Answer:
15min
Explanation:
The speed would be equal to the speed from the walking backwards 5 meter trial and time should be 15 minutes.
Atoms are composed of protons, ______, and electrons.
Atoms are composed of protons, [tex]\sf\purple{neutrons}[/tex]and electrons. ✅
The [tex]\sf\blue{protons}[/tex] (positively charged) and the [tex]\sf\pink{neutrons}[/tex] (no charge) are in the centre of the atom, making up the nucleus.[tex]\sf\red{Electrons}[/tex] (negatively charged) are present in the outermost shell of the atom.[tex]\bold{ \green{ \star{ \orange{Hope\:it\:helps.}}}}⋆[/tex]
An 800-kHz radio signal is detected at a point 9.5 km distant from a transmitter tower. The electric field amplitude of the signal at that point is 0.23 V/m. Assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground is completely absorbed. What is the average electromagnetic energy density at that point
Answer:
[tex]E_{avg}=2.34*10^{-13}J/m^3[/tex]
Explanation:
From the question we are told that:
Frequency [tex]F=800KHz =800*10^3Hz[/tex]
Distance [tex]9.5km=9.5*10^3[/tex]
Electric field amplitude [tex]E=0.23V/m[/tex]
Generally the equation for Average electromagnetic energy density is mathematically given by
[tex]E_{avg}=\frac{1}{2} \epsilon_0 E^2[/tex]
[tex]E_{avg}=\frac{1}{2} 8.85*10^{-12}*(0.23)^2[/tex]
[tex]E_{avg}=\frac{1}{2}* 8.85*10^{-12}*(0.23)^2[/tex]
[tex]E_{avg}=2.34*10^{-13}J/m^3[/tex]
Therefore the average electromagnetic energy density at that point
[tex]E_{avg}=2.34*10^{-13}J/m^3[/tex]
When playing tennis, if you hit the ball off of the top end of the racket, an uncomfortable standing wave vibration is produced in the racket. This wave is
Answer:
Transverse.
Explanation:
Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.
An electromagnetic spectrum refers to a range of frequency and wavelength that an electromagnetic wave is distributed or extends. The electromagnetic spectrum comprises of gamma rays, visible light, ultraviolet radiation, x-rays, radio waves, and infrared radiation.
A transverse wave can be defined as a type of wave in which particles of the medium of propagation oscillates or vibrates in a direction that is perpendicular to the direction that the wave moves i.e at right angle to the direction of propagation of the wave.
Basically, sound is a transverse and all transverse wave are the direct opposite of a longitudinal wave that usually travel in the same direction of its oscillation.
Hence, this wave is transverse.
when applied behavior analysis is used properly what happens???
Answer:
Applied Behavior Analysis therapy (ABA) is a type of intensive therapy that focuses on the principles and techniques of learning theory to help improve social behavior. ABA therapy helps to (1) develop new skills, (2) shape and refine previously learned skills, and (3) decrease socially significant problem behaviors.
Explanation:
A 5.0-m radius playground merry-go-round with a moment of inertia of 1,630 kg m2 is rotating freely with an angular speed of 1.6 rad/s. Two people, each having a mass of 69.5 kg, are standing right outside the edge of the merry-go-round and step on it with negligible speed. What is the angular speed of the merry-go-round right after the two people have stepped on
Answer:
The right solution is "0.511".
Explanation:
Given:
Initial moment of inertia,
= 1630 kg.m²
Radius,
= 5 m
Angular speed,
= 1.6 rad/s
Now,
The moment of inertia after stepping on will be:
= [tex]1630+2\times (69.5\times (5)^2)[/tex]
= [tex]1630+2\times (69.5\times 25)[/tex]
= [tex]5105 \ Kg.m^2[/tex]
hence,
As per the question, the angular speed is conserved, then
⇒ [tex]1630\times 1.6=5105\times \omega'[/tex]
[tex]2608=5105\times \omega'[/tex]
[tex]\omega'=\frac{2608}{5105}[/tex]
[tex]=0.511[/tex]
Can someone help me
At what speed does light travel through water. n=1.33
Answer:
"In water, the speed of light is v01.33=2.26 x 108 m/s."
Explanation:
The atmospheric features of Neptune are easier to see than those of Uranus because A. Neptune has greater warmth and less haze. B. Neptune has more methane. C. The atmosphere of Uranus rotates differentially. D. Uranus has no significant atmosphere.
Answer:
Option B is the correct answer (Neptune has more methane)Explanation:
From the options given,
The atmospheric features of Neptune are easier to see than those of Uranus because Neptune has more methane
Neptune has small amount of methane and water which gives it blue colour and white patches which distinguish it from uranus
For more information, visit
http://abyss.uoregon.edu/~js/ast121/lectures/lec20.html
Two particles in a high-energy accelerator experiment are approaching each other head-on, each with a speed of 0.9520c as measured in the laboratory. What is the magnitudeof the velocity of one particle relative to the other
Answer:
the magnitude of the velocity of one particle relative to the other is 0.9988c
Explanation:
Given the data in the question;
Velocities of the two particles = 0.9520c
Using Lorentz transformation
Let relative velocity be W, so
v[tex]_r[/tex] = ( u + v ) / ( 1 + ( uv / c²) )
since each particle travels with the same speed,
u = v
so
v[tex]_r[/tex] = ( u + u ) / ( 1 + ( u×u / c²) )
v[tex]_r[/tex] = 2(0.9520c) / ( 1 + ( 0.9520c )² / c²) )
we substitute
v[tex]_r[/tex] = 1.904c / ( 1 + ( (0.906304 × c² ) / c²) )
v[tex]_r[/tex] = 1.904c / ( 1 + 0.906304 )
v[tex]_r[/tex] = 1.904c / 1.906304
v[tex]_r[/tex] = 0.9988c
Therefore, the magnitude of the velocity of one particle relative to the other is 0.9988c
A section of a parallel-plate air waveguide with a plate separation of 7.11 mm is constructed to be used at 15 GHz as an evanescent wave attenuator to attenuate all the modes except the TEM mode along the guide. Find the minimum length of this attenuator needed to attenuate each mode by at least 100 dB. Assume perfect conductor plates.
Answer:
the required minimum length of the attenuator is 3.71 cm
Explanation:
Given the data in the question;
we know that;
[tex]f_{c_1[/tex] = c / 2a
where f is frequency, c is the speed of light in air and a is the plate separation distance.
we know that speed of light c = 3 × 10⁸ m/s = 3 × 10¹⁰ cm/s
plate separation distance a = 7.11 mm = 0.0711 cm
so we substitute
[tex]f_{c_1[/tex] = 3 × 10¹⁰ / 2( 0.0711 )
[tex]f_{c_1[/tex] = 3 × 10¹⁰ cm/s / 0.1422 cm
[tex]f_{c_1[/tex] = 21.1 GHz which is larger than 15 GHz { TEM mode is only propagated along the wavelength }
Now, we determine the minimum wavelength required
Each non propagating mode is attenuated by at least 100 dB at 15 GHz
so
Attenuation constant TE₁ and TM₁ expression is;
∝₁ = 2πf/c × √( ([tex]f_{c_1[/tex] / f)² - 1 )
so we substitute
∝₁ = ((2π × 15)/3 × 10⁸ m/s) × √( (21.1 / 15)² - 1 )
∝₁ = 3.1079 × 10⁻⁷
∝₁ = 310.79 np/m
Now, To find the minimum wavelength, lets consider the design constraint;
20log₁₀[tex]e^{-\alpha _1l_{min[/tex] = -100dB
we substitute
20log₁₀[tex]e^{-(310.7np/m)l_{min[/tex] = -100dB
[tex]l_{min[/tex] = 3.71 cm
Therefore, the required minimum length of the attenuator is 3.71 cm
An aggregate is one type of land resource. What is an aggregate?
a layer of solid rock found beneath soil
the top layer of soil
a natural mixture of sand, gravel, and crushed stone
a naturally occurring mineral or rock
Answer:
a natural mixture of sand, gravel, and crushed stone
Explanation:
Soil formation occurs as a result of the the decay or the remains of plants and animals which are used up.
Weathering can be defined as the physical and chemical breakdown of rock into smaller pieces called sediment. Weathering can be classified into two categories namely;
I. Physical weathering : it is the process of breaking rocks into pieces without affecting its chemical composition e.g temperature, abrasion and frost action.
II. Chemical weathering : it is the process of breaking rocks into pieces by chemical action which leads to changes in its chemical composition e.g carbonation, hydration, plant acid and oxidation.
In Science, one of the type of land resource is generally referred to as an aggregate.
Typically, an aggregate is a natural mixture of sand, gravel, and crushed stone. It's a heterogeneous mixture that is commonly mixed with bitumen, gypsum, cement, lime and several other adhesive to form mortar or concrete which are used in building and constructions.
Answer:
C
Explanation:
It's correct have a nice day
During forced exhalation, such as when blowing up a balloon, the diaphragm and chest muscles create a pressure of 72.0 mm Hg between the lungs and chest wall. What force in newtons does this pressure create on the 605 cm2 surface area of the diaphragm
Answer:
F = 580.75 N
Explanation:
The force can be calculated through the following formula:
[tex]F = PA[/tex]
where,
F = Force = ?
P = Pressure = (72 mm Hg)(133.322 Pa/1 mm Hg) = 9599.18 Pa
A = Area = (605 cm²)(1 m²/10⁴ cm²) = 0.0605 m²
Therefore,
[tex]F = (9599.18\ Pa)(0.0605\ m^2)[/tex]
F = 580.75 N
Which ones of the following lights are present in both sunlight and a grow
bulb
Radio waves
Gamma waves
O Visible Light
O Infrared
O Ultraviolet
Answer:
visible and ultraviolet
4- What force must be applied to a surface area of 0.0025m , to create a pressure ol
200.000Pa?
Steel Usually forms a
magnet that keeps its magnetism when moved away from a
magnetic source. What one word completes the sentence?
Answer:
Permanent magnetism (of the steel)
make me brainliestt :))
Why do waves in a tank are 10 cm long if they pass a point at a rate of 3.75 waves per second what is the speed in m/s?
Answer: 0.0267m/s
Explanation: Wave speed in m/s
Speed = Distance/Time
Substitute the given values into the formula
Speed = 0.1/3.75
Speed = 0.0267m/s
The speed of the waves in the tank is 0.375 m/s.
What is a wave?A wave is a disturbance that travels through space and time, often transferring energy from one place to another. Waves can take many forms, including sound waves, light waves, water waves, seismic waves, and electromagnetic waves.
Waves are characterized by their wavelength, frequency, amplitude, and velocity, which determine their properties, such as the pitch of a sound wave, the color of a light wave, or the size of a water wave. Waves can be reflected, refracted, diffracted, or absorbed as they interact with different materials and obstacles in their path. Waves play an essential role in many natural phenomena and technological applications.
Here in the Question,
We can use the formula:
speed (v) = frequency (f) x wavelength (λ)
Given that the frequency is 3.75 waves per second and the wavelength is 10 cm (or 0.1 m), we can plug in these values to get:
v = 3.75 x 0.1
v = 0.375 m/s
Therefore, The waves in the tank move at a 0.375 m/s speed.
To learn more about Frequency click:
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uses of generator
pls in points
if you answer correct i will mark you as brainliest
Answer:
Electric generator, also called dynamo, any machine that converts mechanical energy to electricity for transmission and distribution over power lines to domestic, commercial, and industrial customers. Generators also produce the electrical power required for automobiles, aircraft, ships, and trains.
Answer:
Electric motors are used in a broad range of industrial, commercial, and residential, applications, such as fans, pumps, compressors, elevators, and refrigerators. ... DC motors are used for variable speed control applications such as industrial machinery and motor vehicles.
In electricity generation, a generator is a device that converts mechanical energy to electrical energy for use in an external circuit. Generators provide nearly all of the power for electric power grids.
Hope it helps
differences between relative density and density
Answer:
Density is the ratio between the mass and the volume of a body. Relative density, on the other hand, is the ratio between the density of an object (substance) and the density of some other reference object (substance) at some given temperature.
Explanation:
A 1460 kg car moving north at 27.0 m/s collides with a 2165 kg car moving east at 18.0 m/s. They stick together. In what direction and with what speed do they move after the collision?
Answer in degrees north of east
AND
the speed after the collision in m/s
Answer:
Solution given:
North car
mass[m1]=1460kg
velocity[u1]=27 m/s
mass[m2]=2165kg
velocity [u2]=18m/s
let v be velocity after collision
we have
From the principle of conservation of linear momentum
m1u1+m2u2=(m1+m2)v
1460*27+2165*18=(1460+2165)v
v=[tex] \frac{78390}{3625} [/tex]
v=21.6m/s
the speed after the collision in 21.6 m/s.
For angle.
Tan angle =[tex] \frac{m1u1}{m2u2} [/tex]
Tan angle =[tex] \frac{1460*27}{2165*18} [/tex]
Tan angle=327.74
angle=Tan-¹(327.74)=89.82=90°
in degrees north of east is 90°
A Young’s double-slit apparatus is set up where a screen is positioned 0.80 m from the double slits. If the distance between alternating bright fringes is 0.95 cm, and the light source has a wavelength of 580 nm, what is the separation of the double slits?
Answer: 0.0488 mm
Explanation:
Given
The position of the screen is [tex]D=0.80\ m[/tex]
Distance between alternating bright fringes is [tex]0.95\ cm[/tex]
The wavelength of the light source is [tex]\lambda =580\ nm[/tex]
Distance between successive bright fringes is [tex]\frac{\lambda D}{d}[/tex]
Distance between alternating bright fringes is half of the distance between successive fringes i.e. [tex]\frac{\lambda D}{2d}[/tex]
Insert the values for alternating fringes
[tex]\Rightarrow 0.95\times 10^{-2}=\dfrac{580\times 10^{-9}\times 0.8}{d}\quad [\text{d=separation of the doubleslits}]\\\\\Rightarrow d=\dfrac{464\times 10^{-9}}{0.95\times 10^{-2}}\\\\\Rightarrow d=488.42\times 10^{-7}\ m\\\Rightarrow d=0.0488\ mm[/tex]
Which of the following most
directly limits the number of
organisms in a community?
Answer:
It can either be food, mating, or competition with other organisms for resources.
wha are the role of competition policy authorities
Answer: The competition policy helps in development of the competition in the authority.
Explanation:
In consumer market competition exists between the producers. The main role of the competition policy is to promote competition in the market. It helps multiple businesses or individuals to utilize their resources efficiently and produce products at best quality and at cheapest prices. It allows the consumers to compare and purchase the better deal. It helps in starting of new businesses and also helps in increase in total production output. It is the result of the natural economic growth.
BRAINLIST A wave travels at a constant speed. How does the wavelength change if the
frequency is reduced by a factor of 3? Assume the speed of the wave remains
unchanged.
A. The wavelength does not change.
B. The wavelength increases by a factor of 3.
C. The wavelength decreases by a factor of 3.
D. The wavelength increases by a factor of 9.
At the Olympics, high-diving competition,a diver from the top board curves her body in order to?
A. Dive clearly into the water
B. Spin more
C. Increase her energy
D. Spin more slowly
E. Increase her speed
The correct option is E. Increase her speed
High-diving is the process or way in which a person jump into water or swimming pool from a higher heights.
A Diver is a person who dive or Fall into a water from a top board or diving board .
Therefore she was curving her body from the top board in order to Increase her speed which will enable her to spin or flip more faster.
Inconclusion The correct option is E. Increase her speed.
Learn more about Diving here:
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Why is it important for equipment for sport to be strong? To protect us
Answer:
To protect us.
Explanation:
For ex. your dunking on a basketball hoop if that wasn't strong you would fall on your back and get injured.
What effect does the Duck Velocity have on the waves seen by the observer?
Towards the boat:
Away from the boat:
Same as the boat:
differences between static friction and dynamic friction
Answer:
Static friction acts on stationary objects while kinetic friction acts on those in motion. Static friction is always greater or equal to kinetic friction. This can explain why objects often take more force to get in motion than it takes to continue their motion.
An ideal massless spring with a spring constant of 2.00 N/m is attached to an object of 75.0 g. The system has a small amount of damping. If the amplitude of the oscillations decreases from 10.0 mm to 5.00 mm in 15.0 s, what is the magnitude of the damping constant b
Answer: 0.00693
Explanation:
Given
Spring constant [tex]k=2\ N/m[/tex]
Mass of object [tex]m=75\ g[/tex]
The amplitude of the oscillation decreases from 10 mm to 5 mm in 15 s
Equation of amplitude for the ideal spring-mass system is
[tex]\Rightarrow A=A_oe^{-\frac{bt}{2m}}\quad \quad [\text{b=damping constant}]\\\text{Insert the values}\\\\\Rightarrow 5=10e^{\frac{b\times 15}{2\times 0.075}}\\\\\Rightarrow e^{-\frac{b\times 15}{2\times 0.075}}=0.5\\\\\text{Taking natural log both sides}\\\\\Rightarrow \ln \left(e^{-\frac{b\times 15}{2\times 0.075}}\right)=\ln 0.5\\\\\Rightarrow -\dfrac{15b}{0.15}=-0.693\\\\\Rightarrow b=0.00693[/tex]
the removal of rock in solution by acidic rain water________
Answer:
Solution
Explanation:
Solution is a process in chemical weathering and it is the process of dissolving or removing rock in a solution through the activities of acid rain or solution. Chemical weathering refer to the process where rocks interact with chemical solutions or acid rain which can result in His integration.
An athlete is performing squats in the weight room. The knee is going from anatomical position to 92 degrees and then back to anatomical position each squat. The athlete performs a total of 10 squats. This is done over a time period of 30 seconds. What is the angular acceleration (rad/sec 2) of the knee
Answer:
α = 0.357 ras / s²
Explanation:
This is a rotational kinematics exercise, it tells us that it performs 10 squats in 30 s, for which it performs one squat at t = 3 s, also indicates that the angle of the squat is θ = 92º
θ = θ₀ + w₀ t + ½ α t²
the athlete starts from rest, whereby w₀ = 0 and the initial angle in the vertical position is zero (θ₀=0)
θ = ½ α t²
α = 2 θ /t²
let's reduce the magnitudes to the SI system
θ = 92º (π rad /180º) = 0.511π rad
let's calculate
α = 2 0.5111π /3²
α = 0.1136π rad / s²
α = 0.357 ras / s²