If a compound has a molar mass of 70.13 g/mol and its empirical formula is CH2, what is its molecular formula

Answers

Answer 1

The molecular formula is ALWAYS, a whole number multiple of the empirical formula....and of course the multiple might be one...

And so we can write....

{empirical formula}n=molecular formula

And taking the given molecular mass of 70.13⋅g⋅mol−1

n=70.13⋅g⋅mol^−1/(12.011+1.00794×2)⋅g⋅mol−1=5

And so....

{CH2}×5=C5H10

Answer 2

The empirical formula of the compound is CH₂ . Then, the formula mass is 14 g. If the molar mass of the compound is 70.13 g the compound has the molecular formula of C₅H₁₀.

What is empirical formula ?

The empirical formula of a compound is the formula derived from the number of moles of the constituent elements of the compound. The number of moles of the elements present can be calculated from their given masses and atomic mass.

The formula mass of a compound is the mass of the elements with their number of atoms as in the empirical formula.

given the empirical formula is CH₂.

atomic mass of C = 12 g/mol

atomic mass of H = 1 g/mol

then formula mass = 12 + 2 = 14 g.

Divide the molar mass by formula mass;

molar mass = 70.13 g

70.13 g/14 g =  5

Now, multiply the empirical formula by 5 to get the molecular formula.

ie.  C₅H₁₀.

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Answers

Answer:

16.25g

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Equation for the reaction = Zn + 2Cl = ZnCl2

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The mass of zinc required to combine with 0.5 mol of chlorine to produce zinc chloride is 16.25g.

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The reaction is Zn + 2Cl = ZnCl₂

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Learn more about mass

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A
H
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B
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