I
Table for a linear equation
Fill in the table using this function rule.
y = 5x-2
X
y
Х
?
- 1
0
1
2

Answer:

when the coefficient of x^2 is negative

Step-by-step explanation:

Answer: yes they are perpendicular

Answer: y = 115 and x = 78

Step-by-step explanation:

y = 115 because it is parallel with the angle 115 and parallel are congruent, for x find the angle beside the angle 102 and that angle is parallel with the angle x and that will be 180 - 102 = 78 which is x  

Answer:

B

Step-by-step explanation:

you can break the 78 into 70 and 8, and multiply them separately by 6 and then add the two answers to get 468

Step-by-step:

Use slope formula to find the slope. (y - y)/(x - x)

Make sure the x and y in front of the minus is a pair that goes together, as well as the x and y behind the minus sign. So

8 - -4 goes on top, that's 12

0 - -1 goes under, thats 1

12/1 is the slope which is just 12. Use either point to fill in the second x and the second y in the point-slope equation. m is the slope.

y - y = m(x - x)

y - 8 = 12(x - 0)

y - 8 = 12x

Answer:

11:18

Step-by-step explanation:

Hope this helped!

Answer:

5

7

..................

Answer:

y equals -2x -7

y equals 3/4 x plus 2 1/2

Answer: x = 3 and y = 5

Step-by-step explanation:

Answer:

2/3

Step-by-step explanation:

The answer is simple; the number of non-red marbles over the number of total marbles.

Answer:

[tex](x-2)(x-3)[/tex]

Step-by-step explanation:

[tex]x^2-5x+6[/tex]

[tex]x^2-3x-2x+6[/tex]

[tex]x(x-3)-2(x-3)[/tex]

[tex](x-2)(x-3)[/tex]

Answer:

x=1+sqr57,1-sqr57

Step-by-step explanation:

Answer:

  x = -6.5, x = 8.5

Step-by-step explanation:

The given equation ...

  x^2 -4x -31 = -2x +25

can be rewritten to a form that facilitates completing the square:

  x^2 -2x = 56 . . . . . add 2x+31

  x^2 -2x +1 = 57 . . . add 1 to complete the square

  (x -1)^2 = 57 . . . . . write the left side as a square

  x -1 = ±√57 . . . . . take the square root

  x = 1 ±√57 ≈ {-6.5, 8.5} . . . . . add 1, evaluate

Solutions are near x = -6.5 and x = 8.5.

Answer:

answer is  

A.21,369 or  D. 56,783

Step-by-step explanation:

am  not sure but am mostly sure it is D but i dont know i think is A to but am

99% is D

hope it helps

Answer:

Your answer is C 48,618

Step-by-step explanation:

if you add the sum up of all of the digits it is divisible by both three and nine.

can i plz get brainliest.

Answer:

A pencil is about 19 centimeters long

Answer:

if 100 inches=254 centimeters

then 10 inches=x

100x=2540

x=2540/100

x=25.4 centimeters

Answer:

John spends $23.60 at the barbershop.

Step-by-step explanation:

convert all % to decimals (/100)

0.2 x 25 = 5

25 - 5 = $20

0.18 x 20 = 3.6

20 + 3.6 = $23.6

Answer:6 . 625 or 6 5/8

Step-by-step explanation

10 + (-3 3/8)         (adding a negative is like subtracting a positive)

10 - 3 3/8

6 5/8

Answer:

d

Step-by-step explanation:

they intersect but aren't perpendicular.

Using the histogram, the mean of the data-set is estimated to be of 31.

In this problem, the intervals and relative frequencies are:

Hence, the mean is:

[tex]E(X) = 23\frac{4}{30} + 28\frac{8}{30} + 33\frac{14}{30} + 38\frac{4}{30} = \frac{23(4) + 28(8) + 33(14) + 38(4)}{30} = 31[/tex]

For more on mean of histograms, you can check https://brainly.com/question/24651197

======================================================

Explanation:

Solve the inequality for x.

5x + 4 < 29

5x < 29-4

5x < 25

x < 25/5

x < 5

I subtracted 4 from both sides (step 2). Then I divided both sides by 5 to fully isolate x (step 4). The inequality sign stays the same the entire time.

Since x < 5, this means the original set {3,4,5,6} becomes {3,4} since these values make x < 5 a true statement. In other words, we erase 5 and 6 because something like 6 < 5 is false.

That's why {3, 4} is the final answer.

---------------

An alternative method is to go through the set {3,4,5,6} and plug those items one by one into the original inequality. If you get a true result, then it's part of the answer.

Let's try x = 3

5x + 4 < 29

5(3) + 4 < 29

15+4 < 29

19 < 29

We get a true statement at the end, so x = 3 is part of the solution set. A similar story happens for x = 4 as well.

If we tried x = 5, then,

5x + 4 < 29

5(5) + 4 < 29

25 + 4 < 29

29 < 29

which is false. No number is bigger than itself (or smaller than itself). Therefore, x = 5 is crossed out of the original set. You should get a false statement for x = 6, which means we'll kick this value out as well.

The zeros of

y = x(x + 2)(x + 5)y=x(x+2)(x+5)

are

x=0,x=-2,x=-5x=0,x=−2,x=−5

EXPLANATION

The given function is

y = x(x + 2)(x + 5)y=x(x+2)(x+5)

To find the zeros of the above function, we just have to equate the function to zero and solve for x.

x(x + 2)(x + 5) = 0x(x+2)(x+5)=0

This implies that,

x = 0 \: \: or \: x + 2 = 0 \:or \: x + 5 = 0x=0orx+2=0orx+5=0

x = 0 \: \: or \: x = - 2\:or \: x = - 5x=0orx=−2orx=−5

To graph the above function, we need to consider the multiplicity.

We can see that the multiplicity of the roots are odd. This means that, the graph crosses the x-axis at each x-intercept.

We also need to consider the position of the graph on the following intervals,

x < - 5x<−5

When

x = - 10x=−10

y = - 10( - 8)( - 5) \: < \: 0y=−10(−8)(−5)<0

The graph is below the x-axis.

- 5 \: < \: x \: < \: - 2−5<x<−2

When

x = - 3x=−3

y = - 3(2)( - 1) \: > 0y=−3(2)(−1)>0

The graph is above the x-axis.

- 2 \: < \: x < \: 0−2<x<0

when

x = - 1x=−1

y = -1(1)(4) \: < \: 0y=−1(1)(4)<0

The graph is below the x-axis.

Finally the interval,

x \: > \: 0x>0

when

x = 1x=1

y = 1(3)(6) \: > \: 0y=1(3)(6)>0

The graph is above the x-axis.

We can now use the above information to sketch graph as shown in the diagram above

Answer:

\mathrm{X\:Intercepts}:\:\left(-\frac{431}{26},\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:43.1\right)

Step-by-step explanation:

Answer:

False.

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Calculus

Differentiation

Derivative Rule [Basic Power Rule]:

Derivative Rule [Product Rule]:                                                                             [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify.

[tex]\displaystyle \frac{d}{dx}[x^3e^x][/tex]

Step 2: Differentiate

∴ [tex]\displaystyle \frac{d}{dx}[x^3e^x] \neq x^3e^x(3x + 2)[/tex]  but  [tex]\displaystyle \frac{d}{dx}[x^3e^x] = (x^3 + 3x^2)e^x[/tex].

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Answer:

Hence 27 cubes can be obtained.

Step-by-step explanation:

Volume occupied by one cube of side 2cm = 2*2*2 = 8cm^3

Volume of cube of side 6cm = 216cm^3

Number of cubes of side 2cm which would fit in a cube of side 6cm = 216/8 = 27 cubes

Answer:

1 3/4

Step-by-step explanation:

Given that √2 = 1.414

The value of (1/2)√(16200)

16200 can be written as

16200 = 2×8100

16200 = 2×2×4050

16200 = 2×2×2×2025

16200 = 2×2×2×5×405

16200 = 2×2×2×5×5×81

16200 = 2×2×2×5×5×3×27

16200 = 2×2×2×5×5×3×3×9

16200 = 2×2×2×5×5×3×3×3×3

√16200 = √(2×2×2×5×5×3×3×3×3)

√16200 = √2×(2×2)×(5×5)×(3×3)×(3×3)

√16200 = 2×5×3×3√2

√16200 = 90√2

Now,

(1/2)√16200

⇛(1/2)×90√2

⇛90√2/2

⇛45√2

⇛45×1.414

⇛63.63

Answer: Hence, value of (1/2)√(16200) is 63.63

also read similar questions: if √2=1.414 and√3=1.732,find the value of 1/√2+√3..

https://brainly.com/question/12837303?referrer

If √2 = 1.414 then the value of 5+√2 / 5-√2 is..

https://brainly.com/question/25047005?referrer

The value of 1/2√16200 given the value of √2 = 1.414 is 63.63

Prime factorization of √16200

= 3 × 3 × 5 × √2

= 90√2

Given:

1/2√16200

= 1/2 × 90√2

= 90√2 / 2

= 45√2

= 45 × √2

= 45 × 1.414

= 63.63

Therefore, the value of 1/2√16200 is 63.63

Learn more about prime factorization:

https://brainly.com/question/9523814

That would probably be zero for the answer, because if a number or an equation subtracts the same number or equation it will cancel itself out. Thus giving us zero.

Hope this help :D.

Proof:-

In ∆XYZ and ∆VWZ

[tex]\because\sf\begin{cases}\sf XZ\cong VZ(Given)\\ \sf YZ\cong WZ(Given)\\ \sf <XZY\cong <WZV(Opposite angles)\end{cases}[/tex]

Hence

∆XYZ[tex]\cong[/tex](Side-Angle-Side)