How many liters of Argon gas are present in a 10.5 mole sample?

The change in free energy can help us to discover whether a reaction can be sponteanous or not. The change in free energy fro this reaction is -1.51 kJ/mol.

The change in free energy is referred to as that which determines the spontenity of a chemical reaction. For a spontenous reaction the change in free energy must be negative.

Now;

ΔG = -RTlnK

R = gas constant

T = temperature

K = equilibrium constant

So;

ΔG = -(8.314 * 298 * ln 436)

ΔG = -1.51 kJ/mol

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Answer:

2-pentene

Explanation:

The name of the alkene is 2 pentene. The correct option is B, 2-pentene.

Alkenes with the chemical formula [tex]C_5H_10[/tex] are known as pentene. Within its molecular structure, each has one double bond.

The given alkene [tex]CH_3CH = CHCH_2CH_3[/tex] is 2-pentene because the double bond is present in the second carbon and it's pentene because there are five carbons present.

Thus, the correct option is B. 2-pentene.

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Answer:

643g of methane will there be in the room

Explanation:

To solve this question we must, as first, find the volume of methane after 1h = 3600s. With the volume we can find the moles of methane using PV = nRT -Assuming STP-. With the moles and the molar mass of methane (16g/mol) we can find the mass of methane gas after 1 hour as follows:

Volume Methane:

3600s * (0.25L / s) = 900L Methane

Moles methane:

PV = nRT; PV / RT = n

Where P = 1atm at STP, V is volume = 900L; R is gas constant = 0.082atmL/molK; T is absolute temperature = 273.15K at sTP

Replacing:

PV / RT = n

1atm*900L / 0.082atmL/molK*273.15 = n

n = 40.18mol methane

Mass methane:

40.18 moles * (16g/mol) =

Answer:

22 neutrons

Explanation:

If so please sorry

Answer:

0.004235 M

Explanation:

The neutralization reaction of this question is given as follows:

Mg(OH)2 + 2HCl → MgCl2 + 2H2O

Using the formula below:

CaVa/CbVb = na/nb

Where;

Ca = concentration of acid (M)

Cb = concentration of base (M)

Va = volume of acid (mL)

Vb = volume of base (mL)

na = number of moles of acid = 2

nb = number of moles of base = 1

From the information provided in this question;

Ca = ?

Cb = 0.00125 M

Va = 425 mL

Vb = 720 mL

na (HCl) = 2

nb = (Mg(OH)2) = 1

Using the formula; CaVa/CbVb = na/nb

Ca × 425/0.00125 × 720 = 2/1

425Ca/0.9 = 2

472.2Ca = 2

Ca = 2/472.2

Ca = 0.004235 M

Molarity of acid=2.5M

pH=5.1.

ka=?

Now

We need to write an eqn to show the dissociation of the acid

HA + H2O === H3O+ + A-

Writing The Equilibrium(Or Acid dissociation constant) of this reaction

Ka =[H3O+] {A-]/ {HA].

The concept behind this is

concentration of Products divided by those of reactants. Water is not written because its a pure liquid and does not affect the Equilibrium constant.

Now If you have any Idea on ICE tables..

You'd know that the concentration of acid will decrease by 2.5-x

Whilst the products...will increase by x each

Note: This is when the ratio of their Moles are in 1:1

ka= x.x/2.5-x

Since the Moles of A- and H3O+ are in 1:1... Their concentrations at equilibrium will be the same

so

Ka= x²/2.5-x

Now what is x??

x is the Hydrozonium ion concentration.

we can get it from the pH formula

pH= -log (H3O+)

Making H3O+ subject by applying Logarithm Rules

H3O+ = 10^-ph

x=10^-5.1

=7.94x10^-6.

Now back to Ka

Ka= x²/2.5-x

Ka= (7.94x10^-6)²/2.5-(7.94x10^-6)

Ka= (7.94x10^-6)²/2.4999

Ka= 2.52x10^-11.

Was a Fun One

The ionization constant of this weak acid is [tex]2.52*10^{-11}[/tex]. The values can be substituted in dissociation formula.

What information do we have?
Molarity of acid=2.5M

pH=5.1

To find:

ka=?

[tex]HA + H_2O < === > H_3O^+ + A^-[/tex]

The value of dissociation constant will be:

[tex]Ka =[H_3O^+] [A^-]/ {HA][/tex]

The Moles of A- and H3O+ are in 1:1.Their concentrations at equilibrium will be the same.

[tex]Ka= x.x/2.5-x\\\\Ka= x^2/2.5-x\\\\pH= -log (H_3O^+)\\\\H_3O^+ = 10^{-pH}\\\\x=10^{-5.1}\\\\x=7.94*10^{-6}[/tex]

[tex]Ka= x^2/2.5-x\\\\Ka= (7.94*10^{-6})^2/2.5-(7.94*10^{-6})\\\\Ka= (7.94*10^{-6})^2/2.4999\\\\Ka= 2.52*10^{-11}\\\\[/tex]

Thus, ionization constant of this weak acid is [tex]2.52*10^{-11}[/tex].

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Answer:

3) Q = -836.8 J.

4) Q = 950J.

Explanation:

Hello there!

In this case, for those calorimetry problems, we use the general equation:

[tex]Q=mC\Delta T[/tex]

Thus, we proceed as follows:

3) Here, the temperature difference is from 80 °C to 40 °C, the mass is 5.0 g and the specific heat 4.184 in SI units; thus, the heat is calculated as follows:

[tex]Q=(5g)(4.184\frac{J}{g\°C} )(40\°C-80\°C)\\\\Q=-836.8J[/tex]

4) Here, the temperature difference is from 100 °C to 200 °C, the mass is 5.0 g and the specific heat about 1.90 in SI units; thus, the heat is calculated as follows:

[tex]Q=(5g)(1.90\frac{J}{g\°C} )(200\°C-100\°C)\\\\Q=950J[/tex]

Regards!

Answer: more than 70,00 and most of that population is living on the streets

Answer: First box----Hail

             Second Box-------Snow

             Thrid Box-------Sleet

              Forth Box-----Rain

Hope that helped! :)

Answer:

We will need two potassium ions to balance the charge on the sulfate ion, so the proper chemical formula is K 2SO 4.

Explanation:

hope this helps

Answer:

0.086

Explanation:

The formula for calculating the fraction of a covalent bond can be expressed as:

= exp (-0.25ΔE²)

[tex]= exp[-0.25(E_{Al}-E_{p})^2]---(1)[/tex]

from the equation above;

[tex]E_{Al}[/tex] = the electronegativity of aluminum

[tex]E_P[/tex] = electronegativity of phosphorus

Using the data from periodic table figures;

[tex]E_{Al}[/tex] = 1.5

[tex]E_P[/tex] = 2.1

∴

fraction of the covalent = exp[-0.25(1.5 - 2.1)²]

fraction of the covalent = exp(-0.09)

fraction of the covalent = 0.914

Now, the fraction of ionic bond will be = 1 - the fraction  of covalent bond

= 1 - 0.914

∴

the fraction of bond that is ionic = 0.086

Answer:

C₅H₈O₂

Explanation:

methyl methacrylate = 100 amu

6.91g CO₂ = 0.157 moles

2.26g H₂O = 0.125 moles

0.157 ÷ 0.125 = 1.256

{(CO₂)₁.₂₅₆ + (H₂O)₁} × 4 = (CO₂)₅ + (H₂O)₄

C₅H₈O?

C₅ = 60.05 amu H₈ = 8.064 amu

60.05 + 8.064 = 68.114 amu

100 amu - 68.114 amu = 31.886 amu

O = 16 amu

O = 2

The molecular formula of methyl methacrylate is C₅H₈O₂. The correct option is A, C₅H₈O₂.

What is methyl methacrylate?

Methyl methacrylate (MMA) is a colorless liquid monomer with a distinctive fruity odor. It is an organic compound that belongs to the family of acrylic esters.

We have to determine the empirical formula of methyl methacrylate first and then multiply it by the integer n to determine the molecular formula. Empirical formula:

CO₂ and H₂O are the combustion products of methyl methacrylate.

C₅H₈O₂ + (9n / 2)

O₂ → 5CO₂ + (n)H₂O

There are 5 C atoms and (8 + 2n), H atoms in the left and 5 C atoms, and n H atoms in the right.

5C = 5C, and 8 + 2n = nH.

n = 6

Molecular formula calculation is dividing the molecular weight by the empirical formula weight to determine the multiplication factor.

C₅HₙO₂ (empirical formula) has a weight of:

(5 x 12.011) + (8 x 1.008) + (2 x 15.999) = 100.12 g/mol

The actual molecular weight of methyl methacrylate is 100 g/mol.

Therefore, the molecular formula is (C₅H₈O₂) x 1, which is C₅H₈O₂, option A.

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Answer:

[tex]819 \: g = 819 \times {10}^{ - 3} \: kg = 0.819 \: kg \\ 0.819 \: kg - 0.497 \: kg \\ = 0.322 \: kg[/tex]

Answer:

errccvbnnbb

Explanation:

jjuxxxsyy

Answer:

i think it the third one

Explanation:

sorry if im wrong are u in biology?

Answer:

So when a cat puts up its middle finger its usually trying to scare you off.

Explanation:

it's gonna kill you.

Answer:

exothermic

Explanation:

Answer:

It's

Explanation:

Pbo + c

= pb + co2

While balancing it becomes

2pbo + c = 2pb + co2

(I was also doing same qn)

Explanation:

M(Bapo3) = 216m/mol

n = 3.8 mole

m = M × n = 216 × 3.8 = 820.8g

Answer: A.) 2 is the answer.

Explanation:

Answer:

well please answer me it's question too after you get it

Explanation:

i am also stucked in that question

No. of molecules of any substance is one mole

= Avogadro's Number = (6.022 x 10^23)

So, no. of molecules in 7.2 moles of sodium fluoride

= 7.2 × (6.022 x 10^23)

= 4.33584^24

Answer: 2)gas syringe

Explanation:

the volume of a gas is usually measured with a gas syringe (or sometimes with an upside-down measuring cylinder)

Answer:

top pan balance

Explanation:

[tex]\huge\color{yellow}\boxed{Answer:}[/tex]

My answer is C.Its particles slide past one another

[tex]\huge\color{yellow}\boxed{toshiro hitsugaya}[/tex]

When the  6 liters volume of the substance takes up 12 liter container, we conclude that the substace is highly compressible.

Compressibility is the measure of the relative volume change of a solid or a fluid with respect to pressure change.

Gases are the most compressible susbtance because most of the volume of a gas is composed of the large amounts of empty space between the gas particles.

Therefore, when the  6 liters volume of the substance takes up the entire volume of 12 liter container, we can conclude that the substace is highly compressible.

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Answer:

B. It gains energy in a quantized amount. ​

Answer:

B. strong base titration with a strong acid

Answer:

0.766atm

Explanation:

Boyles law

P1V1=P2V2

1×635=P2×829

P2=635/829

P2=0.766atm

Answer:

[tex]T_2=894.45K=621.30\°C[/tex]

Explanation:

Hell there!

In this case, according to the given information, it turns out possible for us to calculate the new temperature by applying the Charles' law as a directly proportional relationship between temperature and volume:

[tex]\frac{V_2}{T_2} =\frac{V_1}{T_1}[/tex]

Thus, we solve for the final temperature, T2, as shown below (make sure T1 is in Kelvins):

[tex]T_2=\frac{V_2T_1}{V_1} \\\\T_2=\frac{(25+273.15)K*45L}{15L}\\\\T_2=894.45K=621.30\°C[/tex]

Regards!

Explanation:

Write the balance equation for the reaction taking place:

CO(g) + 2H2(g) ==> CH3OH ... balanced equation

Find the limiting reactant:

Because according to the balanced equation it takes 2 moles H2 for every 1 mole CO, there isn't enough H2, so it is limiting and will dictate how much CH3OH can be made.

Mass of CH3OH produced = 0.75 moles H2 x 1 mol CH3OH / 2 mol H2 x 32 g CH3OH / mol = 12 g CH3OH