In the above case, there are 0.103 moles of argon gas as well as 4.12 grams of argon within the holder.
What is the STP?At STP (standard temperature and pressure), 1 mole of any gas involves 22.4 L. Also, the number of moles of argon gas in 2.3 L at STP can be calculated as:
n = V/ V_m
n = 2.3 L / 22.4 L/mol
n = 0.103 moles
To know the mass of argon, we need to make use of its molar mass. Note that the molar mass of argon is said to be 39.95 g/mol. Also , the mass of argon:
m = n × M
m = 0.103 moles × 39.95 g/mol
m = 4.12 g
So, 0.103 moles of argon gas as well as 4.12 grams of argon inside the holder.
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Please help, chemistry is hard
The formula of the hydrate, given that 10.00 g of the hydrated was heated and 7.342 g of solid, (NH₄)₃PO₄ was leftover is (NH₄)₃PO₄.3H₂O (option B)
How do i determine the formulaof the hydrate?First, we shall determine the mass of the water in the hydrate. Details below:
Mass of hydrate = 10.00 gMass of anhydrous, (NH₄)₃PO₄ = 7.342 gMass of water, H₂O = ?Mass of water, H₂O = Mass of hydrate - Mass of anhydrous
Mass of water, H₂O = 10 - 7.342
Mass of water, H₂O = 2.658
Finally, we shall determine the formula of the hydrate. Details below:
Mass of anhydrous, (NH₄)₃PO₄ = 7.342 gMass of water, H₂O = 2.658Formula of hydrate =?Divide by their molar mass
(NH₄)₃PO₄ = 7.342 / 149.09 = 0.049
H₂O = 2.658 / 18 = 0.148
Divide by the smallest
(NH₄)₃PO₄ = 0.049 / 0.049 = 1
H₂O = 0.148 / 0.049 = 3
Thus, the formula of the hydrate is (NH₄)₃PO₄.3H₂O (option B)
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Assign the oxidation numbers of each element given bold in the following chemical species: HCI, NH3, NO3, K₂Cr₂O7, Hg₂Cl2, HgCl2, Al(OH)3, Na3PO4
Answer:
HCI: H has an oxidation number of +1 and Cl has an oxidation number of -1.
NH3: N has an oxidation number of -3 and each H has an oxidation number of +1.
NO3: N has an oxidation number of +5 and each O has an oxidation number of -2.
K₂Cr₂O7: K has an oxidation number of +1, Cr has an oxidation number of +6, and each O has an oxidation number of -2.
Hg₂Cl2: Each Hg has an oxidation number of +1 and each Cl has an oxidation number of -1.
HgCl2: Hg has an oxidation number of +2 and each Cl has an oxidation number of -1.
Al(OH)3: Al has an oxidation number of +3, each O has an oxidation number of -2, and each H has an oxidation number of +1.
Na3PO4: Na has an oxidation number of +1, P has an oxidation number of +5, and each O has an oxidation number of -2.
The value of K for the reaction below is 6.71 at 465 K.
2NO₂(g) <—>N₂04 (g)
Determine the reaction quotient for a mixture of the two gases in which [NO₂] = 0.0212 M and [N₂O4] = 0.00553 M.
The reaction quotient from the calculation is obtained as 12.3
What is the reaction quotient?
The reaction quotient, Q, is a mathematical expression used in chemistry to predict the direction a chemical reaction will proceed under non-standard conditions.
It is calculated in the same way as the equilibrium constant, K, but uses the concentrations (or partial pressures) of the reactants and products at any given moment during a reaction, rather than at equilibrium.
We already know that the reaction quotient would refer to the non equilibrium conditions. Thus we have that;
Q = [N₂04]/[NO₂]^2
Q = 0.00553/(0.0212)^2
Q = 12.3
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What is the mass of 6.02 x 1024 molecules of the compound HCl?
Answer:
First, we need to determine the molar mass of HCl.
The molar mass of HCl = the mass of hydrogen (1.008 g/mol) + the mass of chlorine (35.45 g/mol) = 36.45 g/mol.
Next, we can use Avogadro's number (6.02 x 10^23 molecules/mol) to convert the number of molecules to moles:
6.02 x 10^24 molecules / 6.02 x 10^23 molecules/mol = 10 moles
Finally, we can use the molar mass to convert moles to grams:
10 moles x 36.45 g/mol = 364.5 grams
Therefore, the mass of 6.02 x 10^24 molecules of HCl is 364.5 grams.
Help quick with number 17
The partial pressure of O₂ is 0.954 atm
The moles O₂ that formed is 0.000859 moles
The mass of NaNO₃ that reacted is 0.146 g.
What is Dalton's law of partial pressures?The balanced chemical equation for the reaction is given below:
2 NaNO₃ (s) → 2 NaNO2 (s) + O₂(g)Mole ratio of NaNO₃ to O₂ is 2 : 1
From Dalton's Law of partial pressures:
The partial pressure of O₂ = Total pressure - Partial pressure of water vapor
The partial pressure of O₂ = (0.98 - 0.026) atm
The partial pressure of O₂ is 0.954 atm
b. From the ideal gas law:
PV = nRT
where;
P is pressure = 0.954 atmV is volume = 0.0230 Ln is the number of molesR is molar gas constant = 0.0821 L.atm/mol/KT is the temperature in Kelvin = 295.15 KSolving for n
n = PV/RT
n = (0.954 * 0.0230)/(0.0821 * 295.15)
n = 0.000859 moles
Moles of O₂ formed = 0.000859 moles
c. The mass of NaNO₃ that reacted is calculated using the formula below:
mass NaNO₃ = moles NaNO₃ x molar mass NaNO₃molar mass NaNO = 84.99 g/mol
moles of NaNO₃ = 0.000859 moles * 2
moles of NaNO₃ = 0.001718 moles
Solving for the mass NaNO₃ that reacted;
mass NaNO₃ that reacted = 0.001718 * 84.99
mass NaNO₃ that reacted = 0.146 g
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How many moles of O2 are needed to combine with 6.2 moles of phosphorus
The number of moles of O₂ are needed to combine with 6.2 moles of phosphorus is 7.75 moles.
How to calculate number of moles?The number of moles of a substance can be calculated using stoichiometry. Stoichiometry is the quantitative relationship between the reactants and products of a specific reaction or equation.
According to this question, phosphorus reacts with oxygen gas as follows:
4P + 5O₂ → 2P₂O5
Based on the above equation, 4 moles of phosphorus reacts with 5 moles of oxygen.
If 6.2 moles of P reacts, 7.75 moles of oxygen gas will be produced.
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One day it is clear and sunny, but you notice that the pressure is less than it was the day before. What weather might be coming? Why?
Answer:
I believe your answer is
Explanation:
when the pressure is less I believe it means rain is coming
Readiness Test: Populations, Communities, and Ecosystems
The structure of an ecosystem is characterized by the organization of both biotic and abiotic components. The reduction of the resources decrease the population of a species. The correct option is A.
An ecosystem is defined as the structural and functional unit of ecology in which the living organisms interact with each other and the surrounding environment. The living components of the ecosystem are called biotic components and the non-living components are called abiotic components.
In short, raw material extraction can adversely affect the environment, biodiversity loss, damage to ecosystem functions and global warming.
Thus the correct option is A.
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The specific heat of a certain type of metal is 0.128 J/(g-°C). What is the final temperature if 305 J of heat is added to 91.2 g of
This metal, initially at 20.0 °C?
T final = __ °C
Can someone please help if you know the topic I’ll mark brainliest, if not please do not answer.
Answer: 46.07 °C.
Explanation:
Write a K expression for
[CoCl4]2-(aq)(blue) + 6H2O(l) ⇌ [Co(H2O)6]2+(aq)(pink) + 4Cl-(aq)
The relationship between a reaction's products and reactants with regard to a certain unit is expressed by the equilibrium constant, K.
Thus, When a reaction is homogeneous, all of the products' and reactions' states of matter are the same (the prefix "homo" means "same"). The solvent typically controls the reaction's overall state of matter.
When a reaction is in chemical equilibrium, the concentrations of the reactants and products do not significantly fluctuate over time. A double arrow between the reactants and products denotes these reversible reactions.
As described, this reaction is endothermic, therefore when heat is added, the equilibrium constant moves to the right. In turn, this turns the solution blue. Cl- is drawn out of solution by the addition of AgNO3.
Thus, The relationship between a reaction's products and reactants with regard to a certain unit is expressed by the equilibrium constant, K.
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What molality of nonvolatile solute is needed to lower the melting point of camphor by 1.050°C? (K-39.70°C/m)
______m
The molality of nonvolatile solute needed to lower the melting point of camphor by 1.050°C is 0.0264 m.
Given:
The freezing point depression (ΔTf) = 1.050°C
The freezing point depression constant (Kf) = 39.70°C/m
Use the formula of freezing point depression:
ΔTf = Kf × m
where ΔTf is the freezing point depression, Kf is the freezing point depression constant, and m is the molality of the solute.
m = ΔTf / Kf
Substitute the given values in the equation,
m = 1.050°C / 39.70°C/m
m = 0.0264 m
Thus, 0.0264 m is the molality of nonvolatile solute needed to lower the melting point of camphor by 1.050°C.
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Which best describes homeostasis?
A. altering the external environment to accommodate the body's needs
B. maintaining a relatively stable equilibrium by physiological processes.
C. keeping the body in a fixed and unaltered stated.
D. maintaining a constant internal environment.
Answer:
Yeah, it's B.
Explanation:
Homeostasis is when the body maintains a near constant internal environment.
If you mix 20.0 mL of 0.010 M MgCl2with 20.0 mL of 0.0020 M Na2CO3, will magnesium carbonate, MgCO3, precipitate out from the solution? Explain. Given: Ksp(MgCO3) = 4.0 × 10-5.
If you mix 20.0 mL of 0.010 M MgCl[tex]_2[/tex] with 20.0 mL of 0.0020 M Na[tex]_2[/tex]CO[tex]_3[/tex], magnesium carbonate will not precipitate out from the solution.
The byproduct of the condensing of atmospheric water vapour that falls from clouds as a result of gravitational pull is referred to as precipitation in meteorology. Rain, sleet, slush, ice pellets, graupel, drizzle, and hail are the main types of precipitation.
When a region of the outside world becomes completely saturated with water vapour, the water condenses or "precipitates" or falls. Because the water vapour does not enough condense to precipitate, fog and mist are instead colloids rather than precipitation. magnesium carbonate will not precipitate out from the solution.
Ksp =[Mg²⁺][CO₃²⁻]
[0.010][20] = C₂×40
C₂=0.001M
Q= 0.005×0.001
= 5×10⁻⁶M
Q<Ksp
precipitation will not occur
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If you mix 20.0 mL of 0.010 M MgCl2with 20.0 mL of 0.0020 M Na2CO3, will magnesium carbonate, MgCO3, precipitate out from the solution? Explain. Given: Ksp(MgCO3) = 4.0 × 10-5.
Which salt, copper(I) bromide [CuBr, Ksp = 4.2 × 10-8] or lead(II) iodide [PbI2, Ksp = 1.4 × 10-8], is more soluble in water in terms of molarity? Justify your answer.
0.85 is the molarity because of the number added too AgCl of each solution.
Thus, Chemists need to be able to express the concentration of solutions in a way that takes into consideration the quantity of reacting particles in a given chemical equation.
In general, percentage measurements are not helpful for chemical reactions because they are based on either mass or volume. It is recommended to use a concentration unit based on moles.
The number of moles of solute dissolved in one liter of solution is known as the molarity (M) of a solution.
Thus, 0.85 is the molarity because of the number added too AgCl of each solution.
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If an ideal gas has a pressure of 7.07 atm, a temperature of 43.65 °C, and a volume of 64.01 L, how many moles of gas are in
the sample?
n=_____mol
Will mark brainly please help asap!
Answer:
17.4 mols
Explanation:
Use the ideal gas Law: Pv=nRt where P is pressure, V is volume, n is the number of mols, R is the Gas constant (0.08206 L*atm/mol*K), and T is the temperature in Kelvin.
Convert temperature to Kelvin: 43.65 C+273= 316.65 K
Pv=nRt -----> Plug in what is given and Solve the equation for n
7.07 atm*64.01 L= n *(0.08206 L*atm/mol*K)* 316.65 K
n= 17.4 mols
Balance the following formula equations using the tally method and show your work:
*I have provided the answers for these equations, all you need to do is show your work using the tally method!*
_____ Zn3(PO4)2 + ___2__ AlCl3 → ___3__ ZnCl2 + ___2__ Al(PO4)
___2__ Cr(OH)3 → _____ Cr2O3 + ___3__ H2O
___3__ Na(OH) + _____ H3(PO4) → _____ Na3(PO4) + ___3__ H2O
___2__ Li + ___2__ H2O → ___2__ Li(OH) + ______ H2
The balanced chemical equations using suitable coefficients are Zn₃(PO₄)₂+ 2 AlCl₃ → 3 ZnCl₂ + 2 Al(PO₄),2 Cr(OH)₃ → Cr₂O₃ +3 H₂O,3 NaOH+ H₃PO₄ → Na₃PO₄+ 3 H₂O,2 Li + 2 H₂O → 2 LiOH+ H₂.
Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.
A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .
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I am trying to utilize an acid-base neutralization reaction to remove limescale (CaCO3) from my faucet using hydrochloric acid (HCl). Which would help make this reaction go faster?
There is no way to speed up the reaction
Use less concentrated HCl solution
Using something abrasive to grind the limescale into smaller pieces
Cooling down the faucet by running cold water
Using a more concentrated HCl solution would help make the acid-base neutralization reaction go faster in removing limescale (CaCO₃) from your faucet.
What would help make this reaction go faster?
The rate of the reaction generally increases with the concentration of the reactants, so a more concentrated HCl solution will react more quickly with the limescale than a less concentrated one.
Using something abrasive to grind the limescale into smaller pieces might help expose more surface area of the limescale to the acid, but it would not directly affect the rate of the acid-base neutralization reaction.
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Determine whether each of the following will increase or decrease the rate of a chemical reaction
Lowering the temperature slows down the motion of molecules, leading to fewer effective collisions between reactant molecules, thus decreasing the rate of the reaction.
Decreasing the volume of the system or increasing the pressure of the system can increase the frequency of collisions between reactant molecules, thus increasing the rate of the reaction. This is because a decrease in volume or an increase in pressure leads to an increase in the concentration of reactants in the system.
Decreasing the surface area of the reactants decreases the number of collision sites available, leading to a decrease in the rate of the reaction.
Adding a catalyst lowers the activation energy required for the reaction to take place, leading to an increase in the rate of the reaction.
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5.1 g sodium carbonate solution was dissolved in water to make 500cm³ of solution.20cm³ of this solution was tirated against 20.45 cm³ of 0.04M hydrochloric acid . Calculate the % of purity of the sodium carbonate solid
Answer:
We know that, Va= 20.45 cm³, Vs= 20 cm³, Ma= 0.04M . But molar mass of Na₂CO₃ = 106. So, concentration (g/dm³) = 0.02045 × 106 = 2.1677 g/dm³. Hence, The percentage purity of the sodium carbonate solid is 21.25%.
Use the reaction to answer the question.
Fe2O3 + 3H2SO4
How many atoms of oxygen will be found in the product(s) of the reaction?
4
15
12
3
Answer:
The Correct answer is 15
Answer:
B). 15
Explanation:
The total number of atoms in 3.75 mol of ammonium nitrate, NH4NO3 , is
The total number of atoms in 3.75 mol of ammonium nitrate, NH4NO3, is equal to the Avogadro's number, which is 6.022 x 10^23, times the number of moles, which is 3.75 in this case.
Thus, the total number of atoms in 3.75 mol of ammonium nitrate is equal to 2.26 x 10^24 atoms.
This number can be further broken down into the number of atoms of each element present in the compound. Ammonium nitrate is composed of two elements, nitrogen (N) and hydrogen (H). For each mole of ammonium nitrate, there are 4 moles of hydrogen atoms and 2 moles of nitrogen atoms.
Therefore, in 3.75 moles of ammonium nitrate, there are 15 moles of hydrogen atoms and 7.5 moles of nitrogen atoms, which is equal to 9 x 10^24 hydrogen atoms and 4.05 x 10^24 nitrogen atoms.
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Use the table of molar masses to answer the question.
Please help!
Element Molar Mass (g/mol)
silicon 28.09
oxygen 16.00
How many molecules of silicon dioxide (SiO₂) are there in a 15-gram sample?
6.022 x 1023
2.049 × 1023
1.503 x 1023
1.251 x 1023
The number of molecules of silicon dioxide (SiO₂) present in 15 grams of the sample is 1.503×10²³ molecules (3rd option)
How do i determine the number of molecules present?We'll begin by obtaining the mole of 15 g of SiO₂. This is shown below:
Mass of SiO₂ = 15 grams Molar mass of SiO₂ = 60.09 g/molMole of SiO₂ =?Mole = mass / molar mass
Mole of SiO₂ = 15 / 60.09
Mole of SiO₂ = 0.2496 mole
Haven obtain the mole, we shall determine the number of molecules. Details below:
From Avogadro's hypothesis,
1 mole of SiO₂ = 6.022×10²³ molecules
Therefore,
0.2496 mole of SiO₂ = 0.25 × 6.022×10²³
0.2496 mole of SiO₂ = 1.503×10²³ molecules
Thus, the number of molecules is 1.503×10²³ molecules (3rd option)
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Answer:
Chemistry B Semester Exam 5/4/2023
1. Cs-Br
2. K-C is ionic, and C-O is polar covalent
3. All molecules are in constant motion, so they all have some kinetic energy.
4. The reaction between substances A and B has a lower activation energy than the reaction between substances B and C.
5. More bond energy is absorbed on the reactants side than is released on the products side.
6. an exothermic reaction
7. Endothermic reactions have a higher activation energy. Endothermic reactions require more energy to break up the bonds of the reactants.
8. Heat must be released by the products in order to convert from the reactants.
9. Cooling a purple solution will turn it pink.
10. Both are flexible, but one conducts electricity while the other insulates.
11. high pressure, high-temperature water extraction
12. steel + vanadium for shock absorption
13. 15
14. the number of atoms, type of elements, and mass of reactants and products are equal.
15. 64 grams
16. 1.503x10^23
17. The relative numbers of protons and neutrons can differ before and after the change, but the total number of those particles remains the same.
18. The plastic balls are a good representation of neutrons, but there is no splitting of nuclei as happens in fission.
19. beta minus decay
20. alpha decay
21. Greenhouse gases have more than two atoms, allowing them to vibrate and release radiation, warming the atmosphere.
22. cause: acid rain, consequence: destruction of crops
23. toxic bacteria in the water supply
24. it reaches hard to get to oil and gas deposits.
3 What does this model show?
AECO
A.A single type of atom bonded together
B.An element because all the particles are the same
C.A molecule because there is more than one type of atom
D.An element because there is more than one type of atom
The model shows a molecule because there is more than one type of atom (option C).
What is a molecule?A molecule is the smallest particle of a specific element or compound that retains the chemical properties of that element or compound.
A molecule is made up of two or more atoms held together by chemical bonds.
According to this question, a model AECO is given. Each alphabet represents a different element, hence, indicating that four different atoms are bonded together to form a molecule.
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Na2CO3 + CaCl2 -> 2NaCl + CaCO3
138g of CaCl2 react
how many moles of NaCl are made
According to the balanced chemical equation:
Na₂CO₃ + CaCl₂ → 2NaCl + CaCO₃, 2.4892 moles of NaCl are produced, as this is a stoichiometry problem that involves a chemical reaction between two reactants and products.
For every one mole of CaCl₂, two moles of NaCl are produced. So, first the number of moles of CaCl₂ is calculated in 138 g of CaCl₂,
Molar mass of CaCl₂ = 40.08 g/mol + 2(35.45 g/mol) = 110.98 g/mol
Number of moles of CaCl₂= 138 g / 110.98 g/mol = 1.2446 mol
Since the mole ratio of CaCl₂ to NaCl is 1:2, it is known that twice as many moles of NaCl are produced as moles of CaCl₂ used.
Therefore, the number of moles of NaCl produced is:
Number of moles of NaCl = 2 x 1.2446 mol = 2.4892 mol
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what is empirical formula ?Meaning of empirical formula
Answer: empirical formula of any compound is the simplest proportion of elements in that compound (i.e. the composition of elements in compound is in simplest ratio ) .It does not provide actual formula of any compound.
molecular formula=n-factor * empirical formula
molecular formula - C6H12O6 (glucose)
empirical formula - CH2O
C6H12O6 * CH2O
If the volume of the original sample in Part A ( P1 = 262 torr , V1 = 21.0 L ) changes to 75.0 L , without a change in the temperature or moles of gas molecules, what is the new pressure, P2 ?
Answer:
The answer is 76.36 torr
Explanation:
using P1V1=P2V2
Since temperature did not change
P2=P1V1/V2
P2=262×21/75
P2=73.36 torr
Calculate the volume in mL of 0.567 M Ca(OH)2 needed to neutralize 42.8 mL of 0.490 M H3PO4 in a titration.
The volume in mL of 0.567 M Ca(OH)₂ needed to neutralize 42.8 mL of 0.490 M H₃PO₄ in a titration is 36.98ml.
A neutralization reaction can be defined as a chemical reaction in which an acid and base quantitatively react together to form a salt and water as products.
In a reaction to water, neutralization results in excess hydrogen or hydroxide ions present in the solution. The pH of the neutralized solution depends on the strength of the acid or base involved in it.
Given,
Concentration of calcium hydroxide = 0.567M
Volume of phosphoric acid = 42.8 moles
Concentration of phosphoric acid = 0.49M
During neutralization, the number of moles of acid and base remain same,
M₁V₁ = M₂ V₂
i.e. Moles of acid = moles of base
0.49 × 42.8 = 0.567 × V₂
V₂ = 36.98 ml
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A piece of iron mass equals 25.0 g at 398 Calvin is placed in a Styrofoam cup containing 25.0 mL of water at 298 K assuming that no heat is lost to the cup or the surroundings what will the final temperature of the water
Final Temperature = 308K
We can set this up as
-Q1 = Q2
Q1 = (iron mass)•(specific heat of iron)•(T2-T1)
[where T2 means final temperature and T1 means initial temperature of the iron]
Q2 = (water mass)•(specific heat of water)•(T2-T3)
[where T3 means inital temperature of the water]
Plug in what you know
Q1 = (25.0g)•(0.44J/g•K)•(T2-398K)
[The internet can tell us the specific heat of iron, and the temperature unit is Kelvin]
Q2 = (25.0g)•(4.18J/g•K)•(T2-298K)
[The internet can tell us the specific heat of water, and 1mL = 1g]
Multiply them all
Q1 = 11(T2) - 4378K
Q2 = 104.5(T2) - 31141K
Use these values in the first equation and solve
-Q1 = Q2
-(11(T2) - 4378K) = 104.5(T2) - 31141K
-11(T2) + 4378K = 104.5(T2) - 31141K
35519K = 115.5(T2)
T2 = 308K
[This is not exact since there was some rounding; but it will be very close]
consider the combustion of carbon monoxide in oxygen gas.2CO(g)+O2(g)=2CO2(g).In this reaction 10.8 moles of carbon dioxide was produced. Calculate the number of moles of carbon monoxide used in this reaction to produce such number of moles of carbon dioxide.
In this reaction 10.8 moles of carbon dioxide was produced. 10.8moles of carbon monoxide used in this reaction to produce such number of moles of carbon dioxide.
In chemistry, a mole, usually spelt mol, is a common scientific measurement unit for significant amounts of very small objects like molecules, atoms, or other predetermined particles. The mole designates 6.02214076 1023 units, which is a very large number.
For the Worldwide System of Units (SI), the mole is defined as this number as of May 20, 2019, according to the General Convention on Measurements and Weights. The total amount of atoms discovered through experimentation to be present in 12 grammes of carbon-12 was originally used to define the mole.
2CO(g)+O[tex]_2[/tex](g)=2CO[tex]_2[/tex](g)
moles of carbon dioxide= 10.8 moles
According to stoichiometry
moles of carbon monoxide= (2/2)× 10.8 =10.8moles.
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Please help me as soon as possible! Thanks so so much!!!
The equilibrium constant, which indicates how far a chemical process progresses, is a thermodynamic quantity.
What is the equilibrium constant?
The equilibrium constant is a ratio of the concentrations (or partial pressures) of the products to the concentrations (or partial pressures) of the reactants.
1) The equilibrium constant is;
Keq = 1/(3.5) * (1.5)^2
Keq = 0.13
2) 0.15 = [0.25]/1 * [CO2]
[CO2] = [0.25]/0.15
[CO2] =1.67
3) Ksp = [Mg^+] [Cl^-]^2
4 * 10^-2 = [Mg^+] * [3.5 * 10^-3]^2
[Mg^+] = 4 * 10^-2/ [3.5 * 10^-3]^2
= 3.3 * 10^-5 M
4) Ksp = x^2
Ksp = (2 * 10^-3)^2
= 4 * 10^-6
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