How many liters of 3.0 MNAOH solution will react with 2.4 mole H2 S04

Answers

Answer 1
Hello! I have the answer for your questions!

So happy I found this question!

H2SO4 + NaOH → Na2SO4 + H2O

1.2 L
1.6 L
2.4 L
2.8 L

That’s the answer! I remember learning this :)

Related Questions

How can you tell if an atom has a positive charge? What type of ion is this?

Answers

Answer:i love you

Explanation:

Answer: An atom can acquire a positive charge or a negative charge depending on whether the number of electrons in an atom is greater or less then the number of protons in the atom.  If the atom has more electrons than protons, it is a negative ion, or ANION. If it has more protons than electrons, it is a positive ion.

Explanation:

Explain what might happen to tundra animals, such as polar bears, as earth's climate warms. pls explain

Answers

Answer:

They will die.

Explanation:

Polar Bears were made to live in the frigid temperatures of the tundras. If there is a temperature change it can affect their habitat. It can destroy it and they would have to move out to another place. They can die due to global warming.

URGENT PLEASE HELP! Given 3.4 grams of x element with a molar mass of 24 g/mol and 4.2 grams of y element with a molar mass of 35 g/mol. How much of compound xy2 can be generated?
x + 2y -> xy2

Answers

4.4 g XY

I'm not sure but that's the closest I can get or try

Consider a iron-silver voltaic cell that is constructed such that one half-cell consists of the iron, Fe, electrode immersed in a Fe(NO3)3 solution, and the other half-cell consists of the silver, Ag, electrode immersed in a AgNO3 solution. The two electrodes are connected by a copper wire. The Fe electrode acts as the anode, and the Ag electrode acts as the cathode. To maintain electric neutrality, you add a KNO3 salt bridge separating the two half-cells. Use this information to solve Parts B, C, and D. Part B The half-cell is a chamber in the voltaic cell where one half-cell is the site of the oxidation reaction and the other half-cell is the site of the reduction reaction. Type the half-cell reaction that takes place at the anode for the iron-silver voltaic cell. Indicate the physical states of atoms and ions using the abbreviation (s), (l), or (g) for solid, liquid, or gas, respectively. Use (aq) for an aqueous solution. Do not include phases for electrons. Express your answer as a chemical equation.

Answers

Answer:

See explanation

Explanation:

In the voltaic cell, energy is produced by spontaneous chemical reaction. One half cell functions as the anode (in this case it is the Fe/Fe^2+ half cell) while the other half cell functions as the cathode (in this case it is the the Ag/Ag^+ half cell).

At the anode;

Fe(s) -----> Fe^2+(aq) + 2e

At the anode;

2Ag^+(aq) + 2e ------> 2 Ag(s)

Overall cell equation;

Fe(s) + 2Ag^+(aq)  ------> Fe^2+(aq) + 2 Ag(s)

How many lone pairs are on the central atom of a molecule of RnCl4?
A. 0
B. 2
C. 3
D. 1

Answers

My teacher said it is c

Calculate the molar mass of PbSo3

Answers

Answer:

Lead sulfite is the inorganic compound with the formula PbSo3 or O3PbS.

Explanation:

If 18.0 g of CO2 is produced in the reaction of C2H2 with O2 to form CO2 and
H2O, how many grams of H20 are produced in this reaction?
O 3.68 g
9.0 g
14.7 g
None of the above
7.37 g

Answers

Answer:

3.68 g

Explanation:

[tex]n_{CO2}[/tex] = 18 ÷ 44 = 0.4

2C2H2 + 5O2 → 4CO2 + 2H2O

   2       :    5      :    4      :    2  

                             0.409                 (moles)

⇒ [tex]n_{H2O}[/tex] = 0.409 × 2 ÷ 4 = 0.2045 moles

⇒ [tex]m_{H2O}[/tex] = 0.2045 × 18 = 3.68 grams

During the age of the dinosaurs, most mammals grew no bigger than a?

Answers

Answer:

T-rex

Explanation:

what is the process by which gas changes to a solid

Answers

The process by which gas changes to a solid is deposition.

1) ____C3H8 + ____O2 → ____CO2 + ____H2O

Answers

C3H8 + 5O2 → 3CO2 + 4H2O

What is the difference between 13.254 m/s and 7.7 m/s? Round your answer to the correct number of significant digits.

Answers

Answer:

5.6 m/s

Explanation:

Given,

First number = 13.254 m/s

Second number = 7.7 m/s

We need to find the difference between these two numbers. First we round off 13.254 to one decimal place i.e. 13.254 = 13.3 m/s

The difference between them is given by :

D = 13.3 - 7.7

= 5.6 m/s

Hence, the difference of the two numbers is 5.6 m/s.

4 methyl 2 pentanone structural formula​

Answers

Answer:

(CH3)2CHCH2COCH3

Explanation:

A piece of copper has a density of 8.96 g/cm3, what is the volume of a 4.2 g piece?

Answers

Answer:

0.47 cm³

Explanation:

[tex]Volume=Mass/Density\\[/tex]

Plug in the mass (4.2 grams) and the density (8.96 g/cm³)

[tex]Volume=4.2/8.96\\Volume=0.47[/tex]

Therefore, the volume of a 4.2 g piece of copper is approximately 0.47 cm³.

I hope this helps!

Which of the Following is a true statement regarding a strong acid such as 0.1M HNO3(aq) and weak acid such as HF?

A. 0.1 M HNO3 (aq) solution contains more H+ than HF(aq) solution
B. 0.1 M HNO3 (aq) solution contains less H+ than HF(aq) solution
C. 0.1M HNO3 (aq) solution contains the same amount of H+ as HF (aq) solution
D. 0.1M HNO3 (aq) solution has a higher pH then the HF (aq) solution

Answers

Answer:

A. 0.1 M HNO3 (aq) solution contains more H+ than HF(aq) solution

Crystallization: What is the difference between raw and pure products?

Answers

Answer:

Hello There!!

Explanation:

Pure products come from and made where they are original made and raw products are just pasteurized with no added ingredients included in them.

hope this helps,have a great day!!

~Pinky~

Calculate the pH and pOH of a solution of sodium hypoiodite NaOI, with a formal concentration of 0.05784 mol L-1. Note that the compound is soluble, dissolves into sodium and hypoiodite ions, and these react with water. The p K a of hypoiodous acid at 298 K is 10.64. Calculate the pH and the pOH of the resulting solution. Use all the approximations you can, be sure to verify them.

Answers

Answer:

pH = 11.70

pOH = 2.298

Explanation:

As we know

NaOI + H2O  NaOH + HOI

pH = 7 + ½ (pKa + log (HOI))

Substituting the given values, we get –

pH = 7 + ½ (10.64 + log (0. 0.05784))

pH = 7 + ½ (10.64 -1.2377)

pH = 11.70

pOH = 14 – pH  

pOH = 14 -11.70

pOH = 2.298

Which of the following is NOT correct about the mole concept?
1 point
1 mole of sodium atoms will ionize to produce 1 mole of sodium ions and 1 mole of
electrons
A mole is the number of carbon atoms in 12g of C-12 isotope.
A mole is the number of molecules in 22.4 dm3 of all gases at all temperatures and
pressures
A mole is the number of electrons that carry one Faraday of electricity
A mole is the number of molecules of water in 18 g of ice, water or water vapour

Answers

Answer:

a mole is the number of molecules in 22.4 dm³ for all gases at all temperatures and pressures

what charge does copper have?

Answers

Answer: 1+charge

Explanation: hoped this helped:)

If a gas is cooled from 343.0 K to 283.15 K and the volume is kept constant what final pressure would result if the original pressure was 760.0 mm HG?

Answers

Answer:

627.4 mmHg

Explanation:

From Gay-Lussac law:

[tex] \frac{p1}{t1} = \frac{p2}{t2} [/tex]

p1 = 760 mmHg

t1 = 343 K

t2=283.15 K

[tex]p2 = p1 \times \frac{t2}{t1} [/tex]

[tex]p2 = 760 \times \frac{283.15}{343.0} [/tex]

[tex]p2 = 627.4 \: mmhg[/tex]

If a gas is cooled from 343.0 K to 283.14 K and the volume is kept constant the final pressure would be 627.4 mm Hg if the original pressure was 760.0 mm Hg.

Gay-Lussac's Law

Gay-Lussac's law states that the pressure of a given mass of gas at a constant volume varies directly with the temperature of the gas.  Gay-Lussac's law defined the relationship between pressure and temperature of a gas when kept at a constant volume.

According to the Gay-Lussac's Law

P ∝ T       (When V = constant)

or, P = kT

or, [tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}[/tex]

Here,

[tex]P_{1}[/tex] = 760.0 mm Hg,

[tex]T_{1}[/tex]= 343.0 K

[tex]T_{2}[/tex] = 283.15 K

Now put the values in above formula, we get

[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}[/tex]

[tex]\frac{760.0\ \text{mm Hg}}{343.0K} = \frac{P_2}{283.15\ K}[/tex]

[tex]P_{2} = \frac{760.0\ \text{mm Hg} \times 283.15\ K}{343.0\ K}[/tex]

[tex]P_{2} = \frac{215194\ \text{mm Hg}}{343}[/tex]

[tex]P_{2}[/tex] = 627.4 mm Hg

Thus, we can say that if a gas is cooled from 343.0 K to 283.14 K and the volume is kept constant the final pressure would be 627.4 mm Hg if the original pressure was 760.0 mm Hg.

Learn more about Gay-Lussac's Law here: https://brainly.com/question/24691513

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In order to determine the magnetic properties of phosphorus atom we need to find out the number of unpaired electrons present in the ground state of phosphorus atom! Select one of the answers below that represents this number.
Group of answer choices

1

4

3

0

2

Answers

Answer:

Think of it this way If you have a phosphorus atom whats its oposites once you found that out you may be able to find the answer

Explanation:

Hope this helps :)

Draw the atomic structure with electronic configuration of Potassium​

Answers

Answer:

Explanation:

i try to help you

✧Kindly see the attached picture! ☄

♪ Hope I helped! ♡

[tex] \star[/tex] Best regards! ツ

☞ [tex] \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}[/tex] ✎

Copper can be shaped into wires because it is

Answers

.ANSWER:Copper is a ductile metal

EXPLAIN :This means that it can easily be shaped into pipes and drawn into wires. Copper pipes are lightweight because they can have thin walls. They don't corrode and they can be bent to fit around corners.

Copper is a ductile metal due to ductility.This means that it can easily be shaped into pipes and drawn into wires. Copper pipes are lightweight because they can have thin walls.

Ductility is a mechanical property commonly described as a material's amenability to drawing (e.g. into wire).In materials science, ductility is defined by the degree to which a material can sustain plastic deformation under tensile stress before failure. Ductility is an important consideration in engineering and manufacturing. It defines a material's suitability for certain manufacturing operations (such as cold working) and its capacity to absorb mechanical overload.

Some metals that are generally described as ductile include gold and copper, while platinum is the most ductile of all metals in pure form.However, not all metals experience ductile failure as some can be characterized with brittle failure like cast iron. Polymers generally can be viewed as ductile materials as they typically allow for plastic deformation.

Learn more about ductility,here:

https://brainly.com/question/29416697

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An acetate buffer solution is prepared by combining 50. mL of 0.20 M acetic acid,
HC2H3O2(aq), and 50. mL of 0.20 M sodium acetate, NaC2H3O2(aq). A 5.0 mL sample of 0.10 M NaOH(aq) is added to the buffer solution.
Which of the following is a correct pairing of the acetate species present in greater concentration and of the pH of the solution after the NaOH(aq) is added? (The pKa of acetic acid is 4.7.)
Acetate Species -- pH
(A) HC2H3O2 -- < 4.7
(B) HC2H3O2 -- > 4.7
(C) C2H3O2 -- < 4.7
(D) C2H3O2 -- > 4.7

Answers

Answer:

The answer is "Option B".

Explanation:

[tex]\to CH_3COOH + NaOH \longleftrightarrow CH_3COONa + H_2O\\\\\to CH_3COONa + NaOH\longleftrightarrow CH3COONa\\\\\therefore \ mol\ NaOH = (5 \ E-3\ L)\times(0.10 \ \frac{mol}{L}) = 5 \ E-4\ mol\\\\[/tex]

[tex]\to mol\ CH_3COOH = (0.05 \ L)\times(0.20 \frac{mol}{L}) = 0.01 \ mol\\\\\to C \ CH_3COOH = \frac{(0.01 \ mol - 5 \ E-4\ mol) }{(0.105 \ L)}\\\\\to C \ CH_3COOH = 0.0905 \ M\\\\\therefore \ mol \ CH_3COONa = (0.05\ L )\times (0.20 \ \frac{mol}{L}) = 0.01 \ mol\\\\[/tex]

[tex]\to C \ CH_3COONa = \frac{(0.01\ mol + 5 \ E-4\ mol)}{(0.105\ L )}\\\\\to C \ CH_3COONa = 0.1 \ M\\\\\therefore Ka = ([H_3O^{+}]\times \frac{(0.1 + [H_3O^+]))}{(0.0905 - [H_3O^+])} = 1.75\ E-5\\\\\to 0.1[H_3O^+] + [H_3O^+]^2 = (1.75 E-5)\times (0.0905 - [H_3O^+])\\\\[/tex]

[tex]\to [H_3O^+]^2 \ 0.1[H_3O^+] = 1.584\ E-6 - 1.75\ E-5[H_3O^+]\\\\\to [H_3O^+]^2 + 0.1000175[H_3O^+] - 1.584 \ E-6 = 0\\\\\to [H_3O^+] = 1.5835\ E-5 \ M\\\\\therefore pH = - \log [H_3O^+]\\\\\to pH = - \log (1.5835 \ E-5)\\\\ \to pH = 4.8004 > 4.7[/tex]

Light and radio are examples of the __________________________ or ______________________ energy form, which is ________________ because it is always moving.

Answers

Answer:

Radiant; electromagnetic; kinetic energy.

Explanation:

Energy can be defined as the ability (capacity) to do work. The various forms of energy are solar energy, electrical energy, chemical energy, thermal energy, wind energy, nuclear energy etc.

The two (2) main types of energy are;

a. Gravitational potential energy (GPE): it is an energy possessed by an object or body due to its position above the earth.

b. Kinetic energy (KE): it is an energy possessed by an object or body due to its motion.

Light and radio are examples of the radiant or electromagnetic energy form, which is kinetic energy because it is always moving.

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

[tex] K.E = \frac{1}{2}MV^{2}[/tex]

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

what are the isomers of hexane​

Answers

Physical properties

Isomer M.P. (°C) B.P. (°C)

n-hexane −95.3 68.7

3-methylpentane −118.0 63.3

2-methylpentane (isohexane) −153.7 60.3

2,3-dimethylbutane −128.6 58.0

1 more row

A flexible container at an initial volume of 6.13 L contains 2.51 mol of gas. More gas is then added to the container until it reaches a final volume of 11.3 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Answers

Answer:

2.12 moles of gas were added.

Explanation:

We can solve this problem by using Avogadro's law, which states that at constant temperature and pressure:

V₁n₂=V₂n₁

Where in this case:

V₁ = 6.13 Ln₂ = ?V₂ = 11.3 Ln₁ = 2.51 mol

We input the data:

6.13 L * n₂ = 11.3 L * 2.51 moln₂ = 4.63

As 4.63 moles is the final number of moles, the number of moles added is:

4.63 - 2.51 = 2.12 moles

A cation with a +4 charge has 26 neutrons and 18 electrons. What is the identity of the element?

Answers

Answer: Titanium has 22 protons

Explanation:  If an atoms donates 4 electrons, it forms cation with charge +4. So original atom have 22 electrons and because atom is neutral, it has 22 protons. Number of neutrons does not matter, there are more neutrons than protons  in heavier atoms.

able 1 Cell Type Operating Cell Potential for Commercial Batteries, E (V) Lithium-iodine Zinc-mercury +2.80 +1.35 Table 2 Standard Reduction Potential, E' (V) -1.20 Half-Reaction [Zn(OH)212 +2e → Zn + 4 OH Zn(OH)2 +2e → Zn +20H- HgO + H2O +2e → Hg+20H O2 + 2H20 +40 →40H -1.25 +0.10 +0.40 ctronic devices that help regulate the heart rate. Currently, lithium-iodine cells are commonly used to power pacemakers and have replaced zinc-me otential, E, for each cell. Table 2 provides the standard reduction potentials for several half-reactions related to zinc-mercury and zinc-air cells. dation given, which of the following is a major difference between the zinc-mercury cell and the lithium-iodine cell? 0, +2H2O + 4e +40H +0.40 Pacemakers are electronic devices that help regulate the heart rate Currently, lithium-iodine cells are commonly used to power pacemakers and have replaced zinc-mercury cells. Table 1 provides the operating cell potential, E, for each cell. Table 2 provides the standard reduction potentials for several half-reactions related to zinc-mercury and zinc air cells. Based on the information given, which of the following is a major difference between the zinc mercury cell and the lithium-iodine cell?
A. During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is less thermodynamically favorable.
B. During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable.
C. During the initial cell operation, the oxidation of iodine is thermodynamically favorable but the oxidation of mercury is not.
D. During the initial cell operation, the oxidation of mercury is thermodynamically favorable but not the oxidation of iodine is not.

Answers

Answer:

During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable.  ( B )

During the initial cell operation, the oxidation of iodine is  thermodynamically favorable but the oxidation of mercury is not. ( C )

Explanation:

The major Differences between The Zinc mercury cell and Lithium-iodine cell are :

During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable.   and

During the initial cell operation, the oxidation of iodine is thermodynamically favorable but the oxidation of mercury is not.

Given the relationship below,

Δ G = -nFE

E = emf of cell ,  G = free energy.

This relationship shows that if E is positive the reaction will be thermodynamically favorable also if E is large it will increase the negativity of free energy  also From the question we can see that with the reduction of mercury the value of E is more positive and this shows that Mercury is thermodynamically unfavorable

2) Using the following equation:

Water is added to iron and over time iron (III) oxide along with hydrogen gas is produced.

a. How many grams of iron (III) oxide will be produced when 15.5g of iron reacts with excess water?
b. Calculate the percent yield if your team produced 14.5g of iron (III) oxide.
c. If the reaction takes place under STP then how many liters of hydrogen gas are produced?

Answers

the answer is 133

because thats how the water is

The galaxies pictured above would best be classified as
A barred galaxies
C irregular galaxies
B spiral galaxies
D
elliptical galaxies

Answers

Answer:

Spiral galaxies

Explanation:

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