How much energy (joules) is needed to heat 250 grams of water from 22 °C to 99 °C?

Answer:

[tex]\boxed {\boxed {\sf 80, 465 \ Joules}}[/tex]

Explanation:

We can use the specific heat formula, which is:

[tex]q=mc \Delta T[/tex]

Where q is the energy, m is the mass, c is the specific heat capacity, and ΔT is  the change in temperature.

We know the mass is 250 grams. The specific heat capacity of water is 4.18 joules per gram degree Celsius. Let's find the change in temperature.

Now we know all the values:

Substitute the known values into the formula.

[tex]q=(250 \ g) (4.18 \ J/g \textdegree C)(77 \ \textdegree C)[/tex]

Multiply the first 2 numbers together. The grams will cancel out.

[tex]q=1045 \ J/ \textdegree C (77 \textdegree C)[/tex]

Multiply again. This time the degrees Celsius will cancel out.

[tex]q=80465 \ J[/tex]

The energy needed is 80, 465 Joules.

What is true in a saturated solution?
A. No more solute can be dissolved.
B. No more solution can be made.
C. The concentration cannot be decreased.
D. No more solvent can be dissolved.

Let’s say there are 2 planets similar in size, but one has much more mass. How will that affect the number of moons?

ANSWER ASAP!!

In your own words name two types of acids and two types of bases. Describe how each are used..