I need help with this question

Answer:

Step-by-step explanation:

Given f(x)=40-1.25x, where x=pounds of birdseed and 40=her saved amount, and birdseed costs 1.25/lb.

f(3)=40-1.25(3)

f(3)40-3.75

f(3)=36.25

If she buys (3 pounds) of birdseed, she saves ($36.25).

f(18)=40-1.25(18)

f(18)=40-22.5

f(18)=17.5

If she buys (18 pounds) of birdseed, she saves ($17.5)

f(36)=40-1.25(36)

f(36)=40-45

f(36)=-5

If she buys (36 pounds) of birdseed, she will need an extra $5 to pay off her debt.

If she buys (36 pounds) of birdseed, she will need an extra $5 to pay off her debt.

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Given function f(x)=40-1.25x,

where x=pounds of birdseed and 40 is her saved amount, and birdseed costs is 1.25/lb.

f(3)=40-1.25(3)

f(3)40-3.75

f(3)=36.25

If she buys (3 pounds) of birdseed, she saves ($36.25) then;

f(18)=40-1.25(18)

f(18)=40-22.5

f(18)=17.5

If she buys (18 pounds) of birdseed, she saves ($17.5) then;

f(36)=40-1.25(36)

f(36)=40-45

f(36)=-5

If she buys (36 pounds) of birdseed, she will need an extra $5 to pay off her debt.

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Answer:

x=12

Step-by-step explanation:

you need the x alone so you substract 3 from both sides.

Then you have, -x= -12

You need the x positive so you change the sign for it but as it is an equation you need to do the same thing on the other side, making both sides positive.

x=12

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \impliedby y=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{5}}x+7 \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{1}{5}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{5}{1}}\qquad \stackrel{negative~reciprocal}{-\cfrac{5}{1}\implies -5}}[/tex]

so then line K has a slope of -5 and pass through (-1, -3)

[tex](\stackrel{x_1}{-1}~,~\stackrel{y_1}{-3})\qquad \qquad slope=m=-5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-5}[x-\stackrel{x_1}{(-1)}] \\\\\\ y+3=-5(x+1)\implies y+3=-5x-5\implies y=-5x-8[/tex]

Answer:

The 95% confidence interval for the true mean score is [tex][73.539,76.461][/tex]

Step-by-step explanation:

Note that [tex]CI=\bar x\pm z\frac{s}{\sqrt{n}}[/tex] where [tex]\bar x[/tex] is the sample mean, [tex]z[/tex] is the upper critical value for the desired confidence level, [tex]s[/tex] is the sample standard deviation, and [tex]n[/tex] is the sample size.

Therefore, [tex]CI=75\pm 1.96\frac{5}{\sqrt{45}}\approx[73.539,76.461][/tex]

Answer:

  18 square units

Step-by-step explanation:

When one side is vertical or horizontal, it is convenient to find the height from the opposite vertex to that side. It is generally an integer number of grid squares.

Here, the height is 4 -(-2) = 6. The base length is 1 -(-5) = 6. That means the area is ...

  A = 1/2bh

  A = 1/2(6)(6) = 18 . . . . square units

_____

Alternate solution

If you want to go at this the hard way, you can find the length of LK and the distance of J to that line.

The length of LK is ...

  d = √((x2 -x1)^2 +(y2 -y1)^2) = √((4 -(-2))^2 +(3 -(-5))^2) = √(36 +64) = 10

The distance to line LK can be found by writing the equation of the line LK in general form:

  4x -3y -7 = 0

Then the distance formula for point (x, y) is ...

  d = |4x -3y -7|/√(4^2 +3^2)

  d = |4(-2) -3(1) -7|/5 = |-8 -3 -7|/5 = 3.6

Using the area formula with these dimensions gives ...

  A = 1/2bh = 1/2(10)(3.6) = 18 . . . . square units

Answer:

18 square units

Step-by-step explanation:

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Answer:

8 for tens, 9 for hundredths and thousandths is 1

Step-by-step explanation:

you can find the number by looking at the place of the numbers if it is tens look at the tens place which is the number eight as tens are 2 digit numbers

The equation Q = 2 x M represents the relationship between question and time.

An equation is a combination of different variables, in which two mathematical expressions are equal to each other.

Given that,

Zack takes a test, in which he answers at rate of 2 question per minute.

Also, Q represents questions

And M represents minutes.

According to given condition,

In 1 minute, Zack answers 2 question,

In M minutes, Zack answers 2 x M question,

Total questions presented by Q,

Q = 2 x M.

The required relationship for M and Q is Q = 2 x M.

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Answer:

-35

Step-by-step explanation:

5(4)(-5) + -2(4)(-5) + (-5)²

= -100 + 40 + 25

= -35

Answer: -35

Step-by-step explanation:

5(4)(-5)+(-2)(4)(-5)+(-5)^2

-100+40+25

-35

Answer:

infinite solutions...

Step-by-step explanation:

Is there more information to this problem? It can be pretty much anything.

N=3M

Nina can be 30 and Maryna 10, Nina can be 3 and Maryna 1, Nina can be 15 and Maryna 5...

Answer:

N - 4 = 3(M - 4). Simplified further, N - 4 = 3(M - 4)

Given,

Nina is N years old now and;

Maryna is M years old now

If four years ago, Nina was three times as old as Maryna was, then

Four years ago, Nina's age was N - 4

Four years ago, Maryna's age was M - 4

Given that Nina was three times as old as Maryna was four years ago, it means that

N - 4 = 3(M - 4)

To solve further

N = 3m - 12 + 4

N = 3M - 8

Step-by-step explanation:

Answer:

14/15

Step-by-step explanation:

Answer:

6/11

Step-by-step explanation:

-2 2/3 divided by 1 5/6 = -16/11 and when you add two to that you get 6/11.

Answer:

so there is 14 cards in total so out of those 14 14 cards are either blue or green so 100%

Hope This Helps!!!

Answer:

7x/1+7sin(2)x

Step-by-step explanation:

[tex]z1=\stackrel{a}{3}+\stackrel{b}{3}i~~ \begin{cases} r = \sqrt{a^2+b^2}\\ r = \sqrt{18}\\[-0.5em] \hrulefill\\ \theta =\tan^{-1}\left( \frac{b}{a} \right)\\ \theta =\frac{\pi }{4} \end{cases}~\hfill z1=\sqrt{18}\left[\cos\left( \frac{\pi }{4} \right) i\sin\left( \frac{\pi }{4} \right) \right] \\\\[-0.35em] ~\dotfill[/tex]

[tex]\cfrac{z1}{z2}\implies \cfrac{\sqrt{18}\left[\cos\left( \frac{\pi }{4} \right) i\sin\left( \frac{\pi }{4} \right) \right]} {7\left[\cos\left( \frac{5\pi }{9} \right) i\sin\left( \frac{5\pi }{9} \right) \right]} \\\\[-0.35em] ~\dotfill\\\\ \qquad \textit{division of two complex numbers} \\\\ \cfrac{r_1[\cos(\alpha)+i\sin(\alpha)]}{r_2[\cos(\beta)+i\sin(\beta)]}\implies \cfrac{r_1}{r_2}[\cos(\alpha - \beta)+i\sin(\alpha - \beta)] \\\\[-0.35em] ~\dotfill[/tex]

[tex]\cfrac{z1}{z2}\implies \cfrac{\sqrt{18}}{7}\left[\cos\left( \frac{\pi }{4}-\frac{5\pi }{9} \right)+i\sin\left( \frac{\pi }{4}-\frac{5\pi }{9} \right) \right] \\\\\\ \cfrac{\sqrt{18}}{7}\left[\cos\left( \frac{-11\pi }{36} \right) +i\sin\left( \frac{-11\pi }{36} \right) \right]\implies \cfrac{\sqrt{18}}{7}\left[\cos\left( \frac{83\pi }{36} \right) +i\sin\left( \frac{83\pi }{36} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{z1}{z2}\approx 0.348~~ + ~~0.496i~\hfill[/tex]

The value of z1/z2 is √18/ 7 (cos ( 11π/36 ) - isin ( 11π/36 )).

"A complex number is the sum of a real number and an imaginary number and it is of the form x + iy and is usually represented by z".

For the given situation,

z1= 3+3i and

z2= 7(cos(5π/9) + i sin (5π/9))

To divide the complex numbers, both should be in same form.

Convert z1 in polar form.

z is of the form x+iy, so, r=[tex]\sqrt{x^{2}+y^{2} }[/tex]

⇒[tex]r=\sqrt{3^{2}+3^{2} }[/tex]

⇒[tex]r=\sqrt{18}[/tex]

θ = [tex]tan^{-1}(\frac{b}{a} )[/tex]

⇒[tex]tan^{-1}(\frac{3}{3} )[/tex]

⇒[tex]tan^{-1}(1)[/tex]

⇒[tex]45[/tex]°

The polar form is of the form, z= r (cosθ + i sinθ),

⇒ z1 = [tex]\sqrt{18}[/tex] (cosπ/4 + isinπ/4)

The formula for dividing complex number is

z1/z2 = r1(cos θ1 + isin θ1) / r2(cos θ2 + isin θ2)

⇒ z1/z2 = r(cosθ + isinθ)

where, r = r1/r2 and θ = (θ1 - θ2)

z1/z2 = [tex]\sqrt{18}[/tex] (cos π/4 + isin π/4) / 7 (cos 5π/9 + isin 5π/9)

⇒ r = [tex]\sqrt{18}[/tex] / 7 and

θ = (π/4 - 5π/9 )

⇒ θ = (-11π/36)

cos(-θ) = cos θ

⇒cos( -11π/36 ) = cos ( 11π/36 )

sin(-θ) = -sin θ

⇒ sin ( -11π/36 ) = -sin ( 11π/36 )

Thus, z1/z2 = [tex]\sqrt{18}[/tex] / 7 (cos ( 11π/36 ) - isin ( 11π/36 ))

Hence we can conclude that the value of z1/z2 is

√18/ 7 (cos ( 11π/36 ) - isin ( 11π/36 )).

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first you have to change 1/3 to -3

y=-3x+2

then you have to replace 2 with 'b' because you don't know the y intercept yet

y=-3x+b

then you substitute the point (4,7) into the equation

7= -3(4) + b

7= -12 + b

19 = b

y = -3x + 19 is the equation in slope intercept form

for point slope form:

-3x is still the slope and you replace x and y with the point 4,7

y- 7= -3 (x-4)

in essence it's just asking on getting the equation of that line in more or less slope-intercept form, hmmm well, it's a line, so all we need is two points to get it, hmmm let's see let's use the starting point and terminal point, so we know it goes through the origin, (0,0) and also goes through (1, 0.7), let's change 0.7 to a fraction, so its 7/10, ok, let's use those two points from it.

[tex](\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{\frac{7}{10}}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{\frac{7}{10}}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{0}}}\implies \cfrac{~~ \frac{7}{10}~~}{1}\implies \cfrac{7}{10}[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{\cfrac{7}{10}}(x-\stackrel{x_1}{0})\implies y = \cfrac{7}{10}x[/tex]

Answer:

$500.19 is the answer

Step-by-step explanation:

pls vote branliest

The total cost of 11 printers is $500.19.

Given that,

A retailer needs to purchase 11 printers.

The first printer costs $58, and each additional printer costs 5% less than the price of the previous printer, up to 15 printers.

We have to determine,

What is the total cost of 11 printers?

According to the question,

The first printer costs $58.

Each additional printer costs 5% less than the price of the previous printer, up to 15 printers.

The cost of a second printer is,

= 0.95 × 58 = $55.1

The cost of a third printer is,

= 0.95 × 55.1 = $52.345

The cost of a fourth printer is,

= 0.95 × 52.345 = $49.727

The cost of a fifth printer is,

= 0.95 × 49.727 = $47.241

The cost of a sixth printer is,

= 0.95 × 47.241 = $44.879

The cost of a seventh printer is,

= 0.95 × 44.879 = $42.635

The cost of an eight printer is,

= 0.95 × 42.635 = $40.50

The cost of a nineth printer is,

= 0.95 × 40.50 = $38.478

The cost of tenth printer is,

= 0.95 × 38.478 =  $36.554

The cost of the eleventh printer is,

= 0.95 × 36.554  = $34.726

Therefore,

The total cost of 11 printers is,

= $58 + $55.1 + $52.345 + $49.727 + $47.241 + $44.879 + $42.635 + $40.50 + $38.478 + $36.554 + $34.726 = $500.19.

Hence, The total cost of 11 printers is $500.19.

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Answer:

-15%.

Step-by-step explanation:

Subtract 68 by 80 to get -12.

Divide -12 by the absolute value of 80 to get -0.15.

Multiply 100 to -0.15 to get -15.

Answer:

......................

Answer:

One Solution

Step-by-step explanation:

x + 3y = 3      

x - y = -3        

4y = 6           Subtract to solve by elimination.

y = [tex]\frac{3}{2}[/tex]              Divide by 4.

x - [tex]\frac{3}{2}[/tex]  = -3      Substitute [tex]\frac{3}{2}[/tex] for y in the original equation.

x = -[tex]\frac{3}{2}[/tex]            Add [tex]\frac{3}{2}[/tex].

Answer:37

Step-by-step explanation:

Answer:

C.24

Step-by-step explanation:

First multiply 8 by 24 this is so you know how much 24 adults would be. You will get 192 so next you need to subtract 192 from the total money 272 to get 80 and 80 should be how much all of the kids cost now to check and make sure there are 40 people divide 80 by 5 to get 16 which is the total number of kids no just add 16 and 24 together to get 40

Answer:

10[tex]sin^{2} ([/tex]β[tex])[/tex]

Step-by-step explanation:

We can find this two ways, first by seeing in the step after it, cosines are canceled out. Since you already have 10[tex]sin^{2} ([/tex]β[tex])[/tex] on the next step, you can assume that (since only the cosines changed and the cosine next ot the blank was removed), the value is 10[tex]sin^{2} ([/tex]β[tex])[/tex].

You can also use double angle formulas from the previous step:

(sin(2β) = 2 sin(β) cos(β))and find that:

5 sin (2β) sin(β) = 5 * (2 sin(β) cos(β)) sin(β)) = (10 sin(β) sin(β)) cos(β) =

10[tex]sin^{2} ([/tex]β[tex])[/tex] cos(β)

But since cos(β) is already present, we can see that the answer is 10[tex]sin^{2} ([/tex]β[tex])[/tex]

Answer:

didn't know how to workout iam only 3rd standard

Answer:

Step-by-step explanation:

bubble gum

Answer:

Root:(-⅗,0)

vertical intercept:(0,5)

Step-by-step explanation:

Given that

log √x (x) + log c² (c)

⇛ log x^1/2 (x) + log c² (c)

We know that

log a^m (b^n) = m/n log a (b)

⇛ 1/2 log x (x) + 2 log c (c)

We know that

log a ( a) = 1

⇛ (1/2)(1) + 2(1)

⇛ (1/2)+2

⇛ (1+4)/2

⇛ 5/2

Answer:- log √x (x) + log c² (c) = 5/2

[(x) ,(c) , (a) represents the bases ]

Additional comment:

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Answer:

Step-by-step explanation:

They have different y intercepts.

They have the same slope.

Here are 2 examples

y = 3x + 5

y = 3x + 19

The slopes are both three. The y intercepts are 5 for the top equation and 19 for the bottom equation.

They are both lines. That means their  domain is -infinity <x < + infinity

Their range is - infinity <y < + infinity.

We are excluding  examples like x = 3 and x = 5 and y = 1 and y = 3.

It is true that they both are parallel in both cases, but the discussion for each pair is a little different.