Answer:
35 degrees
Explanation:
The incident angle, an 80-degree angle, and as the angle of incidence increases, the amount of refraction also increases. So, we can expect a significant change in the angle of refraction from blue to red light at an 80-degree angle of incidence.
What is refraction?Refraction refers to the bending of light when it passes from different mediums.The amount of refraction that occurs at an interface between two materials depends on the wavelength of light, the angle of incidence, and the properties of the materials. The relationship between these factors is described by Snell's law:
n1 sinθ1 = n2 sinθ2
where n1 and n2 are the refractive indices of the two materials, θ1 is the angle of incidence, and θ2 is the angle of refraction.
For a given angle of incidence, the amount of refraction that occurs is greater for shorter wavelengths (i.e., blue light) than for longer wavelengths (i.e., red light). This effect is known as dispersion, and it is why we see rainbows when sunlight is refracted through water droplets.
In the absence of any information about the properties of the materials involved, we can assume that the amount of refraction will increase as the wavelength decreases.
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please help!!
A baseball cannon fires balls at an initial speed of 29 m/s. The cannon is tilted at a 52o angle.
(a) How long could one of these balls stay in the air ?
(b) How far from the cannon, will the ball hit the ground ?
(c) What will be ball’s maximum altitude ?
Answer:
(a) The time the ball stays in the air is approximately 4.66 seconds
(b) The distance from the cannon at which the ball will hit the ground is approximately 83.18 meters
(c) The maximum altitude of the ball is approximately 26.62 m
Explanation:
The given parameters of the question are;
The initial velocity at which a baseball cannon fires balls, u = 29 m/s
The angle at which the cannon is tilted, θ = 52°
(a) The time duration the ball stays in the air is given by the time of flight of the projected ball as follows;
[tex]2 \cdot t = \dfrac{2 \cdot u \cdot sin (\theta)}{g}[/tex]
Where;
t = The time it takes the baseball to reach maximum height
2·t = The total time of flight = The time the ball stays in the air
θ = The angle at which the ball is tilted = 52°
g = The acceleration due to gravity ≈ 9.81 m/s²
u = The initial velocity = 29 m/s
Therefore, we have;
[tex]2 \cdot t = \dfrac{2 \times 29 \ m/s\times sin (52^{\circ})}{9.81 \ m/s^2} \approx 4.66 \ s[/tex]
The time the ball stays in the air, 2·t ≈ 4.66 seconds
(b) The distance from the cannon at which the ball will hit the ground is given by the horizontal range, 'R', of the projectile as follows;
[tex]Horizontal \ range, R = \dfrac{u^2 \cdot sin(2 \cdot \theta) }{g}[/tex]
∴ The distance from the cannon at which the ball will hit the ground = R
[tex]Horizontal \ range, R = \dfrac{(29 \ (m/s))^2 \cdot sin(2 \times 52^{\circ}) }{9.81 \ m/s^2} \approx 83.18 \, m[/tex]
The distance from the cannon at which the ball will hit the ground = R ≈ 83.18 meters
(c) The maximum altitude of the ball is equal to the maximum height reached by the ball, H, which is given as follows;
[tex]H = \dfrac{u^2 \cdot sin^2 (\theta)}{2 \cdot g}[/tex]
Therefore, we have;
[tex]H = \dfrac{(29 \ m/s)^2 \times sin^2 (52^{\circ})}{2 \times 9.81 \ m/s^2} \approx 26.62 \ m[/tex]
The maximum altitude of the ball ≈ 26.62 m
2. A3 kg ball rolls forward toward a 6 kg ball moving in the opposite direction at 4.6 m/s to
the left. After their collision, the 3 kg ball bounces backward at 4.2 m/s to the left and the 6 kg
ball continues to the left at 1.5 m/s in the same direction. What was the initial velocity of the
3 kg ball?
Answer:
m1 v1 + m2 v2 = m1 V1 + m2 V2 conservation of momentum
m1 = 3 m2 = 6
v2 = -4.6
V1 = -4.2
V2 = -1.5
v1 = (m1 V1 + m2 V2 - m2 v2) / m1
v1 = (3 * -4.2 + 6 * -1.5 - 6 * -4.6) / 3
v1 = (-12.6 - 9 + 27.6) / 3 = 2 initial velocity of 3 kg ball
Check:
3 * 2 + 6 * -4.6 = -21.6
3 * -4.2 + 6 -1.5 = -21.6
can someone help me :)
Answer:
mass= 60kg
velocity= 10m/s
momentum = mass × velocity
p=m×v
p= 60×10
p= 600kgm/s
a solid sphere of mass and radius 20kg and 4m is rotating with an angular velocity of 40rad/sec is accelerated uniformly to 60rad/sec in 2sec what is the torque acting on the sphere? (I=0•4MR^2)
Answer:
1280Nm
Explanation:
torque= I×alpha(angular acceleration)
so Angular acceleration is found by the following process.
Calculati rezistenta filamentului unui bec al lanternei de buzunar daca la tensiunea de 3,5 v el este parcurs de un curent cu intensitatea de 0,28 A
Answer:
Resistencia = 12.5 Ohmios
Explanation:
Dados los siguientes parámetros;
Voltaje = 3.5 Volts
Corriente = 0.28 Amps
Para encontrar el resistencia;
La ley de Ohm establece que a temperatura constante, la corriente que fluye en un circuito eléctrico es directamente proporcional al voltaje aplicado en los dos puntos e inversamente proporcional a la resistencia en el circuito eléctrico.
Matemáticamente, La ley de Ohm viene dada por la fórmula;
Voltaje = corriente * resistencia
Resistencia = voltaje/corriente
Resistencia = 3.5/0.28
Resistencia = 12.5 Ohmios
Por tanto, la resistencia del filamento de una linterna de bolsillo es de 12,5 ohmios.
An object of mass 1.5 kg is moving forwards along the floor against an applied force of
40.0 N [backwards]. If the coefficient of kinetic friction is 0.25, determine the
acceleration of the object.
Answer:
The acceleration of the object is -29.12 m/s².
Explanation:
The acceleration of the object can be calculated by Newton's second law:
[tex] \Sigma F = ma [/tex]
[tex] - F - F_{\mu} = ma [/tex]
[tex] - F - \mu mg = ma [/tex]
Where:
F: is the applied force = 40.0 N
μ: is the coefficient of kinetic friction = 0.25
m: is the mass of the object = 1.5 kg
g: is the acceleration due to gravity = 9.81 m/s²
a: is the acceleration =?
[tex] a = \frac{- F - \mu mg}{m} = \frac{-40.0 N - 0.25*1.5 kg*9.81 m/s^{2}}{1.5 kg} = -29.12 m/s^{2} [/tex]
The minus sign is because means that the object is decelerating due to the applied force and the friction.
Therefore, the acceleration of the object is -29.12 m/s².
I hope it helps you!
A fruit basket of mass 44.5 kg weighs approximately how much in newton? (Answer should have a number and a proper unit) *
Answer:
445N
Explanation:
F=mg
m=44.5kg
g=10m/s2
F=44.5 * 10
=445N
A race car has a mass of 710kg. It starts from rest and speeds up to 12m/s in 12.0s. The car is uniformly accelerated during the entire time. What net force is applied to it?
10 Waves Question 2 of 10 A wave travels at a speed of 74 m/s. If the distance between crests is 12 m, what is the frequency of the wave? Use j A. 0.16 Hz B. 6.2 Hz C. 890 Hz D. 62 Hz SUBMIT
Answer: B 6.2 Hz
Explanation: Equation for waves v = λf.
Frequency = speed / wavelength f = v/λ
f = 74 m/s / 12 m = 6.166... Hz
Answer:
Rounding is necessary: the answer is 6.2 Hz
Explanation:
1. On planet Jupiter, the acceleration due to
gravity is about 26 m/s2. How high would a boy
be able to throw a ball on Jupiter if he can
throw it vertically 10m high on Earth?
Answer:
The boy can throw the ball to a height of 3.85 m on Jupiter
Explanation:
We'll begin by calculating the initial velocity at which the ball is thrown on EARTH. This can be obtained as follow:
On Earth:
Acceleration due to gravity (g) = 10 m/s²
Maximum height (h) = 10 m
Final velocity (v) = 0 m/s (at maximum height)
Initial velocity (u) =?
v² = u² – 2gh (since the ball is going against gravity)
0² = u² – 2 × 10 × 10
0 = u² – 200
Collect like terms
0 + 200 = u²
200 = u²
Take the square root of both side
u = √200 m/s
Finally, we shall determine the maximum height of the ball at JUPITER. This can be obtained as followb
On Jupiter:
Acceleration due to gravity (g) = 26 m/s²
Initial velocity (u) = √200 m/s
Final velocity (v) = 0 m/s (at maximum height)
Maximum height (h) =..?
v² = u² – 2gh (since the ball is going against gravity)
0² = (√200)² – 2 × 26 × h
0 = 200 – 52h
Collect like terms
0 – 200 = –52h
–200 = –52h
Divide both side by –52
h = –200 / –52
h = 3.85 m
Thus, the boy can throw the ball to a height of 3.85 m on Jupiter.
A object is placed between the focal point and the lens of a concave lens. Where will the image be formed?
Answer:
When object is placed between convex lens and focal point, image formed is virtual and magnified which is shown in the diagram. Was this answer helpful?
A 1,000 kg car traveling 15.0 m/s brakes and comes to a stop after traveling 20.0 m.
a. What is the car’s initial kinetic energy?
b. What is the car’s final kinetic energy?
c. How much work does it take to stop the car?
d. How much constant force is applied in bringing the car to a stop?
A. The car’s initial kinetic energy is 112500 J
B. The car’s final kinetic energy is 0 J
C. The amount of work done to stop the car is –112500 J
D. The force applied in bringing the car to a stop is –5625 N
A. How to determine the initial kinetic energy Mass (m) = 1000 KgInitial velocity (u) = 15 m/sInitial kinetic energy (KEᵢ) =?KEᵢ = ½mu²
KEᵢ = ½ × 1000 × 15²
KEᵢ = 112500 J
B. How to determine the final kinetic energy Mass (m) = 1000 KgFinal velocity (v) = 0 m/sFinal kinetic energy (KEբ) =?KEբ = ½mv²
KEբ = ½ × 1000 × 0²
KEբ = 0 J
C. How to determine the workdone Initial kinetic energy (KEᵢ) = 112500 J Final kinetic energy (KEբ) = 0 JWorkdone (Wd) =?Wd = KEբ – KEᵢ
Wd = 0 – 112500
Wd = –112500 J
D. How to determine the forceWe'll begin by calculating the acceleration. This can be obtained as follow:
Initial velocity (u) = 15 m/sFinal velocity (v) = 0 m/sDistance (s) = 20 mAcceleration (a) =?v² = u² + 2as
0² = 15² + (2 × a × 20)
0 = 225 + 40a
Collect like terms
0 – 225 = 40a
–225 = 40a
Divide both side by 40
a = –225 / 40
a = –5.625 m/s²
Finally, we shall determine the force. This is illustrated below:
Mass (m) = 1000 KgAcceleration (a) = –5.625 m/s²Force (F) =?F = ma
F = 1000 × –5.625
F = –5625 N
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____________ is the rate at which the electric charges move through a given area.
Magnetism
Current
Induction
Flux
Answer:
current is the rate at which the electric charges move through a given areaA wire of radius 5 x 10⁻⁴ m is needed to prepare a coil of resistance 40 Ω. The resistivity of the material of the wire is 3.14x10⁻⁷ Ωm. Calculate the length of the wire.
Answer:
100 m
Explanation:
From the question,
R = Lρ/A.................... Equation 1
Where R = resistance of the wire, L = length of the wire, ρ = resistivity of the wire, A = cross sectional area of the wire.
But,
A = πr².................... Equation 2
Where r = radius of the wire.
Substitute equation 2 into equation 1
R = Lρ/πr²
Make L the subject of the equation
L = Rπr²/ρ...................... Equation 3
Given: R = 40 Ω, r = 5×10⁻⁴ m, ρ = 3.14×10⁻⁷ Ωm
Constant: π = 3.14
Substitute these values into equation 3
L = [40×3.14×( 5×10⁻⁴)²]/ (3.14×10⁻⁷)
L = 40×3.14×25×10⁻⁸/(3.14×10⁻⁷)
L = 100 m
Hence the length of the wire is 100 m
Excluding the noble gas group, how does the number of valence electrons in an element influence its chemical stability?
A. Elements with intermediate numbers of valence electrons are the last chemically stable.
B. Elements with the highest number of valence electrons are the most chemically stable.
C. Elements with intermediate number of valence electrons are the most chemically stable.
D. Elements wit the lowest number of valence electrons are the most chemically stable.
Answer:
C. Elements with intermediate number of valence electrons are the most chemically stable.
Some people say that you can contract HIV by sharing a drink with someone who has HIV. True or false? Why?
Answer: This is definitely false... you have to.. have séx with someone who has H.I.V to actually get H.I.V
.
[tex]25 {?}^{?} \times \frac{?}{?} [/tex]
Answer:
what is your exact question.
9- When the moon comes in an orbit higher from earth, ......... solar eclipse are formed.
a) total
b) annular
c) partial. d) annular and partial
A satellite orbits earth at constant speed in circular orbit.Which statement is correct? A The resultant force on the satellite is zero. B The resultant force on the satellite is towards the Earth. C The resultant force on the satellite is away from the Earth. D The resultant force on the satellite is in the direction of motion.
Answer:
B The resultant force on the satellite is towards the Earth.
Explanation:
In the case when the satellite orbits earth would be at constant speed in the circular orbit so hee the resultant force that on the satellite would be with regard to the earth
So as per the given situation, the option B is correct
And, the rest of the options would be wrong
And, the same would be relevant
The body needs small amounts of ________ to help enzymes break down proteins.
Answer:
I would say vitamin B-6
Explanation:
it is also known as pyridoxine. it helps ebzymes break down protein and carry the dismantled amino acids to the blood stream
Hope this helps ✌✌
Answer:
The body needs small amount of vitamin B-6 to help enzymes break down protein and carry the dismantled amino acids to the blood stream.
A sound wave is propagating through the air from left to right as shown in the diagram below.
Answer:
Explanation: Pules
Answer: longitudinal (compression)
Explanation:
A light wave has a frequency of 5 x 108. What is the wavelength of the light wave? (Assume the speed of light to be 3 x 108.)
Answer:
Wavelength of light wave = 0.6 m
Explanation:
Given:
Frequency of wave = 5 x 10⁸
Speed of light = 3 x 10⁸ m/s
Find:
Wavelength of light wave
Computation:
The size of a wave form is its spatial duration, or the duration in which the wave's form repeats.
Wavelength of light wave = Speed of light / Frequency of wave
Wavelength of light wave = [3 x 10⁸] / [5 x 10⁸]
Wavelength of light wave = 0.6 m
do the planets orbit the sun in a perfect circle
Answer:
All the planets in the Solar System orbit the Sun. When planets orbit the Sun, they don’t move around in a perfect circle. They all follow an 'elliptical path', meaning it looks more like an oval.
Explanation:
Answer:no planets orbit the sun in a perfect circle because they travel in a slightly elliptical orbit
Explanation:
A + 32.2 μC charge feels a 0.544 N force from a + 12.3p μC charge. How far apart are they? (u stands for micro.) [?] m
Answer:
r = 2.55 m
Explanation:
Given that,
First charge, q₁ = 32.2 μC
Second charge, q₂ = + 12.3 μC
The force between charges, F = 0.544 N
We need to find the distance between charges. The force between two charges is given by the formula as follows :
[tex]F=k\dfrac{q_1q_2}{r^2}\\\\r=\sqrt{\dfrac{kq_1q_2}{F}} \\\\r=\sqrt{\dfrac{9\times 10^9\times 32.2\times 10^{-6}\times 12.3\times 10^{-6}}{0.544}} \\\\r=2.55\ m[/tex]
So, the charges are 2.55 m apart.
Answer:
2.55
Explanation:
Right on Acellus
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It takes 20 Newtons to move a box. How long will it take a 25 Watt motor to move this box 5 meters?
Answer:
With F = MA Its should take 500 Newtons
Explanation:
F = MA
Define the unit of current. Name the device which is used to measure
electric current in a circuit.
Answer:
The ampere, symbol A, is the SI unit of electric current. It is defined by taking the fixed numerical value of the elementary charge e to be 1.602 176 634 x 10-19 when expressed in the unit C, which is equal to A s, where the second is defined in terms of ΔνCs.
the device used to measure current in a circuit is ammeter
Explain in detail why you cannot hear in space but you can see light(explanation includes particle movement of liquid, solids, gases, and plasma)
Answer:
The reason why one cannot hear in space but light can be seen is because light and sound are different kinds of wave
Light is an electromagnetic wave that propagates by a changing magnetic field hat creates a changing electric field. Light is created by a vibrating electric charge, and is transmitted through a medium by the absorption and reemission of the light by the medium particles
Sound is a longitudinal mechanical wave that is propagated by the vibration of the particles of the medium.
Sound requires a medium to propagate and it cannot be propagated or heard through space which is a vacuum.
Sound is created by a source that is vibrating and the vibration is transmitted to particles in the medium including solids, liquids, gases and plasma that the vibrating energy is in direct contact with and the transfer of the sound energy continues between layers of adjacent particles for the medium for the sound to be propagated from place to place
Explanation:
A lawn mower is pushed with a force of 79 N. If 11,099 J of work are done on mowing the lawn, what is the total distance the lawn mower was pushed? Round your answer to a whole number (no decimal places).
Answer:
141m
Explanation:
PLZ HELP ME ASAP!!! 50 POINTS IF CORRECT! AND BRAINLEST
Answer:
B and C is the Answer
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Wondering if you have enough rope to rappel to the ground, you drop a rock off the top, and hear the sound of it hitting the bottom 4.2 seconds later. Find the height of the cliff ignoring the time that the sound takes to travel back to you from the bottom.
Answer:
86.5 m
Explanation:
[tex]s = ut + \frac{1}{2} at {}^{2} \\ s = (0)(4.2) + \frac{1}{2} (9.81)(4.2) {}^{2} \\ s = 86.5m [/tex]
Answer:
86.5 m
Explanation: