Answer:
Pressure and force are related, and so you can calculate one if you know the other by using the physics equation, P = F/A. Because pressure is force divided by area, its meter-kilogram-second units are newtons per square meter, or N/m2.
Explanation:
Do you not feel the pressure when mass is on you?
An airplane is flying at an elevation of 6 miles on a flight path that will take it directly over a radar tracking station. Let S represent the distance between the radar station and the plane. If S is decreasing at a rate of 400 mph when S is 10 miles, what is the velocity of the plane
Answer:
[tex]-500\ \text{mph}[/tex]
Explanation:
h = Height at which the plane is flying = 6 miles
S = Distance between plane and radar = 10 miles
[tex]\dfrac{dS}{dt}[/tex] = Rate at which S is decreasing = -400 mph
Distance between S and and the elevation of the plane
[tex]b=\sqrt{S^2-h^2}=\sqrt{10^2-6^2}\\\Rightarrow b=8[/tex]
From Pythagoras theorem we get
[tex]S^2=b^2+h^2[/tex]
Differentiating with respect to time we get
[tex]2S\dfrac{dS}{dt}=2b\dfrac{db}{dt}+2h\dfrac{dh}{dt}\\\Rightarrow S\dfrac{dS}{dt}=b\dfrac{db}{dt}+h\dfrac{dh}{dt}\\\Rightarrow 10\times -400=8\times \dfrac{db}{dt}+0\\\Rightarrow \dfrac{db}{dt}=\dfrac{10\times -400}{8}\\\Rightarrow \dfrac{db}{dt}=-500\ \text{mph}[/tex]
Velocity of the plane is [tex]-500\ \text{mph}[/tex].
If the distance between the radar station and the plane is decreasing at the given rate, the velocity of the plane is -500mph
Given the data in the question;
Elevation; [tex]x = 6miles[/tex]Distance between the radar station and the plane; [tex]S = 10miles[/tex]Since "S" is decreasing at a rate of 400 mph; [tex]\frac{ds}{dt} = -400mph[/tex]As illustrated in the diagram below, we determine the value of "y"
Using Pythagorean theorem:
[tex]S^2 = x^2 + y^2[/tex]------------Let this be Equation 1
We substitute in our value
[tex]y = \sqrt{(10miles)^2- (6miles)^2} \\\\y = \sqrt{100mi^2- 36mi^2}\\\\y = \sqrt{64mi^2}\\\\y = 8miles[/tex]
Now, we determine velocity of the plane i.e the change in distance in horizontal direction ([tex]\frac{dy}{dt}[/tex])
Lets differentiate Equation 1 with respect to time t
[tex]2S\frac{ds}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}[/tex]------ Let this be Equation 2
Since, the plane is not landing, [tex]\frac{dx}{dt} =0[/tex]
We substitute our values into Equation 2 and find [tex]\frac{dy}{dt}[/tex]
[tex][2*10mi*(-400mph) ] = [2*6mi*0] + [2*8mi * \frac{dy}{dt}]\\\\-8000m^2ph = 0 + 16miles * \frac{dy}{dt}\\\\\frac{dy}{dt} = \frac{-8000m^2ph}{16miles}\\\\\frac{dy}{dt} = -500mph[/tex]
Therefore, if the distance between the radar station and the plane is decreasing at the given rate, the velocity of the plane is -500mph
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The figure below shows a 2 kg box. A 10 N force pushes the box horizontally across a level flat surface. The frictional force that results from contact with the surface produces a 2 N force that opposes the direction of the box's movement. image What is the net force acting on the box?
A. 5 N, right
B. 8 N, right
C. 20 N, right
D. 12 N, right
Fricition opposes the pushing force, so the net force is
10 N - 2 N = 8 N
to the right.
different between group IA and IIA elements
Answer:
Group IA elements have only one valency electron while Group IIA have two valency electrons.
Group IA elements have cations with higher charge density hence polarizing anions easier resulting into covalent character while Group IIA elements have cations with lower charge density hence difficulty in distorting anions resulting into a ionic character. This is due to difference in cationic radii and charges
A 747 requires a takeoff speed of 270 meters per second if it is to get off the
ground. Calculate the acceleration required for the 747 that begins from rest
to takeoff on a 1000 meter long runway.
Answer:
a = 36.45[m/s²]
Explanation:
We can calculate the acceleration value by means of the following expression of kinematics.
[tex]v_{f}^{2} =v_{o}^{2} +2*a*x[/tex]
where:
vf = final velocity = 270 [m/s]
Vo = initial velocity = 0 (begins from rest)
a = acceleration [m/s]²
x = distance required by the plane = 1000 [m]
[tex](270)^{2} =0+2*a*1000\\72900=2000*a\\a=36.45 [m/s^{2} ][/tex]
Name three items to remember when completing a job application.
1. ) It's good to remember contact information such as phone number or email.
2.) Your address, so if they need to mail anything to you, they can. This is also a necessary point of information on most job applications anyway.
3.) Past job experiences and ways to contact them. This is probably one of the most important things as it shows you've worked before and are willing to talk to past employers.
May I have brainliest please? :)
Answer:
the other answer is correct
Explanation:
i do flvs and this was on the career final exam
What would be the net force on an object if the object's acceleration is 0?
Answer:
Explain. yes it is possible because when the net force is zero and acceleration is zero. ... no, Neglecting air friction, the only force acting on this object is the force of gravity downward. There is no force of equal magnitude as the force of gravity acting in the opposite direction.
what should we do to be a computer engineer ?
Answer:
to be an eginere u would have to go to college and study hard
Explanation:
Explain how the aperture geometry relates to the
diffraction pattern.
Answer:
The answer to this question is given below in the explanation section.
Explanation:
how the aperture geometry relates to the
diffraction pattern:
Diffraction is the spreading out of waves as they pass through an aperture or around objects.it occurs when the size of the aperture or obstacle is of the same order of magnitude as the wavelength of the incident wave.For every small aperture sizes,the vast majority of the wave is blocked.For large apertures the wave passes by or through the obstacle without any significant of diffraction.
in an aperture with width smaller than the wavelength,the wave transmitted through the aperture spreads all the way around the behave like a point sources of waves.
single slit diffraction pattern
The diffraction pattern made by waves passing through a slit of width [tex]\alpha[/tex] (larger than∫) can be understood by imagining a series of point sources all in phase along the width of the slit.The waves moving directly forward are all in phase,so they from a large central maximum.
if the waves travels at an angle Ф from the normal to the slit,then there is a path difference x between the waves production at the two end of the slit.
x=a sinΦ
The path difference between the top and middle waves is λ/2 then they are exactly out of phase and cancel each other out. This happens to all consecutive pairs of waves (the ones produced by the second source from the top and the second source past the middle etc.)at the angle so there is no resultant wave at this angle.Thus a minimum is the diffraction pattern is obtained at
λ=α sinθ
Now slit can be divided into four equal sections and the pairing of sources to give destructive interference can be repeated for the top two section ,which is identical to the result of pairing off matching sources in the bottom two sections.in this case we obtained from the minimum.
λ/2=α/4 sinθ
we can divided the slit aperture into six equal sections and pair off sources in the top two divisions and then the bottom two,to give destructive interference for every matched pair.The minimum of intensity are obtained at angles
nλ = α sinθ
where n is an integer (1,2,......), but not n=0.There is a maximum of intensity in the center of the pattern. This process only gives the position of the minima,does not work for positions of the maxima,and so does not give the intensities of the maxima.
Find the maximum velocity possible for the person on the swing.
if someone could explain with work that would be very much appreciated since I wasn't there when this was discussed in class.
Answer:
The maximum possible speed is 4.85 m/s.
Explanation:
The Principle Of Conservation Of Mechanical Energy
In the absence of friction, the total mechanical energy is conserved. It means that :
[tex]E_m=U+K[/tex] is constant, being U the potential energy and K the kinetic energy
U=mgh
Where m is the mass of the object, g is the gravitational acceleration and h is the height from a fixed reference.
[tex]\displaystyle K=\frac{mv^2}{2}[/tex]
Where v is the speed.
When the person is at a maximum height of 2 meters, the speed is 0. Thus the mechanical energy is made only of potential energy.
Let's fix the reference for the height to the point where the person is at minimum height (1 m from the ground level). The maximum height with respect to this reference is h=2.2 m - 1 m = 1.2 m.
The potential energy is:
U = m*9.8*1.2
U = 11.76m
When the person is at the minimum (zero) height, the mechanical energy is made only of kinetic energy. Since the mechanical energy is conserved, then:
[tex]\displaystyle \frac{mv^2}{2}=11.76m[/tex]
Multiplying by 2 and simplifying by m:
[tex]v^2=2*11.76=23.52[/tex]
Solving for v:
[tex]v=\sqrt{23.52}=4.85[/tex]
[tex]\boxed{v=4.85}[/tex]
The maximum possible speed is 4.85 m/s.
Do you attract the earth or the earth attract you ?Which one is attracting with a large force ?You or the earth
I need help in question 9 plzzz
True is the correct answer
A star has ______________________________________________; it appears to be moving across the sky as a night progresses.
Answer:
Apparent Motion
Explanation:
Apparent Motion of a star is a scientific term that describes the phenomenon that is observed as a result of the earth's rotation which is based on the area or where the observer is situated, and then the point at which the star is found comparable to the rotation axis of the earth.
This often makes the start to appear like it's moving across the sky.
Hence, A star has APPARENT MOTION; it appears to be moving across the sky as the night progresses.
Describe two adaptations and explain how they help you survive.
Answer:
My feet and my fists
Explanation:
My feet help me walk
and my fists help me one punch people
In which three ways does the double-slit experiment support the wave model
of light?
I A. There are darker bands on the screen.
I B. The light bends as it passes through the small opening.
O c. There are bright bands on the screen.
O D. The light reflects off the screen after passing through the slit.
Answer:
B.
Light rays bends at the sharp edges in YDSE as well as double slit but intensity is much less in double slit exp. .
I hope it will be useful.
A, B, and C are three ways in which the double-slit experiment supports the wave model of light. Therefore, options A, B, and C are correct.
How does the double-slit experiment support the wave theory?The following conclusions can be drawn from the results of the double-slit interference test: The head of the light that is absorbed by the screen is only a portion of the light wave; the light wave without the head can still result in interference phenomena.
An interference pattern, which consists of a mix of dark and bright bands, may be observed on the sensor screen across from the slits. Young used this interference pattern as proof that light was a wave rather than a particle.
The presence of bright and darker bands and the bending of light when it passes through the small opening are only be explained if the light is a wave. Therefore, options A, B, and C are correct.
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marked as brainiest if correct
Answer:
I think the the answer is creating and layout and template style ( C )
Explanation:
I did it before and i was checking my notes and i wrote that down , Hope this Helps :)
PLEASE ANSWER ASAP! It would be EXTREMELY appreciated if you could answer both. These are free responses, so try to make your answer somewhat original. Thanks in advance! And I will mark brainliest!
Why does a third class lever cannot magnify force?
Explanation:
The third class lever cannot magnify our force because in third class lever the effort it between the load and the fulcrum. Also, in this type of lever no matter where the force is applied, it is always greater than the force of load. Hence, That type of lever cannot magnify our force.
14. A 3.0 kg metal ball, at rest, is hit by a 1.0 kg metal ball moving at 4.0 m/s. The 3.0 kg ball moves
forward at 2.0 m/s and the 1.0 kg ball bounces back at 2.0 m/s.
(a) What is the total kinetic energy before the collision?
Answer:
The kinetic energy before the collision was 8 J
Explanation:
The given parameters are;
The mass of the metal ball at rest, m₁ = 3.0 kg
The velocity of the ball at rest = 0 m/s
The mass of the metal ball that hits the one at rest, m₂ = 1.0 kg
The velocity of the metal ball that hits the one at rest, v₂ = 4.0 m/s
The velocity with which the 3.0 kg ball moves forward = 2.0 m/s
The velocity with which the 1.0 kg ball bounces back = 2.0 m/s
a) Kinetic energy, K.E. = 1/2 × m × v²
Where;
m = The mass of the of the object in motion
v = The velocity of the object
Before the collision, we have;
Initial K.E. = 1/2 × m₁ × v₁² + 1/2 × m₂ × v₂²
∴ Initial K.E. = 1/2 × 3.0 kg × (0 m/s)² + 1/2 × 1.0 kg × (4.0 m/s) ² = 8 J
The kinetic energy before the collision = The initial K.E. = 8 J.
What force is represented by vector a
Answer:
velocity
Explanation:
Velocity represents the direction of an object with a specified speed
can someone please explain some calculations on vernier calliper
Answer:
Hey mate here's your answer ⤵️
Vernier caliper least counts formula is calculated by dividing the smallest reading of the main scale with the total number of divisions of the vernier scale.LC of vernier caliper is the difference between one smallest reading of the main scale and one smallest reading of vernier scale which is 0.1 mm 0r 0.01 cm
Hope it was helpfulllImagine you've recently insulated your loft. Give a reason why your heating bill may still increase.
Answer:
follow me for the answer
1. How much heat is produced if you heat .25 kg water from 25 degrees C to 100 degrees C. The specific heat of water is 4180 J/kg C.
Answer:
Q = 78375 [J]
Explanation:
To solve this problem we must use the following ideal equation for the thermal energy of an element or substance depending on the temperature change.
[tex]Q=m*C_{p}*(T_{final}-T_{initial})[/tex]
where:
Q = heat [J]
m = mass = 0.25 [kg]
Cp = specific heat = 4180 [J/kg*C]
Tinitial = 25[°C]
Tfinal = 100 [°C]
[tex]Q =0.25*4180*(100-25)\\Q = 78375 [J][/tex]
When going from a fast speed to a slow speed how is light bent?
1.away from the normal line
2.toward the normal line
Answer:
Toward the normal line
Explanation:
I had the same question on a quiz
Question 7 of 10
Which three statements describe electromagnetic waves?
A. They can transfer energy through a vacuum.
I B. They vibrate parallel to the direction in which the wave travels.
O C. They vibrate in two directions that are perpendicular to each
other.
D. They radiate outward in all directions.
Answer:
A. They can transfer energy through a vacuum
C. They vibrate in two directions that are perpendicular to each other
D. They radiate outward in all directions
Explanation:
A statement (A), a statement (C), and a statement (D) are correct because electromagnetic waves can only transfer energy through the vacuum.
What is an electromagnetic wave?The waves that are related to both electricity and magnetism are known as electromagnetic (EM) waves. These waves are made up of time-varying electric and magnetic fields that travel over space.
The correct statements are:
They can transfer energy through a vacuum.They vibrate in two directions that are perpendicular to each other.They radiate outward in all directions.Thus, a statement (A), a statement (C), and a statement (D) are correct because electromagnetic waves can only transfer energy through the vacuum.
Learn more about the electromagnetic wave here:
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Please help me out
please show solvings
Answer:
5) The approximate height is about 80 m. Choice (c)
6) The stone takes about 3 seconds to rise to its maximum height
Explanation:
Free Fall Motion
A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the gravitational acceleration, which value is [tex]g = 9.8 m/s^2[/tex].
The distance traveled by a dropped object is:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
Question 5
Given the stone reaches the ground in t=4 seconds, the height of the tower is:
[tex]\displaystyle y=\frac{9.8*4^2}{2}=78.4\ m[/tex]
The approximate height is about 80 m. Choice (c)
Question 6
Vertical Motion
The vertical motion of an object is controlled by the force of gravity. This means that there is a non-zero net force acting on the object that makes it accelerate downwards.
If the object is thrown upwards at speed vo, its speed at time t is:
[tex]v_f=v_o-g.t[/tex]
The stone reaches its maximum height when the final speed is zero, thus:
[tex]v_o-g.t=0[/tex]
Solving for t:
[tex]\displaystyle t=\frac{v_o}{g}[/tex]
The stone is thrown vertically upwards with vo=30 m/s, thus:
[tex]\displaystyle t=\frac{30}{9.8}[/tex]
[tex]t=3.06\ s[/tex]
[tex]t\approx 3\ s[/tex]
The stone takes about 3 seconds to rise to its maximum height
Which is true about Earth's energy budget?
A. Most of the energy from the sun is reflected back into space
B. Most of the energy from the sun is absorbed by the atmosphere and surface.
C. Very little of the energy is absorbed by the surface
D. The amount of energy coming back into the atmosphere is less than what leaves Earth's surface
Answer:
I think is B but I'm not sure
The statement which is true about Earth's energy budget is that most of the energy from the sun is absorbed by the atmosphere and surface. Thus, the correct option for this question is B.
What is Earth's energy budget?Earth's energy budget may be characterized as the mutual balance between the radiant energy that significantly reaches Earth from the sun with respect to the energy that flows from Earth back out to space.
In order to maintain a constant global average temperature, all of the sun's radiation that successfully enters Earth's atmosphere must eventually be sent back to space. There are three sources of Earth's energy budget may include incoming solar energy (shortwave radiation), Outgoing longwave radiation, and Earth's internal heat sources and other small effects.
Therefore, the correct option for this question is B.
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Define one joule heat.
Answer:
The joule is the standard unit of energy in electronics and general scientific applications. One joule is defined as the amount of energy exerted when a force of one newton is applied over a displacement of one meter. One joule is the equivalent of one watt of power radiated or dissipated for one second.
Hope it helps ^^
AP physics here! Please help me answer only this question and then explain how you got your answer. After that, I will do the rest of the questions by myself using your explanation. Come here only if you know AP physics.
Answer:
displacement: 0
Distance: 30
Explanation:
lol, i asked my brother, he's also in 10th grade
Alan and Monica tested how fertilizer X affected the growth of a plant. Alan and Monica put 100 grams of fertilizer X in pot 1. They put 0 grams of fertilizer X in pot 2.
What is pot 2 called in science?
A.
a test group
B.
a data group
C.
an observational group
D.
a control group
Answer:
D.
a control group
Explanation:
In a scientific experiment such as the one above, there is an experimental group and a control group. The experimental group is the group that receives the treatment while the control group does not receive any treatment. The control group helps the researcher to observe if the treatment had any significant effect.
In this case, it will help Alan and Monica to determine if fertilizer X actually had an effect on the plant. Therefore, the pot with o grams of fertilizer in it is the control group.
Kate is riding on a train and notices that the wildflowers by the side of the tracks seem to be moving by much faster than the mountains in the distance. This is an example of
Answer: motion parallax
Explanation:
Motion parallax refers to a form of depth perception whereby objects that are closer to an individual appears to move at a faster speed than the objects that are far.
Therefore, Kate is riding on a train and notices that the wildflowers by the side of the tracks seem to be moving by much faster than the mountains in the distance is an example of motion parallax.