HELP ME PLEASEEEEEEEEEE

Answer:

I'm pretty sure it's 10 to the power of 3.

Step-by-step explanation:

Answer:

C) f(x) = 6.25x + 3

Step-by-step explanation:

In order to know which one of the functions could produce the results in the table we simply need to substitute the number of candy bars for x in the function and solve it to see if it provides the correct total weight shown in the table. If we do this with the functions provided we can see that the only one that provides accurate results would be

f(x) = 6.25x + 3

We can input the # of candies for x and see that it provides the exact results every time as seen in the table.

f(x) = 6.25(1) + 3 = 9.25

f(x) = 6.25(2) + 3 = 15.50

f(x) = 6.25(3) + 3 = 21.75

f(x) = 6.25(4) + 3 = 28

Answer:

(H) is your answer i believe

Step-by-step explanation:

i subtracted 18 from each cost then divided it by 4 and got the numbers of game rented.

Answer:

Because tan represents [tex]\frac{opposite}{adjacent}[/tex] from θ (theta), the equation should be [tex]tan0[/tex]=[tex]\frac{15}{x}[/tex]. Let's leave this equation like that. Now, we need to find the unknown side length, x. We need to use Pythagorean Theorem, because we're given the other two side lengths. The equation should be [tex]x^{2}+15^{2}=17^{2}[/tex]. X should equal ±8 or 8, because a side length can't be a negative value. Now, we can plug in 8 into the equation to get [tex]tan0=\frac{15}{8}[/tex].

Answer:

3 gigabytes

Step-by-step explanation:

69.50 dollars + 5 dollars is 74.50 dollars add 5 dollars 79.50 add 5 dollars again and 84.50 Mark brainliest

Inequalities help us to compare two unequal expressions. Alexander can use 3 gigabyte of data to stay within his budget.

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.

Given that Alexander pays a flat cost of $69.50 per month and $5 per gigabyte. Therefore, the total amount that Alexander pays in a month for x Gb of data used is,

Total Bill amount = Fixed cost + Variable cost for x Gb of data

                            = $69.50 + $5x

Now, as Alexander wants to keep his bill under $85 per month. Therefore, we can write the inequality as,

Total Bill amount < $85

69.50 + 5x < 85

5x < 85 - 69.50

5x < 15.5

x < 15.5/5

x < 3.1

Therefore, Alexander can use 3 gigabyte of data to stay within his budget.

Learn more about Inequalities here:

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Answer:

3y-x =-6

Step-by-step explanation:

The equation of a line in point slope form is expressed as;

y-y0 = m(x-x0)

(x0, y0) is the point = (3, -1)

Given the equation 3xs+y = 1

Get the slope

y = -3x + 1

mx = -3x

m = -3

Since the equation needed is perpendicular to the line, the slope will be expressed as;

M = -1/-3

M = 1/3

Substitute and get the equation needed

y-y0 = m(x-x0)

y - (-1) = 1/3(x-3)

y+1 = 1/3(x-3)

3(y+1) = x-3

3y+3 = x-3

3y - x = -3-3

3y-x =-6

This gives the required equation

The correct answer is 14.

Answer:

1055

Step-by-step explanation:

  473

+ 362

---------  3 + 2 = 5, even in base 8

       5

Now 7 + 6 = "thirteen" = 15 in base 8 so write 5 in the next column, carry 1

  1

  473

+ 362

---------  

      55

1 + 4 + 3 = "eight" = 10 in base 8. Write 0 in the next column, carry 1

  1

  473

+ 362

---------  

 1055

Answer: B. 6 because it's the actual answer.

The scale factor from triangle ABC to XYZ is 6.

Option B is the correct answer.

We have,

From the triangles ABC and XYZ.

Corresponding sides are given as:

AB = 6 x (XY)

BC = 6 x (YZ)

AC = 6 x (XZ)

This means,

The scale factor is 6.

Thus,

The scale factor from triangle ABC to XYZ is 6.

Learn more about triangles here:

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Answer:

P(x,y) reflection in x=y line:(y,x)

9514 1404 393

Answer:

  about 1.4288993 radians

Step-by-step explanation:

The angle to terminal arm A is ...

  ∠A = arctan((-4/5)/(-3/5)) ≈ 4.0688879 radians

The angle to terminal arm B is ...

  ∠B = arctan((-1/√2)/(1/√2)) ≈ 5.4977871 radians

Then the angle between the arms is ...

  5.4977871 -4.0688879 ≈ 1.4288993 . . . radians

Answer:

Option (3)

Step-by-step explanation:

Properties of the equal matrices,

1). Every element of the one matrix are equal to the elements of other.

2). Both the matrices have same dimensions.

If,  [tex]\begin{bmatrix}x+3 & y+4\\ 7 & -5\end{bmatrix}=\begin{bmatrix}5 & 0\\ 7 & z\end{bmatrix}[/tex]

[tex]x+3=5[/tex]

[tex]x=2[/tex]

[tex]y+4=0[/tex]

[tex]y=-4[/tex]

[tex]x=-5[/tex]

Therefore, Option (3) will be the correct option.

Answer:

98

196in³

Step-by-step explanation:

number of cubes in two layers

7 * 7 * 2 = 98

New Volume

98 * 2 = 196in³

Answer:

1.) 98

2.) 196

Step-by-step explanation:

49 + 49 = 98

98 + 98 = 196

V = 196

Answer:

sfsvggghsgxfgjgtdghyfys.com

Answer:

Members of Team A are likely older, and they have less variability in their ages.

Step-by-step explanation:

To solve this question, we need to find the mean and the standard deviation for each team.

Team A 16, 13, 12, 16, 13

The mean is:

[tex]M = \frac{16 + 13 + 12 + 16 + 13}{5} = 14[/tex]

The standard deviation is:

[tex]S = \sqrt{\frac{(16-14)^2 + (13-14)^2 + (12-14)^2 + (16-14)^2 + (13-14)^2}{5}} = 1.67[/tex]

Team B: 10, 13, 16, 16, 10

The mean is:

[tex]M = \frac{10 + 13 + 16 + 16 + 10}{5} = 13[/tex]

The standard deviation is:

[tex]S = \sqrt{\frac{(10-13)^2 + (13-13)^2 + (16-13)^2 + (16-13)^2 + (10-13)^2}{5} = 13} = 2.68[/tex]

Which statement appropriately compares the ages of the team members?

Sample of team A has higher mean age, which means that they are likely older. They also have a smaller standard deviation, so they likely have less variability in their ages.

Answer:

a. one-way within-groups ANOVA

Step-by-step explanation:

Here, the research question meets the conditions required for a one-way within group ANOVA. One way within group anova allows for comparison between the mean of three or more groups or levels of one independent variable on a dependent variable. In the scenario above, the one independent variable is stage of the season with levels : (pre-season, throughout active season and post season) and the dependent variable being the athletes academic performance. It is a within group ANOVA as all subjects are used to test each level of the independent variable. Which is different from between groups where different subjects are assigned to different groups.

Answer:

38.48m squared

Step-by-step explanation:

Area = pi x radius squared

So

3.5 squared is 12.25

12.25 x pi is 38.48

Answer:

Answers - 4

Correct Answer - 1

Probability - 1/4

Answer:

c

Step-by-step explanation:

c

Answer:

Dude, that’s hard!

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Khan

Considering that we want to test if the support for the opponent has decreased, the appropriate set of hypotheses for their significance test is given by:

C.

[tex]H_0: p = 0.45[/tex]

[tex]H_1: p < 0.45[/tex]

At the null hypothesis, we test if the support for the opponent has not decreased, that is, it still is of 45%, hence:

[tex]H_0: p = 0.45[/tex]

At the alternative hypothesis, we test if the support has decreased, that is, it is less than 45%, hence:

[tex]H_1: p < 0.45[/tex]

Hence option C is correct.

More can be learned about hypothesis tests at https://brainly.com/question/26454209

Answer:

The answer should be B: -1<y<3

Answer:

By using cross multiplication method, 1/2 is the difference between two fractions 5/6 and 1/3.

Step-by-step explanation:

Answer:

0.5

[tex]\frac{1}{2}[/tex]

Step-by-step explanation:

[tex]1\frac{1}{3}- \frac{5}{6}=\frac{1}{2}[/tex]

0.5

Answer: Hello Luv........

Isolate the variable by dividing each side by factors that don't contain the variable.

x=19

Step-by-step explanation:

Hope this helps.

Mark me brainest please.

Anna ♥

Answer:Mean is 22. Median is 19. Mode is 31. Range is 18.

Step-by-step explanation:

Mean: add all the numbers and divide the answer by the number of numbers there were in the beginning.

31+16+13+19+31=110

110/5=22

Median: arrange the numbers in or Eder and find the middle

13,16,19,31,31

The middle is 19.

Mode: is the number that shows up frequently

Mode is 31 as it shows up twice

Range is the difference between the biggest and smallest number

31-13=18

18 is the range.

Answer:

centre is (8, -5)

[tex]r = \sqrt{ {g}^{2} + {f}^{2} - c } \\ = \sqrt{64 + 25 - 80} \\ = \sqrt{9} \\ r = 3 \\ radius \: = \: 3 \: units[/tex]

Answer:

0.3634 = 36.34% probability that the Wilson family had at least 5 girls.

0.8554 = 85.54% probability that the Wilson family had at most 5 girls.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either it is a girl, or it is not. The probability of a child being a girl is independent of any other child. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

They had 8 children.

This means that [tex]n = 8[/tex]

The probability of a child being a girl is .5

This means that [tex]p = 0.5[/tex]

Probability that the Wilson family had: at least 5 girls?

This is:

[tex]P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 5) = C_{8,5}.(0.5)^{5}.(0.5)^{3} = 0.2188[/tex]

[tex]P(X = 6) = C_{8,6}.(0.5)^{6}.(0.5)^{2} = 0.1094[/tex]

[tex]P(X = 7) = C_{8,7}.(0.5)^{7}.(0.5)^{1} = 0.0313[/tex]

[tex]P(X = 8) = C_{8,8}.(0.5)^{8}.(0.5)^{0} = 0.0039[/tex]

[tex]P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) = 0.2188 + 0.1094 + 0.0313 + 0.0039 = 0.3634[/tex]

0.3634 = 36.34% probability that the Wilson family had at least 5 girls.

At most 5 girls?

This is:

[tex]P(X \leq 5) = 1 - P(X > 5)[/tex]

In which

[tex]P(X > 5) = P(X = 6) + P(X = 7) + P(X = 8) = 0.1094 + 0.0313 + 0.0039 = 0.1446[/tex]

[tex]P(X \leq 5) = 1 - P(X > 5) = 1 - 0.1446 = 0.8554[/tex]

0.8554 = 85.54% probability that the Wilson family had at most 5 girls.