false, an independent event is an event that isn't affected
The statement given is false
What is a dependent event?
Two events are dependent, when the outcome of the first event influences the outcome of the second event.
Given that, Picking the first second and third place winners at a track meet is an independent even,
This statement is not correct.
The event is a dependant variable, the 1st person is picked based on the 1st mark on the track, so is the second and the 3rd. their position influence the outcome of the other.
the position of the 1st, 2nd or 3rd is influenced by time and speed, so the positions will be picked based on the participant scores /effect of time or speed of the 1st person to reach the track meet.
For more references on dependent events, click;
https://brainly.com/question/12138721
#SPJ2
Is this equation linear or nonlinear?
y =x/2
Answer:
linear
Step-by-step explanation:
Solve for X in the equation, where 4B = −2X − 2A
Answer:
X = [tex]\left[\begin{array}{ccc}2&-7&3\\13&0&2\end{array}\right][/tex]
Step-by-step explanation:
4B = -2X - 2A
Dividing both sides by -2
=> -2B = X + A
Subtracting A to both sides
=> X = -2B-A
Now, Let's Solve:
=> X = [tex]-2\left[\begin{array}{ccc}0&2&-2\\5&0&3\end{array}\right] -\left[\begin{array}{ccc}-2&3&1\\-3&0&4\end{array}\right][/tex]
=> X = [tex]\left[\begin{array}{ccc}-2*0&-2*2&-2*-2\\-2*5&-2*0&-2*3\end{array}\right] - \left[\begin{array}{ccc}-2&3&1\\-3&0&4\end{array}\right][/tex]
=> X = [tex]\left[\begin{array}{ccc}0&-4&4\\10&0&6\end{array}\right] - \left[\begin{array}{ccc}-2&3&1\\-3&0&4\end{array}\right][/tex]
=> X = [tex]\left[\begin{array}{ccc}0-(-2)&-4-3&4-1\\10-(-3)&0-0&6-4\end{array}\right][/tex]
=> X = [tex]\left[\begin{array}{ccc}2&-7&3\\13&0&2\end{array}\right][/tex]
please help me please!!!
Answer:
she has covered 6 miles in 1 ½ hours
Step-by-step explanation:
you need to learn how to read a graph.
it quite easy actually.
just look where the line on the graph is on 1.5 hours ( you can count the boxes if you don't know where 1.5 or 1 ½ is)
The daily revenue at a university snack bar has been recorded for the past five years. Records indicate that the mean daily revenue is $2700 and the standard deviation is $400. The distribution is skewed to the right due to several high volume days (football game days). Suppose that 100 days are randomly selected and the average daily revenue computed. According to the Central Limit Theorem, which of the following describes the sampling distribution of the sample mean?
a. Normally distributed with a mean of $2700 and a standard deviation of $40
b. Normally distributed with a mean of $2700 and a standard deviation of $400
c. Skewed to the right with a mean of $2700 and a standard deviation of $400
d. Skewed to the right with a mean of $2700 and a standard deviation of $40
Answer:
a. Normally distributed with a mean of $2700 and a standard deviation of $40
Step-by-step explanation:
Given that:
the mean daily revenue is $2700
the standard deviation is $400
sample size n is 100
According to the Central Limit Theorem, the sampling distribution of the sample mean can be computed as follows:
[tex]\mathbf{standard \ deviation =\dfrac{ \sigma}{\sqrt{n}}}[/tex]
standard deviation = [tex]\dfrac{400}{\sqrt{100}}[/tex]
standard deviation = [tex]\dfrac{400}{10}}[/tex]
standard deviation = 40
This is because the sample size n is large ( i,e n > 30) as a result of that the sampling distribution is normally distributed.
Therefore;
the statement that describes the sampling distribution of the sample mean is : option A.
a. Normally distributed with a mean of $2700 and a standard deviation of $40
Chapter: Simple linear equations (Answer in steps)
Step-by-step explanation:
5) a. x/2 = 7-5
x/2 = 2
x = 2×2
x=4
b.4x - 2 = 3x +7
4x - 3x = 7 + 2
x = 9
c. x+2 = 42 × 3
x+2 = 126
x = 124
d. 13x + 260 = 39
13x = 39 - 260
13x = -221
x = -17
6) a. 6x / 7 = 4 +2
6x = 6 × 7
6x = 42
x = 7
b. -49 = 7x + 7
-49 - 7 = 7x
7x = - 56
x = -8
c. -7 + 7x - 21 = 0
7x - 28 = 0
7x = 28
x = 4
d. 8x - 32 + 2 = 42
8x - 30 = 42
8x = 42 + 30
8x = 72
x = 9
e. 5x + 7 = 18
5x = 11
x = 2.5
Help please! Your effort is appreciated!
Answer:
[tex]a^1[/tex]
Step-by-step explanation:
We want to rewrite [tex]\frac{a * a * a * a * a * a * a}{a * a * a* a * a * a}[/tex] in index form. That is:
[tex]\frac{a * a * a * a * a * a * a}{a * a * a * a * a * a} = \frac{a^7}{a^6}\\ \\= a^{7 - 6}\\\\= a^1[/tex]
where n = 1
Suppose a college student pays $750 for tuition fees. However, she also has to pay $300 for her textbooks (ouch!). What percent of her total education costs does she pay for her books?
Answer:
Total costs = $700 + $300 = $1000.
$300 / $1000 = 0.3 = 3%
Step-by-step explanation:
You are given the following information obtained from a random sample of 5 observations. 20 18 17 22 18 At 90% confidence, you want to determine whether or not the mean of the population from which this sample was taken is significantly less than 21. (Assume the population is normally distributed.) a) State the null and the alternative hypotheses. b) Compute the standard error of the mean. c) Determine the test statistic. d) Test to determine whether or not the mean of the population is significantly less than 21.
Answer:
a
The null hypothesis is
[tex]H_o : \mu = 21[/tex]
The Alternative hypothesis is
[tex]H_a : \mu< 21[/tex]
b
[tex]\sigma_{\= x} = 0.8944[/tex]
c
[tex]t = -2.236[/tex]
d
Yes the mean population is significantly less than 21.
Step-by-step explanation:
From the question we are given
a set of data
20 18 17 22 18
The confidence level is 90%
The sample size is n = 5
Generally the mean of the sample is mathematically evaluated as
[tex]\= x = \frac{20 + 18 + 17 + 22 + 18}{5}[/tex]
[tex]\= x = 19[/tex]
The standard deviation is evaluated as
[tex]\sigma = \sqrt{ \frac{\sum (x_i - \= x)^2}{n} }[/tex]
[tex]\sigma = \sqrt{ \frac{ ( 20- 19 )^2 + ( 18- 19 )^2 +( 17- 19 )^2 +( 22- 19 )^2 +( 18- 19 )^2 }{5} }[/tex]
[tex]\sigma = 2[/tex]
Now the confidence level is given as 90 % hence the level of significance can be evaluated as
[tex]\alpha = 100 - 90[/tex]
[tex]\alpha = 10[/tex]%
[tex]\alpha =0.10[/tex]
Now the null hypothesis is
[tex]H_o : \mu = 21[/tex]
the Alternative hypothesis is
[tex]H_a : \mu< 21[/tex]
The standard error of mean is mathematically evaluated as
[tex]\sigma_{\= x} = \frac{\sigma}{ \sqrt{n} }[/tex]
substituting values
[tex]\sigma_{\= x} = \frac{2}{ \sqrt{5 } }[/tex]
[tex]\sigma_{\= x} = 0.8944[/tex]
The test statistic is evaluated as
[tex]t = \frac{\= x - \mu }{ \frac{\sigma }{\sqrt{n} } }[/tex]
substituting values
[tex]t = \frac{ 19 - 21 }{ 0.8944 }[/tex]
[tex]t = -2.236[/tex]
The critical value of the level of significance is obtained from the critical value table for z values as
[tex]z_{0.10} = 1.28[/tex]
Looking at the obtained value we see that [tex]z_{0.10}[/tex] is greater than the test statistics value so the null hypothesis is rejected
Write the equation 0.3x 2 + 5x - 7 = 0 in general form and then choose the value of "b."
Answer:
3x^2 + 50x - 70 = 0
b = 50
Step-by-step explanation:
0.3x^2 + 5x - 7 = 0
Multiply both sides by 10 to get rid of the decimal coefficient.
3x^2 + 50x - 70 = 0
b = 50
solve for the variable x^2 - 8 = -1 Show all work please
Answer:
x = ±sqrt(7)
Step-by-step explanation:
x^2 - 8 = -1
Add 8 to each side
x^2 - 8+8 = -1+8
x^2 = 7
Take the square root of each side
sqrt(x^2) = ±sqrt(7)
x = ±sqrt(7)
How can I factor these complex conjuages? a^2 + b^2 and a^2 - b
Answer:
1) [tex](a+ib)(a-ib)[/tex]
2) [tex]a^2+i^2b[/tex]
Step-by-step explanation:
1) [tex]a^2+b^2[/tex]
=> [tex]a^2 - (-1)b^2[/tex] (We know that -1 = [tex]i^2[/tex] )
=> [tex]a^2-i^2b^2[/tex]
=> [tex](a)^2-(ib)^2[/tex]
Using Formula [tex]a^2 -b^2 = (a+b)(a-b)[/tex]
=> [tex](a+ib)(a-ib)[/tex]
2) [tex]a^2-b[/tex]
=> [tex]a^2+(-1)b[/tex] (We know that -1 = [tex]i^2[/tex] )
=> [tex]a^2+i^2b[/tex] (It cannot be simplified further)
Answer:
[tex]\boxed{(a+ib)(a-ib)}[/tex]
[tex]\boxed{a^2+i^2b}[/tex]
Step-by-step explanation:
[tex]a^2 + b^2[/tex]
Rewrite expression.
[tex]a^2- (-1)b^2[/tex]
Use identity : [tex]-1=i^2[/tex]
[tex]a^2- i^2 b^2[/tex]
Factor out square.
[tex]a^2-(ib)^2[/tex]
Apply difference of two squares formula : [tex]a^2-b^2 =(a+b)(a-b)[/tex]
[tex](a+ib)(a-ib)[/tex]
[tex]a^2-b[/tex]
Rewrite expression.
[tex]a^2+(-1)b[/tex]
Use identity : [tex]-1=i^2[/tex]
[tex]a^2+i^2b[/tex]
6th grade math , help me please :)
Answer:
a= 7/20
b=35
Step-by-step explanation:
A was simple because 7 people with blue eyes for every 20 people written in fraction form. For b they say what if it was 100 total people so 20 x 5 = 100 so 7 x 5= 35 so your answer to b is 35
6th grade math, help me please:)
Answer:
8:3 is the ratio of kids to adults
32 kids, so there are 12 adults
Answer:
32 kids to 4 adults
Step-by-step explanation:
1st row- 8 kids to 3 adults
2nd row- 16 kids to 6 adults
3rd row- 24 kids to 9 adults
4th row- 32 kids to 12 adults
Victor is in the 28% tax bracket.
a. How much will a $900 tax credit save him?
b. how much will a $900 charitable contribution save him if he itemized his deductions?
Incomplete question. I've made some assumptions to provide clarity.
Answer:
a. $45,743.07
b. $44,843.07
Step-by-step explanation:
Let's assume Victor is a single filer with an income of $100,000.
Using the 2017 tax bracket rates for single filers, Victor would be expected to pay:
- 10 percent on the first $9,325 = 10% x 9525 =$932.5
- plus 15 percent of the amount between $9,326 and $37,950 (37950-9326) x 15% = $4293.6
- plus 25 percent of the amount between $37,951 and $91,900 (91900-37,951 ) x25% = $13487.25
- plus 28 percent of the amount over $91,901-$191,650 (191650-91901) x 28% = 27929.72
Total= $46,643.07
Minus $900 tax credit= $46,643.07-$900= $45,743.07
Minus $900 charitable contribution = $45,743.07-$900= $44,843.07
Hey, the question is with the image. Pls help
Answer:
8
Step-by-step explanation:
Add (7.8x10^5+(2.4x10^5)
answer: 1020000
step-by-step explanation:
(7.8*10^5+(2.4*10^5) given expression
(7.8*10^5)+(2.4*10^5) group with parenthesis
(7.8+2.4)*10^5 combine like terms
10.2*10^5 preform addition
10.2*100000 evaluate the exponent
1020000 multiply out
What is the image of (-8, 10) when reflected in the y-axis?
Answer:
if you're just reflecting the point over the y-axis it just becomes (8,10)
Answer: (8, 10)
Explanation and Example:
I have a trick that I use. I'm not sure if it will make sense to you but I'll explain it. When the question asks you to reflect over the x-axis, then keep the x in (x,y) the same and just flip the sign for the y. If the question asks you to reflect over the y-axis, then keep y the same and flip the sign for x.
Reflect over x-axis:
(-2, 6) -----> (-2, -6)
Reflect over y-axis:
(-4, -8) -----> (4, -8)
an office supply company sells two types of printers. they charge $95 for one of the printers and $125 for the other. if the company sold 32 printers for a total of$3340 last month, how many of each type were sold
Answer:
22 of the 95$ ones and 10 of the 125
Step-by-step explanation:
22 times 95 = 2090
10 times 125 = 1250
2090+1250=3340
hope this helped
10. Here is a list of 25 scores on a Math midterm exam: 38.5, 41.5, 52, 52.5, 61, 63, 63.5, 68, 69, 69, 78.5, 79, 80, 83, 87, 88.5, 88.5, 91, 91.5, 92, 92.5, 94, 94, 97, 97 Find P36:
Answer:
69
Step-by-step explanation:
Since the values in the data set has been ranked already from smallest to largest, as shown in the question.
Then calculate the index,
To find the 36th percentile using the data set,
Multiply k (36/100) by n (25) to reach an index of 9.
Then since the index is whole number,
To calculate percentile according to the 'greater than' method, count the values in the data set from smallest to largest until you reach the number ranked 9th
Which is 69.
Since the value for the 36th percentile must be greater than the first nine values, the 10th ranked value would be the kth (36th) percentile. In this data set, that value is 69.
Alternatively, using the 'greater than or equal to' method, after getting the 9th rank,
Include the ninth-ranked value, (69) in this data set.
The kth (36th) percentile is then calculated by taking the average of that value in the data set (69) and the next ranked value (69). (59 + 69) / 2 = 69.
When solving the equation, which is the best first step to begin to simplify the equation? Equation: -2 (x + 3) = -10 A: (-2)(-2)(x+3)= -10(-2) B: -1/2(-2)(x+3)= -10(-1/2) C: -2/2(x+3)= -10/2 D: -2/-10(x+3)= -10/-10
Answer:
B: -1/2(-2)(x+3)= -10(-1/2)
Step-by-step explanation:
The best step to begin to simplify the equation is to try to get a coefficient for the variable x equal to 1. we can do that if we multiply in both sides of the equation by -1/2 as option B.
So, if we keep simplifying, we get:
-2 (x + 3) = -10
-1/2(-2)(x+3) = -10(-1/2)
x + 3 = 5
x + 3 - 3 = 5 - 3
x = 2
Answer:
The answer is B
Step-by-step explanation:
-1/2(2)(x+3)=-10(1/2)
Line segment TS is tangent to circle O at point N.
Circle O is shown. Line segment Q N goes from one side of the circle to the other side. Tangent T S intersects the circle at point N. Point P is on the circle between points Q and N. Point R is on the circle between points Q and N. Angle Q N T is 74 degrees.
If the measure of Angle Q N T is 74°, what is the measure of Arc Q P N?
37°
74°
148°
212°\
Answer:
148°
Step-by-step explanation:
The measure of the intercepted arc QN is twice the measure of inscribed angle QNT.
arc QN = 2(74°) = 148°
_____
Comment on the question and answer
Your description "on the circle between points Q and N" is ambiguous. You used the same description for both points P and R. The interpretation we used is shown in the attachment. If point P is on the long arc NQ, then the measure of arc QPN will be the difference between 148° and 360°, hence 212°. You need to choose the answer that matches the diagram you have.
__
We call angle QNT an "inscribed angle" because it is a degenerate case of an inscribed angle. The usual case has the vertex of the angle separate from the ends of the arc it intercepts. In the case of a tangent meeting a chord, the vertex is coincident with one of the ends of the intercepted arc. The relation between angle measure and arc measure remains the same: 1 : 2.
Answer:
148
Step-by-step explanation:
Edge 2020
Duane is making cookies. The recipe calls for two times as many cups of sugar as butter, two times as many cups of oats as sugar, and two times as many cups of flour as oats. If Duane puts in one cup of butter, how many cups of flour does he need to add? (also this is from MobyMax)
Answer:
Step-by-step explanation:
Let b represent the number of cups of butter needed.
Let s represent the number of cups of sugar needed.
Let o represent the number of cups of oat needed.
Let f represent the number of cups of flour needed.
The recipe calls for two times as many cups of sugar as butter. It means that
s = 2b
Two times as many cups of oats as sugar. It means that
o = 2s
Two times as many cups of flour as oats. It means that
f = 2o
If Duane puts in one cup of butter, it means that b = 1
Therefore,
s = 2 × 1 = 2 cups
o = 2s = 2 × 2 = 4 cups
f = 2o = 2 × 4 = 8 cups
Therefore, he needs to add 8 cups of flour
Answer: Let b represent the number of cups of butter needed. Let s represent the number of cups of sugar needed. Let o represent the number of cups of oat needed. Let f represent the number of cups of flour needed. The recipe calls for two times as many cups of sugar as butter. It means that s = 2bTwo times as many cups of oats as sugar. It means that o = 2sTwo times as many cups of flour as oats. It means that f = 2oIf Duane puts in one cup of butter, it means that b = 1Therefore, s = 2 × 1 = 2 cupso = 2s = 2 × 2 = 4 cupsf = 2o = 2 × 4 = 8 cups Therefore, he needs to add 8 cups of flour
Step-by-step explanation:
The formula relating linear velocity v and angular velocity ω for a circle of radius r is______ , where the angular velocity must be measured in radians per unit time.
Answer:
[tex]v=wr[/tex]
Step-by-step explanation:
The formula relating linear velocity v and angular velocity ω for a circle of radius r is
[tex]v=wr------1[/tex]
where v = linear velocity in m/s
w= angular velocity in rad/s
r= radius of curve
Both linear and angular velocity relates to speeds of objects, while linear velocity is to objects that moves, angular velocity is to objects that turns
Six years ago, an investor purchased a downtown apartment complex and an adjacent piece of land. The current value of the property is $850,000. Of the total, the current value of the apartment complex is $710,000 and the current value of the land is $140,000. Using the straight-line method, assuming an average appreciation of 6% on the land and an average depreciation of 3% on the apartment complex, what was the original value of the property? Round your answer to the nearest dollar.
Answer: $951,064.06 would be your answer.
Step-by-step explanation: Hope that helped!
Which equation shows y-5=x converted to slope intercept form.
Answer:
C) y = x + 5
Step-by-step explanation
Add 5 to both sides
A lottery ticket has a grand prize of $31 million. The probability of winning the grand prize is .000000018. Determine the expected value of the lottery ticket.
Answer:
$0.558
Step-by-step explanation:
The expected value is the sum of the value of each outcome times the chance that it happens. In this case, there are two outcomes:
Win $31 millionWin $0Then our expected value can be calculated as:
[tex]EV=(31,000,000)(0.000000018)+(0)(1-0.000000018)=0.558[/tex]
3. What is the distance from (−4, 0) to (2, 5)? Round your answer to the nearest hundredth. (4 points)
Answer:
7.81
Step-by-step explanation:
its a triangular shape
let x = 4 + 2 = 6
let y = 5
length between two points = h
h² = x² + y²
h² = 6² + 5²
h = sqrt of 61
h = 7.81
The half-life of radioactive iodine is 60 days. How much of a 50-mg sample will be left in 40 days? Round your answer to the nearest tenth.
Answer:
Remaining amount of the element = 31.5 mg
Step-by-step explanation:
Half life of radioactive Iodine is [tex](T_{\frac{1}{2}})[/tex] = 60 days
Formula to get the remaining element after t days is,
[tex]N=N_0(e)^{\lambda.t}[/tex]
Where [tex]\lambda[/tex] = decay constant of the radioactive element
t = duration of the decay (in days)
[tex]N_0[/tex] = Initial amount of the element
N = final amount after decay
For half life period 't' = 60 days
[tex]\frac{N_0}{2}=N_0(e)^{\lambda\times 60}[/tex]
[tex]e^{60\lambda}=0.5[/tex]
[tex]ln(e^{60\lambda})=ln(0.5)[/tex]
[tex]60\lambda =-0.069315[/tex]
[tex]\lambda=-0.0115524[/tex]
Remaining amount of the element after 40 hours,
N = [tex]50(e^{40\lambda} )[/tex]
= [tex]50(e)^{-(0.0115524)\times 40}[/tex]
= 50(0.62996)
= 31.49
≈ 31.5 mg
Therefore, remaining amount of the element after 40 days is 31.5 mg.
Answer:
In 40 days, there would be approximately 31.5 mg remaining.
Step-by-step explanation:
Jeremy's father drives him to school in rush hour traffic in 20 minutes. One day there is no traffic, so his father can drive him 18 miles per hour faster and gets him to school in 12 minutes. How far (in miles) is it from Jeremy's home to school?
Answer:
9 miles
Step-by-step explanation:
Let's say that the speed that Jeremy's father drives Jeremy through traffic is x. When there is no traffic, Jeremy's father drives 18 miles per hour faster than his speed in traffic, x. This would make the speed that Jeremy's father drives Jeremy to school without traffic, 18 / 60 + x. This is as it is 18 miles per hour faster, not 18 miles per minute faster.
Now recall the formula Speed = Distance / Time, or S = D / T. We want the distance here ( How far (in miles) from Jeremy's home to school ) so let's isolate D here in this formula,
S = D / T ⇒ D = S [tex]*[/tex] T - and as you know, the distance from Jeremy's home to school is the same, with or without traffic. So, we can consider case 1 : Jeremy's " distance traveled " in traffic, and case 2 : Jeremy's " distance traveled " without traffic, and make them equal to one another.
20 [tex]*[/tex] x = 12 [tex]*[/tex] ( 18 / 60 + x ),
20x = 3.6 + 12x,
8x = 3.6,
x = 0.45 - Now the distance is 20 [tex]*[/tex] x, and hence 20 [tex]*[/tex] 0.45 = 9 miles
Winston and Alice are taking a trip. Winston left at 8 am and traveled an average of 50 miles per hour. Alice left at 10 am and traveled an average of 70 miles per hour. At what time are they at the same place at the same time? Write a system of equation to represent this situation. Then use the substitution method with that system to determine at the time they will be in the same location. How many miles away from home will they be at that time?
Answer:
3 PM
350 miles
Step-by-step explanation:
Let's say t is the number of hours since 8 AM.
The distance traveled by Winston is:
w = 50t
The distance traveled by Alice is:
a = 70(t−2)
When w = a:
50t = 70(t−2)
50t = 70t − 140
140 = 20t
t = 7
Winston and Alice will be at the same place 7 hours after 8 AM, or 3 PM.
The distance they travel is 350 miles.