/4.2
v=14.28
round it to 1 decimal place
v= 14.3m/s
If the velocity of an object is zero, then that object cannot be accelerating. | True or False
Answer: False
Explanation:
Where would you find the photosphere
Determine the gain in the potential energy when a 8.0 kg box is raised 17.2 m.
Answer:
The answer is 1376 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
PE = 8 × 10 × 17.2
We have the final answer as
1376 JHope this helps you
Explanation:
potential energy = mgh
potential energy = 8 * 10 * 17.2
potential energy = 1376 joules
You are at a circus and you see a stunt man climb up 29.4 meters into a cannon. He gets fired horizontally out of the cannon with a speed of 57.1 m/s. How long was stunt man in the air for?
Answer:
t = 2.44 s
Explanation:
Given that,
A stunt man climb up 29.4 meters into a cannon. He gets fired horizontally out of the cannon with a speed of 57.1 m/s.
We need to find the time for which was the stunt man in the air. Let it is t. It can be calculated using second equation of motion as follows :
[tex]s=ut+\dfrac{1}{2}gt^2[/tex]
u is initial speed and it is 0
[tex]s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2\times 29.4}{9.8}} \\\\t=2.44\ s[/tex]
So, the stunt man is in the air for 2.44 seconds.
A man carries a load of mass 2.6kg from one end of a uniform pole 100cm long which has a mass 0.4kg. The pole rest on his shoulder at a point 60.0cm from the load and he holds it by the other end. What vertical force must be applied by his hand and what is the force on his shoulder?
Answer:
F = 39.2 N (hand force) and N = 68.6 N (shoulder force)
Explanation:
In this exercise we must use the rotational and translational equilibrium conditions, we have several forces: the weight (W) of the pole applied at its geometric center, the load (w1) at one end, the shoulder support (N) 60 cm from the load and hand force (F) at the other end of the pole
Let's set the reference system at the fit point of the shoulder
∑ τ = 0
We will assume that the counterclockwise turns are positive
w₁ 0.60 + W 0.1 + F₁ 0 - F 0.4 = 0
all distances are measured from the support of the man (x₀ = 0.60 m)
F = (w₁ 0.60 + W 0.1) / 0.4
F = (m₁ 0.6 + m 0.1) g / 0.4
let's calculate
F = (2.6 0.6 + 0.4 0.1) 9.8 / 0.4
F = 39.2 N
this is the force that the hand must exert to keep the system in balance
We apply the translational equilibrium condition
-w₁ -W + N - F = 0
N = w₁ + W + F
N = (m₁ + m) g + F
let's calculate
N = (2.6 + 0.4) 9.8 + 39.2
N = 68.6 N
Which of the following is a FALSE statement? (A) Heat moves through solids by conduction (B) Molecules move faster in warmer substances (C) Warm water is denser than cold water (D) Heat moves through liquids and gases by convection
Answer:
C.
Explanation:
What do scientists use to measure force?
Answer:
force meter
Explanation:
Answer:
Wrong, the correct answer is "newton"
Explanation:
1 Newton = 1 kilogram-meter per second2
According to the Declaration of Independence, all people are created in what manner?
Answer:
All men are created equal.
Explanation:
We hold these truths to be self-evident, that all men are created equal, that they are endowed by their Creator with certain unalienable Rights, that among these are Life, Liberty and the pursuit of Happiness.
-Declaration of Independence
A 3kg ball moving at 8 m/s strikes a 2kg ball at rest,if the collision is elastic,what is the speed of the lighter ball if the heavier ball moves at 2m/s in the opposite direction
Answer:
Speed of lighter ball is 4 m/s.
Explanation:
Applying the principle of conservation of linear momentum,
momentum before collision = momentum after collision.
[tex]m_{1}[/tex][tex]u_{1}[/tex] + [tex]m_{2}[/tex] [tex]u_{2}[/tex] = [tex]m_{1}[/tex][tex]v_{1}[/tex] - [tex]m_{2}[/tex][tex]v_{2}[/tex]
[tex]m_{1}[/tex] = 3 kg, [tex]u_{1}[/tex] = 8 m/s, [tex]m_{2}[/tex] = 2 kg, [tex]u_{2}[/tex] = 0 m/s ( since it is at rest), [tex]v_{1}[/tex] = 2 m/s, [tex]v_{2}[/tex] = ?
(3 x 8) + (2 x 0) = (8 x 2) - (2 x [tex]v_{2}[/tex])
24 + 0 = 16 - 2[tex]v_{2}[/tex]
2[tex]v_{2}[/tex] = 16 - 24
2[tex]v_{2}[/tex] = -8
[tex]v_{2}[/tex] = [tex]\frac{-8}{2}[/tex]
= -4 m/s
This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.
Answer if you know
If you give me a good explanation on how quantum mechanics work, you get 20 points and possibly a brainliest.
Answer:
spectra.
Atomic spectra is series of colored lines which occures when atoms emit light of certain wavelengths. Element produces a particular set of spectral lines.
Electrons exist in shells and each shell has a specific energy. Electrons absorb photons and jump to higher energy levels.
Explanation:
W1 has a weight of 220 N acting 0.6m away from the pivot.
How far does W2 whose weight is 180 N need to sit for the see
saw to be in equilibrium.
&
?
W-220 N
W2 - 180N
a) 0.3 m
Ob) 0.73 m
C) 0.5m
O d) 0.83 m
Answer:
0.73m
Explanation:
Given parameters:
W1 = 220N
D1 = 0.6m
W2 = 180N
Unknown
D2 = ?
Solution:
The torque on each side must be balanced;
Torque = force x distance
T₁ = T₂
W1 x D1 = W2 x D2
Insert the parameters and solve for D2;
220 x 0.6 = 180 x D2
132 = 180D2
D2 = [tex]\frac{132}{180}[/tex] = 0.73m
Disponemos de datos de presión y volumen de tres situaciones de un gas ideal que se han medido manteniendo la temperatura del gas constante representa los valores de un gráfico p-v expresa matemáticamente la ley de Boyle-Mariotte y calcula el valor de la constante
Answer:
Explanation:
This is an exercise in thermodynamics, the ideal gas equation is
PV = n R T
In this case the temperature is constant, so
n R T = cte
throughout the experiment
We can write the relationship for the three points 1, 2 and 3
P₁ V₁ = P₂ V₂ = P₃ V₃ = cte
In the attached graph we can see a graph of this relationship
the data for this graph are
V(m³) P ( Pa)
V₀ P₀
V₀/2 2 P₀
V₀/4 4 P₀
for the graph, let it be assumed that V₀ = 1 and P₀ = 1
To calculate the value of the constant s, you must know the moles of gas and the temperature at which the experiment is carried out, for example, if we have a mole of gas and room temperature (T = 300K), the constant is
n R T = 1 8,314 300
n R T = 2492.2 J
If you committed a crime, would it be easy for investigators to match this print to your records? Why or why not? Hint: how’s the quality of the lifted print? How rare is your pattern? (At least two sentences)
Answer:
This question is incomplete
Explanation:
This question is incomplete because of the absence of the picture of the print in question. However, when the quality of the print obtained from a crime scene is high/good, then this is a good/positive step in identification of a suspect. However, if the quality is bad, other options might need to be explored in addendum to the print obtained in identifying a suspect.
If the quality of the print is good enough to make a pattern, then another factor comes into play. If the pattern is a rare pattern or is not common, then it becomes easier to identify the suspect because there would be fewer people having that fingerprint and fewer people to deal with. Of the three major patterns of fingerprints (whorl, loop and arch), arch fingerprints are the least common.