how does the size of the solar system compare to the Milky Way galaxy?
1. the solar system is larger
2. the solar system is the same size
3. the solar system is much smaller
4. the solar system is about one half the size

Answers

Answer 1

Answer:

either 3 or 4 most likely 3

Explanation:

Answer 2
4 is Half the size because the solar is 200 and milky is 400 so half

Related Questions

Which of the following are examples of
molecules? Check all that apply.
two carbon atoms bonded to each other
a carbon atom
a chain of one hundred carbon atoms bonded
to one another
a carbon atom bonded to an oxygen atom

Answers

Answer:

two carbon atoms bonded to each other

a chain of one hundred carbon atoms bonded to one another

a carbon atom bonded to an oxygen atom

two carbon atoms bonded to each other a carbon atom, a chain of one hundred carbon atoms bonded to one another, a carbon atom bonded to an oxygen atom all these are examples of molecules, therefore all the given options are the correct answer

What is a molecule?

The smallest component of a substance that still has its content and characteristics is called a molecule. It is constructed of two or more atoms connected by chemical bonds. Moles are the foundation of chemistry. Molecules are designated by their elemental symbol and a subscript indicating their atom count.

Atoms are the fundamental unit of an element. They consist of a nucleus and surrounding electrons. When an atom has an incomplete electron shell, it is said to have valence electrons. When two or more atoms come together to share outer shell valence electrons, a covalent bond is formed,

Since molecules include two carbon atoms bonded to each other, one carbon atom, a chain of hundred carbon atoms bonded to one another, and a carbon atom bonded to an oxygen atom, all of the suggested answers are correct.

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Imagine that you throw a rock into the air. When you release the rock, it is moving at 19.4 m/s. The rock flies straight up into the air and returns back to your hand. For how long was the rock in the air? Note: acceleration due to gravity is -9.81 m/s/s.

Answers

Answer:

4 s

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 19.4 m/s.

Acceleration due to gravity (g) = –9.81 m/s²

Total time (T) =.?

Next, we shall determine the time take by the rock to get to the maximum height. This can be obtained as follow:

NOTE: At maximum height, the final velocity is zero.

Initial velocity (u) = 19.4 m/s.

Acceleration due to gravity (g) = –9.81 m/s²

Final velocity (v) = 0 m/s

Time taken to reach the maximum height (t) =.?

v = u + gt

0 = 19.4 + (–9.81 × t)

0 = 19.4 – 9.81t

Collect like terms

0 – 19.4 = –9.81t

–19.4 = –9.81t

Divide both side by –9.81

t = –19.4 / –9.81

t ≈ 2 s

Thus, it took approximately 2 s for the rock to reach its maximum height.

Finally, we shall determine the total time spent by the rock in the air as follow:

Time taken to reach the maximum height (t) = 2 s

Total time spent in air (T) =?

The total time (T) spent by the rock in the air will be two times the time taken (t) to reach the maximum height i.e

T = 2t

t = 2 s

T = 2 × 2

T = 4 s

Therefore, the rock spent approximately 4 s in the air.

Which of the following choices is not part of the scientific method

Answers

Answer:

What are the choices?

Explanation:

why cats cannot run on smoth table​

Answers

Answer:

bc of their paw pads, they don't get the traction they need in order to be able to get a firm grip to push off of on the table for each bound

Explanation:

Like chargers attract one another

Answers

nope. opposite charges attract. like charges repel.

Compact fluorescent bulbs are much more efficient at producing light than are ordinary incandescent bulbs. They initially cost much more, but last far longer and use much less electricity. According to one study of these bulbs, a compact bulb that produces as much light as a 100 W incandescent bulb uses only 23.0 W of power. The compact bulb lasts 10000 hours, on the average, and costs $ 12.00, whereas the incandescent bulb costs only $ 0.76, but lasts just 750 hours. The study assumed that electricity cost $ 0.090 per kilowatt-hour and that the bulbs were on for 4.0 h per day.

Required:
a. What is the total cost (including the price of the bulbs) to run each bulb for 3.0 years?
b. How much do you save over 3.0 years if you use a compact fluorescent bulb instead of an incandescent bulb?
c. What is the resistance of a "100-W" fluorescent bulb?

Answers

Answer:

a

[tex]The  \ price \  for \   Compact\ fluorescent\ bulbs \ is  \ C_T  = \$ 21.067\\The   \ price \  for \    incandescent\ bulb \ is \ C_t  = \$ 43.98[/tex]

b

[tex]The \  amount  \  saved \ is  \ C_S =  \$ 22.913[/tex]

c

[tex]The \ resistance \  is \ R =  626.1 \Omega[/tex]

Explanation:

From the question we are told that

   The power used by incandescent bulb [tex]P_r  =  23.0 W[/tex]

    The power used by  Compact fluorescent bulb [tex]P_p  =  100W[/tex]

     The life span of  Compact fluorescent bulb is  [tex]t = 1000 \  hours[/tex]

    The  prices of   Compact fluorescent bulb is [tex]C_c = \$ 12 [/tex]

    The  prices of incandescent bulb is [tex]C_i = \$ 0.76 [/tex]

     The life span of   incandescent bulb is  [tex]t_k = 750   \ hours[/tex]

      The cost of electricity is [tex]C_e =  \$ 0.090/ kilowatt-hour = \frac{0.090}{1000} = \$0.00009 / W / h[/tex]

    The duration of daily bulb usage is [tex]t_d  =  4 \  hours[/tex]

     

Generally 3 years of bulb usage  in hours is mathematically evaluated as

    [tex]t_3 =  3 *  365 *  t_d[/tex]

=>   [tex]t_3 =  3 *  365 *  4[/tex]

=>   [tex]t_3 =  4380 \ h [/tex]

Generally the cost to power a 23W bulb for the above duration  is mathematically represented as

 [tex]Z = 23 *  t_3 * C_e[/tex]

=>   [tex]Z = 23 *  4380 * 0.00009[/tex]

=>   [tex]Z = \$ 9.0667[/tex]

The number of Compact fluorescent bulbs required to  achieve this about of time is mathematically represented as

       [tex]N  =  \frac{t_3}{ t}[/tex]

=>  [tex]N  =  \frac{4380}{1000}[/tex]

=>   [tex]N  = 0.438 [/tex]

=>  [tex]N  \approx  1 [/tex]

The total cost of  usage  for the Compact fluorescent bulb   is  mathematically represented as

      [tex]C_T  =  Z +C_c[/tex]

=>   [tex]C_T  =  9.0667 +12[/tex]

=>   [tex]C_T  = \$ 21.067 [/tex]    

The number of  incandescent bulbs required to  achieve this about of time is mathematically represented as

       [tex]M =  \frac{t_3}{ t_k}[/tex]

=>  [tex]M  =  \frac{4380}{750}[/tex]

=>   [tex]M  = 6 [/tex]

Generally the cost to power a 100W bulb for the above duration  is mathematically represented as

 [tex]Z = 100 *  t_3 * C_e[/tex]

=>   [tex]Z = 100 *  4380 * 0.00009[/tex]

=>   [tex]Z = \$ 39.42[/tex]

The total cost of  usage  for the incandescent bulbs    is  mathematically represented as

      [tex]C_t  =  C_e + [6 *C_i][/tex]

=>   [tex]C_t  =  39.42 + [0.76 *  6][/tex]

=>   [tex]C_t  = \$ 43.98[/tex]    

Generally the total amount saved is mathematically represented as

   [tex]C_S =  C_t - C_T[/tex]

=>   [tex]C_S =  43.98 - 21.067[/tex]

=>   [tex]C_S =  \$ 22.913[/tex]

Generally the resistance of the Compact fluorescent bulb is  

    [tex]R =  \frac{V^2}{P}[/tex]

    [tex]R  =  \frac{120^2}{23}[/tex]

[tex]R =  626.1 \Omega[/tex]

What kind of workplace is a mine?

Answers

For gold
For lithium
For Crystals
For coal
For silver
For minerals
For uranium

When a 600 g mass is suspended from a spring, the spring stretches 1.2 cm. What is the spring constant of the spring? ​

Answers

Well first you need to know the formula for the spring force. It’s -1/2k*d

K being the constant

D being the displacement

We can actually find the force on the spring by calculating the weight of the block. It would be mass multiplied by gravity, convert the grams to kilograms first tho.

600/1000 = 0.6kg

0.6kg * 9.8 m/s^2 = 5.88N

Now plug everything into the equation, also convert the centimeters to meters:

1.2/100 = 0.012 meters

5.88 = -1/2k*(0.012)

5.88 = k*(0.006)

We could drop the negative sign because we really just want the magnitude of the spring constant.

K = 980N

A 100 kg disc with radius 1.6 m is spinning horizontally at 25 rad/s. You place a 20 kg brick quickly and gently on the disc so that it sticks to the edge of the disc. Determine the final angular speed of the disc-brick system.

Answers

Answer:

20.83rad/s

Explanation:

Using the law of conservation of momentum

m1u1+m2u2 = (m1+m2)v

m1 and m2 are the mass of the disc and Brick respectively

u1 and u2 are the linear velocities respectively

v is their final velocity of the block-disc system

Given

m1 = 100kg

m2 = 20kg

u1 = wr =25×1.6

u1 = 40m/s

u2 = 0m/s (brick is stationary)

Substitute and the final linear velocity v

100(40)+20(0) = (100+20)v

4000 = 120v

v = 4000/120

v = 33.3m/s

From the formula;

v = wr

w = v/r

w= 33.3/1.6

w = 20.83rad/s.

Hence the final angular speed of the disc-brick system is 20.83rad/s

a single frictionless roller coaster car of mass m=750 kg tops the first hill with speed v=15 m/s ar height h =40m as shown

1) Find the speed of the car at B and C

2) if mass m were doubled, would the speed at B increase, decrease, or remain the same?

Answers

1. The speed of the roller coaster car at point B and C: are 19.8 m/s and 0 m/s respectively.

2. If mass (m) of the roller coaster car were doubled, the speed at B would increase because energy is dependent on  the mass of an object.

Given the following data:

Mass of roller coaster car = 750 kgSpeed of roller coaster car = 15 m/sHeight = 40 meters

1. To find the speed of the roller coaster car at point B and C:

First of all, we would determine the potential energy of the roller coaster car by using the formula:

[tex]P.E = mgh[/tex]

Where:

m is the mass of object.g is the acceleration due to gravity ([tex]9.8\;m/s^2[/tex]).h is the height of an object.

From the diagram, height at point B = [tex]\frac{h}{2} = \frac{40}{2} = 20[/tex] meters

[tex]P.E = 750(9.8)(20)[/tex]

P.E = 147000 Joules.

Next, we would determine the speed by applying the law of conservation of energy.

[tex]Kinetic\;energy = Potential\;energy\\\\\frac{1}{2} mv^2 = mgh[/tex]

Substituting the values, we have;

[tex]147000 = \frac{1}{2} (750)v^2\\\\147000 = 375v^2\\\\v^2 = \frac{147000}{375} \\\\v^2 = 392\\\\v = \sqrt{392}[/tex]

Speed, v = 19.8 m/s

From the diagram, at point C, the speed is equal to zero (0) meters per seconds.

2. If mass (m) of the roller coaster car were doubled, the speed at B would increase because energy is dependent on  the mass of an object.

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3. A cat is moving at 18 m/s when it accelerates at 4 m/s? for 2 seconds. What is his new
velocity?

Answers

Answer:

26 m/s

Explanation:

v = u + at

Given that,

u(initial speed) = 18 m/sa (acceleration) = 4m/s^2t ( time) = 2s

and v ( final velocity) = ?

v = 18 + ( 4 × 2)

v = 18 + 8

v = 26 m/s

A storm is moving east toward your house at an average speed of 35 km an hour if the storm is currently 80 km from your house and how much time do you expect it to arrive

Answers

Answer: 2 hours 17 minutes

Explanation: 80/35h = 16/7 = 2hrs 17 minutes

SOMEONE PLEASE PLEASE HELP QUICK PICTURE INCLUDED

Answers

Answer:

A

Explanation:

Switches are used to block electrical currents, thus needing to be made out of insulating material.

A fundraising company agrees to donate an extra $75 for every $100 the school raises through selling cookies. Part A: What is the constant of proportionality

Answers

Answer:

3/4 0r 0.75

Explanation:

Let E represent the extra cash.

Let R represent the amount raised.

From the question given above, we can say that:

The extra cash (E) is directly proportional to the amount raised (R) i.e

Extra cash (E) ∝ Amount raised (R)

E ∝ R

E = KR

NOTE: K is the constant of proportionality.

With the above formula, we can obtain the value of K as follow:

Extra cash (E) = $ 75

Amount raised (R) = $ 100

Constant of proportionality (K) =?

E = KR

75 = K × 100

Divide both side by 100

K = 75/100

K = 3/4 0r 0.75

Thus, the constant of proportionality is 3/4 0r 0.75

One end of a horizontal string is attached to a vibrating blade, and the other end passes over a pulley as in Figure (a). A sphere of mass 1.00 kg hangs on the end of the string. The string is vibrating in its second harmonic. A container of water is raised under the sphere so that the sphere is completely submerged. In this configuration, the string vibrates in its second harmonic (or the third normal mode of oscillation) as shown in Figure (b). What is the radius of the sphere?

Answers

Answer:

when it weighs 2kg it is 7.38

Explanation:

hope this helps

A net force of 275 N accelerates a 18.0 kg mass. What is the resulting acceleration? (5 points)

Answers

Answer:

The answer is 15.28 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

where

m is the mass

f is the force

We have

[tex]a = \frac{275}{18} \\ = 15.277777...[/tex]

We have the final answer as

15.28 m/s²

Hope this helps you

1) A rigid tank contains 2 kg of 134a refrigerant at 800 kPa and 120°C. Determine tank volume and total internal energy.

Answers

Answer:

V = 0.07525 [m³]

U  = 655.74 [kJ]

Explanation:

To solve this problem we must use the superheated refrigerant table for refrigerant 134a. The attached image shows the specific volume and specific internal energy values for a pressure of 800 [kPa] and a temperature of 120 [°C].

m = mass =2 [kg]

the specific volume = v = 0.037625 [m³/kg]

The volume of the tank can be found using the following expression:

V = v*m

V = 0.037625*2 = 0.07525 [m³]

The Specific internal energy = u = 327.87 [kJ/kg]

U = u*m

U = 327.87*2 = 655.74 [kJ]

Tell which is the answer
help please

Answers

Answer: a constant? im not sure that just sounds like itd be right.

Explanation:

Answer:

b

Explanation:

because he isn't moving

Select the correct answer.
Which scientist discovered the relationship between electricity and magnetism?
OA.
Nikola Tesla
OB
Alessandro Volta
OC.
Hans Christian Oersted
OD
Isaac Newton

Answers

Answer:

Hans Christian Oersted

Explanation:

the wire is 5.20 cm from the charge and carries a current of 68.5 A in a direction opposite to that of the moving charge. Calculate the magnitude of the force on the charge.

Answers

Complete Question

A 6.00-µc charge is moving with a speed of 7.50x10^4 m/s parallel to a very long, straight wire. the wire is 5.20 cm from the charge and carries a current of 68.5 A in a direction opposite to that of the moving charge. Calculate the magnitude of the force on the charge.

Answer:

The value is [tex]F =1.20 *10^{-4} \ N[/tex]

Explanation:

From the question we are told that

     The magnitude of the charge is  [tex]Q = 6.00\muC = 6.00 *10^{-6} \ C[/tex]

      The speed is  [tex]v = 7.50 *10^{4} \ m/s[/tex]

      The distance of the wire from the charge is  [tex]d = 5.20 \ cm = 0.0520 \ m[/tex]

       The current flowing through the wire in the opposite direction to the charge  is  [tex]I _2 = 68.5 \ A[/tex]

  Gnerally the magnitude of force on that charge is mathematically represented as

      [tex]F = qvB[/tex]

Here B is magnetic field which is mathematically represented as

              [tex]B = \frac{\mu_o * I}{2\pi d}[/tex]

Here  [tex]\mu_o[/tex] is the permeability of free space with value  [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]

 So

       [tex]F = qv[\frac{\mu_o * I}{2\pi d}][/tex]

=>     [tex]F = 6.0*10^{-6} * (7.50 *10^{4})[\frac{4\pi * 10^{-7} * 68.5 }{2* 3.142 * 0.0520 }][/tex]      

=>    [tex]F =1.20 *10^{-4} \ N[/tex]

 

An airplane flying at 119 m/s is accelerated uniformly at the rate of 0.5 m/s2 for 10
seconds. What is its final speed?

Answers

Answer:

124m/s

Explanation:

v=u+at

v=119+(0.5×10)

v=119+5

v=124m/s

A ball is thrown horizontally from a 12 m
building with a speed of 2.0 m/s.
-high
How far from the base of the building does the ball hit the ground ?

Answers

Answer:

24

Explanation:

you multiply 2.0x12

Centripetal acceleration must involve a change in

Answers

Answer:

Centripetal acceleration must involve a change in a. an object's tangential speed.

Explanation:

Centripetal acceleration must involve a change in direction of motion of the object.

What is centripetal acceleration?

centripetal acceleration is the acceleration of a body traversing a circular path. Because velocity is a vector quantity (that is, it has both a magnitude, the speed, and a direction), when a body travels on a circular path, its direction constantly changes and thus its velocity changes, producing an acceleration. The acceleration is directed radially toward the center of the circle.

In your daily existence, you must have encountered numerous instances of centripetal acceleration. A centripetal acceleration occurs when you drive in a circle, and a centripetal acceleration also occurs when a satellite orbits the earth. Centripetal refers to being in the center.

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In what climates would you expect soil to form fastest? Why?

Answers

Answer:

Soils develop faster in warm, moist climates and slowest in cold or arid ones. Rainfall is one of the most important climate factors in soil formation.

Please mark me brainliest!

Hope this helped God bless :)

Soil formation occurs more swiftly in warm, humid areas than it does in cold or arid ones.One of the most crucial climatic variables for the formation of soil is rainfall. The breakdown of large soil particles into smaller ones is accelerated by creatures such as bacteria, plants, and animals.

What climates soil to form fastest?

The rate of chemical reactions is accelerated by rising temperature, which also accelerates soil formation. Faster plant and bacterial growth in warmer climates aids in the weathering of materials and the formation of soils.

The formation of soil is another indirect effect of climate on organisms. Weathering is accelerated by precipitation and warm temperatures, which increases the amount of soil development. Rainfall increases the amount of organic matter, lowers pH, accelerates the leaching of basic ions, moves mud, etc.

Therefore, In warm, wet regions, soil development happens more quickly than in cold or arid ones. One of the most crucial climatic variables for the formation of soil is rainfall.

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This is about acceleration, velocity and all that mumbo jumbo

Which best depicts the data?

1, From 0 to 2 seconds, Anna experienced negative acceleration.
2, From 3 to 6 seconds, Elan accelerated while Anna did not.
3, From 6 to 8 seconds, Elan accelerated faster than Anna.
4, From 8 to 10 seconds, Elan experienced negative acceleration.

Answers

Answer:

[tex]3. \: From \: 6 \: to \: 8 \: seconds, \: Elan \: \\ accelerated \: \: faster \: than \: Anna. [/tex]

Object has a mass of 35g and a density of 5g/cm3.
What is the volume? *

Answers

Answer:

The answer is 7.0 mL

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\[/tex]

From the question

mass = 35 g

volume = 5 g/cm³

We have

[tex]volume = \frac{35}{5} \\ [/tex]

We have the final answer as

7.0 mL

Hope this helps you

Add the following vectors:

(a) (12, 5) + (6, 3)
(b) (−3, 8) + (6, −2)
(c) (3, 8, −7) + (7, 2, 17)
(d) (a, b, c) + (d, e, f)

Answers

Answer:

a. (18,8)

b. (3, 6)

c. (10, 10, 10)

d. (a+d, b+e, c+f)

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A 10 [kg] object is dropped from rest. a. How far will it drop in 2 [s]?

Answers

Answer:

y=0.5 g t^2

=0.5*10*2^2

=20 m

A 65.25 kg person holding a steel ball stands motionless on a frozen lake.
The person then throws the ball, which propels the person at 1.25 m/s to the
right and the ball 4.05 m/s to the left. If the initial momentum of the system is
zero, what is the mass of the steel ball?

Answers

Answer:

20.14 KG

Explanation:

apex keepy o heads up stay positive don't stress over something useless big future 4 all of yall!

The mass is 20.14 kg


What is the average velocity of a boy moving from initial position of 4 m to a final position of 8 min 20 s. Show steps of solving:


please please heeeeelp​

Answers

9514 1404 393

Answer:

  0.2 m/s

Explanation:

The average velocity is the change in position divided by the change in time:

  (8 m -4 m)/(20 s) = (4/20) m/s = 1/5 m/s = 0.2 m/s

The boy's average velocity is 0.2 m/s.

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