If you have 24 questions how many answers can you miss to have a passing grade

Answer:

Step-by-step explanation:

OB = 10 cm

OA = OC = Radius = 4 cm

COS <AB = OA/OB = 4/10 = 2/5 =

COS< COB = OC/OB = 4/10 = 2/5

=> <AOC = <AOB + <COB

=> <AOC = Cos-¹(2/5) + Cos-¹(2/5)

=> <AOC = 2 Cos-¹(2/5)

=> <AOC = 2 * 66.42

=> <AOC = 132.84°

if D is in minor arc then length of arc ADC. = ( 132.84°/360°) 2π = 9.274 cm

if D is in major arc then length of arc ADC. = ((360° -132.84°)/360°) 2π = 15.859 cm

Answer:

V=72x³y³

Step-by-step explanation:

The formula to apply is;

V= l * w * h where

V= volume in units cubed.

l= length = 3xy

w=width = 4xy

h= height = 6xy

Substitute values in the formula as;

V= l*w*h

V=3xy * 4xy * 6xy ----find product for the numbers {3*4*6=72} then multiply by the product for x's {x*x*x =x³} that of y's {y*y*y=y³}

V= 72*x³*y³

V= 72x³y³  --------where xy are the units used.

Answer:

16√3 cm²

Step-by-step explanation:

The perimeter of a triangle is the sum of its all three sides. Since this is an equilateral triangle, all sides are equal.

Let's consider one side of the triangle to be 'x'

Givent that, the perimeter is 24cm,

The equation should be x + x + x = 24

⇒3x = 24

∴ x = 8 cm

To find the area of the triangle, we need to find the height, and for that, we can use trigonometry.

Since it is an equilateral triangle, all angles are exact 60°.

let's draw a line and mark it as 'h'.

we can use sine formula to find out the opposite i.e. h

sin∅ = opposite ÷ hypotaneous

sin 60° = h ÷ 8

h = 8 sin 60°

h= 4√3

Now, let's find the area

Area = 1/2 × base × height

Area = 1/2 × 8 × 4√3

area= 16√3 cm²

Answer:

-17

Step-by-step explanation:

The angles are corresponding angles so when the lines are parallel, the lines are equal

3x-12 = 4x+5

Subtract 3x from each side

3x-12 -3x = 4x+5-3x

-12 = x+5

Subtract 5 from each side

-12 -5 = x+5-5

-17 = x

Answer:

-17

Step-by-step explanation:

The two angles that are shown are *corresponding angles* which means they lie in the same spot, just on two different parallel lines. They are congruent angles. Therefore, you should set up an equation to solve for x. Since the two angles are congruent, you should set the expressions equal to each other. 3x-12=4x+5.

Answer:

x=3

Step-by-step explanation:

Answer:

x = 3

Step-by-step explanation:

3 * 3 * 3 = 27

Hope this helps and pls do mark me brainliest if you can:)

Answer:

$7.50/lb    answer A is correct

Step-by-step explanation:

Find the unit cost:  $ per pound:

 Calculate

      $3.00

--------------------

   (2/5) lb

It's slightly easier to calculate the equivalent

 $3.00

------------- = $7.50/lb    answer A is correct

 0.4 lb

Answer: D. $1.20 per pound

Step-by-step explanation:

Because 2/5= 0.4 in a decimal form.

If you multiply 0.4 times 3= 1.2 just that in D they are adding a zero (0).

1.20= 1.2

Answer:

Range is (-5,5)

Step-by-step explanation:

It is the range of y values for the graph

Answer:

B

Step-by-step explanation:

the line is perpendicular to y=1/2x-3

so its gradient, m, would be -2 (m¹m²= -1)

sub the coordinates and the gradient into this equation to find the equation of line in slope intercept form

y-y¹ = m(x-x¹)

The equation of the line  in slope-intercept form that passes through (-2,2) and is perpendicular to the graph of y= 1/2x-3 is; y = -2x - 2

The equation of the straight line has its slope and given point.

If we have a non-vertical line that passes through any point(x1, y1) and has a gradient m. then general point (x, y) must satisfy the equation

y-y₁ = m(x-x₁)

Where x₁ - x coordinate, y₁ - y coordinate, m - slope

Point (-2,2)

Then the equation of a line perpendicular to the graph of y= 1/2x-3.

its gradient, m, would be; -2 (m¹m²= -1)

Now Write the equation as;

y-y₁ = m(x-x₁)

y - 2= -2(x + 2)

y = -2x - 2

Hence, the equation of the line  in slope-intercept form that passes through (-2,2) and is perpendicular to the graph of y= 1/2x-3 is; y = -2x - 2

Learn more about equations here;

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Answer

There are two common ways of describing or specifying the members of a set: roster notation and set builder notation. These are examples of extensional and intensional definitions of sets, respectively