I REALLY NEED HELP FOR THIS ONE

Answer:

720 seating arrangments

Step-by-step explanation:

There are eight people but driver is always the same so we only have to deal with combinations of the other 7 seats.

the combination of the five seats has 5! times 2 combinations for each of the 3 passengers willing to ride in the two boat seats thus the total number of different seating arrangements is 5! times 3! or 720

hope this helps :)

Using the Fundamental Counting Theorem, it is found that there are 5760 possible seating arrangements.

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

In this problem:

Hence:

[tex]N = 8 \times 6 \times 5! = 5760[/tex]

There are 5760 possible seating arrangements.

More can be learned about the Fundamental Counting Theorem at https://brainly.com/question/24314866

Answer:

4x-2

Step-by-step explanation:

4x(3x+5)-2(3x+5)

(4x-2)(3x+5)

you can see that 4x-2 is a factor

Answer:

x = - 1, x = 1

Step-by-step explanation:

Given

f(x) = [tex]\frac{2x^2+3x+6}{x^2-1}[/tex]

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.

x² - 1 = 0 ← difference of squares

(x - 1)(x + 1) = 0

x - 1 = 0 ⇒ x = 1

x + 1 = 0 ⇒ x = - 1

x = - 1 and x = 1 are vertical asymptotes

Diagram related to the question can be found in the attached picture below :

Answer: 6 units

Step-by-step explanation:

From the diagram attached to the question:

Length AB = 17

Length DC = 8

height (h) = x

Area of trapezium = 75sq units

The Area (A) of a trapezium is given by:

(1/2) × (a + b) × h

Where ;

a and b are the upper and base lengths of the trapezium

h = height of trapezium

A = (1/2) × (a + b) × h

75 = (1/2) * (17 + 8) * x

75 = 0.5*25*x

75 = 12.5x

x = 75 / 12.5

x = 6 units

Answer:

If you wish to find any term (also known as the {n^{th}}n  

th

 term) in the arithmetic sequence, the arithmetic sequence formula should help you to do so. The critical step is to be able to identify or extract known values from the problem that will eventually be substituted into the formula itself.

Step-by-step explanation:

Answer:

25 ( A)

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Answer:

A

Step-by-step explanation:

The first ten primes are

2,3,5,7,11,13,17,19,23,27

so the number is

2*3*5*7*11*13*17*23*27

so

2*11 is 22, so 22 divides the number

2*3 is 6, so 6 divides the number

2 is there so 2 divides the number

So the only one is 25.

Answer: 6 - 5

Step-by-step explanation:

|z - 6| - |z - 5|    ; z < 5

Since z < 5, then

|z - 6| will be the absolute value of a negative number. Replace the absolute value with a negative and parentheses:

-(z - 6) =  -z + 6

|z - 5| will be the absolute value of a negative number. Replace the absolute value with a negative and parentheses:  

-(z - 5) = -z + 5

Now subtract them without the absolute value signs:

-z + 6 - (-z + 5)

Distribute the negative sign:

-z + 6 + z - 5

-z + z = 0 which leaves:

6 - 5

Answer: 1

Step-by-step explanation: first you need to pretend that the absolute value bars are parentheses. Then substitute a with any number less that five, for example z=3

Now we can write our new equation: (3-6)-(3-5)

now we have to determine if the final answer inside the parentheses is positive or negative. In the first parentheses 3-6=-3 with is negative. In our second parentheses we have 3-5=-2 which is a also negative.

Knowing that both parentheses are negative results we can set up an equation using z instead of 3:

-(z-6)-(-(z-5)) is our new equation. If we simplify this equation we get 1 for an answer

Answer:

46°

Step-by-step explanation:

We can tell that this triangle is an isosceles triangle because 2 of it's sides are the same, therefore, two of it's angles are the same.

Looking at it, we can assume that the two angles not defined (x and the other one) are the two angles that are the same because they look similar.

Now, the angles of all triangles add up to 180°. So, we can subtract 88° from 180 to see what the two angles add up to.

[tex]180-88=92[/tex]

So both of these angles add up to 92 degrees. Since there are two, we divide 92 by 2.

[tex]92 \div 2 = 46[/tex]

Hope this helped!

Answer: x = 137°

Step-by-step explanation:

When a quadrilateral is inscribed in a circle, the opposite angles are supplementary.

x + 43° = 180°

      x   =  137°

The value of x is 137°.

The quadrilateral whose all 4 vertices lie on the circumference of the circle is called an inscribed quadrilateral.

In inscribed quadrilateral opposite angles are supplementary i.e. sum of those opposite angles is 180°.

Here given in the picture that the measurements of the two opposite angles in the inscribed quadrilateral in the circle are 43° and x°.

So as we know in the inscribed quadrilateral opposite angles are supplementary.

So sum of those opposite angles in the quadrilateral is 180°.

so we can write x+43°= 180°

⇒ x = 180°- 43°

⇒ x = 137°

Therefore the value of x is 137°.

Learn more about inscribed quadrilateral

here: https://brainly.com/question/26690979

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Answer:

Increasing if X is positive decreasnig if X is negative

Step-by-step explanation:

Answer:

increasing

Step-by-step explanation:

positive slope of 75 so line goes up to the right

Answer:

X ^3 (4x+1) (4x-1)

Step-by-step explanation:

Factor x3 out of  16x5−x3

Rewrite 16x2 as  (4x)2

Rewrite 1 as 1^2

Factor

x^3 (4x+1) (4x-1)

I hope I helped

Answer:

[tex]3 -\sqrt[2]3[/tex]

Step-by-step explanation:

Given

[tex]\frac{2\sqrt[3]{9}}{1 + \sqrt[3]{3} + \sqrt[3]{9}}[/tex]

Required

Simplify

Rewrite the given expression in index form

[tex]\frac{2 * 9 ^\frac{1}{3}}{1 + 3^{\frac{1}{3}} + 9^{\frac{1}{3}}}[/tex]

Express 9 as 3²

[tex]\frac{2 * 3^2^*^\frac{1}{3}}{1 + 3^{\frac{1}{3}} + 3^2^*^{\frac{1}{3}}}[/tex]

[tex]\frac{2 * 3^\frac{2}{3}}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}}}[/tex]

Multiply the numerator and denominator by [tex]1 - 3^{\frac{1}{3}}[/tex]

[tex]\frac{2 * 3^\frac{2}{3}}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}}} * \frac{1 - 3^{\frac{1}{3}}}{1 - 3^{\frac{1}{3}}}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) (1 - 3^{\frac{1}{3}})}{(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})(1 - 3^{\frac{1}{3}})}[/tex]

Open the bracket

[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{2}{3})(3^{\frac{1}{3}})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]

Simplify the Numerator using Laws of Indices

[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{2+1}{3})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]

Further Simplify

[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{3}{3})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) -2 (3^1)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]

Simplify the denominator

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - (3^{\frac{1}{3}})(3^{\frac{1}{3}}) - (3^{\frac{1}{3}})(3^{\frac{2}{3}})}[/tex]

Further Simplify Using Laws of Indices

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - (3^{\frac{1+1}{3}}) - (3^{\frac{1+2}{3}})}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3^{\frac{3}{3}}}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3^1}}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3}}[/tex]

Collect Like Terms

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 - 3+ 3^{\frac{1}{3}} - 3^{\frac{1}{3}}+ 3^{\frac{2}{3}} - 3^{\frac{2}{3}} }}[/tex]

Group Like Terms for Clarity

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{(1 - 3) + (3^{\frac{1}{3}} - 3^{\frac{1}{3}}) + (3^{\frac{2}{3}} - 3^{\frac{2}{3}} )}}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{(- 2)+ (0) + (0)}}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{-2}}[/tex]

Divide the fraction

[tex]-(3^\frac{2}{3}) + (3)[/tex]

Reorder the above expression

[tex]3 -3^\frac{2}{3}[/tex]

The expression can be represented as

[tex]3 -\sqrt[2]3[/tex]

Hence;

[tex]\frac{2\sqrt[3]{9}}{1 + \sqrt[3]{3} + \sqrt[3]{9}}[/tex] when simplified is equivalent to [tex]3 -\sqrt[2]3[/tex]

Answer:

1290000

Step-by-step explanation: Given that

The volume of the Sun is about = 1.41 x 10^18 cubic kilometers.

The volume of Earth is about 1.09 x 10^12 cubic kilometers.

The number of Earths that can fit inside the Sun can be found by dividing the Sun's volume by Earth's volume.

= Volume of Sun ÷ Volume of the Earth

= 1.41 x 10^18 cubic km/1.09 x 10^12 cubic km

= 1.41 x 10^18/1.09 x 10^12

=(1.42/1.09)× 10^18-12

= 1.29×10^6

n is 1.29×10^6.

Hence the number of Earth that can be fitted in the Sun is 1290000

Answer:

2 possible values

Step-by-step explanation:

The given expression is:

[tex]\sqrt[3]{\frac{144}{y} }[/tex]

In order for this to result in a whole number, 144/y must be a perfect cube, the possible perfect cubes (under 144) are:

1, 8, 27, 64, 125

The values of y that would result in those numbers are:

[tex]y=\frac{144}{1}=144 \\y=\frac{144}{8}=18 \\y=\frac{144}{27}=5.333\\y=\frac{144}{64}=2.25\\y=\frac{144}{125}=1.152[/tex]

Only two values of y are integers, therefore, there are only two possible values of y for which the given expression results in a whole number.

Answer:it’s b

Step-by-step explanation:

Just took quiz on edge 2020

Answer:

The expression for the shaded region is 10x² + 12x .

Step-by-step explanation:

First, you have to find the area of both rectangles using the formula :

[tex]area = length \times height[/tex]

Small rectangle,

[tex]area = x \times (5x - 2)[/tex]

[tex]area = 5 {x}^{2} - 2x[/tex]

Large rectangle,

[tex]area = (3x + 2) \times 5x[/tex]

[tex]area = 15 {x}^{2} + 10x[/tex]

In order to find the shaded region, you have to subtract the smaller from the larger one :

[tex]area \: of \: shaded = large - small[/tex]

[tex]area = 15 {x}^{2} + 10x - 5 {x}^{2} + 2x [/tex]

[tex]area = 10 {x}^{2} + 12x[/tex]

Answer: A. 82

Step-by-step explanation:

The measure of <BAD can be found by simply adding 25(<BAC)+57(<CAD) = 82.

[tex]\mathrm{BAD}=\mathrm{BAC}+\mathrm{CAD}=25^{\circ}+57^{\circ}=82^{\circ}[/tex].

Hope this helps.

Answer:

The possible number of goats is 6 and the possible number of chicken is 24

Step-by-step explanation:

Let

chicken=c

Goat=g

the number of chickens could be four times the number of goats

c=4g

Total number of animals=30

c+g=30

Recall, c=4g

So,

c+g=30

4g+g=30

5g=30

Divide both sides by 5

5g/5=30/5

g=6

Recall,

c+g=30

c+6=30

c=30-6

=24

c=24

The possible number of goats is 6 and the possible number of chicken is 24 making a total of 30 animals

Answer:

C

Step-by-step explanation:

Given

2x² + x - 1 = 2 ( subtract 2 from both sides )

2x² + x - 3 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 2 × - 3 = - 6 and sum = + 1

The factors are - 2 and + 3

Use these factors to split the x- term

2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )

2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term

(x - 1)(2x + 3) = 0

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = - [tex]\frac{3}{2}[/tex]

Answer:

option three!!!!!

Step-by-step explanation:

its closed circle

on 6

and pointing  left

Answer:

b^8

Step-by-step explanation:

When multiplying exponents with the same base, we can add the exponents

b^2 * b^6

b^ (2+6)

b^8

Answer:b8 x

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): "b6"   was replaced by   "b^6".  1 more similar replacement(s).

STEP

1

:

Multiplying exponential expressions

1.1    b2 multiplied by b6 = b(2 + 6) = b8

Final result :

 b8x

The pyramid consists of 4 congruent triangular faces, and 1 square base.

Area of 1 triangular face:

1/2 * (5 in)/2 * (5.6 in) = 7 in^2

Area of base:

(5 in)^2 = 25 in^2

Then the total surface area is

4 * (7 in^2) + 25 in^2 = (28 + 25) in^2 = 53 in^2

Answer:

The answer is 429 = 3×11×13.

Step-by-step explanation:

You have to divide by prime number :

429 ÷ 3 = 143

143 ÷ 11 = 13

13 ÷ 13 = 1

Answer:

3×11×13

Step-by-step explanation:

Answer:

2 should be distributed as 2y + 8; y = 4

Step-by-step explanation:

Step 2 is wrong.

2(y + 4) = 4y

The step to solve is to expand brackets or distribute 2, not divide both sides by 2.

2y + 8 = 4y

Subtract both sides by 2y.

8 = 2y

Divide both sides by 2.

4 = y

Answer:

(a) The probability that the average of the draws will be in the range 80 to 120 is 1.

(b) The probability that the average of the draws will be in the range 99 to 101 is 0.6827.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.  

Then, the mean of the sample means is given by,

[tex]\mu_{\bar x}=\mu[/tex]

And the standard deviation of the sample means is given by,

[tex]\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}[/tex]

As the sample selected is quite large, i.e. n = 400 > 30, then the sampling distribution of sample means will be approximately normally distributed.

Compute the mean and standard deviation of sample mean as follows:

[tex]\mu_{\bar x}=\mu=100\\\\\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{20}{\sqrt{400}}=1[/tex]

So, [tex]\bar X\sim N(100, 1)[/tex]

(a)

Compute the probability that the average of the draws will be in the range 80 to 120 as follows:

[tex]P(80<\bar X<120)=P(\frac{80-100}{1}<\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}<\frac{120-100}{1})[/tex]

                            [tex]=P(-20<Z<20)\\\\=P(Z<20)-P(Z<-20)\\\\=(\approx1)-(\approx0)\\\\=1[/tex]

Thus, the probability that the average of the draws will be in the range 80 to 120 is 1.

(b)

Compute the probability that the average of the draws will be in the range 99 to 101 as follows:

[tex]P(99<\bar X<101)=P(\frac{99-100}{1}<\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}<\frac{101-100}{1})[/tex]

                            [tex]=P(-1<Z<1)\\\\=P(Z<1)-P(Z<-1)\\\\=0.6827[/tex]

Thus, the probability that the average of the draws will be in the range 99 to 101 is 0.6827.

Answer:

Toa

48/55

Step-by-step explanation:

O/A

48/55

Answer:

Hello! The answer to your question will be below.

Step-by-step explanation:

The answer would be clockwise.

So point k was rotated 90 degrees clockwise.....

Review.....

Question:

Point K is rotated 90 degrees. The coordinate of the pre-image point K was (2,-6) and it’s image K’ is at the coordinate (-6,-2).Find the direction of the rotation.

THE DIRECTION OF THE ROTATION WAS CLOCKWISE.

Hope this helps! :)

⭐️Have a wonderful day!⭐️

Answer:

clockwise.

So point k was rotated 90 degrees clockwise.....

Review.....

Question:

Point K is rotated 90 degrees. The coordinate of the pre-image point K was (2,-6) and it’s image K’ is at the coordinate (-6,-2).Find the direction of the rotation.

Step-by-step explanation:

Answer:

{ 1,2}

Step-by-step explanation:

The ∩ means intersection, or what is in common for the two sets

The intersection of A and B is what is in the overlapping circles

The intersection of A and B is { 1,2}