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Answer:

$72.80

Step-by-step explanation:

1.) Find 60% of 45.50

0.60 * 45.50 = 27.3

2.) Add this to the cost

27.30 + 45.50 = 72.80

Answer:

b. (6, 4)

Step-by-step explanation:

i hope this helps :)

Answer:

B. (6,4)

Step-by-step explanation:

The point is inside the triangle.

Answer:

It will drop 16.875 degrees

Step-by-step explanation:

3.75 × 4 = 15

.5 × 3.75 1.875

Answer:

-16.875

Step-by-step explanation:

This equation is quite simple and will only require one equation to solve. This is the equation,

-3.75×4.5=-16.875

The final answer is -16.875

Answer:

the answer of the question is 25

Answer:

A. 9,006

Step-by-step explanation:

First we need to find 25% of 4,000

4,000/4 = 1000

So we know there are 1,000 mosquitoes a month.

So In 4 months it would be 4,000 more mosquitoes.

That would be 8,000 but i don't see that so I would say A.

Let me know if I'm correct.

Answer:

Here, I graphed this especially for you.

Check attachment.

Answer:

A. -25

Step-by-step explanation:

sana nakatulong :-)

Answer:

a.

Step-by-step explanation:

please click the heart and rate excellent and pa brainleist po please ☻❤☺️☺️❤☻

Answer:

118 yards

Step-by-step explanation:

Tamia is getting balloons for her father's birthday party

She wants each balloon to be 6 feet long

Tamia wants to get 59 balloons

Therefore the yards of string needed can be calculated as follows

= 59×6

= 354 feet to yards

= 118 yards

Hence the number of yards needed is 118 yards

Answer:

96

Step-by-step explanation:

12.50 + 18.50 + 20 + 20 + 13 + 12 = 96

Answer:

Height of building = 86.9 ft

Step-by-step explanation:

I've drawn a triangle image to depict this question and I have attached it.

From the attached image, we can see that ABC is the height of the building.

We can see the distance from your eye to the ground indicated and also the distance from the horizontal distance from the building to you indicated.

We can use pythagoras theorem to find AB.

AB/57 = tan 55°

AB = 57 × 1.4281

AB = 81.4 ft

Now, total height of the building is AB + BC.

BC = 5.5 ft since B is parallel to your eye and height from there to the ground is 5.5 ft.

Thus;. Height of building = 81.4 + 5.5 = 86.9 ft

Answer:

a. The distance the train travelled in the first hour is approximately 28.3 miles

b. The location of the train at 5:00 p.m. is 53 miles east, and 46 miles west

c. The location of the train at any given time by the function, f(t) = (-8 + 24·t, -10 + 15·t)

d. The train does not collide with the cyclist when the bike goes over the train tracks

Step-by-step explanation:

a. The given information on the train's motion are;

The location south the train is spotted = 10 miles south and 8 miles west

The time the observer spotted the train = 2:00 pm

The location the train is spotted at 3:00 p.m. = 5 miles north and 16 miles east

Therefore, the difference between the two times the train was spotted, t = 3:00 p.m. - 2:00 p.m. = 1 hour

Making use of the coordinate plane for the two locations the train was spotted, we have;

The initial location of the train = (-10, -8)

The final location of the train = (5, 16)

Therefore the distance the train travelled in the first hour is given by the formula for finding the distance, 'd', between two points, (x₁, y₁) and (x₂, y₂) as follows;

[tex]d = \sqrt{\left (x_{2}-x_{1} \right )^{2}+\left (y_{2}-y_{1} \right )^{2}}[/tex]

Therefore;

[tex]d = \sqrt{\left (5-(-10) \right )^{2}+\left (16-(-8) \right )^{2}} = 3 \cdot\sqrt{89}[/tex]

The distance the train travelled in the first hour, d = 3·√89 ≈ 28.3 miles

b. The speed of the train, v = (Distance travelled by the train)/Time

∴ v ≈ 28.3 miles/(1 hour) = 28.3 miles per hour

The speed of the train in the first hour, v ≈ 28.3 mph

The direction of the train, θ, is given by the arctangent of the slope, 'm', of the path of the train;

[tex]\therefore The \ slope \ of \ the \ path \ of \ the \ train, \, m =tan(\theta) = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

∴ m = tan(θ) = (5 - (-10))/(16 - (-8)) = 0.625

c. Distance = Velocity × Time

At 5:00 p.m., we have;

The time difference, Δt = 5:00 p.m. - 3:00 p.m. = 2 hours

The distance, d₁ = (28.3 mph × 2 hours = 56.6 miles

Using trigonometry, we have the horizonal distance travelled, 'Δx', in the 2 hours is given as follows;

Δx = d₁ × cos(θ)

∴ Δx = 56.6 × cos(arctan(0.625)) ≈ 48

The increase in the horizontal position of the train, relative to the point (5, 16), Δx ≈ 48 miles

The vertical distance increase in the two hours, Δy is given as follows;

Δy = 56.6 × sin(arctan(0.625)) ≈ 30

The increase in the vertical position of the train, relative to the point (5, 16), Δy ≈ 30 miles miles

Therefore; the location of the train at 5:00 p.m. = ((5 + 48), (16 + 30)) = (53, 46)

The location of the train at 5:00 p.m. = 53 miles east, and 46 miles west

c. The function, 'f', that would give the train's position at time-t is given as follows;

The P = f(28.3·t, θ)

Where;

28.3·t = √(x² + y²)

θ = arctan(y/x)

Parametric equations

y - 5 = 0.625·(x - 16)

∴ y = 0.625·x - 10 + 5

The equation of the train's track is therefore, presented as follows;

y = 0.625·x - 5

d = 28.3·t

The y-component of the velocity, [tex]v_y[/tex] = 3*√89 mph × sin(arctan(0.625)) = 15 mph

Therefore, we have;

y = -10 + 15·t

The x-component of the velocity, vₓ = 3*√89 mph × cos(arctan(0.625)) = 24 mph

Therefore, we have;

x = -8 + 24·t

The location of the train at any given time, 't', f(t) = (-8 + 24·t, -10 + 15·t)

d. The speed of the cyclist next to the observer at 2:00 p.m., v = 10 mph

The distance of the cyclist from the track = The x-intercept = 5/0.625 = 8

The distance of the cyclist from the track = 8 miles

The time it would take the cyclist to react the track, t = 8 miles/10 mph = 0.8 hours

The location of the train in 0.8 hours, is f(0.8) = (-8 + 24×0.8, -10 + 15×0.8)

∴ f(0.8) = (11.2, 2)

At the time the cyclist is at the track along the east-west axis, at the point (8, 0), the train is at the point (11.2, 2) therefore, the train does not collide with the cyclist when the bike goes over the train tracks.

If the cyclist is travelling at 10 mph the train does not collide with the cyclist when the bike goes over the train tracks.

The location south the train is spotted = 10 miles south and 8 miles west

The time the observer spotted the train = 2:00 pm

The location of the train is spotted at 3:00 p.m. = 5 miles north and 16 miles east

Thus, the difference between the two times the train was spotted,

t = 3:00 p.m. - 2:00 p.m. = 1 hour

The distance is the product of velocity and time.

Distance = Velocity × Time

The initial location of the train = (-10, -8)

The final location of the train = (5, 16)

Therefore the distance the train travelled in the first hour

[tex]d = \sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} } \\d = \sqrt{(5 -(-10) )^{2} +(16-(-8) )^{2} }[/tex]

d = 3√89

The distance the train travelled in the first hour, d = 28.3 miles

b. The speed of the train, v = (Distance travelled by train)/Time

∴ v ≈ 28.3 miles/(1 hour) = 28.3 miles per hour

The speed of the train in the first hour, v ≈ 28.3 mph

The direction of the train, θ, is given by the arc tangent of the slope, 'm', of the path of the train;

∴ m = tan(θ) = (5 - (-10))/(16 - (-8))

m = 0.625

c. Distance = Velocity × Time

At 5:00 p.m., we have;

The time difference, Δt = 5:00 p.m. - 3:00 p.m. = 2 hours

The distance, d₁ = (28.3 mph × 2 hours = 56.6 miles

Using trigonometry, we have the horizontal distance travelled, 'Δx', in the 2 hours is given as follows;

Δx = d₁ × cos(θ)

∴ Δx = 56.6 × cos(arctan(0.625)) ≈ 48

The increase in the horizontal position of the train, relative to the point (5, 16), Δx ≈ 48 miles

The vertical distance increase in the two hours, Δy is given as follows;

Δy = 56.6 × sin(arctan(0.625)) ≈ 30

The increase in the vertical position of the train, relative to the point (5, 16), Δy ≈ 30 miles miles

Therefore; the location of the train at 5:00 p.m. = ((5 + 48), (16 + 30)) = (53, 46)

The location of the train at 5:00 p.m. = 53 miles east, and 46 miles west

c. The function, 'f', that would give the train's position at time-t is given as follows;

The P = f(28.3·t, θ)

28.3·t = √(x² + y²)

θ = arctan(y/x)

Parametric equations

y - 5 = 0.625·(x - 16)

∴ y = 0.625·x - 10 + 5

The equation of the train's track is, therefore, presented as follows;

y = 0.625·x - 5

d = 28.3·t

The y-component of the velocity,

= 3 × √89 mph × sin(arctan(0.625)) = 15 mph

Therefore, we have

y = -10 + 15·t

The x-component of the velocity,

vₓ = 3 × √89 mph × cos(arctan(0.625))

= 24 mph

Therefore, we have;

x = -8 + 24·t

The location of the train at any given time, 't',

f(t) = (-8 + 24·t, -10 + 15·t)

d. The speed of the cyclist next to the observer at 2:00 p.m., v = 10 mph

The distance of the cyclist from the track = The x-intercept

                                                                   = 5/0.625 = 8

The distance of the cyclist from the track = 8 miles

The time it would take the cyclist to reach the track, t = 8 miles/10 mph = 0.8 hours

The location of the train in 0.8 hours, is f(0.8)

= (-8 + 24×0.8, -10 + 15×0.8)

∴ f(0.8) = (11.2, 2)

therefore, If the cyclist is travelling at 10 mph the train does not collide with the cyclist when the bike goes over the train tracks.

Learn more about distance;

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Answer:

I think its A

Step-by-step explanation:

because it's a tighter angle than 29,46,and 134 degrees i might not be right but i hope it is :)

Answer:

x = -3, x = 2

Step-by-step explanation:

re-order the terms to get this quadratic:  x² + x - 6 = 0

factor:  (x + 3)(x-2) = 0

x = -3, x = 2

Answer:

volume = 10,082.5 in³

Step-by-step explanation:

radius = 26/2 = 13

volume = πr²L = (3.14)(13²)(19) = 10,082.54 in³

Answer:

7.833 yards²

Step-by-step explanation:

I can't take a pic but heres a link that does the math for you and explains. The top of the rectangular prism btw is called the surface area

https://www.omnicalculator.com/math/surface-area-rectangular-prism

Answer:

[tex] Mean = 10.5[/tex]

Step-by-step explanation:

Mean of a data is defined as the sum of all observations divided by the sum of observations . So add all of the data and divide it by Total number of terms.

[tex]\implies Mean = \dfrac{\sum x_i}{n}\\\\\implies Mean = \dfrac{ 8 + 10 + 8 + 14 + 8 + 15 }{6} \\\\\implies Mean =\dfrac{63}{6} \\\\\implies \boxed{\boxed{ Mean = 10.5}}[/tex]

Answer:

1. 23/4  ,  2. 5.555...   , 3. 5 1/2   ,    4. √28

you want to make them all into decimals so you can compare then easier

23/4 would be 5.75

√28 (just put it in a calculator)  would be 5.29

5 1/2  would be 5.5  (make  it into a improper fraction 11/2 then do 11/2 and you get 5.5)

and you have 5.555.

so...

5.75

5.29

5.5

5.55555

first is 5.75 it's bigger because of the .(75)

then 5.555 because it's .(55)

then 5.5 because it's .(50)

and the last one 5.(29)

Answer:

khing chong

Step-by-step explanation:

Answer:

the answer is in the photo above

Answer: 7x - y = 17

Step-by-step explanation:

Answer:

Standard 7x-y=17 or Slope Intercept y=7x-17

Step-by-step explanation:

Answer:

8a:15b:6c

a:b:c = 8:15:6

The value of w is 54 degrees

From the figure, we can see that:

The angle w intercepts the arc that has a measure of 108 degrees

This means that:

w = 0.5 * 108

Evaluate the product

w = 54

Hence, the value of w is 54

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Answer:

Step-by-step explanation:

Answer: 10.2

Step-by-step explanation:

b = 15² - 11²

= 225 - 121

= 104

= √104

= 10.2

Answer:

The answer is 7

Step-by-step explanation:

Q11-4=7

Hope this helped!!!

Answer: B

Step-by-step explanation: Hope this help :D

Answer:

x = - 2

y = 6

Step-by-step explanation:

The best way to do this is to put - 3x in for y in the second equation.

4x - 2(-3x) = - 20        Watch the signs. You have 2 minus signs.

4x - - 6x = -20            Change - - 6x to 6x

4x + 6x = - 20              Add

10x = - 20                   Divide by 10

x = -20/10

x = - 2

============================

Find y

y = - 3x

y = -3 * -2

y = 6

Answer:

77

Step-by-step explanation:

Is this a trick question? If it is I love the challenge

The value of the number is 43

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the number be = A

Now , let the ones digit of the number be = x

Let the tens digit of the number be = y

Now , the equation will be

The number of ten blocks = 7 base ten blocks

So , the equation is

x + y = 7

Now , one of the digits is 4

And , number of tens blocks is greater than the number of ones blocks

So , the next digit of the number is 3

4 > 3

Therefore , the number from the equation is 43

Hence , The value of the number is 43

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