How much heat is required to boil 78.5 gg of water at its boiling point?

Answers

Answer 1

Answer:

206 kj of heat is required to boil 78.5 kg of water at its boiling point


Related Questions

Silver nitrate and magnesium chloride react according to the following equation:
2AgNO3(aq) + MgCl2(aq) — 2AgCl(s) + Mg(NO3)2(aq)
What volume (in ml) of 0.247M MgCl2(aq) is required to react with 63.2 mL of 0.192M AgNO3(aq)?

Answers

Answer:

V=24,3mL

Explanation:

1)n(AgNO3)=Cm*V=0.063l*0.192M=0.012

2)n(AgNO3)/2=n(MgCl2) => MgCl2=0.012/2=0.006

3)V(MgCl2)=n/Cm=0.006/0.247=0.0243L=24,3ml

How many moles of nitrogen gas would be produced if 3.27 moles of copper(II) oxide were reacted with excess ammonia in the following chemical reaction? 2 NH3(g) + 3 CuO (s) – 3 Cu(s) + N2(g) + 3 H2O(g)​

Answers

Moles of Nitrogen(N₂) gas would be produced : 1.09

Further explanation

The reaction coefficient in a chemical equation shows the mole ratio of the components of the reactants and products

If one mole of the reactant or product is known, then we can determine the moles of the other compounds involved in the reaction

Reaction

2NH₃(g) + 3CuO (s) ⇒ 3Cu(s) + N₂(g) + 3 H₂O(g)​

Copper(II) oxide was reacted with excess Ammonia, so CuO as a limiting reactant and moles of the product is based on moles of CuO

moles of CuO = 3.27

From the equation, the mol ratio of CuO : mol N₂ = 3 : 1, so mol  N₂ :

[tex]\tt \dfrac{1}{3}\times 3.27=1.09[/tex]

Carbon-14 has a half-life of 5715 years. It is used to determine the age of
ancient objects. If a sample today contains 0.060 mg of carbon-14, how much
carbon-14 will be present after 28,575?

Answers

The sample of Carbon-14 after 28,575 years=0.001875 mg

Further explanation

General formulas used in decay:  

[tex]\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{T/t\frac{1}{2} }}}[/tex]

T = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Carbon-14 has a half-life of 5715 years, so t1/2=5715 years

A sample today contains 0.060 mg of carbon-14, so No=0.06 mg, then :

[tex]\tt Nt=0.06(\dfrac{1}{2})^{28575/5715}\\\\Nt=0.06(\dfrac{1}{2})^5\\\\Nt=0.001875~mg[/tex]

Car battery energy that makes device work

Answers

engine is it ok ksndjsjja

Answer:

No it's not make device work

Explanation:

I think soo

Which of the following is a simple definition of reduction?

A. the loss of electrons

B. the gain of electrons

C. an agent that oxidizes something

D. an agent that reduces something

The answer is B on Edg 2020

Answers

Answer:

B. the gain of electrons

Explanation:

An easy way to remember this concept is the pneumonic OIL RIG:

Oxidation is Loss (of electrons)

Reduction is Gain (of electrons)

B. The gain of electrons

The common name for butanone, a readily available solvent, is ​

Answers

The answer is ethyl methyl ketone.

Answer:

methyl ethyl ketone

Explanation:

(MEK)

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