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Which material is used to magnetically screen electrical equipment from unwanted magnetic
fields?
A: aluminium
B : copper
C : iron
D :steel

Answer:

C) 26.6

Explanation:

I don't know how to calculate vector

The angle between the two vectors is 117⁰

The given parameters;

vector A = 3.00i + 1.00j

vector B = -3.00i + 3.00j

The  angle between the two vectors is calculated as follows;

[tex]cos \ \theta = \frac{A\ . \ B}{|A| \ . \ |B|}[/tex]

The dot product of vector A and B is calculated as;

[tex]A \ . \ B = (3i \ + j) \ . \ (-3i \ + 3j) = (3\times -3) + (1 \times 3) = -9 + 3 =- 6[/tex]

The magnitude of vector A and B is calculated as;

[tex]|A| = \sqrt{3^2 + 1^2} = \sqrt{10} \\\\|B| = \sqrt{(-3)^2 + (3)^2} = \sqrt{18}[/tex]

The  angle between the two vectors is calculated as;

[tex]cos \ \theta = \frac{-6}{\sqrt{10} \ . \sqrt{18} } \\\\cos \ \theta = \frac{-6}{\sqrt{180} } \\\\cos \ \theta = -0.4472\\\\\theta = cos \ ^{-1} (-0.4472) \\\\\theta = 116.6^0 \approx 117^0[/tex]

Thus, the angle between the two vectors is 117⁰

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Answer:

15N

Explanation:

F¹=150N

A=0.01m2²

F2=?

A2=0.1m²

P=F/A

F1/A2=F2/A1

150/0.1=F2/0.01

Answer:

W

Explanation:

The closer you get to the center of the positive point of the electrical feild the stronger the pull gets. Therfore W is the best option.

Answer:

W

Explanation:

The closer you get to the center of the positive point of the electrical feild the stronger the pull gets. Therfore W is the best option.

Answer:

The thickness of the oil slick. t = 173.91 nm

Explanation:

Oil film thickness t is given by the equation

[tex]t = \frac{\lambda}{2n}[/tex]

where λ = wavelength of incident light in air = 400 nm

and n = index of refraction of oil

therefore,

[tex]t =\frac{400}{2\times 1.15}\\t= 173.91 nm[/tex]

The thickness of the oil slick. t = 173.91 nm

Answer:

It makes it lighter when its closer and heavier when its farther way.

Explanation:

Answer:

a. When the magnetic field is constant, there is only a magnetic field in the region of space. When the magnetic field is time dependent, there will be both a magnetic field and an electric field in the region of space.

Explanation:

This is true because according to Maxwell's equation, a time dependent magnetic field produces an electric field.

When the magnetic field is constant, there is no electric field in that region of space. But, when it begins to vary, an electric field is then generated by Maxwell's equation which is given by

CurlE = -dB/dt

So, there is initially no electric field when the magnetic field is constant, but it exists when the magnetic field becomes time dependent.

So when dB/dt = 0

CurlE = 0 ⇒ E = 0

So when dB/dt ≠ 0

CurlE ≠ 0 ⇒ E ≠ 0

Answer:

Explanation:

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Answer:

0.3625

Explanation:

From the given information:

Consider the equilibrium conditions;

On the ladder, net torque= 0

Thus,

[tex]\tau_{net} = 0[/tex]; and

[tex]-fL \s in \theta +m_L g \dfrac{L}{2} cos \theta + mg (7.46\ m) cos \theta = 0[/tex]

However, by rearrangement;

[tex]fL \s in \theta =m_L g \dfrac{L}{2} cos \theta + mg (7.46\ m) cos \theta \\ \\ \mu(m_L + m) gL \ sin \theta = (323 \ N) ( 10.8 \ meters) \ cos 56^0 + (734 \ N) (7.46 \ m) \ cos \ 66.46^0[/tex]

[tex]\mu= \dfrac{ (323 \ N) ( 10.8 \ m) \ cos 56^0 + (734 \ N) (7.46 \ m) \ cos \ 66.46^0}{\Big [(323 \ N)+(734 \ N) \Big] (10.8 \ m)}[/tex]

[tex]\mathbf{\mu= 0.3625 }[/tex]

                  least two STDs that are caused by different microorganisms (such as bacteria, viruses, and so on). Propose at least two ethical strategies for helping to prevent these STDs OTHER THAN abstinence and male and female condoms.

Answer:

Explanation:

Chlamydia is a bacterial infection that affects the reproductive system in a myriad of nasty and invasive ways, including pain during micturition, genital discharge, and spreading to the rectum and eyes. Other than safe sex practices and abstinence, ways to prevent and treat Chlamydia are antibiotics for both partners (if they're both infected) and surgical intervention in severe cases.

Trichomoniasis is a parasitic sexually transmitted disease that infects women but can affect men during intercourse, women who are infected are more likely to suffer from pain in the vaginal area during moments including micturition and intercourse as foul-smelling discharge. The more concerning aspect of this disease is how women afflicted are more likely to give premature birth and spread the infection to the baby upon birth. Much like Chlamydia, Trichomoniasis can be prevented via safe-sex practices and abstinence, but it can also be treated by antibiotics for both sexual partners to prevent spreading it between them.

Answer:

Explanation:

Momentum conservation

[tex]m2v_0+2mv_0=mv_1+2mv_2 \quad (1/m) \quad 4v_0=v_1+2v_2\\[/tex]

Kinetic energy conservation

[tex]\displaystyle \frac{1}{2}m(2v_0)^2+\frac{1}{2}2mv_0^2=\frac{1}{2}mv_1^2+\frac{1}{2}2mv_2^2 \quad (1/m) \quad 6v_0^2=v_1^2+2v_2^2[/tex]

Solve the system

Answer:

cart 1 of mass m is traveling with 2v0 in the +x-direction when it has an elastic collision with cart 2 of mass 2m traveling with speed v0 in the same direction.

What are the velocities of the carts after the collision?

The specific heat of the solid phase is 0.333 joules per gram-degree Celsius.

The specific heat of the liquid phase is 0.593 joules per gram-degree Celsius.

In this case, we need to determine that specific heat for solid and liquid states of matter. By Heat Physics, we understand that specific heat is contained in the slopes of the two sensible phases in the following form:

[tex]\frac{\Delta T}{\Delta Q} = \frac{1}{m\cdot c}[/tex] (1)

Where:

Solid phase

If we know that [tex]m = 9.80\,g[/tex], [tex]T_{1} = 40\,^{\circ}C[/tex], [tex]T_{2} = 235\,^{\circ}C[/tex], [tex]Q_{1} = 183\,J[/tex] and [tex]Q_{2} = 819\,J[/tex], then the specific heat of the solid phase is:

[tex]c = \frac{\Delta Q}{m\cdot \Delta T}[/tex]

[tex]c = \frac{819\,J-183\,J}{(9.80\,g)\cdot (235\,^{\circ}C - 40\,^{\circ}C)}[/tex]

[tex]c = 0.333\,\frac{J}{g\cdot ^{\circ}C}[/tex]

The specific heat of the solid phase is 0.333 joules per gram-degree Celsius.

Liquid phase

If we know that [tex]m = 9.80\,g[/tex], [tex]T_{3} = 230\,^{\circ}C[/tex], [tex]T_{4} = 471\,^{\circ}C[/tex], [tex]Q_{3} = 1470\,J[/tex] and [tex]Q_{4} = 2870\,J[/tex], then the specific heat of the liquid phase is:

[tex]c = \frac{\Delta Q}{m\cdot \Delta T}[/tex]

[tex]c = \frac{2870\,J - 1470\,J}{(9.80\,g)\cdot (471\,^{\circ}C - 230\,^{\circ}C)}[/tex]

[tex]c = 0.593\,\frac{J}{g\cdot ^{\circ}C}[/tex]

The specific heat of the liquid phase is 0.593 joules per gram-degree Celsius.

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Answer:

B

Explanation:

Answer:

B

Explanation:

Answer:

The correct option is D) Fission

Explanation:

There are several methods through which Radioactive isotopes are created.

Cheers

Answer:

Workdone = 20 Joules

Explanation:

Given the following data;

Force = 10N

Extension, e = 4cm to meters = 4/100 = 0.04 meters

Workdone extension = 40cm to meters = 40/100 = 0.4 meters

To find the work done;

First of all, we would find the spring constant using the formula;

Force = spring constant * extension

10 = spring constant * 0.04

Spring constant = 10/0.04

Spring constant = 250 N/m

Next, we find the work done;

Workdone = ½ke²

Where;

k is the spring constant.

e is the extension.

Substituting into the formula, we have;

Workdone = ½ * 250 * 0.4²

Workdone = 125 * 0.16

Workdone = 20 Joules

Answer:

0.5 m/s 2 is the acceleration

Explanation:

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In mathematics, an algebraic expression is an expression built up from integer constants, variables, and the algebraic operations. For example, 3x² − 2xy + c is an algebraic expression.

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Using ohm's law and the characteristics of series and parallel circuits, we find that the correct answer is B: Voltage on the voltmeter 1.5 V

given parameters

    * The element X has a resistance Rₓ = R

    * Element Y with resistance R_y = R / 2

     * The voltmeter with internal resistance R_v = R

    * Battery voltage V = 6V

    * the circuit is in the diagram

To find

     The Voltmeter reading.

For this exercise we use ohm's law which establishes a linear relationship between voltage and current

      V = i R

Let's solve the circuit in parts:

1 part.  We reduce the part in parallel, finding its equivalent resistance

            R_ {eq1}

The equivalent resistance between Y element and the voltmeter that is in parallel, therefore their equivalent resistance is

         [tex]\frac{1}{R_{eq1} } = \frac{1}{R_y} + \frac{1}{R_v}[/tex]

         [tex]\frac{1}{R_{eq1} }= \frac{1}{\frac{R}{2} } + \frac{1}{R} = \frac{3}{R}[/tex]

         [tex]R_{eq1} = \frac{R}{3}[/tex]

Now element X and this equivalent resistance are in series ( see attached), so the equivalent resistance of the entire circuit is

        R_{eq} = Rₓ + R_{eq1}

we substitute

       R_{eq} = [tex]R + \frac{R}{3} = \frac{4}{3} \ R[/tex]

2 part. We look for the current of the circuit, usin the ohm's Law

        V = i R_{eq}

        i = [tex]\frac{V}{R_{eq} }[/tex]

        i = [tex]\frac{6}{\frac{4R}{3} } = \frac{18}{4R}[/tex]

        i = 4.5 / R

In a series circuit the current is constant and the total voltage is the sum voltage of each element, so the voltage in the parallel R_{eq1}

        V₂ = I R_{eq1}

        V₂ = [tex]\frac{4.5}{R} \ \frac{R}{3}[/tex]4.5 / R R / 3

        V₂ = 1.5 V

3 part. The voltmeter and the Y element  are in parallel, so the voltage in the two elects is the same,  consequently the voltage of the voltmeter (V_v)

          V_v = V₂ = 1.5 V

Using ohm's law and the properties of series and parellel circuits we find the voltage across the voltmeter

           V_v = 1.5 V

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Answer:

moving

Explanation:

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Answer:

B

Explanation:

Answer:

There are 5 general layers; organism, population, community, ecosystem, and biosphere.

Explanation:

Hope this helps!

Answer:The three main types are reflecting telescopes, refracting telescopes, and catadioptric telescopes. Radio telescopes collect and focus radio waves from distant objects. Space telescopes orbit Earth, collecting wavelengths of light that are normally blocked by the atmosphere.

Answer:

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