Help me please. I kinda need it right now.!

Step-by-step explanation:

Given

[tex]5y - 4 = 126(corresponding \: angles) \\ 5y = 126 + 4 \\ 5y = 130 \\ y = 130 \div 5 \\ = 26[/tex]

Also given

[tex]126 + (6z + 6) = 180(angles \: on \: a \: straight \: line) \\ 132 + 6z = 180 \\ 6z = 18 0 - 132 \\ 6z = 48 \\ z = 48 \div 6 \\ = 8[/tex]

Lastly,

[tex]x = 180 - 126 \\ = 54(angles \: on \: the \: same \: straight \: line \: and \: corresponding \: angles)[/tex]

Answer:

x = 126

y = 26

z = 8

Step-by-step explanation:

6z + 6 + 126 = 180

6z + 132 = 180

6z = 180 - 132

6z = 48

z = 8

6z + 6 + 5y - 4 = 180

6(8) + 6 + 5y - 4 = 180

48 + 2 + 5y = 180

50 + 5y = 180

5y = 180 - 50

5y = 130

y = 26

x = 126 (Because of alternate exterior angles thm)

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