Answer:
Option A
Explanation:
Nylon retainers are knocking screws that have nylon coating on their thread which prevents them from loosening. It generally has two heads Hex Key an star screw. For high mount fixing, star screw is used as it is less prone to stripping. The nylon insert of a Nylock nuts enters into the screw and prevent it from loosening. It is useful in areas where there is high vibration.
Hence, option A is correct
Sarah and Raj take/takes me to a baseball game every year.
Either the Cubs or the Orioles play/plays the Yankees tonight.
There is/are nine players on a baseball team.
The home team sit/sits in the dugout on the third-base side of the field.
One of the players called the catcher crouch/crouches behind home plate
I learned how to play soccer from my sister.
Last year, I bought myself season tickets to the local team’s matches.
Only the goalie can use their hands to catch the ball.
The players must quickly move the ball down the field.
This year, my sister gave me my favorite player’s jersey for Christmas.
Answer:
take
play
are
sits
crouches
direct
indirect
direct
direct
indirect
Explanation:
i had just taken the test
g A 12,000 m3/day treatment plant has a rectangular sedimentation basin with dimensions 12 meters wide, 3 meters deep, and 25 meters long. Will particles with a settling velocity of 6 x 10-3 m/s be removed in this basin
Answer:
The settling velocity of the particles (Vs) is greater than the overflow rate (V₀), thus the particles will settle out and will be removed.
Explanation:
Given;
volumetric flow rate of the treatment, Q₀ = 12,000 m³/day
length of the rectangular tank, L = 25 m
width of the tank, W = 12 m
height of the tank, H = 3 m
settling velocity of the particles, [tex]V_s[/tex] = 6 x 10⁻³ m/s
The overflow rate of the sediments are calculated as follows;
[tex]V_o = \frac{Q_o}{A_s}[/tex]
where;
As is the surface area of the tank, m²
Q₀ is the flow rate, m³/s
As = 2LW + 2LH + 2WH
As = (2 x 25 x 12) + (2 x 25 x 3) + (2 x 12 x 3)
As = 822 m²
[tex]Q_0 (m^3/s)= \frac{12,000 \ m^3}{day} \times \frac{1 \ day}{24 \ hr} \times \frac{1 \ hour}{60 \ \min} \times \frac{1 \ \min}{60 \ s} = \frac{12,000}{24 \times 60 \times 60} (m^3/s)= \frac{12,000}{86,400} \ m^3/s\\\\Q_o = 0.139 \ m^3/s[/tex]
The overflow rate;
[tex]V_o = \frac{Q_0}{A_s} = \frac{0.139}{822} = 1.69 \times 10^{-4} \ m/s[/tex]
The settling velocity of the particles (Vs) is greater than the overflow rate (V₀), thus the particles will settle out and will be removed.
Expression for calories burned during workout
Explain the importance of wearing appropriate protective clothing and equipment (PPE), and keeping the work area safe and tidy
Answer:
The wearing of appropriate protective clothing and equipment (PPE) and the keeping of the work area safe and tidy achieve the following for the employees and employers: safety from physical and biological harm that may occur as a result of their contact with the work environment; reduces the cost of insurance and other risk management activities.
Explanation:
The personal protective equipment (PPE) is a safety equipment that protects workers from health or safety risks at their various workplaces. The main purpose is to reduce the workers' exposure to environmental hazards. PPE reduces accidents, improves the health of workers, and reduces the spread of contagious diseases. Above all, it creates safe, secure, and healthy work environments for all.
Estimate the maximum expected thermal conductivity for a Cermet that contains 58 vol% titanium carbide (TiC) particles in a cobalt matrix. Assume thermal conductivities of 27 and 69 W/m-K for TiC and Co respectively.
Answer:
The right answer is "36.32 W/mk".
Explanation:
According to the question,
TiC = 76%
or,
= 0.76
CO = 24%
or,
= 0.24
Thermal conductivity of TiC,
= 26 W/mk
Thermal conductivity of CO,
= 69 W/mk
On applying the rule, we get
⇒ [tex]"K" \ of \ Cermet=(K)_{TiC} (V_f)_{TiC}+(K)_{CO} (V_m)_{CO}[/tex]
On putting the given values, we get
⇒ [tex]=(26)(0.76)+(69)(0.24)[/tex]
⇒ [tex]=19.76+16.56[/tex]
⇒ [tex]=36.32 \ W/mk[/tex]
Users of E85 see a drop in gas mileage because ethanol can't produce the same
amount of energy gasoline can. How much of a drop do they see?
Select one:
a. They see a 10-20% drop in gas mileage
b. The statement is wrong. There is no drop in gas mileage.
c. They see a 30-40% drop in gas mileage
d. They see a 20-30% drop in gas mileage
Answer:
A
Explanation:
Due to ethanol's lower energy content, FFVs operating on E85 get roughly 15% to 27% fewer miles per gallon than when operating on regular gasoline, depending on the ethanol content.
This String method removes beginning and ending spaces of the given string.
Solactone
Answer:
The trim() method will remove both leading and trailing whitespace from a string and return the result. The original string will remain unchanged. If there is no leading or trailing whitespace to be removed, the original string is returned. Both spaces and tab characters will be removed.
This is very useful when comparing user input with existing data. A programmer often racks his brain for hours trying to figure out why what he enters is not the same as a stored string, only to find out that the difference is only a trailing space. Trimming data prior to comparison will eliminate this problem.
Answer:
String result = str. trim(); The trim() method will remove both leading and trailing whitespace from a string and return the result.
Explanation:
The electron concentration in silicon at T = 300 K is given by
n(x) = 10^16exp(-x/18) cm^-3
where x is measured in μm and is limited to 0 ≤ x ≤ 25 μm. The electron diffusion coefficient is Dn = 25 cm2/s and the electron mobility is μn = 960 cm2/V-s. The total electron current density through the semiconductor is constant and equal to Jn = -40 A/cm2. The electron current has both diffusion and drift current components. Determine the electric field as a function of x which must exist in the semiconductor.
Answer:
[tex]E=1.44*10^-7-2.6exp(\frac{-x}{18} )v/m[/tex]
Explanation:
From the question we are told that:
Temperature of silicon [tex]T=300k[/tex]
Electron concentration [tex]n(x)=10^{16}\exp (\frac{-x}{18})[/tex]
[tex]\frac{dn}{dx}=(10^{16} *(\frac{-1}{16})\exp\frac{-x}{16})[/tex]
Electron diffusion coefficient is [tex]Dn = 25cm^2/s \approx 2.5*10^{-3}[/tex]
Electron mobility is [tex]\mu n = 960 cm^2/V-s \approx0.096m/V[/tex]
Electron current density [tex]Jn = -40 A/cm^2 \approx -40*10^{4}A/m^2[/tex]
Generally the equation for the semiconductor is mathematically given by
[tex]Jn=qb_n\frac{dn}{dx}+nq \mu E[/tex]
Therefore
[tex]-40*10^{4}=1.6*10^{-19} *(2.5*10^{-3})*(10^{16} *(\frac{-1}{16})\exp\frac{-x}{16})+(10^{16}\exp (\frac{-x}{18}))*1.6*10^{-19}*0.096* E[/tex]
[tex]E=\frac{-2.5*10^-^7 exp(\frac{-x}{18})+40*10^{4}}{1.536*10^-4exp(\frac{-x}{18} )}[/tex]
[tex]E=1.44*10^-7-2.6exp(\frac{-x}{18} )v/m[/tex]