pls help it's due today​

Happy Holidays!

Recall that:

Impulse = Change in Momentum = mass × change in velocity

Since both cars are identical and have the same initial velocity of 60 mph, them breaking to a stop means that they both experience the same change in velocity.

Thus, both of the cars' impulses are equal.

The two chemical compounds having a molar ratio of 1 : 1 is CO₂ and K₂CO₃

                4KO₂ + 2CO₂ —> 2K₂CO₃ + 3O₂

                4       :    2         :   2       :       3

From the balanced equation above, the coefficients are 4, 2, 2, 3

A careful observation of the equation shows that CO₂ and K₂CO₃ exist in ratio 2 : 2 which can be simplified as 1 : 1

Therefore, we can conclude that CO₂ and K₂CO₃ has molar ratio of 1 : 1

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Answer:

model A

Explanation:

model A is more expensive to buy but you pay less per month to run it making it a better purchase in the long run. The cheaper cost of running it is better for the environment due to there being less electricity needed to power it.

If F = Gm₁m₂/d², and we change m₁ to 5m₁ and m₂ to 2m₂, then the new magnitude of the gravitational force is

F' = G (5m₁) (2m₂) / d²

F' = 10  Gm₁m₂ / d²

but this is really just F' = 10F. So J is the correct choice.

Hi there!

Using Newton's Law of Universal Gravitation:

[tex]\large\boxed{F_g = G\frac{m_1m_2}{d^2}}[/tex]

Fg = Force of gravity (N)

G = Gravitational Constant

m₁ = mass of object 1 (kg)

m₂ = mass of object 2 (kg)

d = distance between the objects (m)

There is a direct relationship between the masses of the objects and the resulting force of gravity, so we can plug new values in:

[tex]F_g = G\frac{5m_12m_2}{d^2}} = 10G\frac{m_1m_2}{d^2}} = 10F_g[/tex]

Thus, the correct answer is J. 10Fg.

[tex]\text{The unit of work is same as energy. Newton-meters(Nm) or Joules(J).}\\[/tex]

Answer:

The magnitude of a gravity is always 9.8 which is later approximated to 10m/s.

Answer:

a. 9.8

Explanation:

The magnitude of acceleration due to gravity is 9.8

The order of the location of each process in the carbon cycle are as follows;

Reasons:

Ingestion; During the ingestion process, the products of the direct Sunlight and photosynthesis, which

are energy rich chemical substances are ingested by herbivores.

Decomposition; The plants and animals die and undergo decomposition.

Fossilization; A long period the decomposed plants and animals manifest

into hard petrified materials, with their parts transformed to fossils.

Combustion; The remains of plants and animals, subjected to heat and

pressure due to compression, as when as bacteria decomposition that

removes several other elements, leaving a carbon and hydrogen rich

sludge that can be processed into fuel used for combustion. The

combustion process produces carbon dioxide which restarts the cycle.

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Answer:

The big bang

Explanation:

It is theorized the expansion of the universe began with the big bang, the universes expansion therefore did not begin in a spot of the universe rather the universe expanded from the big bang.

Answer:

“The only true wisdom is in knowing you know nothing.” ― Socrates. Socrates had it right. Remain humble and appreciate the fact that you don't know everything. ... Thankfully, one's search for knowledge has no end as there is always something new to learn, giving one's life meaning and purpose.

Explanation:

Answer:

knowing wisdom cool

Explanation:

lol

Answer:

What does this mean? please provide more explanation when asking for help

The given vectors quantities can be described by their properties of both

magnitude and direction.

Reasons:

a. The magnitude of the vector = 190 N

The direction in which the vector acts = East

Therefore, in vector form, we have;

[tex]\vec{F}[/tex] = 190 × cos(0)·i + 190 × sin(0)·j = 190·i

The vector can be represented by an horizontal line, 190 units long

Coordinate points on the vector = (0, 0) and (190, 0)

The drawing of the vector with the above points using MS Excel is attached.

b. Magnitude of the velocity vector = 120 km/hr. 25° North of east

Solution;

The vector form of the velocity is; [tex]\vec{v}[/tex] = 120 × cos(25)·i + 120×sin(25)·j, which gives;

[tex]\vec{v}[/tex] = 120 × cos(25)·i + 120×sin(25)·j ≈ 108.76·i + 50.714·j

[tex]\vec{v}[/tex] ≈ 108.76·i + 50.714·j

Therefore, points that define the vector are; (0, 0) and (108.76, 50.714)

The drawing of the vector is attached

c. The magnitude of the vector = 60 m

The direction of the vector is southwest = West 45° south

The vector form of the displacement is [tex]\vec{d}[/tex] = 60 × cos(45°)·i + 60 × sin(45°)·j

Which gives;

[tex]\vec{d}[/tex] = 30·√2·i + 30·√2·j

Points on the vector are therefore; (0, 0), and (30·√2, 30·√2)

The drawing of the vector is attached

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Using the gravitational force of F= G(m1*m2/r^2)

m1= 5.97 x 10^24 kg (Earth)

m2= 1.99 x 10^30 kg (Sun)

r= 1.48 x 10^11 m

G is a known value, it is 6.672 x 10^-11

All units are proper. Therefore plug in the values and you get 3.16 x 10^22 N.

Let me know if I calculated this wrong and it is something else so I can delete this. Thank you. I don't want to make other students put down the wrong answer.

Answer:

[tex]\boxed {\boxed {\sf F_g \approx 3.62 *10^{22} \ N}}[/tex]

Explanation:

We are asked to find the gravitational force between Earth and the Sun. Use the following formula:

[tex]F_g= \frac{Gm_1m_2}{r^2}[/tex]

G is the universal gravitational constant. One mass (m₁) is the Earth and the other (m₂) is the Sun. r is the distance between the planets.

Substitute the values into the formula.

[tex]F_g = \frac{ (6.67*10^{-11} N*m^2/kg^2)(5.97*10^{24} \ kg)(1.99*10^{30} \ kg) }{ (1.48 *10^{11} \ m)^2}}[/tex]

Multiply the numerator. The units of kilograms cancel.

[tex]F_g = \frac {7.9241601 *10^{44} \ N*m^2}{ (1.48 *10^{11} \ m)^2 }[/tex]

Solve the exponent in the denominator.

[tex]F_g= \frac {7.9241601 *10^{44} \ N*m^2}{ 2.1904*10^{22} \ m^2}[/tex]

Divide. The units of meters squared cancel.

[tex]F_g=3.61767718 *10^{22} \ N[/tex]

The original values all have 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 7 in the thousandth place tells us to round the 1 up to a 2.

[tex]F_g \approx 3.62 *10^{22} \ N[/tex]

The gravitational force between Earth and the Sun is approximately 3.62 *10²² Newtons.

The magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Given that a racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction).

mass m  = 42g = 42/1000 = 0.042kg

initial velocity before collision u = 7 m/s

It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/s to the left (-x direction). That is,

velocity after collision v = 7 m/s

To calculate the magnitude of the racquetball's change in momentum, we will use the formula below

Change in momentum = Mv - Mu

Since momentum is a vector quantity, we will consider the direction.

Change in momentum = 0.042 x 7 - ( 0.042 x - 7)

Change in momentum = 0.294 + 0.294

Change in momentum = 0.588 kgm/s

Therefore, the magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

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Answer:

Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=

r

1

mv

2

=

r

2

mu

2

................ii

form i and ii we can write

v^2= \frac{1}{2} u^2v

2

=

2

1

u

2

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

7777Answer:

Explanation:

Explanation:

the sum of its potential (position) energy and kinetic (motion) energy.

The federal government sets upper limits for exposure to electromagnetic energy from telephones known as the SAR.

Answer:

applications of density measurements. The densities of brass and aluminum will be calculated from mass and volume measurements.

Explanation:

Answer:

13,720 joules

Explanation:

Epotential = mgh

mass x gravity x height

Ep= 14 x 9.8 x 100

Ep=13,720 joules

Answer:

answer to this question is c

Answer:

3

Explanation:

because the battery's power is not functioning well

Answer:

They are both moving at the same speed since they will have the same acceleration

F = M a    describes acceleration

M a = M g sin theta    where theta is the slope

One can easily see that

a = g sin theta   and the weight does not enter into the equation

The distance is equal to 6 m traveled by elevator between 8 s and 24 s.

The distance is described as the total length covered by an object. Distance is a scalar parameter with no direction. The distance covered by an object is always +ve, it can never be zero.

The displacement is described as the shortest length between two points by the object. The displacement is a vector parameter with direction & magnitude. The displacement can be +ve, -ve, or zero and can increase or decrease over time.

Given the position of the elevator at time t = 8 s at d = 9 m

The position of the elevator at time t = 24 s at d = 15 m

The distance covered by the elevator = 15 - (9) =  15 - 9 = 6 m

Therefore, the distance traveled by an elevator between 8 s and 24 s is equal to 6 m.

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Answer:

147 Joules

Explanation:

It would be potential energy because it is stored. Potential energy = gravity * mass * height. Gravity is 9.8 m/s² or more specific 9.807 m/s². Potential energy is written in Joules.

9.8 * 5 * 3 = 147 Joules

More specific:

9.807 * 5 * 3 = 147.105 Joules

Answer:

The magnitude of acceleration is 9.8 m/s

Explanation:

Its not always in m/s^2 but in m/s due to the unit of distance and time

Answer:

The quantity of heat given to body depends on: (i) The mass of the body, (ii) The rise (or fall) in the temperature of the body, and (iii) Nature of the material of the body.

Explanation:

Hope this helps

have a great day

~Zero

Answer:

0.7m/s

Explanation:

According to the conservation of linear momentum, the moment before a collision is equal to the moment after the collision. The equation is written as follows: [tex]m_{a}u_{a} + m_{b}u_{b} = m_{a}v_{a} + m_{b}v_{b}[/tex], where [tex]m[/tex] is the mass of the object, [tex]u[/tex] is the initial velocity, and [tex]v[/tex] is the final velocity.

Let's say the object [tex]a[/tex] is our moving wagon and the object [tex]b[/tex] is our stationary wagon. [tex]m_{a} = 500kg, u_{a} = 1.6ms^{-1}[/tex],  [tex]m_{b} = 3000kg, u_{b} = 0[/tex], since the wagon is stationary, it doesn't have any initial velocity. After collision, the mass remains the same, but the velocity changes: [tex]v_{a} = ?, v_{b} = 1.5ms^{-1}[/tex]

We can observe that [tex]v_{a}[/tex] is what we're looking for according to the question. Now let's substitute our values.

[tex](5000 * 1.6) + (0) = 5000v_{a} + (3000 * 1.5)[/tex]

[tex]v_{a} = \frac{(5000 * 1.6) - (3000*1.5)}{5000}[/tex] = 0.7m/s